Explanation:
Answers1.Electromagnetic waves
2.Electromagnetic radiation
3.Electromagneticwaves
PLS HELP ME!!!
The engine cars that pull high-speed trains usually taper to a point in front, as shown in the illustration. How does this shape change the forces acting on the moving engine car?
An electron and a proton are held on an x axis, with the electron at x = + 1.000 m
and the proton at x = - 1.000 m . If a second electron is initially at x = + 20.00 m on the x axis and is given an initial velocity of 450 m/s towards the origin, will it reach and origin? And how close will it get to the origin if it doesn't?
Answer:
r2 = 1 m
therefore the electron that comes with velocity does not reach the origin, it stops when it reaches the position of the electron at x = 1m
Explanation:
For this exercise we must use conservation of energy
the electric potential energy is
U = [tex]k \frac{q_1q_2}{r_{12}}[/tex]
for the proton at x = -1 m
U₁ =[tex]- k \frac{e^2 }{r+1}[/tex]
for the electron at x = 1 m
U₂ = [tex]k \frac{e^2 }{r-1}[/tex]
starting point.
Em₀ = K + U₁ + U₂
Em₀ = [tex]\frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1}[/tex]
final point
Em_f = [tex]k e^2 ( -\frac{1}{r_2 +1} + \frac{1}{r_2 -1})[/tex]
energy is conserved
Em₀ = Em_f
\frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1} = k e^2 (- \frac{1}{r_2 +1} + \frac{1}{r_2 -1})
\frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1} = k e²( [tex]\frac{2}{(r_2+1)(r_2-1)}[/tex] )
we substitute the values
½ 9.1 10⁻³¹ 450 + 9 10⁹ (1.6 10⁻¹⁹)² [ [tex]- \frac{1}{20+1} + \frac{1}{20-1}[/tex] ) = 9 109 (1.6 10-19) ²( [tex]\frac{2}{r_2^2 -1}[/tex] )
2.0475 10⁻²⁸ + 2.304 10⁻³⁷ (5.0125 10⁻³) = 4.608 10⁻³⁷ ( [tex]\frac{1}{r_2^2 -1}[/tex] )
2.0475 10⁻²⁸ + 1.1549 10⁻³⁹ = 4.608 10⁻³⁷ [tex]\frac{1}{r_2^2 -1}[/tex]
[tex]\frac{2.0475 \ 10^{-28} }{1.1549 \ 10^{-37} } = \frac{1}{r_2^2 -1}[/tex]
r₂² -1 = (4.443 10⁸)⁻¹
r2 = [tex]\sqrt{1 + 2.25 10^{-9}}[/tex]
r2 = 1 m
therefore the electron that comes with velocity does not reach the origin, it stops when it reaches the position of the electron at x = 1m
Shown below is a 10 kg block being pushed by a horizontal force F of magnitude 200N. The coefficient of kinetic friction between the two surface is 0.50. Find the acceleration of the block.
Answer:
15.1 m/s²
Explanation:
Step 1: Calculate the force exerted by the friction
Friction exerts a force against the direction of the movement. On a horizontal plane, we can calculate the value of that force using the following expression.
Ff = μ × m × g
where,
μ: coefficient of kinetic friction
m: mass of the block
g: gravity
Ff = 0.50 × 10 kg × 9.81 m/s² = 49 N
Step 2: Calculate the resulting force
The horizontal force F and the friction force Ff are vectors that act in opposite directions. We can calculate the resulting force (R) by doing the subtraction.
R = F - Ff = R = 200 N - 49 N = 151 N
Step 3: Calculate the acceleration of the block
We will use Newton's second law of motion.
R = m × a
a = R/m
a = 151 N/10 kg = 15.1 m/s²
The density of the atmosphere on a certain planet is found to decrease as altitude increases (as measured from the planet's surface). What is the graphical relationship between altitude and atmospheric density on this planet? Altitude (km) Almospheric Density (km/mº)
Α.inverse plot B. quadratic plot C. velocity plot D. acceleration plot E.parabolic plot
Answer:I think it’s Velocity plot.
Explanation:
I hope i can help you, have a great day and good like with everything.
Answer: inverse plot
Explanation: lucky guess lmk if its right
What is physic?............
Physics is the study of nature and law
Answer:
Physics is the science of matter and how matter interacts. Matter is any physical material in the universe. Everything is made of matter. Physics is used to describe the physical universe around us, and to predict how it will behave.
If the frequency of a sound wave increases, the wavelength of the wave in air
a. Increases
b. Decreases
c. Remains the same
A specified volume of space contains an electric field for which the magnitude is given by E=E0cos(ωt). Suppose that E0 = 20 V/m and ω = 1.0 × 107 s−1. What is the maximum displacement current through a 0.40 m2 cross-sectional area of this volume?
Answer: [tex]0.708\ mA[/tex]
Explanation:
Given
[tex]E_o=20\ V/m[/tex]
[tex]\omega =10^7\ s^{-1}[/tex]
Cross-sectional area [tex]A=0.40\ m^2[/tex]
Current density is given by
[tex]J=\epsilon_o \dfrac{dE}{dt}[/tex]
Displacement current
[tex]\Rightarrow I=JA\\\Rightarrow I=8.854\times 10^{-12}\times 20\times 10^7\times 0.4\\\Rightarrow I=0.708\times 10^{-3}\ A[/tex]
The required value of the maximum displacement current of the given space is [tex]7.08 \times 10^{-4} \;\rm A[/tex].
Given data:
The intensity of electric field is, [tex]E_{0}=20 \;\rm V/m[/tex].
The angular frequency of electric field is, [tex]\omega=1.0 \times 10^{7} \;\rm s^{-1}[/tex].
The cross-sectional area of space is, [tex]A =0.40 \;\rm m^{2}[/tex].
In the given problem, the instantaneous electric field is given by [tex]E = E_{0} \times cos(\omega t)[/tex]
So, the expression for the current density is,
[tex]J= \epsilon_{0} \times \dfrac{dE}{dt}[/tex]
Here, [tex]\epsilon_{0}[/tex] is the permittivity of free space. Solving as,
[tex]J= \epsilon_{0} \times \dfrac{d(E_{0} \times cos(\omega t))}{dt}\\\\J= -\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)[/tex]
And the expression for the maximum displacement current is,
[tex]I = J \times A[/tex]
And the maximum displacement current is possible only when, J is positive and J will be positive for [tex]sin(\omega t)=-1[/tex].
Then solving as,
[tex]I = (-\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)) \times A\\\\I = (-8.85 \times 10^{-12} \times 20 \times (1.0 \times 10^{7}) \times (-1)) \times 0.40\\\\I = 7.08 \times 10^{-4} \;\rm A[/tex]
Thus, we can conclude that the required value of the maximum displacement current of the given space is [tex]7.08 \times 10^{-4} \;\rm A[/tex].
Learn more about the displacement current here:
https://brainly.com/question/20344850
I’m think 3 or 1.. am I right?
Answer:
C-3 I beleive it is three!!!!
Explanation:
Hope this helps!
Have a grreat day!
-Hailey
Answer:
it is n2+3
Explanation:
100 points!!! Please help!!!
In the system shown above, the pulley is a uniform disk with a mass of .75 kg and a radius of 6.5 cm. The coefficient of friction between the 5.8 kg mass and the horizontal surface is .25, and the ropes does not slip on the pulley. They system is released from rest. Use work-energy principles to determine the kinetic energy of the (a) 2.8 kg mass and (b) the pulley after the 5.8 kg mass has moved 2.2 meters.
Answer:
please find the answer in the attached image, divided in 2 parts.
Whats a recent new discovery made in physics ? please add a link to the study if you can !
Answer:
Heres the link!
Explanation:
https://www.bbc.co.uk/news/science-environment-56491033
Answer:
here's the link you asked for: https://www.nyas.org/ebriefings/the-physics-of-everything/ and here's the info inside the link: During the second quarter of 2016, the Academy hosted a series of evening panel discussions boldly titled "." With grant support from The John Templeton Foundation, the six panels addressed how physics is addressing grand questions and the potential limitations on what we may be able to learn using physics to address those questions.
The first session posed the question "" Three physicists explored the frontiers of cosmology and quantum physics. There may always be limits to our understanding in areas such as string theory, dark matter, and multiverses. But the panelists agreed that it is best to proceed as if explanations based in physics can be found.
The second session asked "" The panelists argued that philosophy has much to offer physics, in contrast to the assertions of some prominent physicists. In such areas as the role of observations in quantum mechanics and the experimental validation of theory, the panelists illustrated the power of a critical, interdisciplinary approach to understanding not only the facts but the significance of physics ideas.
Physics has achieved its success in part by selecting problems that can be addressed by reducing them to simple parts following simple laws. Less amenable subjects were discussed in the third session, "" Biology, ecology, and social phenomena such as cities are all not easily described with simple equations, but still show amazing regularities. The panelists, including two physicists, a philosopher, and a computer scientist, sketched their hopes for unifying principles that explain these regularities.
One complex phenomenon that has so far evaded physical analysis was the topic of the fourth session, "." Two of the panelists, a neuroscientist and a roboticist, did not even regard consciousness as a distinct phenomenon but rather as a byproduct of systems that model themselves. In contrast, a philosopher and a physicist felt that this behavioral description misses something essential about what consciousness "feels like." Both groups expressed hope for experimental tests of their views.
The fifth session addressed the question, "" Recent experimental observations of thousands of planets orbiting other stars bolster the expectation that ours is not the first civilization. The panelists explored how we might look for others and why we have not encountered any yet. One troubling possibility is that civilizations that achieve global scale inevitably encounter challenges such as climate change that they fail to overcome.
The sixth session was entitled "." Two physicists and a computer scientist discussed amazing developments at the intersection of quantum gravity (as manifested in black holes) and quantum information. Trying to reconcile these disparate observations has overturned the traditional view of black holes, with no clear resolution so far. At the same time, an abstract connection between gravitational models and quantum models in one fewer dimension is providing insight into both fields, including new methods for error correction in quantum computing as well as benchtop tests of black hole physics.
The wide ranging discussions of the six panels illustrate the power of physics to explain the universe as well as the vast frontiers of that universe that still remain to be explored.
Explanation:
hope this helped plz give brainliest and rating ^_^
Convertir 0.3 Hm en cm.
Answer:
3000 cm
Explanation:
Horticulture 120 pts (HURRY)
Auto-steer technology is dependent on the use of
tracking relayed from satellites to receivers and transmitters in the farm equipment.
Answer: GPS
Explanation:
I took the test 2021
Answer:
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Explain why the weather changes with the season's temperate climate zones.
where would a car traveling on a roller coaster have the most kinetic energy ? and why?
Answer:
As the car travels up the coaster it is gaining potential energy.
Explanation:
Because It has the greatest in amount of potential energy at the top of the coaster. when the car travels down the roller coaster it obtains speed and kinetic energy.
Can someone help me with this please
The downward force acting on an object in free fall is the force of ___________
An ocean wave travels at 2.2m/s if the wavelength is 11 meters what’s the frequency of the wave in Hz
Answer:
0.2 Hz
Explanation:
f = v / λ.
Where f = frequency,
v = velocity/speed,
λ = wavelength.
f = v / λ →
f = 2.2m/s / 11 m
f = 2.2 / 11 [1 / s]
f = 1 / 5 [Hz]
f = 0.2 Hz
Why do electric fish need to force electric charges to move?
What is the driving force behind the movement of Earth's plates?
Convection currents in the mantle are slowly causing the plates to move.
The magnetic pull of the poles are pulling the plates apart.
The inertia of the rotation of the Earth causes the plates to move.
The aliens are playing with the Earth like a puzzle.
Convection currents in the mantle are slowly causing the plates to move.
What different forms of energy are present when an egg crashes into the egg catcher?
Answer:
An egg raised above the ground has potential energy due to the force of gravity. When dropped, the egg's potential energy is converted into the kinetic energy of motion. :)
Explanation:
Can someone please help me with history.
Answer:
Yes my name is Axelrod I can help you
A 0.500 kg mass is oscillating on a spring with k = 330 N/m. The total energy of its oscillation is 3.24 J. What is the amplitude of the oscillation? (Unit = m)
Answer:
0.140
Explanation:
may i be marked brainliest
- Determine the speed of a 350 Hz sound wave with a wavelength of 0.971 m
adio wave transmitted to the moon through snace by
Explanation:
[tex]from \: the \: wave \: equation \\ Speed \: \: V = f \lambda \\ = 350 \times 0.971 \\ = 339 850 \: {ms}^{ - 1} [/tex]
While traveling along a highway a driver slows from 31 m/s to 15 m/s in 8 seconds. What is the automobile’s acceleration? (Remember that a negative value indicates a slowing down or deceleration.)
Answer:
The automobile's acceleration in that time interval is -2 m/s^2
Explanation:
The acceleration is defined as the rate of change of the velocity.
The average acceleration in a given lapse of time is calculated as:
A = (final velocity - initial velocity)/time.
In this case, we have:
initial velocity = 31 m/s
final velocity = 15 m/s
time = 8 seconds.
Then the average acceleration is:
A = (15m/s - 31m/s)/8s = -2 m/s^2
Help me with this Bell Ringer / Answer Only / Ez 30 Points /
identifying the forces among the four particles in the Helium nucleus atom and explain why the nucleus stays together.
(Write a paragraph)
Explanation:
the forces among the four particles in the helium nucleus atom are strong, weak, electromagnetic and gravity
A friend insists that electric current is the same as electrical energy. Work with a partner to develop a rebuttal
against your friend's misconception.
Answer: The electrons flowing through the wire are referred to as a quantity of electricity, and the flow of electricity is referred to as “an electric current.”
Explanation: Hope it Helps have a blessed day
how do we calculate the value of work?
Answer:
Work = Force × Distance
Explanation:
Work = Force × Distance
The SI unit of work is Joule
-TheUnknownScientist
Cuales podrian ser las causas y consecuencias del aumento de problemas de salud mental en la población chilena
Explanation:
CAUSAS:
-El gobierno de chile ha destinado el 2% de sus recursos de salud pública para tratar los problemas de salud mental,lo cual es insuficiente debido a la alta demanda de pacientes que requieren atención especializada. Según la OMS (organización mundial de la salud) , cada gobierno debería destinar al menos el 5% de sus recursos para tratar este tipo de patologías o enfermedades mentales como la depresión,la ansiedad u otros trastornos bipolares
- El personal capacitado para tratar este tipo de enfermedades es muy escaso.
- Muchos de los chilenos que padecen este tipo de enfermedades no buscan ayuda inmediata, algunos recurren al alcohol o a los vicios como el cigarrillo o la marihuana , pensando que lograrán calmar la ansiedad o sus preocupaciones pero en realidad sucede lo contrario, aumentan la depresión y la ansiedad.
-Los problemas sociales, la crisis económica y el aumento de la pobreza así como el limitado acceso que tiene la población pobre chilena a un buen sistema de salud integrado,genera un significativo aumento de problemas de salud mental en especial en la población pobre o más desfavorecida del país.
CONSECUENCIAS:
Debido a los problemas de salud mental las incapacidades laborales han aumentado, afectando la economía del país.
Debido a la falta de tratamiento ,el suicidio y otras enfermedades como la esquizofrenia han aumentado. De igual manera la violencia intrafamiliar se ha incrementado e inclusive hasta los niños están empezando a sufrir este tipo de trastornos o enfermedades mentales,lo cual está afectando su desempeño escolar.
True or False. The Magnitude of the induced voltage in a coil of wire depends on how quickly the magnetic flux through the coil of wire changes.
Answer:
Yes, its true
Explanation:
hdheheishdhieijzuwhs
Answer: yes its true
Explanation:
nmo
Two resistors, R1 and R2, are connected
in series to a 5.00 V battery. R1 is
12.0 Ohm. A current of 0.167 A flows
through the circuit.
What is resistance of R2?
Answer:
18 ohms
Explanation:
V = I(R1 + R2)
5V = (0.167A)(12 ohms + R2)
Solving for R2
R2 = 18 ohms