Answer:
The agricultural revolution increased agricultural production and technological advancements. I think this led to population growth because the increase in labor and the increase in technologies increased human deveolpment. The revolution also allowed farmers to grow and produce more food and transport it to where it was needed.
Explanation:
A rock is made of the same substance while a mineral is made up of different type of
rocks
True
False
Answer:
False i think
Oxalic Acid, a compound found in plants and vegetables such as rhubarb, has a mass percent composition of 26.7% C, 2.24% H, and 71.1% O. Oxalic acid can interfere with respiration and cause kidney or bladder stones. If a large quantity of rhubarb leaves is ingested, the oxalic acid can be toxic. The lethal dose (LD50) in rats for oxalic acid is 375 mg/kg. Rhubarb leaves contain about 0.5% by mass of oxalic acid. (Show your work, using the insert equation tool :) What is the empirical formula of oxalic acid
Answer:
HCO₂
Explanation:
From the information given:
The mass of the elements are:
Carbon C = 26.7 g; Hydrogen H = 2.24 g Oxygen O = 71.1 g
To determine the empirical formula;
First thing is to find the numbers of moles of each atom.
For Carbon:
[tex]=26.7 \ g\times \dfrac{1 \ mol }{12.01 \ g} \\ \\ =2.22 \ mol \ of \ Carbon[/tex]
For Hydrogen:
[tex]=2.24 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =2.22 \ mol \ of \ Hydrogen[/tex]
For Oxygen:
[tex]=71.1 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =4.44 \ mol \ of \ oxygen[/tex]
Now; we use the smallest no of moles to divide the respective moles from above.
For carbon:
[tex]\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ carbon[/tex]
For Hydrogen:
[tex]\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ hydrogen[/tex]
For Oxygen:
[tex]\dfrac{4.44 \ mol \ of \ Oxygen}{2.22} =2 \ mol \ of \ oxygen[/tex]
Thus, the empirical formula is HCO₂
pls help What are the benefits and limitations of scientific experiments and investigations?
what happens to particles when they are heated?
A. STop moving
B.Slow down and compress
C.Move closer together and speed up
D.Speed up and spread out
Answer:
D. Speed up and spread out
PLEASE HELP ASAP
A sample of a gas has a volume V1 = 3L at a temperature T1 = 290K. Determine V2 when the temperature is T2
= 700K, while the pressure remains constant.
a.- 7.00L
b.- 7.24L
c.-2.74L
Eaterfication experiment
Answer:
Do you mean Esterification experiment?
Explanation:
Plzzzzz help me to solve this question.
Answer:
Explanation:
A1. Chemical indicator, any substance that gives a visible sign, usually by a colour change, of the presence or absence of a threshold concentration of a chemical species, such as an acid or an alkali in a solution. An example is the substance called methyl yellow, which imparts a yellow colour to an alkaline solution.
A2. The reaction of an acid with a base is called a neutralization reaction. The products of this reaction are a salt and water. ... For example, the reaction of hydrochloric acid, HCl, with sodium hydroxide, NaOH, solutions produces a solution of sodium chloride, NaCl, and some additional water molecules
A3. Methyl orange has the property to color alkaline and neutral water yellow. If the water becomes acidic, it turns red immediately.
Data Table 3: Polystyrene Test Tube, 12x75mm
Volume of water at room temperature (V1 in ml)
Volume of gas in polystyrene tube at boil (V2 in mL)
Temperature of gas at boil inside polystyrene tube (°C)
Volume of gas in polystyrenetube at room temperature (V3 in mL)
Temperature of gas at room temperature (°C)
Need help with data table 3: polystyrene test tube, 12x75mm
Answer:
Experiment 8 E Data Table 3 fl Data Table 4 fl Data Table 5 fl Data Table 6 Data Table 3: Polystyrene Test Tube, 12x75mm Volume of water at room temperature (V1 in mL) Volume of gas in polystyrene tube at boil (V2 in mL) Temperature of gas at boil inside polystyrene tube (°C) Volume of gas in polystyrenetube at room temperature (V3 in mL) Temperature of gas.
Explanation:
Hope this helps
Mark as Brainliest please
When you work out your cells need
Answer:
Waterrrr
Explanation:
H2O
Answer:
Muscle contraction
Explanation:
According to the new study, exercise improves muscle health by renewing its cellular powerhouse: the mitochondria. Mitochondria are crucial to the good functioning of our bodies, as well as to our overall health and longevity. These tiny parts of the cell turn the food we eat into energy.
The following containers have the same number of molecules and temperature. Which container has the most collisions?
Answer:
Container 1 I think.
The containers have the same number of molecules and temperature. The container 1.
What is collision?Collision is the encounter between two particles or object. There are three type of collision: perfectly elastic collision, inelastic collision, perfectly inelastic collision.
Container 1 is smallest, so there will be less distance between the molecules, so they will collide most.
Thus, the containers have the same number of molecules and temperature. The container 1.
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Select the correct structure that
corresponds to the name.
3-bromo-6-methyl-4-octene
CHE
A
Br
B.
CH3CH2CHBrCH = CHCH(CH3)CH2CH3
C. both
Someone please help
Answer:
b
Explanation:
one clue is the double bond at 4 carbon c=c
The correct structure that corresponds to the name.
3-bromo-6-methyl-4-octene is [tex]$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHBrCH}=\mathrm{CHCH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{CH}_{3}$[/tex] .
What is 3-bromo-6-methyl-4-octene?The molecule in which bromine is attached with C-3 carbon and double present at C-4 carbon containing total number of 8 carbon atom can be considered as 3-bromo-6-methyl-4-octene.
What is structure?
A chemist specifies the molecular geometry and, where possible and required, the electronic structure of such given molecule as well as other solid during a chemical structure determination.
It can be seen that in molecule [tex]$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHBrCH}=\mathrm{CHCH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{CH}_{3}$[/tex] bromine is attached with C-3 carbona and double bond exist at C-4 carbon. the total number of carbon atom is 8.
therefore, the structure of the compound will be [tex]$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHBrCH}=\mathrm{CHCH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{CH}_{3}$[/tex].
To know more about structure of the 3-bromo-6-methyl-4-octene click here.
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Calculate the pH of a solution containing 25 g of barium hydroxide (171.34 mel) dissolved in 250 mL of
solution.
Answer:
14
Explanation:
Step 1: Calculate the moles corresponding to 25 g of Ba(OH)₂
The molar mass of Ba(OH)₂ is 171.34 g/mol.
25 g × 1 mol/171.34 g = 0.15 mol
Step 2: Calculate the molar concentration of Ba(OH)₂
Molarity is equal to the moles of solute divided by the liters of solution.
[Ba(OH)₂] = 0.15 mol/0.250 L = 0.60 M
Step 3: Calculate the molar concentration of OH⁻
Ba(OH)₂ is a strong base according to the following equation.
Ba(OH)₂ ⇒ Ba²⁺ + 2 OH⁻
The molar ratio of Ba(OH)₂ to OH⁻ is 1:2. The molar concentration of OH⁻ is 2/1 × 0.60 M = 1.2 M.
Step 4: Calculate the concentration of H⁺
We will use the ionic product of water expression.
Kw = 1.0 × 10⁻¹⁴ = [H⁺] × [OH⁻]
[H⁺] = 1.0 × 10⁻¹⁴/[OH⁻] = 1.0 × 10⁻¹⁴/1.2 = 8.3 × 10⁻¹⁵ M
Step 5: Calculate the pH of the solution
We will use the definition of pH.
pH = -log [H⁺] = -log 8.3 × 10⁻¹⁵ = 14
Plz help me I am timed!!
Which is the correct statement regarding the relative Rf values of the starting methyl benzoate vs the product, methyl m-nitrobenzoate on a silica gel TLC plate. The product has a higher Rf value on a silica gel TLC plate because it is less polar than the starting methyl benzoate. The product has a lower Rf value on a silica gel TLC plate because it is less polar than the starting methyl benzoate. The product has a higher Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate. The product has a lower Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate. 1.5 points QUESTION 2 Methyl benzoate is more reactive than benzene in Electrophilic Aromatic Substition [EAS] reactions. True False 1 points QUESTION 3 Methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substition [EAS] reactions. True False
Answer:
1. The product has a higher Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate.
2. False
3. True
Explanation:
In chromatography, there is a stationary phase and a mobile phase. The ratio of the distance moved by a component and the distance moved by the solvent gives the retention factor (Rf).
Since silica gel is a polar solvent, it will retain the more polar product methyl m-nitrobenzoate compared to the methyl benzoate starting material.
In comparing the electrophillic aromatic substitution of m-nitrobenzoate and methyl benzoate, we must remember that the presence of electron withdrawing groups (such as -NO2 and -CHO) on the aromatic compound deactivates the compound towards electrophillic aromatic substitution hence, methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substition and Methyl benzoate is less reactive than benzene in Electrophilic Aromatic Substition
The final result has a higher Rf value because the TLC plate has more polarity than the other compound.
The answer to the following question is as follows:-
False True
In chromatography, it is a process that is used to separate the different components on the basis of their votality. The ratio of the distance moved by a component and the distance moved by the solvent gives the retention factor (Rf).
In comparing the electrophilic aromatic substitution of m-nitrobenzoate and methyl benzoate, we must remember that the presence of electron-withdrawing groups on the aromatic compound deactivates.
The compound towards electrophilic aromatic substitution hence, methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substitution and Methyl benzoate is less reactive than benzene in Electrophilic Aromatic Substitution.
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Imagine that you have an ideal gas in a 5.80 L container, and that 2950 molecules of this gas collide with a square-centimetre area of the container at any given instant.
If the volume is increased to 46.4 L at constant temperature, how many collisions will occur per square centimetre of this larger container?
Answer:
23,600 collisions.
Explanation:
Hello there!
In this case, according to the Avogadro's law, which help us to understand the molecules-volume relationship as directly proportional:
[tex]\frac{molecules_2}{V_2}=\frac{molecules_1}{V_1}[/tex]
It is possible for us to compute the collisions once the volume is increased as shown below:
[tex]molecules_2=\frac{molecules_1V_2}{V_1}\\\\molecules_2=\frac{2950*46.4L}{5.80L}\\\\molecules_2=23600[/tex]
Which means 23,600 collisions will occur per square centimeter.
Regards!
At which point on the roller coaster will the car have the greatest amount of Kinetic energy?
Answer please correctly
Answer:
the correct answere to that is q
Answer:
D.
Explanation:
3. You will need to make ~0.1 M solutions of one (or more) of the following salts. For each compound, determine (or look up) its molecular weight, and determine the mass necessary to make 100.0 mL of 0.100 M solution. Pay attention to significant figures! Sodium acetate anhydrous Sodium acetate trihydrate Iron(III) chloride hexahydrate g
Answer: The mass of sodium acetate anhydrous required is 0.820 g
The mass of sodium acetate trihydrate required is 1.36 g
The mass of Iron (III) chloride required is 2.70 g
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n = moles of solute
= volume of solution in ml
1. moles of =
Now put all the given values in the formula of molarity, we get
[tex]0.100=\frac{x\times 1000}{82.03\times 100.0}[/tex]
[tex]x=0.820g[/tex]
Therefore, the mass of sodium acetate anhydrous required is 0.820 g
2. moles of [tex]CH_3COONa.3H_2O[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{136.08g/mol}[/tex]
Now put all the given values in the formula of molarity, we get
[tex]0.100=\frac{x\times 1000}{136.08\times 100.0}[/tex]
[tex]x=1.36[/tex]
Therefore, the mass of sodium acetate trihydrate required is 1.36 g
3. moles of [tex]FeCl_3.6H_2O[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{g/mol}[/tex]
Now put all the given values in the formula of molarity, we get
[tex]0.100=\frac{x\times 1000}{270.33\times 100.0}[/tex]
[tex]x=2.70g[/tex]
Therefore, the mass of Iron (III) chloride required is 2.70 g
C12H26+Oxygen=12CO2+water
calculate the mass of one mole of the liquid alkane C12H26.
Answer:
170.38g is the mass of 1 mole of C₁₂H₂₆
Explanation:
To solve this question we must find the molar mass of the alkane C₁₂H₂₆. The molar mass is defined as the mass of one mole of a substance.
In 1 mole of C₁₂H₂₆ we have 12 moles of Carbon and 26 moles of Hydrogen. With the periodic table of elements we can know the molar mass of 1 mole of Carbon and 1 mole of hydrogen, and, thus, the molar mass of the alkane (Molar mass C = 12.01g/mol, H = 1.01g/mol)
Molar mass C₁₂H₂₆:
12C = 12*12.01g/mol = 144.12g/mol
26H = 26*1.01g/mol = 26.26g/mol
144.12g/mol + 26.26g/mol =
170.38g is the mass of 1 mole of C₁₂H₂₆HELP PLS IL GIVE YOU BRAINLIEST PLS IT BY TODAY AT 7 PLS HELP
Answer:
Calm down is this what you need?
Answer:
calm down, what kind of container and things do you need?
Explanation:
You and your lab partner are asked to determine the density of an aluminum bar. The mass is known accurately (to four significant figures). You use a simple metric ruler to measure its dimensions and obtain the results for Method A. Your partner uses a precision micrometer and obtains the results for Method B.
Method A (g/cm3) 2.7 Method B (g/cm3) 2.703 2.701 2.705 5.811
The accepted density of aluminum is 2.702 g/cm 3 .
(a) Calculate the average density for each method.
Should all the experimental results be included in your calculations? If not, justify any omissions.
(b) Calculate the percent error for each method’s average value.
(c) Calculate the standard deviation for each set of data.
(d) Which method’s average value is more precise? Which method is more accurate?
Complete Question
You and your lab partner are asked to determine the density of an aluminum bar. The mass is known accurately (to four significant figures). You use a simple metric ruler to measure its dimensions and obtain the results for Method A. Your partner uses a precision micrometer and obtains the results for Method B.
Method A (g/cm3) 2.2,2.3,2.7,2.4 Method B (g/cm3) 2.703 2.701 2.705 5.811
The accepted density of aluminum is 2.702 g/cm 3 .
(a) Calculate the average density for each method.
Should all the experimental results be included in your calculations? If not, justify any omissions.
(b) Calculate the percent error for each method’s average value.
(c) Calculate the standard deviation for each set of data.
(d) Which method’s average value is more precise? Which method is more accurate?
Answer:
a)[tex]Ma_{avg}= 2.4g/cm^3[/tex]
[tex]Mb_{avg}=2701g/cm^3[/tex]
b)[tex]PE_a=7.5\%[/tex]
[tex]P.E_b=28.8 \%[/tex]
c) [tex]\sigma_A=0.35[/tex]
[tex]\sigma_B=0.0545[/tex]
d)Method A
Explanation:
From the question we are told that:
Method A Density values
2.7
Method B Density values
2.703,2.701,2.705,5.811
Density of aluminium [tex]p_d=2.702 g/cm^3[/tex].
a)
Generally the average density for each method is mathematically given by
Method A
[tex]Ma_{avg}= \frac{2.2+2.3+2.7+2.4}{4}[/tex]
[tex]Ma_{avg}= 2.4g/cm^3[/tex]
Method B
[tex]Mb_{avg}=\frac{2.703+2.701+2.705}{3}[/tex]
[tex]Mb_{avg}=2701g/cm^3[/tex]
b)
Generally the equation for percentage error [tex]PE[/tex] is is mathematically given by
percent error = (measured- real)/real *100
Given real = 2.702 g/ cm3
Method A =
[tex]PE_a=(2.5- 2.702)* \frac{100}{2.702}[/tex]
[tex]PE_a=7.5\%[/tex]
Method B =
[tex]PE_b=( 3.481- 2.702)*\frac{100}{2.702}[/tex]
[tex]P.E_b=28.8 \%[/tex]
c)
Generally the standard deviation [tex]\sigma[/tex] for each method is mathematically given by
Method A
[tex]\sigma=\sqrt{\frac{\sum(x-a)^2}{N} }[/tex]
[tex]\sigma=\sqrt{\frac{0.25+0.16+0+0.09}{4} }[/tex]
[tex]\sigma_A=0.35[/tex]
Method B
[tex]\sigma=\sqrt{\frac{\sum(x-a)^2}{N} }[/tex]
[tex]\sigma=\sqrt{\frac{0.000001+0.00000+0.000009+0.011881}{4} }[/tex]
[tex]\sigma_B=0.0545[/tex]
d)
Therefore with lower percentage error the method who's average value is more precise is
Method A
7th grade science lol help
Answer:
The process you are referrring to is erosion.
Explanation:
Weathering would be the breaking down of rock/other land debris. Its more active counterpart would be erosion, wherein the process transports the bits of rock and minerals away. Hope it helps!
How do you decrease the amount of energy storage molecules there are in an ecosystem?
a) increase sunlight
b) decrease sunlight
c) burn dead matter
d) bury dead matter
e) trap carbon dioxide
Decreasing sunlight will decrease the amount of energy storage molecules in an ecosystem.
What is Photosynthesis?This is the process in which green plants manufacture food in the presence of sunlight. Primary producers are involved in this process of providing energy to the ecosystem.
This therefore means that a decrease in sunlight means a decrease in photosynthesis and energy production.
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Two objects of equal mass have a force of gravity of 6 N between them. Imagine the mass of one is cut in half and the other stays the same, what is the force due to gravity?
Answer:
F' = 3 N
Explanation:
Given that,
Two objects of equal mass have a force of gravity of 6 N between them.
If the mass of one is cut in half and the other stays the same such that,
m₁' = m₁ and m₂' = (m₂/2)
We need to find the new force. The gravitational force between two objects is given by :
[tex]F=G\dfrac{m_1m_2}{r^2}[/tex]
We have, F = 6 N
New force,
[tex]F'=G\dfrac{m_1'm_2'}{r^2}\\\\F'=\dfrac{Gm_1\times \dfrac{m_1}{2}}{r^2}\\\\=\dfrac{1}{2}\times \dfrac{Gm_1m_2}{r^2}\\\\F'=\dfrac{F}{2}\\\\F'=\dfrac{6}{2}\\\\F'=3\ N[/tex]
So, the new force becomes 3 N.
True or False?
A hydrogen bond is an attraction between molecules containing hydrogen that is not considered a true chemical bond.
Answer:TRUE
Explanation:
A hydrogen bond is the electromagnetic attraction created between a partially positively charged hydrogen atom attached to a highly electronegative atom and another nearby electronegative atom. A hydrogen bond is a type of dipole-dipole interaction; it is not a true chemical bond.
Which among the following is not required in the synthesis of fatty acids.
A). Acetyl-CoA
B). Biotin
C). Carbon iv oxide
D). NADH
Answer:
D). NADH
Explanation:
Sulfuric acid (H₂SO₄), is formed when sulfur dioxide (SO₂) reacts with oxygen and water. Using the balanced chemical reaction above, how many moles of H₂SO₄ are produced from 8.5 moles of SO₂?
Answer:
8.5 mol H₂SO₄
Explanation:
It seems the balanced reaction the problem is referring to is absent, however the description matches the following balanced reaction:
2SO₂ + O₂ + 2H₂O → 2H₂SO₄Now we can convert 8.5 moles of SO₂ into moles of H₂SO₄, using the stoichiometric coefficients of the balanced reaction:
8.5 mol SO₂ * [tex]\frac{2molH_2SO_4}{2molSO_2}[/tex] = 8.5 mol H₂SO₄What is the pH of a neutral solution at 25ºC?
a. 14
b. 0
c. 1
d. 7
Answer:
d.7 is the correct answer
Which months have an average high of 47 degrees Fahrenheit
Answer:
Explanation:
july
How many moles of aspirin (C9H8O4) are contained in 3.13 g of aspirin?
Answer:
The correct answer is - 0.0173888 moles.
Explanation:
Aspirin, C 9 H 8 O 4 , the atomic mass rounded to the nearest whole number, so: c- 12 h- 1 o - 16
now multiply these number by how many of each there are in the formula:
c - 12 x 9 = 108
h - 1 x 8 = 8
0 - 16 x 4 = 64
add these numbers up 108 + 8 + 64 = 180
aspirin has a molar mass of
180.g mol ^− 1 . This means that one mole of aspirin will have a mass of 180 g .
You're dealing with 3.13 g of aspirin, which will be equivalent to
3.13 g /180g
= 0.0173888 moles aspirin