2. Write the correct equation that you would use to solve for side x.
Z
X
520
y = 13cm
Z
Y
Answers
The correct equation that could be used to solve for side x is x = sin52° × (Hypotenuse)
Trigonometry: Determining the correct equation to solve for side xFrom the question, we are to determine the correct equation that could be used to solve for side x
From the given diagram, we observe that
Side x is the Opposite
Side z is the Adjacent
Side y is the Hypotenuse
Using SOH CAH TOA, we can write that
sin (angle) = Opposite / Hypotenuse
From the diagram,
Given angle = 52°
Hypotenuse = y = 13
Thus,
sin 52° = x/13
x = sin 52° × 13
OR
x = sin52° × (Hypotenuse)
Hence, the equation is x = sin52° × (Hypotenuse)
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Related Questions
which represents a rotation of 189
degrees?
(X,y) -> (-X,-y)
(X,y) -> (X,-y)
(X,y) -> (y,X)
(X,4) -> (-X,4)
Answers
The required rotation of the 180° is given by, (X,y) -> (-X,-y), option A is correct and the required translation is given by (x + 6, y - 2), option D is correct.
Given that,
To determine which option shows the rotation of 180°, and translation of right 6 units and down 2 units.
Coordinate, is represented as the values on the x-axis and y-axis of the graph. while the coordinate x is called abscissa and the coordinate of the y is called ordinate.
Here,
For the rotation of the 180°, the given coordinate undergoes the change in direction so the required coordinate after 180° rotation is given as (-x, -y).
Now, for the translation of 6 units right we must add x with 6 and for 2 units down we must subtract y by 2, the required translation is given as(x + 6, y -2).
Thus, the required rotation of the 180° is given by, (X,y) -> (-X,-y), and the required translation is given by (x + 6, y - 2).
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Please help these lessons are confusing me
Answers
Answer: y-9 = 17(x+7)
Step-by-step explanation:
We will use the second coordinate point to use in the equation and the first coordinate (-8, -8) to figure out the slope of this line.
Answer:
y-9=17x+119
Step-by-step explanation:
given points (-8,-8) & (-7,9)
let's take (-7,9) as (x1,y1) and (-8,-8) as (x2,y2)
now for finding out equation through two points, we use
[tex] \frac{x-x_{1} }{x_{1}-x_{2} } =\frac{y-y_{1} }{y_{1}-y_{2} } [/tex]
So accordingly, we input the values
[tex] \frac{x-(-7) }{-7-(-8)} } =\frac{y-9 }{9-(-8) } [/tex]
[tex] \frac{x+7 }{-7+8} } =\frac{y-9 }{9+8 } [/tex]
[tex] \frac{x+7 }{1} } =\frac{y-9 }{17 } [/tex]
[tex] 17(x+7) = y-9 [/tex]
[tex] 17x+119 = y-9 [/tex]
Make the subject of
x − 5 = t
Answers
add 5 on both sides
this will cancel the five on the left side
as you are making x the subject your answer will be: x = t + 5
Define the formula for a parabola (a quadratic function) that has horizontal intercepts (roots) at x=9.9 and x = 8.7 and passes through the point ( 0, 8.5 )
Answers
Answer:
ft HD st he do it to we if do ks do just bc
How many terms are in this expression?
6w + 7x
Answers
Answer:
2
Step-by-step explanation:
6w is a term
7x is a term
Which values from the given replacement set make up the solution set of the inequality?
2b≥6; {1, 2, 3, 4}
Responses
{1, 2, 3}
left curly bracket 1 comma 2 comma 3 right curly bracket
{1, 2}
left curly bracket 1 comma 2 right curly bracket
{3, 4}
left curly bracket 3 comma 4 right curly bracket
{2, 3, 4}
PLS HURRY AHHH
Answers
{3, 4} are the values which make up the solution set of the inequality
2b ≥ 6.
Given, an inequality
2b ≥ 6.
Now, we have to find the solution set of the given inequality,
2b ≥ 6
On dividing both the sides by 2, we get
2b/2 ≥ 6/2
b ≥ 3
So, the solution set of the given inequality, be
the values of b must be greater than or equal to 3.
So, Option (3) i.e. {3 , 4} is the solution set of the inequality.
Hence, {3, 4} are the values which make up the solution set of the inequality 2b ≥ 6.
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How do you solve this problem step-by-step? 15(40-9)x3+6
Answers
Answer:
The answer to this problem is 1401.
Step-by-step explanation:
By using the order of operations listed here, we can solve the problem very easily.
EVALUATE IN PARENTHESES [tex]40-9[/tex]: 40 minus 9 is 31, so now the problem is 15(31) x 3 + 6
MULTIPLY/DIVIDE [tex]15(31)*3[/tex]: X times Y can be [tex]X*Y[/tex] or [tex]X (Y)[/tex]. This evaluates to [tex]15*31*3[/tex] which is 1395.
ADD/SUBTRACT: The problem now is just [tex]1395+6[/tex] which evaluates to a total of [tex]1401[/tex].
find the values of x, y, and z.
Answers
To find x, you would do 180-36-63, which would be 81.
Then you would do 180-81 to find z, which is 99.
To find y, would do do 180-99-13, which is 68.
Answer:
x=81
y=68
Z=99
Step-by-step explanation:
to find x we have to remember the rule that all 3 angles sum up to be 180 in a triangle
So we use this to find x
180-(63+36)=x
180-99=x
81=x
Now to find z since it is on a flat plane you just subtract 81 from 180 to find z
180-81=z
99=z
Now to find y we add all the angles of the second triangle and then subtract that sum by 180
180-(13+99)=y
180-112=y
68=y
Hopes this helps please mark brainliest
#11 i
Graph the polygon with the given vertices and its image after the given rotation about point A.
A(-2,-5), B(-7, 3), C(-4, 3), D(-1, -3); 270° counterclockwise.
Answers
Check the picture below.
Cheng is thinking a of a number
what number is Cheng thinking of ?
cheng thinking ;
I multiply my number by 100,hen divide by 10,then multiply by 1000.
My answer is 170'000
Is Cheng's answer is correct or incorrect
Answers
The number is 17
Let the number = x
From the question, we have
(x*100)/10*1000 = 170000
x = 17
Multiplication:
Mathematicians use multiplication to calculate the product of two or more numbers. It is a fundamental operation in mathematics that is frequently utilized in everyday life. When we need to combine groups of similar sizes, we utilize multiplication. The fundamental concept of repeatedly adding the same number is represented by the process of multiplication. The results of multiplying two or more numbers are known as the product of those numbers, and the factors that are multiplied are referred to as the factors. Repeated addition of the same number is made easier by multiplying the numbers.
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A right triangle has a leg that measures 7 in. The angle opposite this side measures
62°. What is the length of the hypotenuse of this triangle? Round to the nearest tenth.
(Remember to include the correct units in your answer)
Please help
Answers
The hypotenuse of the right triangle is 7.93 inches.
According to the question,
We have the following information:
A right triangle has a leg that measures 7 in. The angle opposite this side measures 62°.
Now, the hypotenuse can be easily found using the trigonometric function.
(More to know: in a right triangle, we can use the Pythagoras theorem. This theorem can not used in any other triangle.)
We will use sin 62 to find hypotenuse.
Sin 62 = perpendicular/hypotenuse
Hypotenuse = perpendicular/sin 62
Hypotenuse = 7/0.88295
Hypotenuse = 7.93 inches
Hence, the hypotenuse of the right triangle is 7.93 inches.
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hi thank you for seeing this
Answers
Each pair of angles should be matched with the correct property (theorem) as follows:
e. Vertical Angles: Angles 7 and 6.
a. Alternate Exterior Angles: Angles 1 and 8.
g. Alternate Interior Angles: Angles 4 and 5.
h. Corresponding Angles: Angles 2 and 6.
d. Supplementary Angles: Angles 6 and 8.
What are parallel lines?Parallel lines simply refers to two (2) lines that always have the same or equal distance apart and never meet.
What is the alternate exterior angle theorem?The alternate exterior angle theorem states that when two (2) parallel lines are cut through by a transversal, the alternate exterior angles that are formed are congruent or angles of equal measure and magnitude such as Angles 1 and 8.
What is the alternate interior angles theorem?The alternate interior angles theorem states that when two (2) parallel lines are cut through by a transversal, the alternate interior angles that are formed are congruent such as Angles 4 and 5.
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*URGENT + 100 POINTS*
A right triangle is shown in the graph.
right triangle on coordinate plane with hypotenuse labeled t and one endpoint of hypotenuse at r comma s and the other endpoint at x comma y, vertical line from point x comma y and horizontal line from r comma s that meet at right angle of triangle, horizontal dotted line from point r comma s to point s on y axis, horizontal dotted line from point x comma y to point y on y axis, vertical dotted line from point r comma s to point r on x axis, and vertical dotted line from right angle to point x on x axis
Part A: Use the Pythagorean Theorem to derive the standard equation of the circle with center at (r, s) and a point on the circle at (x, y). Show all necessary math work. (3 points)
Part B: If (r, s) = (7, –4) and t = 10, determine the domain and range of the circle. (4 points)
Part C: Is the point (9, 1) inside the border of the circle if (r, s) = (7, –4) and t = 10? Explain using mathematical evidence. (3 points)
Answers
Answer:
Part A
[tex](x-r)^2+(y-s)^2=t^2[/tex]
where:
(r, s) is the center of the circle.(x, y) is a point on the circle.t is the radius of the circle.Part B
Domain = [-3, 17]
Range = [-14, 6]
Part C
Point (9, 1) is inside the border of the circle.
Step-by-step explanation:
Part A[tex]\boxed{\begin{minipage}{9 cm}\underline{Pythagoras Theorem} \\\\$a^2+b^2=c^2$\\\\where:\\ \phantom{ww}$\bullet$ $a$ and $b$ are the legs of the right triangle. \\ \phantom{ww}$\bullet$ $c$ is the hypotenuse (longest side) of the right triangle.\\\end{minipage}}[/tex]
From inspection of the given triangle:
a = x - rb = y - sc = tSubstitute these values into the formula to derive the standard equation of the circle:
[tex]\boxed{ (x-r)^2+(y-s)^2=t^2}[/tex]
where:
(r, s) is the center of the circle.(x, y) is a point on the circle.t is the radius of the circle.Part BGiven the center of the circle (r, s) is (7, -4) and the radius (t) is 10.
The domain of the circle is the x-value of the center minus and plus the radius:
[tex]\begin{aligned}\implies \textsf{Domain}&=[r-t,r+t]\\&= [7-10, 7+10] \\&= [-3, 17]\end{aligned}[/tex]
The range of the circle is the y-value of the center minus and plus the radius:
[tex]\begin{aligned}\implies \textsf{Range}&=[s-t,s+t]\\&=[-4-10, -4+10]\\& = [-14, 6]\end{aligned}[/tex]
Part CSubstitute (r, s) = (7, –4) and t = 10 into the derived equation from part A:
[tex]\implies (x-r)^2+(y-s)^2=t^2[/tex]
[tex]\implies (x-7)^2+(y-(-4))^2=10^2[/tex]
[tex]\implies (x-7)^2+(y+4)^2=100[/tex]
Substitute the given point (9, 1) into the equation:
[tex]\begin{aligned}\implies (9-7)^2+(1+4)^2&=2^2+5^2\\&=4+25\\&=29\end{aligned}[/tex]
As 29 < 100, the point (9, 1) is inside the border of the circle.
A quadratic function
y
=
f
(
x
)
y=f(x) is plotted on a graph and the vertex of the resulting parabola is
(
−
5
,
6
)
(−5,6). What is the vertex of the function defined as
g
(
x
)
=
f
(
x
−
2
)
g(x)=f(x−2)?
Answers
Step-by-step explanation:
g(x) = the original function at x-2.
just means it is the same function as the original function, just moved 2 units to the right.
just think about it :
e.g.
g(3) is the same as the originated function at x=1.
g(4) is the same as the original function at x=2.
...
so, everything that happened for the original function at x, happens now for g at x+2.
therefore, again, things move 2 units to the right (positive x direction) .
that means the vertex "moves" from
(-5, 6) to (-3, 6)
the vertex of g(x) = (-3, 6)
please help. I don't get it.
Answers
Step-by-step explanation:
what is the problem to solve ?
I assume we need to calculate the area of the whole figure ?
in any case, we have a problem :
a rhombus is a tilted square, a special parallelogram, as it has 4 equal sides.
that would mean all 4 sides of that central rhombus are 5 in.
that would make both triangles equilateral triangles (all 3 sides are equally long : 5 in).
but in order for a right-angled triangle to have the Hypotenuse = 5 in and the height (= left leg) = 4 in, that must make the right leg
5² = 4² + leg²
25 = 16 + leg²
9 = leg²
leg = 3 in
and so, the baseline of the large triangle 2×3 = 6 in.
and not 5 in, which must be the top and base line of the rhombus.
so, the whole problem definition is wrong.
the only solution when accepting the given lengths, is that the triangle sides are NOT a straight extension of the rhombus sides.
the triangle side is the Hypotenuse of the smaller internal right-angled triangle
side² = 4² + (5/2)² = 16 + 6.25 = 22.25
side = 4.716990566... in
anyway, the area of each of the large triangles is
baseline×height / 2 = 5×4/2 = 10 in²
we have 2 triangles = 2×10 = 20 in²
the area of the rhombus is
baseline×height = 5×4 = 20 in²
please note that the area of a rhombus is also
diagonal1 × diagonal2 / 2
but that applies only, when we have the lengths of the diagonals. both approaches give the same result, of course.
so, the whole area is
20 + 20 = 40 in²
Question in file please help!!!!
Answers
Answer:
Step-by-step explanation:
Ok:
Area of circle:
A=πr^2
1. Apply to question!
5^2π=
25π/4: Since it is a 1/4 of the circle
6.25π
Answer: 6.25π or 6.25 pie
Answer:
about 19.63496 m^2
Step-by-step explanation:
this is 1/4 of a circle so we find the are of the full circle
pi(r)^2
pi(5)^2
pi25
78.53982
Divide by 4
78.53982/4
19.63496
Hopes this helps please mark brainliestC
b) On the grid draw the graph of x+y=6 for values of c between -2 and 3
Answers
U= {2, 3, 4, 5, 7}
C= {2, 4}
D= {2, 7}
(a) (C n D)’=
(b) C’ U D=
Answers
The value of (CnD)'= {3,5} and the valueof C' U D = { 2,3,5,7}
What is complement of a set?The complement of a set is the set that includes all the elements of the universal set that are not present in the given set. Let's say A is a set of all coins which is a subset of a universal set that contains all coins and notes, so the complement of set A is a set of notes (which do not includes coins).
if U = { 2,3,4,5,7}
C= { 2,4}
D= { 2,7}
therefore (CnD)= { 2,4,7}
the complement of set (CnD) that is, (CnD)' = {3,5}
complement of set C (C')= { 3,5,7}
Therefore the union of C' and D(C' U D) = { 2,3,5,7}
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A rectangular plece of carpet covers 180 yd². The width is 7 yd less than the length. Find the length and width.
Round your answers to the nearest tenth of a yard.
The length is approximately
yd.
The width?
Answers
THE LENGTH AND WIDTH WILL BE = length: 5.7 yd
width: 1.7 yd.
What is unitary method?The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units. What can be values and units.Let's say you go to the store to buy six apples. You are informed by the shopkeeper that he is offering 10 apples for Rs 100. In this instance, the value and the units are the price of the apples.Recognizing the units and values is crucial when using the unitary technique to a problem.Always write the items that need to be computed on the right side and the things that are known on the left side to simplify things.We are aware of the quantity of apples and the amount of money in the aforesaid problem.According to our question-
w(w +4) = 10
w² +4w = 10 . . . . . eliminate parentheses
w² +4w +4 = 14 . . . . . . add the square of half the w-coefficient to complete the square
(w +2)² = 14 . . . . . . . . . rewrite as a square
w +2 = √14 . . . . . . . . . take the square root
2 = -2 +√14 ≈ 1.7 . . . . yards (width)
Then the length is 4 more yards than this, so is ...
length = 1.7 +4 = 5.7 . . . yards
The length and width are 5.7 and 1.7 yards, respectively.
In the attached graph, we let x represent the length. As you can see, the magnitudes of the two zeros are width and length.
HENCE,THE LENGTH AND WIDTH WILL BE = length: 5.7 yd width: 1.7 yd.
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This is the initial tableau of a linear programming problem. Solve by the simplex method.
x 1
x1
x 2
x2
s 1
s1
s 2
s2
s 3
s3
z
1
3
3
1
0
0
0
12
2
4
4
0
1
0
0
2
2
1
1
1
0
0
1
0
4
minus
−2
minus
−1
0
0
0
1
0
Question content area bottom
Part 1
The maximum is
enter your response here
when
x 1
x1
equals
=
enter your response here
,
x 2
x2
equals
=
enter your response here
,
s 1
s1
equals
=
11
11,
s 2
s2
equals
=0, and
s 3
s3
equals
=
3
3.
Answers
The solution of linear programming problem is the maximum value is 2, x_1 = 1, x _2 =0.
What is linear programming problem?
The goal of the Linear Programming Problems (LPP) is to determine the best value for a given linear function. The ideal value may be either the highest or lowest value. The specified linear function is regarded as an objective function in this situation. The objective function may have a number of variables that must meet a set of linear inequalities known as linear constraints. These variables may also be subject to conditions. The following scenarios, such as manufacturing difficulties, diet problems, transportation challenges, allocation problems, and so on, can be solved optimally using the linear programming problems.
After first iteration,
Negative minimum Z_j-C_j is -2 and its column index is 1. So, the entering variable is x_1.
Minimum ratio is 1 and its row index is 2. So, the leaving basis variable is S_2.
∴ The pivot element is 2.
Entering =x_1, Departing =S_2, Key Element =2
After second iteration:
Since all Z_j-C_j≥0
Hence, optimal solution is arrived with value of variables as :
x_1=1,x_2=0
Max Z=2
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Solve the following system of linear equations by graphing:
4x + 2y = -4
4x + 2y = -20
Graph the linear equations by writing the equations in slope-intercept form:
y= ___x + ___
y= ___x + ___
Identify the appropriate number of solutions. If there’s a solution, give the point.
Answers
Answer:
No solution. The lines are parallel
Step-by-step explanation:
I graphed with Desmos. It is a free.
I earn $285/week. There are 4 pays in most months. So, my monthly pay is $285 x 4 or $1140 per month.
Is my calculation of my monthly income accurate? Please explain.
Answers
Answer: Yes
Step-by-step explanation: Most month have 4 weeks so your right.
What is 1 2/3 of 32 in fractions?
Answers
Answer:
53 1/3
Step-by-step explanation:
[tex]1\frac{2}{3} =\frac{3+2}{3} =\frac{5}{3}[/tex]
[tex](32)(\frac{5}{3} )=\frac{(32)(5)}{3} =\frac{160}{3}[/tex]
[tex]\frac{160}{3} =53 +\frac{1}{3} =53\frac{1}{3}[/tex]
Hope this helps
The value of the expression is [tex]\frac{160}{3}[/tex].
What is an expression?An expression contains one or more terms with addition, subtraction, multiplication, and division.
We always combine the like terms in an expression when we simplify.
We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.
Example:
1 + 3x + 4y = 7 is an expression.
3 + 4 is an expression.
2 x 4 + 6 x 7 – 9 is an expression.
33 + 77 – 88 is an expression.
We have,
[tex]1\frac{2}{3}[/tex] of 32
= [tex]\frac{5}{3}[/tex] x 32
[ 5 x 32 = 160 ]
= [tex]\frac{160}{3}[/tex]
Thus,
The value of the expression is [tex]\frac{160}{3}[/tex].
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let f(x) = x-1 graph g(x)=f(3/4x)
Answers
The graph of the function g(x) after putting the value in function f(x) is attached with the answer.
What is function?
A relation b/w a collection of inputs and outputs is known as a function. A function is a relationship between inputs in which each input is connected to precisely one output.
Given function: f(x) = x-1
we have to find: g(x)=f(3/4x)
Putting the value of f(x) in g(x),
g(x) = 3/4x - 1
Now, the graph of the function (3/4)x - 1 is attached in the question.
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A $26,000 car is on sale for 5% off with 3% tax. Interpret the change of the price as a percentage. Round to the nearest hundredth.
Answers
The new price of the car is $25441.
How to calculate the price?Given that the $26,000 car is on sale for 5% off with 3% tax.
The discount will be:
= 5% × $26000
= $1300
The tax will be:
= 3% × ($26000 - $1300)
= 3% × $24700
= $741
The new price will be:
= Amount - Discount + Tax
= $26000 - $1300 + $741
= $25441
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I need help please and thank you.
Answers
The inequality that relates [tex]LN[/tex] and [tex]OQ[/tex] is [tex]LN>OQ[/tex].
A stockbroker charges a 1.5% commission to sell shares of a stock for a client. Find the value of stock sold by a broker if the commission was $420.
Answers
Answer:
value of stock =1.5% × 420?= 6.3
Write the equation of a sine function that has the given characteristics.
Amplitude: 4
Period: 3pie
Answers
Answer:
y = 4 sin(2x/3)
Step-by-step explanation:
The parent function for sine functions is: y = a sin b(x - c) + d
"a" defines amplitude/vertical dilation
"b" defines the change to the period/horizontal dilation
"c" defines the phase shift/horizontal translation
"d" defines the midline/vertical translation
We can already set "a = 4" because 4 is the amplitude.
However, to include the period into the function, we have to take note of the parent sine function already having a period of 2π.
This means: 2π/b = period
2π/period = b
2π/3π = b
2/3 = b
Knowing the "a" and "b" values, we can set up the equation:
y = 4 sin(2x/3)
No horizontal/vertical translations were applied, so "c" and "d" are both zero.
I need the Answer Options are also given
Answers
The simplified form of the expression, [tex]\frac{6^{\frac{2}{3} } \times 8^{\frac{1}{3} } }{12^{\frac{2}{3} } }[/tex] after evaluating is equal to [tex]\sqrt[3]{2}[/tex]
What are Powers?
A power is created when a number is multiplied by itself. A power is typically represented by a base number and an exponent. The multiplier is revealed by the base number while the exponents, which are little numbers written above and to the right of base numbers, indicate how many times the base number has been multiplied.If a number is written as 6 to the power of 2, it is represented as, [tex]6^{2}[/tex]. Here, 6 is the base and 2 is the power.Steps to Combine and Simplify Exponents
The three basic rules of exponents used to combine the exponents and simplify the expression are as follows:
[tex]a^{m} \times a^{n} =a^{m+n}[/tex] -----(1)[tex]\frac{a^{m} }{a^{n} } =a^{m-n}[/tex] -----(2)[tex](a^{m})^{n} =a^{m \times n}[/tex] ------(3)Here, we have to simplify and evaluate the given expression using the rules of exponents.
We have the given expression, [tex]\frac{6^{\frac{2}{3} } \times 8^{\frac{1}{3} } }{12^{\frac{2}{3} } }[/tex] -------(4)
Using the exponents rules, [tex](a^{m})^{n} =a^{m \times n}[/tex] and [tex](a \times b)^{m}=a^{m} \times b^{m}[/tex] in the above expression, we get
[tex]\frac{6^{\frac{2}{3} } \times 8^{\frac{1}{3} } }{12^{\frac{2}{3} } } = \frac{2^{\frac{2}{3} } \times 3^{\frac{2}{3} } \times 2^{3 \times \frac{1}{3} } }{2^{\frac{2}{3} } \times 2^{\frac{2}{3} } \times 3^{\frac{2}{3} }}[/tex]
Simplifying further using (1) and (2), we get (4) as,
[tex]\frac{6^{\frac{2}{3} } \times 8^{\frac{1}{3} } }{12^{\frac{2}{3} } } = \frac{2^{\frac{2}{3}}}{2^{\frac{2}{3}+\frac{2}{3} }} \times \frac{3^{\frac{2}{3} } }{3^{\frac{2}{3} }} \times 2^{1} \\\implies \frac{6^{\frac{2}{3} } \times 8^{\frac{1}{3} } }{12^{\frac{2}{3} } } =\frac{2^{\frac{2}{3}}}{2^{\frac{4}{3} }} \times 2^{\frac{2}{3}-\frac{2}{3} } \times 2\\\implies \frac{6^{\frac{2}{3} } \times 8^{\frac{1}{3} } }{12^{\frac{2}{3} } } =2^{\frac{2}{3}-\frac{4}{3} } \times 2^{0} \times 2[/tex]
We know that, [tex]a^{0} =1[/tex]
So, further simplifying we get
[tex]\frac{6^{\frac{2}{3} } \times 8^{\frac{1}{3} } }{12^{\frac{2}{3} } } =2^{-\frac{2}{3} } \times 1 \times 2\\\imples \frac{6^{\frac{2}{3} } \times 8^{\frac{1}{3} } }{12^{\frac{2}{3} } } = 2^{-\frac{2}{3}+1 } \\\imples \frac{6^{\frac{2}{3} } \times 8^{\frac{1}{3} } }{12^{\frac{2}{3} } }=2^{\frac{1}{3}}\\ \imples \frac{6^{\frac{2}{3} } \times 8^{\frac{1}{3} } }{12^{\frac{2}{3} } }=\sqrt[3]{2}[/tex]
Therefore, the simplied form of the given expression is [tex]\sqrt[3]{2}[/tex]
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a store sells a $400 microscope after a markup of 32% what is the price of the microscope at the store
Answers
A 32% mark up means that the price goes up by 32 percent. The way to find this is by finding 132% of $400.
1.32 x 400 = $528.
I hope this helps!
The price of the microscope after the markup of 32% at the store will be equal to $528.
What is Percentage?The Latin term "per centum," which signifies "by the hundredth," was the source of the English word "percentage." Segments with a denominator of 100 are considered percentages. In other terms, it is a relationship where the worth of the entire is always considered to be 100.
As per the given data in the question,
Price of microscope = $400
Markup percentage = 32%
Increase in price = 400 × 32/100
= $128.
Price after markup will be,
$400 + $128 = $528.
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