2^5×8^4/16=2^5×(2^a)4/2^4=2^5×2^b/2^4=2^c
A=
B=
C=
Please I'm gonna fail math

9514 1404 393

Answer:

  a = 3, b = 12, c = 13

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

  (a^b)^c = a^(bc)

___

You seem to have ...

  [tex]\dfrac{2^5\times8^4}{16}=\dfrac{2^5\times(2^3)^4}{2^4}\qquad (a=3)\\\\=\dfrac{2^5\times2^{3\cdot4}}{2^4}=\dfrac{2^5\times2^{12}}{2^4}\qquad (b=12)\\\\=2^{5+12-4}=2^{13}\qquad(c=13)[/tex]

_____

Additional comment

I find it easy to remember the rules of exponents by remembering that an exponent signifies repeated multiplication. It tells you how many times the base is a factor in the product.

  [tex]2\cdot2\cdot2 = 2^3\qquad\text{2 is a factor 3 times}[/tex]

Multiplication increases the number of times the base is a factor.

  [tex](2\cdot2\cdot2)\times(2\cdot2)=(2\cdot2\cdot2\cdot2\cdot2)\\\\2^3\times2^2=2^{3+2}=2^5[/tex]

Similarly, division cancels factors from numerator and denominator, so decreases the number of times the base is a factor.

  [tex]\dfrac{(2\cdot2\cdot2)}{(2\cdot2)}=2\\\\\dfrac{2^3}{2^2}=2^{3-2}=2^1[/tex]

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