3. Cameron has been given 4 boxes with samples
of soil. If all of the samples can either be
classified as mineral-rich, mineral-neutral, or
mineral-poor, how many different ways could
Cameron possibly classify all 4 samples, given
that they could all be classified as the same type
if that were the case?
A. 3
B. 4
C. 12
D. 81

The value of q after solving the inequality, 3q-9 ≤ 8q+10, is q ≤ -19/5.

According to the question,

We have the following information:

3q-9 ≤ 8q+10

Adding 9 to both sides of the inequality:

3q ≤8q+10+9

3q ≤ 8q+19

Subtracting 8q from both sides of the expression:

3q-8q ≤ 19

-5q ≤ 19

Dividing both sides by -5:

q ≤ -19/5

(More to know: inequalities can solved like an equation but the only difference is that the sign of equal has to be replaced by the signs of inequality.)

Hence, the value of q after solving the inequality, 3q-9 ≤ 8q+10, is q ≤ -19/5.

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Step-by-step explanation:

domain: x is any value, ⇒ x∈(-∝;+∝);

range: y is not greater, than 4, ⇒ y∈(-∝;4].

Answer:

option 1

Step-by-step explanation:

for every 10 students 4 like mathematics , then

80 ÷ 10 = 8

so 8 × 4 = 32

it is predicted that out of 80 students 32 like mathematics

The type of variable that C is can be said to be the binomial variable.

A binomial random variable counts the number of times a specific event occurs in a given number of tries or trials. To be a binomial random variable, a variable must be There is a set number of trials.

It should be noted that the features of the binomial variable include:

1: The number of observations, n, is constant.

2: Each observation is distinct.

3: Each observation denotes one of two possible outcomes ("success" or "failure").

4: The "success" probability p is the same for each outcome.

In this case, the number of coupons the family wins illustrate a binomial.

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Answer:

slope = 4

Step-by-step explanation:

There are two points plotted at: ( -1 , 0) and ( 0 , 4)

slope = change in rise / change in run

slope = change in y / change in x

slope = (0 - 4) / (-1 - 0)

slope = -4/-1

slope = 4

A is the Point of representation of the colder midnight temperature in degrees Celsius.

The temperature in Quebec City was 5°C at 4 pm. By midnight, the temperature dropped 15 degrees.

To find out which point is a representation of the colder midnight temperature in degrees Celsius:

We know that the temperature dropped 15 degrees, and that it was initially of 5°C. So, by midnight, the temperature will be of -10°C (5-15=-10).

We also know that the distance between points is of 5°C. So, the point that we have to mark is point A, which represents -10°C.

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The equation has a unit rate of 3/4

From the question, we have the following parameters

16y = 12x

The above equation is a linear equation

In fact, it is a linear equation that shows a proportional relationship

Note that all linear equations have a constant rate of change

So, the proportional relationship is given as

16y = 12x

Make y the subject

y = 12/16x

This gives

y = 3/4x

As a general rule

A proportional relationship is represented as y = kx

Where k represents the unit rate

So, we have the following representation

y = 3/4x and y = kx

By comparing the equations

k = 3/4

Hence, the unit rate of the equation is 3/4

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Possible question

Find the unit rate.

16y = 12x

The value of the function f(1) and f(3) is 11 and 1 when the function is f(x)= -2x² + 3x + 10

Given that,

The function is f(x)= -2x² + 3x + 10

We have to find f(1) and f(3).

The core concept of mathematics' calculus is functions. The functions are special types of relations. In mathematics, a function is represented as a rule that produces a distinct result for each input x.

Take the function

f(x)= -2x² + 3x + 10

Take x as 1

f(1)= -2(1)² + 3(1) +10

f(1)= -2+3+10

f(1) = 11

Now, Take x as 3

f(3)= -2(3)² + 3(3) +10

f(3)= -18+9+10

f(3) = 1

Therefore, The value of the function f(1) and f(3) is 11 and 1 when the function is f(x)= -2x² + 3x + 10

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The mean of the given scores is 15.43

It is the average value of the set given.

It is calculated as:

Mean = Sum of all the values of the set given / Number of values in the set

We have,

Score       Mid-values       Frequency      Total score

1 - 7                  4                  19                 19 x 4 = 76

8 - 10               9                  16                  16 x 9 = 144

11 - 15              13                  6                   13 x 6 = 78

16 - 20            18                  14                  18 x 14 = 252

21 - 35            28                 15                  28 x 15 = 420  

36 - 50           43                  4                   43 x 4 = 172

Total                                     74                  1142

Mean = 1142 / 74 = 15.43

Thus,

The mean of the given scores is 15.43

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The geometric sequence in which the 3rd term is of 18 and the 7th term is of 29/8 is defined as follows:

[tex]a_n = 40(0.67)^{n - 1}[/tex]

A geometric sequence is a sequence in which the result of the division of consecutive terms yields always the same result, called common ratio q.

The nth term of a geometric sequence is given by the rule presented as follows:

[tex]a_n = a_1q^{n-1}[/tex]

In which [tex]a_1[/tex] is the first term.

The rule for the nth term is also called the general rule.

The general takes the first term as the reference term, however, the 7th term can be written as a function of the 3rd term, as follows:

[tex]a_7 = a_3q^{4}[/tex]

The fraction that represents the mixed number 3 and 5/8 is:

(3 x 8 + 5)/8 = 29/8.

Then the common ratio of the sequence is calculated as follows:

[tex]\frac{29}{8} = 18q^{4}[/tex]

[tex]q^4 = \frac{29}{144}[/tex]

[tex]q = \sqrt[4]{\frac{29}{144}}[/tex]

[tex]q = \left(\frac{29}{144}\right)^{\frac{1}{4}}[/tex]

q = 0.67.

Then the first term of the sequence is obtained as follows:

[tex]a_3 = a_1q^2[/tex]

[tex]a_1 = \frac{a_3}{q^2}[/tex]

[tex]a_1 = \frac{18}{(0.67)^2}[/tex]

[tex]a_1 = 40[/tex]

Then the definition of the geometric sequence is:

[tex]a_n = 40(0.67)^{n - 1}[/tex]

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In order to hit the UFO, the Anti Aircraft gun should be set an an angle of elevation of approximately 63.435° above the horizontal in the direction of the UFO

An angle of elevation is an angle that the line of sight makes with the horizontal.

The location of the UFO are;

The angle, θ, to which the anti aircraft gun needs to be set is found from the trigonometric ratio for tangent as follows.

[tex]tan(\theta) = \dfrac{Length \, of \, the \, side \, opposite \, to \, angle \, \theta}{Length \, of \, the \, side \, adjacent \, to \, \theta}[/tex]

The length of the side opposite to the angle θ to which the gun should be directed is the length of the height of the UFO from the observer, therefore;

Length of the side opposite to θ = 100 feet

Length of the side adjacent to θ is the length of the horizontal distance from the observer;

Length of the adjacent side to θ = 50 feet

Therefore;

[tex]tan(\theta) = \dfrac{100\, feet}{50\, feet} = 2[/tex]

tan(θ) = 2

θ is found using the inverse tangent function (arctangent) as follows;

θ = arctan(2) ≈ 63.435°

The direction the anti aircraft un should be set is at angle of elevation of approximately 63.435° above the horizontal

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The number of tapes Melanie must sell to break even is 360 tapes.

To find the number of tapes Melanie must sell to break even, we must follow these steps.

We must identify how much she earns for each tape that she sells, for this we must subtract the sale price of each tape, by the value that she pays to make each tape.

Now we must divide the total cost of the mother tape by the profit she makes on each tape she sells.

Based on the above, we can infer that she must sell 360 tapes to cover the value of the mother tape and each of the tapes that she needs to sell. Next it is checked:

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The projected cash receipts for April and the projected cash receipts for May can be found to be:

The projected cash receipts in April would be:

= ( 25% x Projected sales for April ) + ( 75% x Projected sales for March)

= (25% x 210, 000) + ( 75% x 180, 000)

= 52, 500 + 135, 000

= $187, 500

The projected cash receipts for May is then:

= ( 25% x Projected sales for May ) + ( 75% x Projected sales for April )

= ( 25% x 195, 000) + ( 75% x 210, 000)

= $ 48, 750 + 157, 500

= $206, 250

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Answer:1 hour and 15 minutes

Step-by-step explanation:

so it takes her 34 minutes for 4 problems so for 2 problems its 17 minutes

and then you do the 34 times 2 because its 4 problems so you add that and that = 68 minutes and then you add 17 for the 2 problems and thats 85 minutes or 1 hour and 15 minutes

Answer:

1 hour & 25 minutes (85 minutes)

Step-by-step explanation:

Time taken for 1 problem,

→ 34 ÷ 4

→ 8.5 minutes

Now time taken for 10 problems,

→ 8.5 × 10

→ 85 minutes

Hence, answer is 85 minutes.

The equation (in slope-intercept form) of the line passing through the points (5,3) and (4,1) is y = 2x -7

The equation of a line in slope intercept form can be represented as follows:

y = mx + c

where

let's find the slope as follows:

(5, 3)(4, 1)

m = 1 - 3 / 4 - 5

m = - 2 / -1

m = 2

Therefore, let's find the y-intercept using (4, 1)

y = 2x + c

1 = 2(4) + c

c = 1 - 8

c = -7

Therefore, the equation of the line is y = 2x -7

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The estimates for the number of transistors per IC, using Moore's Law, are given as follows:

Moore's Law states that the number of transistors per IC is expected to double every two years.

From the chart shown by the image at the end of the answer, the reference number is given as follows:

4000 transistors per IC in 1972.

The number of years between 1972 and 2012 is of:

2012 - 1972 = 40.

Hence the number of doubling periods is of:

40/2 = 20 doubling periods.

Thus the estimate for the number of transistors per IC in 2012 = 20 doubling periods is of:

4000 x 2^20 = 4,194,304,000 transistors per IC.

The number of years between 1972 and 2040 is of:

2040 - 1972 = 68.

Hence the number of doubling periods is of:

68/2 = 34 doubling periods.

Thus the estimate for the number of transistors per IC in 2012 = 20 doubling periods is of:

4000 x 2^34 = 6.87 x 10¹³ transistors per IC.

The chart is given by the image at the end of the answer.

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The next number in the number sequence using inductive reasoning 100,90,92,82,84,74,76,… is 66.

What is number series?

 A series is a way of speaking casually of numbers. It is the total of a sequence's terms. A series of numbers is called a number series. We must identify the laws that lead to the production of a number series in order to answer the questions about number series. The questions that might arise from these topics are as varied as these series themselves.

Here the given number series,

=> 100,90,92,82,84,74,76,….

Here , first term = 100

Second term = 100-10=90

Third term= 90+2=92

Fourth term = 92-10=82

Fifth term = 82+2=84

Sixth term = 84-10=74

seventh term = 74+2=76

Eighth term= 76-10 = 66.

Therefore next term of the number Series is 66.

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Yes, Dan productivity is constant and slope is given as 3/2.

What is slope?

The slope of a line is also called its gradient or rate of change. The slope formula is the vertical change in y divided by the horizontal change in x, sometimes called rise over run. The slope formula uses two points, (x1, y1) and (x2, y2), to calculate the change in y over the change in x.

Let we take one pair of point (4,6) and (2,3) and other pair of point is (6,9) and (0,0)

The slope between  (4,6) and (2,3)  is

m = y2-y1/x2-x1

m = 3-6/2-4

=3/2

The slope between (6,9) and (0,0)

m = 0-9/0-6

=3/2

Hence, both the slopes are equal, therefore his work is constant.

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The domain is the set of all real numbers and the range is:

R: (-∞, 4]

For any function, we define the domain as the set of possible inputs, the ones in the horizontal axis, and the range as the set of the output, the ones in the vertical axis.

We can see that we have a parabola that in the bottom part has two arrows, so it extends in the wole domain (the set of all real numbers).

Instead for the range we can see that there is a maximum at y  = 4, so the range is:

R: (-∞, 4]

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The graph of the system of equations shows that there is no solution to the system.

To solve a system of equations by graphing, plot each of the lines on a graph. Then, find the point where both lines intersect each other.

The x-coordinate and the y-coordinate of the point where both lines of the equations intersect is the solution to the system.

Given the system of equations, x = -y and x + y = 7, both lines have been plotted on a graph shown below. It shows that there are is no point of intersection which means the system of equations have no solution.

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The equation for the situation is written as y = 35x + 10

Information gotten from the question include

a tank is filing with petrol at rate of 35 liter per minute

the tank already had 10 liters in it before the filling began

A linear function consists of functions where the variables has exponents of 1. The graph of linear functions is a straight line graph and the relationship is expressed in the form.

y = mx + c

Definition of variables to suit the problem to be solved

y = total petrol in  the tank in  liters

m = rate of filling liter per minute = 35

x = number of liters

c = quantity prior to filling = 10

The equation is written as

y = 35x + 10

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10 kilograms of the 50% fat-content chocolate and 20 kilograms of the 20%, fat-content chocolate are used to make the required 30 kilograms.

Equations are statements that affirm the equivalence of two expressions that are joined by the equals symbol "=". An equal sign ("=") links two expressions together to form an equation.

The two expressions on each side of the equals sign are referred to as the "left-hand side" and "right-hand side" of the equation. The right side of an equation is typically assumed to be zero. Since we can balance this by deducting the expression on the right from the expressions on both sides, this won't reduce the generality.

Suppose the amount of 50% fat content chocolate is x and the amount of 20% fat content chocolate is y,

Since the candy company wants to produce 30 kilograms,

x+y=30 -----(1)

If a candy manufacturer wishes to meet the dietary requirements of its customers, it may make 30 kg of special chocolate with a 30% fat content. A specific melting procedure is used to blend local chocolate with 20% fat content with foreign chocolate with 50% fat content to create this. The resultant equation reads,

50x + 20y = 30(30)

5x+2y=90 -------(2)

After solving the equation 1 and 2 we get,

x=10

y=20

Thus, 10 kilograms of the 50% fat-content chocolate and 20 kilograms of the 20%, fat-content chocolate are used to make the required 30 kilograms.

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Answer: 28 and 45

Step-by-step explanation: you add 11 and 17 to get 28 and then add 28 and 17 to get 45

The measure of  the angle AEG = 92°

Corresponding angles are the angles that are formed when two parallel lines are intersected by the transversal. The opening and shutting of a lunchbox, solving a Rubik's cube, and never-ending parallel railway tracks are a few everyday examples of corresponding angles. These are formed in the matching corners or corresponding corners with the transversal.

∠CFH + ∠EFC = 180( angles on a straight line)

making ∠EFC subject and substituting ∠CFH = 2x + 20, we have

∠EFC = 180 - ( 2x + 20)

∠EFC = 180 - 2x -20

∠EFC = 160 - 2x

but ∠EFC = ∠BEF ( alternate angles are equal)

substituting their values

160 - 2x = 3x - 10

collect like terms

-2x - 3x = -10 - 160

-5x = -170

x = -170/-5

x = 34

Also ∠EFC = ∠AEG = 160 -2x ( corresponding angles are equal)

∠AEG = 160 -2X, but x = 34

∠AEG = 160 - 2(34)

∠AEG =160 - 68 = 92°

In conclusion, The value of the ∠AEG = 92°

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The addition using Least multiple, [tex]\frac{2}{8}+\frac{1}{2}[/tex] is equal to [tex]\frac{3}{4}[/tex].

When two or more fractions are there, the least common denominator is the lowest number among all the common multiples of the denominators.

To find the LCD of numbers, factorization method can be used and if the numbers are co-prime then the LCD is just the multiplication of those numbers.

The denominator of given fractions is 8 and 2.

Now, finding the lowest common multiple of 8 and 2,

LCD is 8,

Now, renaming the fraction by multiplying 4 on numerator and denominator of [tex]\frac{1}{2}[/tex],

[tex]\frac{1 \times4}{2 \times4} =\frac{4}{8}[/tex]

Now, denominator is same, so adding the fractions,

[tex]\frac{2}{8}+\frac{4}{8} =\frac{2+4}{8} \\\\=\frac{6}{8}[/tex]

Dividing the numerator and denominator by 2,

[tex]\frac{6}{8} =\frac{6/2}{8/2}\\ =\frac{3}{4}[/tex]

Therefore, by adding the given fractions we get [tex]\frac{3}{4}[/tex].

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Answer:

105 Children and 3 cooks

Step-by-step explanation:

I took the test :)

a) The total number of children watching the movie is 105 children

b) The total number of cooks that worked at the event is 3 cooks

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

a)

Let the number of children be = a

Let the number of adults be = b

Let the total number of people in the theater be = 140

Now , the equation will be

a + b = 140   equation (1)

And , the number of children present is 3 times the number of adults

So ,

a = 3b

Divide by 3 on both sides of the equation , we get

b = a/3

Substituting the value of b in equation (1) , we get

a + b = 140

a + a/3 = 140

( 4a ) / 3 = 140

Multiply by 3 on both sides of the equation , we get

4a = 420

Divide by 4 on both sides of the equation , we get

a = 105

Therefore , the value of a is 105 and the number of children watching the movie is 105 children

b)

Let the number of cooks be = x

Let the number of waiters be = y

Let the amount for each cook be = $ 85

Let the amount for each waiter be = $ 45

The total number of workers = 10

Now , the equation will be

x + y = 10   be equation (1)

The total amount paid to the employees be = $ 570

Now , the equation will be

85x + 45y = 570   be equation (2)

On simplifying equation (1) and equation (2) , we get

Multiply equation (1) by 45 , we get

45x + 45y = 450   be equation (3)

Subtract equation (3) from equation (2) , we get

40x = 120

Divide by 3 on both sides of the equation , we get

x = 3

Therefore , the value of x is 3 and the number of cooks that worked in the event is 3 cooks

Hence ,

a) The total number of children watching the movie is 105 children

b) The total number of cooks that worked at the event is 3 cooks

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The number of packages that need to be delivered daily by UpEx to make a profit of $32 is 115 packages

First, find the contribution margin of each package:

= Charge to deliver package - Cost to deliver package

= 3.50 - 1.50

= $2.00

To find the number of packages needed to make a profit of $32, the formula is:

= (Fixed cost + projected profit) / Contribution margin

= ( 198 + 32) / 2

= 230 / 2

= 115 packages

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Answer:

  (-12, 10)

Step-by-step explanation:

You want to solve by elimination the system of equations ...

The point of elimination is to make one of the variables disappear from the equation.

Here, we observe that the x-coefficients are opposites in the two equations. When we add them, the result is 0: the x-term disappears. Adding the two equations, we have ...

  (2x +4y) +(-2x -3y) = (16) +(-6)

  y = 10 . . . . . . . . simplified

Using this value for y, we can find x. Substituting into the first equation gives ...

  2x +4(10) = 16

  2x = 16 -40 = -24 . . . . . subtract 40 and simplify

  x = -12 . . . . divide by 2

The ordered pair that is the solution is (x, y) = (-12, 10).

The domain of the given function { x | x ≥ -4 } & { y l y ≥ 2 } is

[ -4 , ∞ ).

Given, a graph of the function,

{ x | x ≥ -4 }

{ y l y ≥ 2 }

Now, we have to find the domain of the function

As, we know that the domain of a function is the set of real values on which the given function is defined.

so, it is clear that the function is defined for all the real values greater than or equal to -4.

Hence, the domain of the given function { x | x ≥ -4 } & { y l y ≥ 2 } is

[ -4 , ∞ ).

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