2. Suppose you save $2000 in a bank account that earns an annual interest rate of 1.2% compounded
continuously.
(a) How much money would be in the account after 5 years?

Answer:

2.94 in

Step-by-step explanation:

Explanation:

The slope of the line is found by the method: rise/run

You calculate how much the slope rises(goes up) and divide it by run(goes horizontal).

One more thing to note is that: the slope is negative BECAUSE ITS DECREASING.

Your answer:   -3/2

Answer:

2) 9/4

Step-by-step explanation:

12/5 in decimal form is 2.4. As a mixed number, 12/5 is 2 2/5. And, 12/5 is just a reduced form of 36/15. So, the only answer it can be is answer 2: 9/4

Answer:

A.true)

Step-by-step explanation:

Hope this helps!

Answer:  

470

Step-by-step explanation:

Replace x with 10:  470

5(10)(10 - 3( = 500 - 30 = 470

470

Answer:

diameter ÷ 2 = 8 ÷ 2 = 4

Step-by-step explanation:

Answer:

Standard Deviation and Below are, in fact, the right answer.

Step-by-step explanation:

Edge. :)

Answer:

The person above is right, they deserve brainliest.

-standard deviations

-below

ED2021

The answer is A

Hope this helps!

Answer:

5

Step-by-step explanation:

Since Riley has already saved 80 dollars and she needs to save 150 dollars.

150-80=70

She earns 14 dollars per week:

70/14=5

I also wrote a equation:

(150-80)/14=x

Hope this was helpful!

Answer:

Mrs Barnes has the highest

Answer: The unit price is $6.59 per pair of socks

Step-by-step explanation: 26.36. divided by 4 = 6.59

Answer:

Option (4) and Option (6)

Step-by-step explanation:

By the zero product property,

If (x - a)(x - b) = 0

Then, (x - a) = 0 ⇒ x = a

(x - b) = 0 ⇒ x = b

By following the zero product property,

From the given equation,

3(x - 4)(2x - 3) = 0

x - 4 = 0 ⇒ x = 4

2x - 3 = 0 ⇒ x = [tex]\frac{3}{2}[/tex]

Therefore, options (4) and (6) will be the correct options.

Answer:

4 and 6 :)

Step-by-step explanation:

edge

Answer: 24

Step-by-step explanation: negative multiples by a negative is a positive

The opposite of -(-24) is -24.

A number is additive inverse of a given number when sum of the two number is zero and a number is a multiplicative inverse of a given number when product of two number is 1.

According to the given question statement we have to determine what is opposite of -(-24).

We know opposite of two numbers sums to zero.

Given -(-24).              ( negative signs will distribute and it'll become 24).

Let the opposite number be x.

∴ 24 + x = 0

x = -24.

So the opposite of -(-24) is - 24.

learn more about additive and multiplicative inverse here :

https://brainly.com/question/13715269

#SPJ2

Answer:

A=-4/3

B=1/5

C=-5/4

Step-by-step explanation:

Answer:

She got 63 chocolates.

Step-by-step explanation:

Answer:

Yes it is

Step-by-step explanation:

Because

2) x (sqrt 3) times (sqrt 12)

Two is also equivalent to sqrt of 4. The operation may be expressed as,

                                  (sqrt 4) x (sqrt 3) x sqrt (12)

The product is sqrt (144). This gives an answer of 12 and it is rational.

So, the answer is Yes!

Hope this helped! :)

May i have brainliest!

Answer:

Yes it is

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

12 is the answer and 12 is a rational number

Radicand = The number under the inclusion bar of the radical sign.

Product = The result of two numbers being multiplied together.

Factor = One of two or more expressions that are multiplied together to get a product.

Answer:

9. -3/4

10. -5/1

11. UNDEFINED

12. 2/3

Answer:

9. -3/4

10. -5

11. undefined

12. 2/3

Step-by-step explanation:

Answer:

She will pay $2.

Step-by-step explanation:

Answer:

8 mi

Step-by-step explanation:

Answer:

The answer is A

Step-by-step explanation:

I just did it on edge and got it right.

Answer:

Yes, because the plot shows no apparent pattern.

Step-by-step explanation:

Yes, because the plot is a residual plot from a regression of a variable with the independent variable x.

Therefore, the correct option is 1.)Yes, because the plot shows no apparent pattern.

To learn more about regression refer to:

brainly.com/question/26755306

#SPJ2

Answer:

12 Notebooks And 16 Erasers

Step-by-step explanation:

Let x represent the number of notebooks and y represent the number of erasers. (x+y=28) Then, input the cent numbers into the equation. (90x+45y=1800) The 1800 represents the amount of dollars spent. Then simplfy the equation, which gives you 12 notebooks and 16 erasers.

Answer:

8.no answer A. x=8

Step-by-step explanation:

10.no answer B. x= -3

Answer:

8. (A) x = 8 , 10. (C.) x = 3

Step-by-step explanation:

Number 8 you could do 75 - 35 = 40

so what can you multiply 5 by (x) to get 40? you would multiply 5 by 8 or (x) and get 40

then add 35 + 40 to get 75 degrees which is the parallel angle to the other 75 degrees.

Number 10 you just want to get them to the same number.

so you would do ( 97 - 3 ) to get the ANSWER 87.

so x = 3

Answer:

36

Step-by-step explanation:

Answer:

19.2

Step-by-step explanation:

Use distributive property: 11+28 / 7-5

Add: 11+28 ( 39 ) Subtract: 7-5 ( 2 )

Divide: 39/2 ( 19.2 )

Answer:

Step 2 shows Emily's first mistake.

Step-by-step explanation:

3(2) = 6

But instead of this Emily wrote 3(2) = 9.

Answer:

The correct answer is B. The rate of 7% compounded quarterly is better.

Step-by-step explanation:

In the case of investment at 7% compounded quarterly, the final result after 4 years of investment arises from the following calculation:

X = 7000 x (1 + 0.7 / 3) 4x3

X = 9,232.16

Therefore, after 4 years of investment, the amount in the account would be $ 9,232.16.

In turn, in the case of the investment at 6.85% compounded monthly, the final result after the same investment period arises from the following calculation:

X = 7000 x (1 + 0.685 / 12) 4x12

X = 9,199.33

Thus, in this case, the amount in the account after 4 years of investment would be $ 9,199.33.

Answer:

See explanation

Step-by-step explanation:

Solving (a):

[tex]a_n = 6a_{n-1}[/tex] where [tex]a_0 = 2[/tex]

n = 1

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_1 = 6a_{1-1}[/tex]

[tex]a_1 = 6a_{0}[/tex]

Substitute 2 for [tex]a_0[/tex]

[tex]a_1= 6 * 2[/tex]

[tex]a_1= 12[/tex]

n = 2

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_2 = 6a_{2-1}[/tex]

[tex]a_2 = 6a_{1}[/tex]

Substitute 12 for [tex]a_1[/tex]

[tex]a_2= 6 * 12[/tex]

[tex]a_2= 72[/tex]

n = 3

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_3 = 6a_{3-1}[/tex]

[tex]a_3 = 6a_2[/tex]

Substitute 72 for [tex]a_2[/tex]

[tex]a_3= 6 * 72[/tex]

[tex]a_3= 432[/tex]

n = 4

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_4 = 6a_{4-1}[/tex]

[tex]a_4 = 6a_{3}[/tex]

Substitute 432 for [tex]a_3[/tex]

[tex]a_4 = 6 * 432[/tex]

[tex]a_4 = 2592[/tex]

n = 5

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_5 = 6a_{5-1}[/tex]

[tex]a_5 = 6a_4[/tex]

Substitute 2592 for [tex]a_4[/tex]

[tex]a_5 = 6 * 2592[/tex]

[tex]a_5 = 15552[/tex]

n = 6

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_6 = 6a_{6-1}[/tex]

[tex]a_6 = 6a_{5}[/tex]

Substitute 15552 for [tex]a_5[/tex]

[tex]a_6 = 6 * 15552[/tex]

[tex]a_6 = 93312[/tex]

[tex]a_1= 12[/tex]   [tex]a_2= 72[/tex]   [tex]a_3= 432[/tex]   [tex]a_4 = 2592[/tex]   [tex]a_5 = 15552[/tex]   [tex]a_6 = 93312[/tex]

Solving (b):

[tex]a_n = a^2_{n - 1[/tex] where [tex]a_1 = 2[/tex]

We have

[tex]a_1 = 2[/tex] which serves as the first term

n =2

[tex]a_n = a^2_{n - 1[/tex]

[tex]a_2 = a^2_{2-1}[/tex]

[tex]a_2 = a^2_{1}[/tex]

Substitute 2 for [tex]a_1[/tex]

[tex]a_2 = 2^2[/tex]

[tex]a_2 = 4[/tex]

n = 3

[tex]a_3 = a^2_{3-1}[/tex]

[tex]a_3 = a^2_{2}[/tex]

[tex]a_3 = 4^2[/tex]

[tex]a_3 = 16[/tex]

n = 4

[tex]a_4 = a^2_{4-1}[/tex]

[tex]a_4 = a^2_3[/tex]

[tex]a_4 = 16^2[/tex]

[tex]a_4 = 256[/tex]

n =5

[tex]a_5 = a^2_{5-1[/tex]

[tex]a_5 = a^2_4[/tex]

[tex]a_5 = 256^2[/tex]

[tex]a_5 = 65536[/tex]

n = 6

[tex]a_6 = a^2_{6-1[/tex]

[tex]a_6 = a^2_{5[/tex]

[tex]a_6 = 65536^2[/tex]

[tex]a_6 = 4294967296[/tex]

[tex]a_1 = 2[/tex]   [tex]a_2 = 4[/tex]   [tex]a_3 = 16[/tex]   [tex]a_4 = 256[/tex]   [tex]a_5 = 65536[/tex]   [tex]a_6 = 4294967296[/tex]

Solving (c):

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] [tex]a_0=1[/tex]  ; ;  [tex]a_1=2[/tex]

[tex]a_1=2[/tex] ---- First term

n = 2

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_2=a_{2-1}+3a_{2-2}[/tex]

[tex]a_2=a_1+3a_0[/tex]

Substitute values for a1 and a0

[tex]a_2=2+3 * 1[/tex]

[tex]a_2=2+3[/tex]

[tex]a_2=5[/tex]

n = 3

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_3=a_{3-1}+3a_{3-2}[/tex]

[tex]a_3=a_{2}+3a_{1}[/tex]

[tex]a_3=5+3 * 2[/tex]

[tex]a_3=5+6[/tex]

[tex]a_3=11[/tex]

n = 4

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_4=a_{4-1}+3a_{4-2}[/tex]

[tex]a_4=a_{3}+3a_{2}[/tex]

[tex]a_4=11+3 * 5[/tex]

[tex]a_4=11+15[/tex]

[tex]a_4=26[/tex]

n = 5

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_5=a_{5-1}+3a_{5-2};[/tex]

[tex]a_5=a_{4}+3a_3[/tex]

[tex]a_5=26+3 * 11[/tex]

[tex]a_5=26+33[/tex]

[tex]a_5=59[/tex]

n = 6

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_6=a_{6-1}+3a_{6-2}[/tex]

[tex]a_6=a_{5}+3a_4[/tex]

[tex]a_6=59+3*26[/tex]

[tex]a_6=59+78[/tex]

[tex]a_6=137[/tex]

[tex]a_1=2[/tex]   [tex]a_2=5[/tex]   [tex]a_3=11[/tex]   [tex]a_4=26[/tex]   [tex]a_5=59[/tex]   [tex]a_6=137[/tex]

Solving (d):

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex];     [tex]a_0=1[/tex]; [tex]a_1=1[/tex]

[tex]a_1=1[/tex] --- First term

n = 2

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_2=2 * a_{2-1}+2^2a_{2-2}[/tex]

[tex]a_2=2 * a_1+4*a_0[/tex]

[tex]a_2=2 * 1+4*1[/tex]

[tex]a_2=2 +4[/tex]

[tex]a_2=6[/tex]

n = 3

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_3=3 * a_{3-1}+3^2 * a_{3-2}[/tex]

[tex]a_3=3 * a_{2}+9 * a_{1}[/tex]

[tex]a_3=3 * 6+9 * 1[/tex]

[tex]a_3=18+9[/tex]

[tex]a_3=27[/tex]

n = 4

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_4=4*a_{4-1}+4^2*a_{4-2}[/tex]

[tex]a_4=4*a_{3}+16*a_{2}[/tex]

[tex]a_4=4*27+16*6[/tex]

[tex]a_4=204[/tex]

n = 5

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_5=5 * a_{5-1}+5^2 * a_{5-2}[/tex]

[tex]a_5=5 * a_{4}+25 * a_{3}[/tex]

[tex]a_5=5 * 204+25 *27[/tex]

[tex]a_5=1695[/tex]

n = 6

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_6=6 * a_{6-1}+6^2*a_{6-2}[/tex]

[tex]a_6=6 * a_{5}+36*a_{4}[/tex]

[tex]a_6=6 * 1695+36*204[/tex]

[tex]a_6=17514[/tex]

[tex]a_1=1[/tex]   [tex]a_2=6[/tex]   [tex]a_3=27[/tex]   [tex]a_4=204[/tex]   [tex]a_5=1695[/tex]   [tex]a_6=17514[/tex]

Solving (e):

[tex]a_n= a_{n-1}+a_{n-3};\ a_0=1; a_1=2; a_2=0[/tex]

First term: [tex]a_1=2[/tex]

Second Term: [tex]a_2=0[/tex]

n = 3

[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes

[tex]a_3= a_{3-1}+a_{3-3}[/tex]

[tex]a_3= a_{2}+a_0[/tex]

[tex]a_3= 0+1[/tex]

[tex]a_3= 1[/tex]

n = 4

[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes

[tex]a_4= a_{4-1}+a_{4-3}[/tex]

[tex]a_4= a_{3}+a_{1}[/tex]

[tex]a_4= 1+2[/tex]

[tex]a_4=3[/tex]

n = 5

[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes

[tex]a_5= a_{5-1}+a_{5-3}[/tex]

[tex]a_5= a_{4}+a_{2}[/tex]

[tex]a_5= 3 + 0[/tex]

[tex]a_5= 3[/tex]

n = 6

[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes

[tex]a_6= a_{6-1}+a_{6-3}[/tex]

[tex]a_6= a_{5}+a_{3}[/tex]

[tex]a_6= 3 + 1[/tex]

[tex]a_6= 4[/tex]

[tex]a_1=2[/tex]   [tex]a_2=0[/tex]   [tex]a_3= 1[/tex]   [tex]a_4=3[/tex]   [tex]a_5= 3[/tex]   [tex]a_6= 4[/tex]

Answer:

My best conclusion (simply put) is that you had a higher score than the average class.

Step-by-step explanation:

It obvious that the green dots is above the averages of both bars. It would be safe to think that you scored higher than the average of the entire class in both predictions and parabolas.