2 points
What element in this equation indicates that this is a combustion reaction: CH4(g) + 2 O2(g) — CO2(g) + 2 H2O(g)? i

Answer:

Explanation:god is good because the god is what it stays

god is good because the god is what it staysgod is good because the god is what it staysgod is good because the god is what it stays

Answer:

The upper limit of metamorphism occurs at the pressure and temperature of wet partial melting of the rock in question. Once melting begins, the process changes to an igneous process rather than a metamorphic process. During metamorphism the protolith undergoes changes in texture of the rock and the mineral make up of the rock.

Explanation:

i hope this helps

When melting of a metamorphic rock occurs, it changes into Magma and igneous rock will emerge as a result of this..

Sedimentary, igneous, and metamorphic rocks are the three distinct types of rocks that make up the rock cycle. Rocks such as sedimentary and igneous rocks were not always rocks.

A very particular set of circumstances must exist for a rock to undergo metamorphism. It is necessary to subject the preexisting rock to extreme temperatures, high pressures, or hot, mineral-rich fluids. All three of these conditions are typically true. The Earth's crust is where these conditions are most frequently encountered, either there or at plate borders when tectonic plates meet.

It is essential that the current rock not melt in order to produce metamorphic rock. The rock will melt under excessive heat or pressure and turn into magma. Instead of a metamorphic rock, an igneous rock will emerge as a result of this.

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Answer:

It increases.

Explanation:

If a force acts in the same direction as the object's motion, then the force speeds the object up. Either way, a force will change the velocity of an object. And if the velocity of the object is changed, then the momentum of the object is changed.

here you go thank bob not me he will be very thankful

Answer:

Given Mas (m) =63kg

velocity (v) =4.3m/s

momentum (p) =?

p=mv

63kgx4.3m/s

270.9kg.m/s

the momentum =270.9kg.m /s

If a ball of mass 0.63 kilograms is moving at 4.3 meters/seconds, then the momentum of the ball would be 2.709-kilogram meters/second.

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle.

Momentum = mass of the object × velocity of the object

As given in the problem we have to calculate the momentum of the ball if it has a mass of 0.63 kilograms and moving with a speed of  4.3 meters/seconds,

The momentum of the ball = 0.63× 4.3

                                             =2.709 kilogram meters/second

Thus, the momentum of the ball comes out to be 2.709-kilogram meters/second.

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Answer:

There are 5 lobes in the lungs.

Explanation:

The right lung consists of three lobes: the RUL, the RML, and the RLL. While the left lung consists of two lobes: the LUL, and the LLL.

Answer:

Amplitude is a measure of the size of sound waves. It depends on the amount of energy that started the waves. Greater amplitude waves have more energy and greater intensity, so they sound louder. The same amount of energy is spread over a greater area, so the intensity and loudness of the sound is less.

Explanation:

Answer:

The velocity will be "76.8 m/s".

Explanation:

The given values are:

Acceleration,

a = 2.4 m/s²

Time,

t = 32 seconds

By equation of motion,

⇒  [tex]v=u+at[/tex]

On substituting the values, we get

⇒     [tex]=0+2.4\times 32[/tex]

⇒     [tex]=0+76.8[/tex]

⇒     [tex]=76.8 \ m/s[/tex]

Answer:

That guy is right i got a 100 as my score :)

Explanation:

The linear velocity is changing and the angular velocity is Constant best describes the passenger’s linear and angular velocity while passing a point.

The rate of change of angular displacement is defined as angular speed, and it is stated as follows:

ω = θ t

Where,

θ is the angle of rotation,

t is the time

ω is the angular velocity

The linear velocity is given as the product of angular velocity and radius.

v=ωr

In the circular motion, the linear velocity is changing. Because the radius is changing.While the angular velocity is constant.Because it is an independent quantity.

Hence the Linear velocity is changing and the angular velocity is Constant best describing the passenger’s linear and angular velocity while passing a point.

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Answer:

0.714 m

Explanation:

From the question,

v = λf......................... Equation 1

Where v = velocity of visible light, f = frequency of visible light, λ = wave length of visible light.

make λ the subject of the equation

λ = v/f.................. Equation 2

Given: f = 4.2×10⁸ Hz

Note: Light is an electromagnetic wave, and all electromagnetic waves travels with the same speed (3×10⁸ m/s)

Constant: v = 3×10⁸ m/s

Substitute these values into equation 2

λ = 3×10⁸/4.2×10⁸

λ = 0.714 m

Answer:

m/s

Explanation:

The SI unit of speed is the metre per second, but the most common unit of speed in everyday usage is the kilometre per hour or, in the US and the UK, miles per hour.

m/s

which is also written as

ms-¹

The above mentioned symbols are said as 'meter per second'

hope it helps!

Answer:343

Explanation:

Answer:

0.368 Newtons

Explanation:

Answer:

i think it's 0.88

Explanation:

Answer:

Your answer is B co2

Explanation:

Answer: CO2

Explanation:

Carbon dioxide is consisted of one carbon molecule and 2 oxygen molecules, therefore CO2

Answer:

the answer would be conductors

Answer:

r = 0.2499 m

Explanation:

Use Coulomb's Law: [tex]F_{e} = kq_{1}q_{2} / r^{2}[/tex] where Fe is the electric force, q1 and q2 are the 2 charges respectively, k is a constant (8.99*10^9 N • m^2 / C^2) and r is the distance.

[tex]3.6 N = (8.99*10^{9})(5*10^{-6})(5*10^{-6}) / r^{2}[/tex]

r = 0.2499 m

The distance that should be apart from these charges should be considered when the r = 0.2499 m.

Since

Two charges of 5 x 10-6 C are a certain distance apart. These two positive charges experience 3.6 N of repelling electrical force between them

So

here we use Columb law

Electric force = k * two charges * two charges)r^2

3.6 N = (8.99*10^9) * ( 5 * 10^-6) * (5*10^-6)r^2

r = 0.2499 m.

Hence, The distance that should be apart from these charges should be considered when the r = 0.2499 m.

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Answer:

Element Symbol # of Atoms

Oxygen O 2

Sulfur S 1

Explanation:

Answer:

B. It has a central nucleus composed of 29 protons and 35 neutrons,

surrounded by an electron cloud containing 29 electrons.

Explanation:

Protons and neutrons are the only subatomic particles with mass, and they are located in the nucleus. If this atom has an atomic number of 29 and is copper, it must have 29 protons (protons define which element is being observed). This means all remaining mass is from neutrons. 64-29 = 35.

Electrons have no mass and orbit the nucleus in the electron cloud. Since this copper atom is neutral (we are not told it has a charge), there must be an equal number of protons and electrons.

Answer:

B. It has a central nucleus composed of 29 protons and 35 neutrons,

surrounded by an electron cloud containing 29 electrons.

Explanation:

Hope this helps

Answer:

-5000 N

Explanation:

Newtons third law of motion states that action and reaction are equal and opposite. This means that to every action, there is an equal opposite reaction.

Hence when a body A exerts a force FA on another body B, the body B also exerts a force FB on A which is equal in magnitude to FA but opposite in direction. FB is the reaction force due to FA.

Hence, when a car hits a wall with a force of 5000N, the reaction of the wall on the car is -5000N

Answer:

Explanation:

a. The frequency increases.

b. The period increases.

c. The frequency stays the same.

d. The period stays the same

Gravitational force increases as the mass increases and decreases as the distance between the bodies is increased.

Reasons:

The given parameters are;

The moons of the planet = Moon A and Moon B

Mass of Moon A = 2·M

Mass of moon B = M

The distance between Moon B and the planet = 2 × The distance between Moon A and the planet

Required:

Comparison (compare) of the force exerted from the planet on Moon A and Moon B.

Solution:

The force, F, exerted from the planet is the gravitational force which is given by Newton's Law of Gravitation as follows;

Where;

G = Universal gravitational constant

[tex]M_{planet}[/tex] = Mass of the planet

M = Mass of the Moon

R = The distance from the planet to the Moon

For Moon A, we have;

Mass = 2·M

Distance = R

Which gives;

[tex]\displaystyle F_A = G \cdot \frac{M_{planet} \times 2\cdot M}{R^2} = 2\cdotG \cdot \frac{M_{planet} \times M}{R^2} = \mathbf{2 \cdot F}[/tex]

With Moon B, we have;

Mass = M

Distance = 2·R

Therefore;

[tex]\displaystyle F_B = G \cdot \frac{M_{planet} \times M}{(2 \cdot R)^2} = G \cdot \frac{M_{planet} \times M}{4 \cdot R^2} = \frac{1}{4} \cdot G \cdot \frac{M_{planet} \times M}{R^2} = \mathbf{\frac{1}{4} \cdot F}[/tex]

Which gives;

[tex]\displaystyle \frac{F_A}{F_B} = \frac{2 \cdot F}{\frac{1}{4} \cdot F } =2 \times \frac{4}{1} = \mathbf{8}[/tex]

[tex]\displaystyle \frac{F_A}{F_B} = 8[/tex]

[tex]F_A = \mathbf{8 \times F_B}[/tex]

The force from the planet on Moon A, [tex]F_A[/tex], is 8 times the force from the planet on Moon B.

Therefore, whereby option B is;

The correct option is option B

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Answer:

6.32m/s

Explanation:

note:Now these calculations are based in the fact that acc. due to gravity is 10m/s²

okay so I'm thinking you think the speed of a body depends on the mass of the body also,umh... well it doesn't at all!

when two bodies of different masses fall from the same height,they fall at the same time( this is just to say)

now enough of the talking let solve....

so the ball was dropped .ie from rest to the ground through a distance of 2m,

the formula for calculating the distance if a body moving in a straight line is given by:

S=ut + ½at² where u is initial velocity, a is acceleration ( of the body or due to gravity, but since its falling freely under the influence of gravity its " we use the acceleration due to gravity ,which is 10m/s²) and t is the time taken to cover the distance.

from our question the ball was dropped from rest thus its u is 0 therefore we use this equation to find the time it took to touch ground (S=½at²)

solving ....

we get t to be 0.632s

to find the speed we substitute t in the equation below:

V=u+at ,but since u=0

V=at =10•0.632=6.32m/s

therefore the speed the body uses to strike the ground is 6.32m/s

B,C,D maybe

Explanation:

plz dont get mad

Answer:

you gotta shoot your shot.

Explanation:

look for the signs. ask her out before someone else does. you got this dawg

Answer:

0.3956

Explanation:

Newton's 2nd law of motion says that Force = Mass*Acceleration (f=ma) so to find the force used on the football you multiply it's mass by its acceleration.

0.43*0.92 = 0.3956.

0.4 if you round