1.Why do you think the agricultural revolution led to more population growth?

Answers

Answer 1

Answer:

The agricultural revolution increased agricultural production and technological advancements. I think this led to population growth because the increase in labor and the increase in technologies increased human deveolpment. The revolution also allowed farmers to grow and produce more food and transport it to where it was needed.

Explanation:


Related Questions

True or False?
A hydrogen bond is an attraction between molecules containing hydrogen that is not considered a true chemical bond.

Answers

Answer:TRUE

Explanation:

A hydrogen bond is the electromagnetic attraction created between a partially positively charged hydrogen atom attached to a highly electronegative atom and another nearby electronegative atom. A hydrogen bond is a type of dipole-dipole interaction; it is not a true chemical bond.

You and your lab partner are asked to determine the density of an aluminum bar. The mass is known accu­rately (to four significant figures). You use a simple metric ruler to measure its dimensions and obtain the results for Method A. Your partner uses a precision micrometer and obtains the results for Method B.
Method A (g/cm3) 2.7 Method B (g/cm3) 2.703 2.701 2.705 5.811
The accepted density of aluminum is 2.702 g/cm 3 .
(a) Calculate the average density for each method.
Should all the experimental results be included in your calculations? If not, justify any omissions.
(b) Calculate the percent error for each method’s average value.
(c) Calculate the standard deviation for each set of data.
(d) Which method’s average value is more precise? Which method is more accurate?

Answers

Complete Question

You and your lab partner are asked to determine the density of an aluminum bar. The mass is known accu­rately (to four significant figures). You use a simple metric ruler to measure its dimensions and obtain the results for Method A. Your partner uses a precision micrometer and obtains the results for Method B.

Method A (g/cm3) 2.2,2.3,2.7,2.4 Method B (g/cm3) 2.703 2.701 2.705 5.811

The accepted density of aluminum is 2.702 g/cm 3 .

(a) Calculate the average density for each method.

Should all the experimental results be included in your calculations? If not, justify any omissions.

(b) Calculate the percent error for each method’s average value.

(c) Calculate the standard deviation for each set of data.

(d) Which method’s average value is more precise? Which method is more accurate?

Answer:

a)[tex]Ma_{avg}= 2.4g/cm^3[/tex]

   [tex]Mb_{avg}=2701g/cm^3[/tex]

b)[tex]PE_a=7.5\%[/tex]

  [tex]P.E_b=28.8 \%[/tex]

c) [tex]\sigma_A=0.35[/tex]

   [tex]\sigma_B=0.0545[/tex]

d)Method A

Explanation:

From the question we are told that:

Method A Density values

2.7

Method B Density values

2.703,2.701,2.705,5.811

Density of aluminium [tex]p_d=2.702 g/cm^3[/tex].

a)  

Generally the average density for each method is mathematically given by

Method A

[tex]Ma_{avg}= \frac{2.2+2.3+2.7+2.4}{4}[/tex]

[tex]Ma_{avg}= 2.4g/cm^3[/tex]

Method B

[tex]Mb_{avg}=\frac{2.703+2.701+2.705}{3}[/tex]

[tex]Mb_{avg}=2701g/cm^3[/tex]

b)

Generally the equation for percentage error [tex]PE[/tex] is is mathematically given by

percent error = (measured- real)/real *100

Given real = 2.702 g/ cm​​​3

Method A =

[tex]PE_a=(2.5- 2.702)* \frac{100}{2.702}[/tex]

[tex]PE_a=7.5\%[/tex]

Method B =

[tex]PE_b=( 3.481- 2.702)*\frac{100}{2.702}[/tex]

[tex]P.E_b=28.8 \%[/tex]

c)

Generally the standard deviation [tex]\sigma[/tex] for each method is mathematically given by

Method A

[tex]\sigma=\sqrt{\frac{\sum(x-a)^2}{N} }[/tex]

[tex]\sigma=\sqrt{\frac{0.25+0.16+0+0.09}{4} }[/tex]

[tex]\sigma_A=0.35[/tex]

Method B

[tex]\sigma=\sqrt{\frac{\sum(x-a)^2}{N} }[/tex]

[tex]\sigma=\sqrt{\frac{0.000001+0.00000+0.000009+0.011881}{4} }[/tex]

[tex]\sigma_B=0.0545[/tex]

d)

Therefore with lower percentage error the method who's average value is more precise is

Method A

Answer please correctly

Answers

Answer:

the correct answere to that is q

Answer:

D.

Explanation:

Select the correct structure that
corresponds to the name.
3-bromo-6-methyl-4-octene
CHE
A
Br
B.
CH3CH2CHBrCH = CHCH(CH3)CH2CH3
C. both

Someone please help

Answers

Answer:

b

Explanation:

one clue is the double bond at 4 carbon c=c

The correct structure that corresponds to the name.

3-bromo-6-methyl-4-octene is   [tex]$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHBrCH}=\mathrm{CHCH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{CH}_{3}$[/tex] .

What is 3-bromo-6-methyl-4-octene?

The molecule in which bromine is attached with C-3 carbon and double present at C-4 carbon containing total number of 8 carbon atom can be considered as 3-bromo-6-methyl-4-octene.

What is structure?

A chemist specifies the molecular geometry and, where possible and required, the electronic structure of such given molecule as well as other solid during a chemical structure determination.

It can be seen that in molecule [tex]$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHBrCH}=\mathrm{CHCH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{CH}_{3}$[/tex] bromine is attached with C-3 carbona and double bond exist at C-4 carbon. the total number of carbon atom is 8.

therefore, the structure of the compound will be [tex]$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHBrCH}=\mathrm{CHCH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{CH}_{3}$[/tex].

To know more about  structure of the  3-bromo-6-methyl-4-octene click here.

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The following containers have the same number of molecules and temperature. Which container has the most collisions?

Answers

Answer:

Container 1 I think.

The containers have the same number of molecules and temperature. The container 1.

What is collision?

Collision is the encounter between two particles or object. There are three type of collision: perfectly elastic collision, inelastic collision, perfectly inelastic collision.

Container 1 is smallest, so there will be less distance between the molecules, so they will collide most.

Thus, the containers have the same number of molecules and temperature. The container 1.

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A rock is made of the same substance while a mineral is made up of different type of
rocks

True

False

Answers

Answer:

False i think

7th grade science lol help​

Answers

Answer:

The process you are referrring to is erosion.

Explanation:

Weathering would be the breaking down of rock/other land debris. Its more active counterpart would be erosion, wherein the process transports the bits of rock and minerals away. Hope it helps!

Which months have an average high of 47 degrees Fahrenheit

Answers

Answer:

Explanation:

july

3. You will need to make ~0.1 M solutions of one (or more) of the following salts. For each compound, determine (or look up) its molecular weight, and determine the mass necessary to make 100.0 mL of 0.100 M solution. Pay attention to significant figures! Sodium acetate anhydrous Sodium acetate trihydrate Iron(III) chloride hexahydrate g

Answers

Answer: The mass of sodium acetate anhydrous required is 0.820 g

The mass of sodium acetate trihydrate required is 1.36 g

The mass of Iron (III) chloride required is 2.70 g

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute

= volume of solution in ml

1. moles of =

Now put all the given values in the formula of molarity, we get

[tex]0.100=\frac{x\times 1000}{82.03\times 100.0}[/tex]

[tex]x=0.820g[/tex]

Therefore, the mass of sodium acetate anhydrous required is 0.820 g

2.   moles of [tex]CH_3COONa.3H_2O[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{136.08g/mol}[/tex]

Now put all the given values in the formula of molarity, we get

[tex]0.100=\frac{x\times 1000}{136.08\times 100.0}[/tex]

[tex]x=1.36[/tex]

Therefore, the mass of sodium acetate trihydrate required is 1.36 g

3. moles of [tex]FeCl_3.6H_2O[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{g/mol}[/tex]

Now put all the given values in the formula of molarity, we get

[tex]0.100=\frac{x\times 1000}{270.33\times 100.0}[/tex]

[tex]x=2.70g[/tex]

Therefore, the mass of Iron (III) chloride required is 2.70 g

Which is the correct statement regarding the relative Rf values of the starting methyl benzoate vs the product, methyl m-nitrobenzoate on a silica gel TLC plate. The product has a higher Rf value on a silica gel TLC plate because it is less polar than the starting methyl benzoate. The product has a lower Rf value on a silica gel TLC plate because it is less polar than the starting methyl benzoate. The product has a higher Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate. The product has a lower Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate. 1.5 points QUESTION 2 Methyl benzoate is more reactive than benzene in Electrophilic Aromatic Substition [EAS] reactions. True False 1 points QUESTION 3 Methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substition [EAS] reactions. True False

Answers

Answer:

1. The product has a higher Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate.

2. False

3. True

Explanation:

In chromatography, there is a stationary phase and a mobile phase. The ratio of the distance moved by a component and the distance moved by the solvent gives the retention factor (Rf).

Since silica gel is a polar solvent, it will retain the more polar product methyl m-nitrobenzoate compared to the methyl benzoate starting material.

In comparing the electrophillic aromatic substitution of m-nitrobenzoate  and methyl benzoate, we must remember that the presence of electron withdrawing groups (such as -NO2 and -CHO) on the aromatic compound deactivates the compound towards electrophillic aromatic substitution hence, methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substition and Methyl benzoate is less reactive than benzene in Electrophilic Aromatic Substition

The final result has a higher Rf value because the TLC plate has more polarity than the other compound.

The answer to the following question is as follows:-

False True

In chromatography, it is a process that is used to separate the different components on the basis of their votality. The ratio of the distance moved by a component and the distance moved by the solvent gives the retention factor (Rf).

In comparing the electrophilic aromatic substitution of m-nitrobenzoate and methyl benzoate, we must remember that the presence of electron-withdrawing groups on the aromatic compound deactivates.

The compound towards electrophilic aromatic substitution hence, methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substitution and Methyl benzoate is less reactive than benzene in Electrophilic Aromatic Substitution.  

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When you work out your cells need

Answers

Answer:

Waterrrr

Explanation:

H2O

Answer:

Muscle contraction

Explanation:

According to the new study, exercise improves muscle health by renewing its cellular powerhouse: the mitochondria. Mitochondria are crucial to the good functioning of our bodies, as well as to our overall health and longevity. These tiny parts of the cell turn the food we eat into energy.

Calculate the pH of a solution containing 25 g of barium hydroxide (171.34 mel) dissolved in 250 mL of
solution.

Answers

Answer:

14

Explanation:

Step 1: Calculate the moles corresponding to 25 g of Ba(OH)₂

The molar mass of Ba(OH)₂ is 171.34 g/mol.

25 g × 1 mol/171.34 g = 0.15 mol

Step 2: Calculate the molar concentration of Ba(OH)₂

Molarity is equal to the moles of solute divided by the liters of solution.

[Ba(OH)₂] = 0.15 mol/0.250 L = 0.60 M

Step 3: Calculate the molar concentration of OH⁻

Ba(OH)₂ is a strong base according to the following equation.

Ba(OH)₂ ⇒ Ba²⁺ + 2 OH⁻

The molar ratio of Ba(OH)₂ to OH⁻ is 1:2. The molar concentration of OH⁻ is 2/1 × 0.60 M = 1.2 M.

Step 4: Calculate the concentration of H⁺

We will use the ionic product of water expression.

Kw = 1.0 × 10⁻¹⁴ = [H⁺] × [OH⁻]

[H⁺] = 1.0 × 10⁻¹⁴/[OH⁻] = 1.0 × 10⁻¹⁴/1.2 = 8.3 × 10⁻¹⁵ M

Step 5: Calculate the pH of the solution

We will use the definition of pH.

pH = -log [H⁺] = -log 8.3 × 10⁻¹⁵ = 14

C12H26+Oxygen=12CO2+water
calculate the mass of one mole of the liquid alkane C12H26.​

Answers

Answer:

170.38g is the mass of 1 mole of C₁₂H₂₆

Explanation:

To solve this question we must find the molar mass of the alkane C₁₂H₂₆. The molar mass is defined as the mass of one mole of a substance.

In 1 mole of C₁₂H₂₆ we have 12  moles of Carbon and 26 moles of Hydrogen. With the periodic table of elements we can know the molar mass of 1 mole of Carbon and 1 mole of hydrogen, and, thus, the molar mass of the alkane (Molar mass C = 12.01g/mol, H = 1.01g/mol)

Molar mass C₁₂H₂₆:

12C = 12*12.01g/mol = 144.12g/mol

26H = 26*1.01g/mol = 26.26g/mol

144.12g/mol + 26.26g/mol =

170.38g is the mass of 1 mole of C₁₂H₂₆

What is the pH of a neutral solution at 25ºC?
a. 14
b. 0
c. 1
d. 7

Answers

Answer:

d.7 is the correct answer

Two objects of equal mass have a force of gravity of 6 N between them. Imagine the mass of one is cut in half and the other stays the same, what is the force due to gravity?

Answers

Answer:

F' = 3 N

Explanation:

Given that,

Two objects of equal mass have a force of gravity of 6 N between them.

If the mass of one is cut in half and the other stays the same such that,

m₁' = m₁ and m₂' = (m₂/2)

We need to find the new force. The gravitational force between two objects is given by :

[tex]F=G\dfrac{m_1m_2}{r^2}[/tex]

We have, F = 6 N

New force,

[tex]F'=G\dfrac{m_1'm_2'}{r^2}\\\\F'=\dfrac{Gm_1\times \dfrac{m_1}{2}}{r^2}\\\\=\dfrac{1}{2}\times \dfrac{Gm_1m_2}{r^2}\\\\F'=\dfrac{F}{2}\\\\F'=\dfrac{6}{2}\\\\F'=3\ N[/tex]

So, the new force becomes 3 N.

Plzzzzz help me to solve this question.​

Answers

Answer:

Explanation:

A1. Chemical indicator, any substance that gives a visible sign, usually by a colour change, of the presence or absence of a threshold concentration of a chemical species, such as an acid or an alkali in a solution. An example is the substance called methyl yellow, which imparts a yellow colour to an alkaline solution.

A2. The reaction of an acid with a base is called a neutralization reaction. The products of this reaction are a salt and water. ... For example, the reaction of hydrochloric acid, HCl, with sodium hydroxide, NaOH, solutions produces a solution of sodium chloride, NaCl, and some additional water molecules

A3. Methyl orange has the property to color alkaline and neutral water yellow. If the water becomes acidic, it turns red immediately.

Imagine that you have an ideal gas in a 5.80 L container, and that 2950 molecules of this gas collide with a square-centimetre area of the container at any given instant.

If the volume is increased to 46.4 L at constant temperature, how many collisions will occur per square centimetre of this larger container?

Answers

Answer:

23,600 collisions.

Explanation:

Hello there!

In this case, according to the Avogadro's law, which help us to understand the molecules-volume relationship as directly proportional:

[tex]\frac{molecules_2}{V_2}=\frac{molecules_1}{V_1}[/tex]

It is possible for us to compute the collisions once the volume is increased as shown below:

[tex]molecules_2=\frac{molecules_1V_2}{V_1}\\\\molecules_2=\frac{2950*46.4L}{5.80L}\\\\molecules_2=23600[/tex]

Which means 23,600 collisions will occur per square centimeter.

Regards!

At which point on the roller coaster will the car have the greatest amount of Kinetic energy?

Answers

I’m going to say the answer is most likely X because memetic energy is energy being used at that moment. Because the coaster is going fastest at X we can assume that the answer is X

PLEASE HELP ASAP
A sample of a gas has a volume V1 = 3L at a temperature T1 = 290K. Determine V2 when the temperature is T2
= 700K, while the pressure remains constant.
a.- 7.00L
b.- 7.24L
c.-2.74L​

Answers

I think the answer is b

HELP PLS IL GIVE YOU BRAINLIEST PLS IT BY TODAY AT 7 PLS HELP

Answers

Answer:

Calm down is this what you need?

Answer:

calm down, what kind of container and things do you need?

Explanation:

Which among the following is not required in the synthesis of fatty acids.
A). Acetyl-CoA
B). Biotin
C). Carbon iv oxide
D). NADH

Answers

Answer:

D). NADH

Explanation:

Oxalic Acid, a compound found in plants and vegetables such as rhubarb, has a mass percent composition of 26.7% C, 2.24% H, and 71.1% O. Oxalic acid can interfere with respiration and cause kidney or bladder stones. If a large quantity of rhubarb leaves is ingested, the oxalic acid can be toxic. The lethal dose (LD50) in rats for oxalic acid is 375 mg/kg. Rhubarb leaves contain about 0.5% by mass of oxalic acid. (Show your work, using the insert equation tool :) What is the empirical formula of oxalic acid

Answers

Answer:

HCO₂

Explanation:

From the information given:

The mass of the elements are:

Carbon C = 26.7 g;     Hydrogen H = 2.24 g     Oxygen O = 71.1 g

To determine the empirical formula;

First thing is to find the numbers of moles of each atom.

For Carbon:

[tex]=26.7 \ g\times \dfrac{1 \ mol }{12.01 \ g} \\ \\ =2.22 \ mol \ of \ Carbon[/tex]

For Hydrogen:

[tex]=2.24 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =2.22 \ mol \ of \ Hydrogen[/tex]

For Oxygen:

[tex]=71.1 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =4.44 \ mol \ of \ oxygen[/tex]

Now; we use the smallest no of moles to divide the respective moles from above.

For carbon:

[tex]\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ carbon[/tex]

For Hydrogen:

[tex]\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ hydrogen[/tex]

For Oxygen:

[tex]\dfrac{4.44 \ mol \ of \ Oxygen}{2.22} =2 \ mol \ of \ oxygen[/tex]

Thus, the empirical formula is HCO₂

Data Table 3: Polystyrene Test Tube, 12x75mm
Volume of water at room temperature (V1 in ml)
Volume of gas in polystyrene tube at boil (V2 in mL)
Temperature of gas at boil inside polystyrene tube (°C)
Volume of gas in polystyrenetube at room temperature (V3 in mL)
Temperature of gas at room temperature (°C)


Need help with data table 3: polystyrene test tube, 12x75mm

Answers

Answer:

Experiment 8 E Data Table 3 fl Data Table 4 fl Data Table 5 fl Data Table 6 Data Table 3: Polystyrene Test Tube, 12x75mm Volume of water at room temperature (V1 in mL) Volume of gas in polystyrene tube at boil (V2 in mL) Temperature of gas at boil inside polystyrene tube (°C) Volume of gas in polystyrenetube at room temperature (V3 in mL) Temperature of gas.

Explanation:

Hope this helps

Mark as Brainliest please

pls help What are the benefits and limitations of scientific experiments and investigations?

Answers

The benefits and limitations of scientific experiments and investigations is the knowledge allows us to develop new technologies

Plz help me I am timed!!

Answers

answer: i think it is C

How do you decrease the amount of energy storage molecules there are in an ecosystem?
a) increase sunlight
b) decrease sunlight
c) burn dead matter
d) bury dead matter
e) trap carbon dioxide

Answers

Decreasing sunlight will decrease the amount of energy storage molecules in an ecosystem.

What is Photosynthesis?

This is the process in which green plants manufacture food in the presence of sunlight. Primary producers are involved in this process of providing energy to the ecosystem.

This therefore means that a decrease in sunlight means a decrease in photosynthesis and energy production.

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Sulfuric acid (H₂SO₄), is formed when sulfur dioxide (SO₂) reacts with oxygen and water. Using the balanced chemical reaction above, how many moles of H₂SO₄ are produced from 8.5 moles of SO₂?

Answers

Answer:

8.5 mol H₂SO₄

Explanation:

It seems the balanced reaction the problem is referring to is absent, however the description matches the following balanced reaction:

2SO₂ + O₂ + 2H₂O → 2H₂SO₄

Now we can convert 8.5 moles of SO₂ into moles of H₂SO₄, using the stoichiometric coefficients of the balanced reaction:

8.5 mol SO₂ * [tex]\frac{2molH_2SO_4}{2molSO_2}[/tex] = 8.5 mol H₂SO₄

what happens to particles when they are heated?
A. STop moving
B.Slow down and compress
C.Move closer together and speed up
D.Speed up and spread out​

Answers

Answer:

D. Speed up and spread out

Eaterfication experiment

Answers

Answer:

Do you mean Esterification experiment?

Explanation:

How many moles of aspirin (C9H8O4) are contained in 3.13 g of aspirin?

Answers

Answer:

The correct answer is - 0.0173888 moles.

Explanation:

Aspirin,  C 9 H 8 O 4 , the atomic mass rounded to the nearest whole number, so: c- 12 h- 1 o - 16

now multiply these number by how many of each there are in the formula:

c - 12 x 9 = 108

h - 1 x 8 = 8

0 - 16 x 4 = 64

add these numbers up 108 + 8 + 64 = 180

aspirin has a molar mass of  

180.g mol ^− 1 . This means that one mole of aspirin will have a mass of 180 g .

You're dealing with 3.13 g  of aspirin, which will be equivalent to

3.13 g  /180g

=  0.0173888 moles aspirin

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