1
Which is the equation of a line that has a slope 1/2 and passes through point (2, -3)?
Oy-x-4
0y=x-2
Oy-x+2
Oy=x+3

Answers

Answer 1

Answer:

[tex]y = \dfrac{1}{2}x-4[/tex]

Step-by-step explanation:

Equation of line in slope y-intercept form:

       [tex]\sf slope = m =\dfrac{1}{2}\\\\Point (2, -3) ; x_1 = 2 \ \& y_1 = -3\\\\\boxed{\bf y - y_1 =m(x -x_1)}[/tex]

         [tex]\sf y - [-3] = \dfrac{1}{2}(x - 2)\\\\y + 3 = \dfrac{1}{2}x - 2*\dfrac{1}{2}\\\\y + 3 = \dfrac{1}{2}x-1\\\\[/tex]

                [tex]\sf y = \dfrac{1}{2}x - 1 - 3\\\\ y =\dfrac{1}{2}x-4[/tex]


Related Questions

PLEASE HELP I HAVE 45 min to SUBMIT WILL GIVE BRAINLY

Answers

Answer:

Step-by-step explanation:

f (1/2)pi = cos(1/2) pi

the answer to this equation should be 0 but i’m not sure how to do the work could someone help/ explain

Answers

Answer:

Step-by-step explanation:

1/2 pi is an angle ( in radians)

in degrees its 90 degrees.

cos 90 = 0.

Coordinate Geometry Use the graph. Write each
ratio in simplest form.
33. BD
AC
AE
EC
34. A
35. slope of EB
36. slope of ED
8
6
D
O
y
E
6
LO

Answers

33) [tex]AC=6[/tex] and [tex]BD=6[/tex], so [tex]AC/BD=1[/tex]

34) By the distance formula,

[tex]AE=\sqrt{(-2-4)^2 + (8-0)^2 }=10\\[/tex]

Also, EC = 8. So, [tex]AE/EC = 5/4[/tex].

35) [tex]\frac{8-0}{4-2}=4[/tex]

36) [tex]\frac{8-0}{4-8}=-2[/tex]

A medical researcher has two petri dishes containing viruses. Dish B has a population density of 1.2 viruses per square millimeter. Dish A has an area of about 2,826 square millimeters.

If both petri dishes have the same population density, approximately how many viruses are in Dish A?

2,355 viruses
3,391 viruses
23,550 viruses
33,912 viruses

Answers

The population of viruses in the dish A is 3,391 viruses.

What is the population?

Population density measures the amount of organisms in 1 square millimeters of a place (in this case the dish)

Population density = population / area

Population = population density x area

1.2 x 2826 = 3,391 viruses

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Volume=
Please help thankss

Answers

the answer is 64. volume is A^2
4^2=64

Answer:

Volume = 64

Step-by-step explanation:

To find the volume of the cube use the formula.

Formula: l×b×h

l=length

b=base

h=height

Use the information given to solve using the formula.

4×4×4=64

The volume of this cube is 64.

Hope this helps!

If not, I am sorry.

Write the equation of the line that passes through the point (-8,-3) with : slope of -1/4

Answers

Answer:

In slope-intercept form:

[tex]y = - \frac{1}{4} x - 5[/tex]

In standard form:

[tex]x + 4y = - 20[/tex]

Step-by-step explanation:

[tex] - 3 = - \frac{1}{4} ( - 8) + b[/tex]

[tex] - 3 = 2 + b[/tex]

[tex]b = - 5[/tex]

[tex]y = - \frac{1}{4} x - 5[/tex]

[tex] - 4y = x + 20[/tex]

[tex] - x - 4y = 20[/tex]

[tex]x + 4y = - 20[/tex]

Help me please find the value of x then find the measure of each unknown angle

Answers

The value of x is 103.

The value of x is 59.

The value of x is 134.

The value of x is 12

The value of x is 50

The value of x is 135

What is the value of x?

The sum of angles on a straight line add up to 180 degrees.

180 - 77 = 103

180 - 121 = 59

180 - 46 = 134

12 x + 36 = 180

12x = 180 - 36

12x = 144

x = 12

24 + 3x + 6 = 180

3x = 180 - 24 - 6

3x = 150

x - 50

[tex]\frac{x}{3}[/tex] + 99 + 36 = 180

[tex]\frac{x}{3}[/tex] = 180 - 36 - 99

[tex]\frac{x}{3}[/tex] = 45

x = 45 x 3

x = 135

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I’m so confused on how to do this one pls help me out I would appreciate it

Answers

First of all, a pair of angles that are complementary means that they add up to 90 degrees. In this case, angle b + 63 degree = 90 degree (because they are complementary), which mean angle b = 90 - 63 = 27 degree.

Answer: 27°

Step-by-step explanation:

Hello.

Complementary angles add up to 90°

Therefore,

63° + ? = 90°

Now we can subtract!

90° - 63° = 27°

Hope this helps and have a nice day :)

ken needs to order 8 new uniform for the soccer team. Each uniform cost $14 and a pair of shorts. The cost of the shorts, c is unknown. 2 equivalent expressions for the cost of 8 uniforms

Answers

The equivalent expressions for the costs are 8 * (14 + c) and 112 + 8c

How to determine the total cost?

The given parameters are:

Number of uniform = 8

Cost of each = $14

The cost of the uniforms and the shorts is then calculated as:

Cost = Number of uniforms * (Cost of uniform + Cost of short)

This gives

Cost= 8 * (14 + c)

Expand

Cost = 112 + 8c

Hence, the equivalent expressions for the costs are 8 * (14 + c) and 112 + 8c

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In the following exercises, multiply the binomials. Use any method.
255. (a + b)(2a + 3b)

Answers

Answer:

Hence the expression [tex]$$(a+b)(2a+3b)=2a^2+5ab+3b^2$$[/tex]

Step-by-step explanation:

Explanation

The given expression is (a + b)(2a+3 b).We have to multiply the given expression.Multiply the (a + b) by 3b, multiply the (a + b) by 2a then add like terms.

[tex]$$\begin{matrix}{} & {} & {} & {} & a & + & b \\ \times & {} & {} & {} & 2a & + & 3b \\ \end{matrix}$$[/tex]

___________________

[tex]$$\begin{matrix}{} & {} & {} & {} & 3ab & + & 3{{b}^2} \\ {} & {} & 2{{a}^2} & + & 2ab & {} & {} \\ \end{matrix}$$[/tex]

___________________

[tex]$$\begin{matrix}{} & {} & 2{{a}^2} & + & 5ab & + & 3{{b}^2} \\ \end{matrix}$$[/tex]

Name the variable in each algebraic expression
4y+12

Answers

Answer:

y is the variable in that expression.

can you help me I am stuck

Answers

Answer:

False, False, True

Step-by-step explanation:

Matrix addition or subtraction can only be performed on two matrices if they are the same dimensions.  The number of rows for both must match, and the number of columns for both must match.  If either is different, they cannot be combined with addition or subtraction.

So, the first two questions are false because the first number from each pair doesn't match (and neither does the second number from each pair, but we just need one mismatch for it to fail).


The last question is true because both of the first numbers are a 3, and both of the second numbers are a 4.

Jon teaches a fourth grade class at an elementary school where class sizes are always at least 20 students and at most 28. One day Jon decides that he wants to arrange the students in their desks in a rectangular grid with no gaps. Unfortunately for Jon he discovers that doing so could only result in one straight line of desks. How many students does Jon have in his class

Answers

Based on the information provided and the requirements to organize the students, Jon most likely has 23 students.

How many students are needed to organize them in a rectangular grid?

In general, Jon will need a number that is not prime as this type of number will not allow him to complete all the grid.

Which are possible numbers?

20 = A rectangular grid of 5 x 4 seats can be arranged

21= A rectangular grid of 7 x 3 can be arranged

22 = A rectangular grid of 2 x 11 can be arranged

23 = It is impossible to organize 23 seats in a rectangular grid without gaps

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Jon has 23 students in his class.

How to determine the number of students

Number of students = Least 20 and most 28

In this case, we are getting a 1 * x rectangle of desks, which is the only possible arrangement.

'x' is a prime number.

Since his classes can't have less than 20 and more than 28, it means we are  looking out for a prime number between 20 and 28.

Let's sort out a prime number between the numbers, 20 and 28

20: 1,2,4,5,10,20

21: 1,3,7,21

22: 1,2,11,22

23: 1,23

24: 1,2,3,4,6,8,12,24

25: 1,5,25

26: 1,2,13,26

27: 1,3,9,27

28: 1,2,4,7,14,28

From what we have, 23 is a prime number because it is only divisible by one and itself.

Therefore, Jon has 23 students in his class.

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there is a mound of g pounds of gravel in a quarry. throughout the day, 300 pounds of gravel are added to the mound. two orders of 900 pounds are sold and the gravel is removed from the mound. at the end of the day, the mound has 1,300 pounds of gravel. write the equation that describes the situation. then solve for g.

Answers

The required equation is g+300-900-900=1300.

The value of g is 2800 pounds.

What is the solution to the equation?

The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions.

Initially, there is a mound of g pounds of gravel, then 300 pounds are added, and then two orders of 900 pounds are sold. At the end of the day, the mound has 1,300 pounds of gravel.

The equation for the given information is formed as follows:

g+300-900-900=1300

Solve the equation to find the value of g,

g+300-1800=1300

g-1500=1300

g=1300+1500

g=2800

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can you pls helpppp lol there’s the picture igs

Answers

Using the bisection concept, it is found that the measure of angle PQR is of 130º.

What is a bisection?

A bisection divides an angle into two equal angles. In this problem, the angles are given as follows:

(3x + 5)º.(2x + 25)º.

Hence the value of x is given as follows:

3x + 5 = 2x + 25

x = 20º.

Hence the measure of angle PQR is given as follows:

m<PQR = 3x + 5 + 2x + 25 = 5x + 30 = 5 x 20º + 30º = 130º.

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Two circles, each of radius 5 units, are drawn in the coordinate plane with their
centers (0, 0) and (8, 0) respectively. How many points where both coordinates are
integers lie within the intersection of these circles, including its boundary?

Answers

The points where both coordinates are integers lie within the intersection of these circles, including its boundary are 8 points.

To answer the question, we need to find the equation of the circles.

What is the equation of a circle?

The equation of a circle with center (h, k) and radius r is

(x - h)² + (y - k)² = r²

Equation of first circle

Given that the first circle has

center (0, 0) and radius, r = 5,

Its equation is

(x - 0)² + (y - 0)² = 5²

x² + y² = 25  (1)

Equation of second circle

Given that the second circle has

center (8, 0) and radius, r = 5,

Its equation is

(x - 8)² + (y - 0)² = 5²

x² - 16x + 64 + y² = 25  (2)

Point of intersection o the circles

To find the point of intersection of both circles, subtracting (1) from (2), we have

x² - 16x + 64 + y² = 25  (2)

-

x² + y² = 25  (1)

-16x + 64 = 0

-16x = -64

x = -64/-16

x = 4

Substituting x = 4 into (1), we have

x² + y² = 25

4² + y² = 25

16 + y² = 25

y² = 25 - 16

y² = 9

y = ±√9

y = ±3

So, the circles intersect at (4,-3) and (4, 3).

So, all the points that lie within their points of intersection where both coordinates are integers including their points of intersection are

(4, -3), (3, -2), (2, -1), (1, 0), (0, 1), (1, 2), (2, 3) and (3, 4).

So, there are 8 points.

So, all the points where both coordinates are integers lie within the intersection of these circles, including its boundary are 8 points.

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A board game allows players to trade game pieces of equal value. The diagram shows two fair trades. The hotel is worth $2400. How much is a car worth?

Answers

Answer:

Step-by-step explanation:

please help me find the solution

Answers

Step-by-step explanation:

ATTACHED IS THE SOLUTION!!

Find the measure of angle 4.
O 130
O 75
O 4
O 69

Answers

Step-by-step explanation:

the sum of all angles in a triangle is always 180°.

so,

180 = 60 + 45 + angle4 = 105 + angle4

75° = angle4

HURRY ANSWER NOW PLS
Which scenario is modeled by the equation (x) (0.6) = 86 dollars and 46 cents?
A. A picnic table is on sale for 60 percent off. The sale price of the picnic table is x, $144.10.
B. A picnic table is on sale for 40 percent off. The sale price of the picnic table is x, $144.10
C. A picnic table is on sale for 60 percent off. The original price of the picnic table is x, $144.10.
D. A picnic table is on sale for 40 percent off. The original price of the picnic table is x, $144.10

Answers

Using proportions, the scenario modeled by the equation 0.6x = 86.46 is:

D. A picnic table is on sale for 40 percent off. The original price of the picnic table is x, $144.10.

What is a proportion?

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

When a product is 40% off, 100 - 40 = 60% of the original price x is paid, hence the expression for the price is:

0.6x.

In this problem, the expression is:

0.6x = 86.46

x = 86.46/0.6

x = 144.1.

Hence option D is correct.

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Find the GCF of the monomials: 32x^2 and 24x^2y

Answers

Answer:

8x^2

Explanation:

First, do prime factorization of each of the coefficients:

32   ⇒   2^5

24   ⇒   2^3, 3

The greatest common factor (GCF) of the coefficients is 2^3 = 8.

Next, find the GCF of the variables:

x^2

x^2, y

The GCF of the variables is x^2.

Finally, multiply the GCF of the coefficients by the GCF of the variables to get:

8x^2

Answer: 4x^2

Step-by-step explanation: I took the test and got this answer right

M angle DPR=
Help me please thank u:)

Answers

Formula:

[tex]\frac{1}{2}(Big Arc- Small Arc)[/tex]

[tex]\frac{1}{2} (118-26)[/tex]

[tex]\frac{1}{2}(92)\\[/tex]

=46

m∠DPR = 46°

I hope it helps! :)

First person to solve this question with STEP BY STEP explanation will be marked as brainliest

Answers

Answer:

C. 2y²

Step-by-step explanation:

[tex] \sf{( {3}^{0}y) {}^{2} \times 2(xy {)}^{0} = }[/tex]

[tex] \boxed{\sf{X^{0} = 1}} [/tex]

[tex]\sf{ = (\red{1} \times y)^{2} \times (2 \times \red{1}) }[/tex]

[tex]\sf{ = (y)^{2} \times 2 }[/tex]

[tex]\sf{ =2 {y}^{2} }[/tex]

Answer:

[tex]\textsf{C.} \quad 2y^2[/tex]

Step-by-step explanation:

Given:

[tex](3^0y)^2 \times 2(xy)^0[/tex]

[tex]\textsf{Apply exponent rule} \quad a=a^1:[/tex]

[tex](3^0y^1)^2 \times 2(x^1y^1)^0[/tex]

[tex]\textsf{Apply exponent rule} \quad(a^n)^c=a^{nc} \implies (a^nb^n)^c=a^{nc}b^{nc}:[/tex]

[tex]\implies 3^{(0 \times 2)}y^{(1 \times 2)} \times 2 \left(x^{(1 \times 0)}y^{(1 \times 0)} \right)[/tex]

[tex]\implies 3^0y^2 \times 2\left(x^0y^0\right)[/tex]

[tex]\textsf{Apply exponent rule} \quad a^0=1:[/tex]

[tex]\implies (1)y^2 \times 2\left(1 \times 1 \right)[/tex]

Simplify:

[tex]\implies (1)y^2 \times 2(1)[/tex]

[tex]\implies y^2 \times 2[/tex]

[tex]\implies 2y^2[/tex]

How many integers in the set of all integers from 1 to 200, inclusive, are not the cube of an integer

Answers

Cubing of integers from 1 to 5 will have their cubes in the interval 1 to 200. There are such 5 positive numbers (1,2,3,4,5).

To calculate the variety of integers, locate and subtract the integers of the hobby after which subtract 1. As evidence of the concept, calculate the wide variety of integers that fall between five and 10 on more than a few lines. We realize there are four (6, 7, 8, 9).

All entire numbers are integers (and all herbal numbers are integers), however now not all integers are whole numbers or natural numbers. as an example, -five is an integer but not an entire variety or a natural quantity. An integer is an entire variety (not a fractional number) that can be fine, bad, or 0. Examples of integers are: -5, 1, 5, 8, 97, and 3,043. Examples of numbers that are not integers are: -1.forty three, 1 3/four, three.14, . 09, and five,643.1.

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1. Are you given enough information to prove that these two triangles are congruent? If so,
what reason would you give?

Answers

Answer:

Yes, because they are congruent by AAS (angle angle side)

Step-by-step explanation:

One of the congruence theorem is AAS. If you follow the sides of the triangle, you will see that they are marked with an angle, another angle, and a side being congruent. I hope this helps!

Simplify. Rewrite the expression in the form 3^n3 n 3, start superscript, n, end superscript. 3^4\cdot 3^2=3 4 ⋅3 2 =3, start superscript, 4, end superscript, dot, 3, squared, equals

Answers

The expression 3⁴ × 3² when rewritten in the form 3ⁿ is;  (3²)³

How to use law of exponents?

We want to find the expression;

3⁴ × 3²

Now, according to law of exponents, we know that;

y² × y³ = y⁽² ⁺ ³⁾

Thus, applying that exponent form to our question gives us;

3⁴ × 3² = 3⁽⁴ ⁺ ²⁾ = 3⁶

Now, we want to find the answer in the form 3ⁿ. Thus;

3⁶ = (3²)³

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Answer: 3^6 on khan academy

Step-by-step explanation: add the exponents 4 and 2 and you get the exponent 6

Find a39 of the arithmetic sequence given a1 = -28 and d = -4.
-
A. -104
B. -106
C. 8
D. -180
Reset Selection

Answers

Hello !

[tex]a_{n} = a_{1} + (n - 1) \times d[/tex]

[tex]a_{39} = - 28 + (39 - 1) \times ( - 4) = - 28 + 38 \times ( - 4) = - 180[/tex]

The required a39 of the arithmetic sequence is -180.


Given that,
To find a39 of the arithmetic sequence given a1 = -28 and d = - 4.

What is arithmetic progression?

Arithmetic progression is the series of numbers that have common differences between adjacent values.

What is geometric progression?

Geometric progression is a sequence of series whose ratio with adjacent values remains the same.

The nth term of an arithmetic sequence is given as
an = a1 + (n - 1) * d
for term n = 39
a39 = -28 + (39 - 1) * -8
a39 = -28 - 152
a39 = - 180

Thus, the required a39 of the arithmetic sequence is -180.


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Consider the relation given by the graph below.
a) Is the relation a function? Why or why not?
b) Determine the domain and range of the graph.

Answers

The given relation is function, because the curve of y = p(x) has its exist for every x in its domain(-6, 3) and the range of the function is lies between (-1, 9).


What are functions?

Functions is the relationship between sets of values. e g y=f(x), for every value of x there is its exists in set of y. x is independent while Y is dependent variable.

As Clearly the shows in the graph the structure is decreasing, increasing and then decreasing. And implies, curve is continuous in its limits and for every x (-6,3) there is exist in range of y(-1, 9).

Thus, The given relation is function, and domain is (-6, 3) and the range of the function is lies between (-1, 9).

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sin 3x + 2cos^2 (3x) = 1

Answers

Recall the Pythagorean identity,

[tex]\sin^2(x) + \cos^2(x) = 1[/tex]

Then we can rewrite the equation as

[tex]\sin(3x) + 2 \cos^2(3x) = 1[/tex]

[tex]\sin(3x) + 2 (1 - \sin^2(3x)) = 1[/tex]

[tex]1 + \sin(3x) - 2 \sin^2(3x) = 0[/tex]

Factorize the left side.

[tex](1 + 2 \sin(3x)) (1 - \sin(3x)) = 0[/tex]

Then we have

[tex]1 + 2\sin(3x) = 0 \text{ or } 1 - \sin(3x) = 0[/tex]

[tex]\sin(3x) = -\dfrac12 \text{ or } \sin(3x) = 1[/tex]

Solve for [tex]x[/tex]. We get two families of solutions:

[tex]3x = \sin^{-1}\left(-\dfrac12\right) + 2n\pi \text{ or } 3x = \pi - \sin^{-1}\left(-\dfrac12\right) + 2n\pi[/tex]

[tex]\implies 3x = -\dfrac\pi6 + 2n\pi \text{ or } 3x = \dfrac{7\pi}6 + 2n\pi[/tex]

[tex]\implies \boxed{x = -\dfrac\pi{18} + \dfrac{2n\pi}3} \text{ or } \boxed{x = \dfrac{7\pi}{18} + \dfrac{2n\pi}3}[/tex]

and

[tex]3x = \sin^{-1}(1) + 2n\pi[/tex]

[tex]\implies 3x = \dfrac\pi2 + 2n\pi[/tex]

[tex]\implies \boxed{x = \dfrac\pi6 + \dfrac{2n\pi}3}[/tex]

(where [tex]n[/tex] is any integer)

cho Q(x)=x^2+mx-12.Biết Q(-3)=0.tìm nghiệm còn lại

Answers

Answer: m=-1.

Step-by-step explanation:

[tex]Q(x)=x^2+mx-12\ \ \ \ Q(-3)=0\ \ \ \ \ m=?\\Q(-3)=(-3)^2+m*(-3)-12=0\\9-3m-12=0\\-3m-3=0\\3m=-3\ |:3\\m=-1.[/tex]

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