3-2 Roof area can be broken down into three basic shapes: rectangle, triangle, and trapezoid. (True or False)

A right pyramid with an isosceles triangle base has one plane of symmetry.

A plane of symmetry is a plane that can be passed through an object such that the object is divided into two halves that are mirror images of each other.

In the case of a right pyramid with an isosceles triangle base, if a plane passes through the apex (the top point) of the pyramid and is perpendicular to the base, it will bisect the base into two halves that are mirror images of each other. This is the only plane of symmetry that exists for this particular pyramid.

Thus, the right pyramid with isosceles triangle base has one plane of symmetry.

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Answer:

21. x=70

22. x=15

*Not sure what the red arc is, but I found the value of x for both 21 and 22*

Step-by-step explanation:

Let's start with 21 first.

Line AB is a straight line, meaning the arc length of AB is 180 degrees.  So,

(2x-30)+x=180

let's solve:

3x-30=180

3x=210

x=70

I'm not sure what the red arc is, so I can't help you there.

Next, 22.

All the arcs in a complete circle need to add up to 360 degrees, so:

4x+6x+7x+7x=360

simplify first:

24x=360

let's solve:

x=15

Again, not sure where or what the red arc is, so can't help again.  I hope that the x values help.

Answer:

66/5 or 13.2

Step-by-step explanation:

..........

Inequality for this scenario

x ≤ 4.75

So, each package must weigh less than or equal to 4.75 pounds in order for Devin to stay within the weight limit of 40 pounds on Ernest Airlines.

Let x be the weight of each package (in pounds).

The inequality for the scenario can be written as:

21 + 4x ≤ 40

This represents the total weight of Devin's clothes (21 pounds) plus the total weight of the four packages (4x pounds) cannot exceed the weight limit of 40 pounds on Ernest Airlines.

To solve for x, we can subtract 21 from both sides of the inequality:

4x ≤ 40 - 21

4x ≤ 19

Finally, we divide both sides by 4 to isolate x:

x ≤ 19 / 4

Let x be the weight of each package (in pounds).

The inequality for the scenario can be written as:

21 + 4x ≤ 40

This represents the total weight of Devin's clothes (21 pounds) plus the total weight of the four packages (4x pounds) cannot exceed the weight limit of 40 pounds on Ernest Airlines.

To solve for x, we can subtract 21 from both sides of the inequality:

4x ≤ 40 - 21

4x ≤ 19

Finally, we divide both sides by 4 to isolate x:

x ≤ 19 / 4

x ≤ 4.75

So, each package must weigh less than or equal to 4.75 pounds in order for Devin to stay within the weight limit of 40 pounds on Ernest Airlines.

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the least common multiple of 43, 24, and 17 is 87,672.To find the least common multiple (LCM) of three numbers, we first need to find their prime factorization.

what is prime factorization ?

Prime factorization is the process of finding the prime numbers that multiply together to give a given composite number. A composite number is any positive integer greater than 1 that is not itself a prime number.

In the given question,

To find the least common multiple (LCM) of three numbers, we first need to find their prime factorization.

Prime factorization of 43: 43 is a prime number, so its prime factorization is simply 43.

Prime factorization of 24: 24 can be factored as 2 × 2 × 2 × 3.

Prime factorization of 17: 17 is a prime number, so its prime factorization is simply 17.

Next, we find the highest power of each prime factor that appears in any of the three factorizations:

The prime factor 2 appears to the third power in the factorization of 24, and to the first power in the factorizations of 43 and 17.

The prime factor 3 appears to the first power in the factorization of 24, and to the zero power in the factorizations of 43 and 17.

The prime factor 17 appears to the first power in the factorization of 17, and to the zero power in the factorizations of 43 and 24.

The prime factor 43 appears to the first power in the factorization of 43, and to the zero power in the factorizations of 24 and 17.

Therefore, the LCM of 43, 24, and 17 is:

2³ × 3¹ × 17¹ × 43¹ = 87,672

Hence, the least common multiple of 43, 24, and 17 is 87,672.

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Then the answer is C. not a real number

An exponent of 1/2 is equivalent to the square root, so we can write:

√-25

That is the square root of a negative number, so we will get the complex numbers ±i

Then the answer is C.

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The distance between Thomas St and Denny Way on Broad St is approximately 0.2 miles (rounded to the nearest tenth of a mile).

To determine the distance between Thomas St and Denny Way on Broad St, we can use the Pythagorean theorem.

Let x be the distance between Thomas St and Denny Way on Broad St. We can draw a right triangle where the hypotenuse is 0.2 miles (the distance between Thomas St and Denny Way on Aurora Ave), and one leg is x (the distance between Thomas St and Denny Way on Broad St). The other leg is the distance between Aurora Ave and Broad St.

Using the Pythagorean theorem, we have:

[tex]0.2^2 = x^2 + d^2[/tex]

where d is the distance between Aurora Ave and Broad St.

Assuming d is negligible, we can solve for x:

[tex]x^2 = 0.2^2 - d^2x^2 = 0.2^2x = sqrt(0.2^2) = 0.2[/tex]

Therefore, the distance between Thomas St and Denny Way on Broad St is approximately 0.2 miles (rounded to the nearest tenth of a mile).

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The 95% confidence interval for the true mean weight loss is (11.168, 18.832).

To find the 95% confidence interval for the true mean weight loss, we can use the formula:

CI = x(bar) ± t*(s/√n)

where:

x(bar) = sample mean weight loss

s = sample standard deviation of weight loss

n = sample size

t = t-value from the t-distribution table with (n-1) degrees of freedom and a 95% confidence level

Using the values given in the table, we have:

x(bar) = 15

s = 3.786

n = 7

The t-value for a 95% confidence level with 6 degrees of freedom (n-1) is 2.447.

Substituting these values into the formula, we get:

CI = 15 ± 2.447*(3.786/√7)

CI = 15 ± 3.832

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The closest option is (b) 23 12/15.

What are mean in statistics?

Mean: The average of a set of values, is calculated by adding up all the values in the set and dividing by the total number of values.

To find the mean (average) of the data set, we need to first find the sum of all the lengths of roses multiplied by their respective frequencies, and then divide by the total number of roses:

(22 x 2) + (23 x 4) + (24 x 5) + (25 x 3) + (26 x 1) = 344

Total number of roses = 2 + 4 + 5 + 3 + 1 = 15

Mean = Sum of all lengths / Total number of roses = 344 / 15 ≈ 22.93 cm

Rounding to the nearest whole number, the mean length of roses in this data set is 23 cm. Therefore, the closest option is (b) 23 12/15.

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For the region above x + 3y = 9 and below x + 9 = y², we have:

a = 18, b = -9, f(x) = (y² - 9)/3, and g(x) = (9 - x)/3.

For single integration: α = -6, β = 3 and h(y) = [(9 - y²)/3 - (y² - 9)].

To solve this problem, we first need to find the intersection points of the two curves x + 3y = 9 and x + 9 = y². We can do this by solving the system of equations:

x + 3y = 9

x + 9 = y²

Rearranging the first equation, we get:

x = 9 - 3y

Substituting this expression for x into the second equation, we get:

9 - 3y + 9 = y²

Simplifying, we get:

y² - 3y - 18 = 0

Factorizing, we get:

(y - 6)(y + 3) = 0

So the solutions are:

y = 6 or y = -3

Substituting these values of y into the equation x + 3y = 9, we get:

When y = 6, x = -9

When y = -3, x = 18

So the intersection points of the two curves are (-9, 6) and (18, -3).

Now we can find the area between the two curves by splitting it into two regions: the region above the curve x + 3y = 9 and below the curve x + 9 = y², and the region below the curve x + 3y = 9 and above the curve x + 9 = y².

For the region above x + 3y = 9 and below x + 9 = y², we have:

a = 18

b = -9

f(x) = (y² - 9)/3

g(x) = (9 - x)/3

Alternatively, to compute the area between the two curves x + 3y = 9 and x + 9 = y² using a single integral, we need to express the area as a function of y instead of x.

We can rearrange the equations x + 3y = 9 and x + 9 = y² to get:

x = 9 - 3y

x = y² - 9

Setting these two expressions equal to each other, we get:

9 - 3y = y² - 9

Simplifying, we get:

y² + 3y - 18 = 0

Factorizing, we get:

(y + 6)(y - 3) = 0

So the solutions are:

y = -6 or y = 3

Substituting these values of y into the equation x + 3y = 9, we get:

When y = -6, x = 27

When y = 3, x = 0

So the intersection points of the two curves are (27, -6) and (0, 3).

The area between the curves can be expressed as the difference between the integrals of the curves' respective functions with respect to y, since the curves are better expressed in terms of y.

The function representing the curve x + 3y = 9 in terms of y is:

x = 9 - 3y

We can rearrange this equation to get:

y = (9 - x)/3

Substituting x = y² - 9, we get:

y = (9 - y² + 9)/3

Simplifying, we get:

y² + 3y - 18 = 0

This is the same equation we obtained before, so we know that the bounds of integration are -6 and 3.

The function representing the curve x + 9 = y² in terms of y is:

x = y² - 9

Substituting this expression into the formula for the area of a region between two curves, we get:

Area = ∫(y=α)^(y=β) [(9 - y²)/3 - (y² - 9)] dy

Where;

α = -6 and β = 3 are the bounds of integration, and

the integrand [(9 - y²)/3 - (y² - 9)] represents the difference between the y-values of the two curves at a given x-value.

Simplifying the integrand, we get:

Area = ∫(y=-6)^(y=3) (18 - 2y²)/3 dy

Integrating, we get:

Area = [(6y - (2/3)y³)/3] |(y=-6)^(y=3)

Plugging in the limits of integration, we get:

Area = [(18 - 216)/3] - [(-36 + 216)/3]

Simplifying, we get:

Area = 66

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Answer:

$2,611.9.

Step-by-step explanation:

To find the operating cost for the lowest 2% of the airplanes, we need to find the corresponding z-score from the standard normal distribution using a z-table.

Using the formula:

z = (x - μ) / σ

where x is the cost we are interested in, μ is the mean cost, and σ is the standard deviation.

For the lowest 2% of airplanes, the z-score can be found by looking up the area to the left of z in the z-table. This area is 0.02.

Looking up 0.02 in the z-table gives a z-score of approximately -2.05.

So we have:

-2.05 = (x - 3403) / 398

Solving for x, we get:

x = -2.05 * 398 + 3403 = $2,611.9

Therefore, the operating cost for the lowest 2% of the airplanes is approximately $2,611.9.

We got x = 84.50 by using Pythagorean theorem.

angle of semicircle is always be 90°.

[tex]115^2 = 78^2 + x^2[/tex]

[tex]13225 = 6084 + x^2[/tex]

[tex]x^2 = 13225- 6084[/tex]

[tex]= 7141[/tex]

[tex]x = \sqrt{7141}[/tex]

[tex]x = 84.50[/tex]

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The theoretical probability of a fair coin landing on heads is 1/2 or 0.5. The experimental probability of landing on heads is also 0.5, which matches the theoretical probability.

Probability is a measure of the likelihood or chance of an event occurring. It is a number between 0 and 1, with 0 representing an impossible event and 1 representing a certain event. The probability of an event is calculated by dividing the number of ways the event can occur by the total number of possible outcomes.

Part A: The theoretical probability of a fair coin landing on heads is 1/2 or 0.5.

Part B: Let's record the outcomes of flipping a coin 14 times and count the frequency of each outcome:

HHHHHHHHHHHHHH - 14 heads

TTTTTTTTTTTTTT - 14 tails

The frequency of heads is 14, and the frequency of tails is also 14.

To find the experimental probability of landing on heads, we divide the frequency of heads by the total number of flips:

experimental probability of heads = frequency of heads / total number of flips = 14 / 28 = 0.5

The experimental probability of landing on heads is the same as the theoretical probability. This is not surprising since the number of trials is large enough to approach the theoretical probability.

Therefore,The theoretical probability of a fair coin landing on heads is 1/2 or 0.5. The experimental probability of landing on heads is also 0.5, which matches the theoretical probability.

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Answer:

All of the above.

Quadrilateral's must have at the maximum 4 equal sides, or the minimum 2 equal sides.

a square has 4 equal sides.

a rectangle has 2 equal side. (that add up to 4 because each side is a pair of 2)

a rhombus can be a quadrlaterial depending on the shape.

a parrellelogram mostly have atleast 2 equal sides.

and a trapezoid mostly has atleast 2 equal sides.

Hope this helps!

Answer:

C

Step-by-step explanation:

Recall the point-slope form of a linear equation:

[tex]y-y_{1}=m(x-x_{1} )[/tex]

Where y1 and x1 are points from the ordered pair (x1, y1),

and m represents the slope of the line.

We are given that the point (-5, 7) belongs to the graph. Here, the x-coordinate is -5, and the y-coordinate is 7.

Let's plug in these values, were x1=-5, and y1=7:

[tex]y-y_{1}=m(x-x_{1} )=\\y-7=m(x-(-5))=\\y-7=m(x+5)[/tex]

We are also given that the slope is -4/3.

In other words, m=-4/3. Let's plug this value in:

[tex]y-7=m(x+5)=\\y-7=-\frac{4}{3}(x+5)[/tex]

Thus, the answer is C.

Answer:

C

Step-by-step explanation:

The point-slope form of the equation of a line passing through the point (x1, y1)with a slope of m is given by:

y - y1 = m(x - x1)

To find the equation of the line passing through the point (-5, 7)with a slope of -4/3, we substitute m = -4/3, x1 = -5, and y1 = 7 into the point-slope form equation:

y - 7 = (-4/3)(x - (-5))

Simplifying this equation, we get the final result in slope-intercept form:

y = (-4/3)x + (17/3)

Therefore, the equation of the line in a point-slope form that passes through (-5,7) and has a slope of -4/3 is y + 7 = -4/3 (x + 5)

Answer:

below

Step-by-step explanation:

Yes, there is another exponent.

When you are multiplying exponents, you add the exponents.

So from the equation 2^6 x 2^5, you can keep the 2 the same, as this is the base:

2^11

and add the exponents (6+5)

To check:

2^6=64

2^5=32

64x32=2048

2^11=2048

So, 2^11 is equivalent to your equation.  Hope this helps ;)

Answer:

137%

Step-by-step explanation:

1.37 x 100 = 137%

As a result, the function's slope at [1, pi/2] is [-24] as where the derivative of y with respect to x is denoted by y'.

The slope of a line in mathematics serves as a gauge for how steep it is. Between any two locations on the line, it is the proportion of the shift in the vertical motion (y) to the shift in the horizontal position (x). If we take into account two points on a line, (x1, y1) and (x2, y2), we can use the following formula to get the slope of the line: slope equals (y2 - y1)/. (x2 - x1) . Depending on the line's direction, the inclination can be zero, positive, or negative. A line with a positive slope is moving upward from left to right, whereas one with a negative slope is moving downward.

given

Finding the derivative of the given function with respect to x can be our first step. By applying the quotient rule, we get:

F(x) = 8x 3 sin (y)

[tex][(sin(y))(-24x2)] = f'(x) - (-8x^3) (cos(y))(y')] / (sin(y))^2[/tex]

where the derivative of y with respect to x is denoted by y'.

We can change x=1 and y=pi/2 in the equation above since we are interested in the slope at the position [1, pi/2].

Due to the fact that cos(pi/2) = 0 and sin(pi/2) = 1, we can write:

[tex]f'(1) = [(1)(-24) (-24) - (-8)(1)(0)(y')] / (1)^2[/tex]

f'(1) = -24 + 0

f'(1) = -24

As a result, the function's slope at [1, pi/2] is [-24] as where the derivative of y with respect to x is denoted by y'.

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The value of v is 13 degrees.

Supplementary angles are a set of given measure of angles which add up to 180 degrees. Thus producing a measure of the sum of angles on a straight line.

To determine the value of v in the given diagram, we have;

60 + (9v + 3) = 180       (sum of angles on a straight line)

So that;

9v + 3 = 1890 - 60

9v + 3 = 120

9v = 120 - 3

    = 117

v = 117/ 9

  = 13

v = 13^o

The value of v in the question is 13 degrees.

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Answer:

1 x 10^-12

Step-by-step explanation:

....

The most useful visual representation of the teacher's data on the preferred subjects of 100 kids at the school would be a histogram. answer is option (a).

In a histogram, which is a graphical depiction of the distribution of a set of continuous or discrete data, the height of a bar above the bin on the x-axis represents the frequency or count of the data falling within each bin. On the y-axis of the histogram, the frequency or count of the data points that fall into each bin is displayed.

The most useful visual representation of the teacher's data on the preferred subjects of 100 kids at the school would be a histogram. In a histogram, bars are used to illustrate the frequency distribution of a group of continuous or discrete data points.

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The mean of the following data 0,5,30,25,16,18,19,26,0,20,28 is 17.

Hence option D is the correct option.

Mean is the average value of a given set of data. It is calculated by the formula,

Mean =  {Summation of all the values in the data set} / {Number of observations is the data set}

That is, Mean = {Σ all values in the data set} / {number of observations}

The given data set is as follows,

0,5,30,25,16,18,19,26,0,20,28

The number of observations in the data set is 11.

The summation of all the values in the data set is = {0 + 5 + 30 + 25 +
16 + 18 + 19 +26 + 0 + 20 + 28} = 187

Therefore, by applying  the formula of Mean we get

Mean = 187/ 11 = 17

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The height of the antenna is approximately 29 meters.

The point of rise is a point that is framed between the even line and the view. An angle of elevation is formed when the line of sight extends upward from the horizontal line.

We should refer to the level of the structure as "h" and the level of the receiving wire "x". Two equations can be created with the help of the tangent function:

Since the elevation angle to the roof is 32 degrees,

tan(32) = h/20, and

tan(43) = (h+x)/20

because the elevation angle to the antenna's peak is 43 degrees.

We can solve for "h" in the first equation by multiplying both sides by 20:

h = 20 tan(32)

We can substitute this expression for "h" into the second equation:

tan(43) = (20 tan(32) + x)/20

Now we can solve for "x":

x = 20 tan(43) - 20 tan(32)

We can then add the height of Isaiah's eyes (1.62 meters) to get the total height of the antenna:

height = x + 1.62

Plugging in the values and using a calculator, we get:

height ≈ 28.7 meters

As a result, the antenna stands about 28.7 meters tall. The answer is 29 meters when rounded to the nearest meter.

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Is the relation a function:

To determine if the relation is a function, we need to check if there is exactly one output for each input.

Looking at the given set of points, we see that there are two points with an x-coordinate of -1: (-1, 3) and (-1, -2).

This means that there are two outputs for the same input, so the relation is not a function.

Therefore, the correct answer is: "No, because for each input there is not exactly one output."

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False. The environmental lapse rate, which changes based on various variables like humidity and atmospheric stability, is the real rate at which temperature decreases with increasing altitude in the atmosphere.

The pace at which a parcel of dry air cools as it ascends in the atmosphere, on the other hand, is known as the dry adiabatic rate and is set at around 9.8 degrees Celsius per 1000 meters of ascension.

Although it is not often the same, the environmental lapse rate can occasionally be comparable to the dry adiabatic rate. The environmental lapse rate can differ from the dry adiabatic rate due to things like the presence of moisture or atmospheric instability.

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A blocked design compares different independent variable levels by using homogeneous groups of experimental units.

In this type of experimental design, subjects are divided into homogeneous groups, or blocks, based on similar characteristics or traits. These blocks help to control or account for potential confounding variables that may affect the outcome of the experiment.

By grouping subjects into blocks, researchers can reduce the variability within each group and increase the accuracy of the experimental results. This allows for a more precise comparison of the effects of different levels of the independent variable on the dependent variable. Blocked designs are particularly useful when there are natural groupings within the experimental units or when the variability between units is high.

In summary, a blocked design is a powerful experimental tool that can help researchers account for potential confounding factors and reduce variability among experimental units. By doing so, it enables the accurate comparison of different levels of the independent variable, ultimately leading to more reliable and valid results.

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