Answer:
40cm³
Explanation:
I only have an answer to 1a
Volume = Length X breadth X height
where;
length = 10cm
breadth = 2cm and;
width = 2cm
*Find*
V = ?
V = L X B X H
V = 10 X 2 X 2
= 40cm³✓
[tex] \huge{ \mathrm{question \hookleftarrow}}[/tex]
Calculate equivalent resistance of two resistors R1 and R2 in parallel where,
[tex] \sf R_ 1 = (6 \pm0.2 )\: \: ohms[/tex]
[tex] \sf R_ 2 = (3 \pm0.1 )\: \: ohms[/tex]
[tex]it \: was \: helpful \: to \: you[/tex]
# be careful#
1) A plane takes off from an O'Hare runway heading due west with a speed of 210.1 m/s. Once in the air, it encounters a north wind (blowing south) with a speed of 55.0 m/s. What is the magnitude of its velocity relative to the ground?
2) What is the direction of the resulting velocity (relative to its initial direction)?
when did humans learn that the earth is not the center of the universe?
Answer:
When did humans learn that the Earth is not the center of the universe?
Answer
1
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4 Answers
Asked in 3 Spaces


Science - Next Generation
Alexander Somm
, Consultant, Investor Relations at Novelpharm AG (2015-present)
Answered Oct 16
What, it isn’t?!
Sorry, I had to.
As far as I have read and understood, the Sumerians and later the Babylonians both had astronomical calendars that already differentiated planets and stars. Earth was not the center to them, the Sun likely was. That was around 2,200 - 1,600 BC.
After that, Greek philosopher Aristarchus of Samos (310 - 230 BC) was the first (recorded) to have believed the solar system was organized around the Sun, rather than the Earth. His heliocentric model was unpopular during Aristarchus’ lifetime, although it would inspire astronomers centuries later, such as Copernicus and Galileo.
Now, there are numerous archeological findings (cave paintings) and studies, that all suggest an understanding of complex astronomy in prehistoric times dating back as far as 40,000 years. This also explains how early, prehistoric migrants may have navigated the seas.
Explanation:
hope it helps
have a good day
El. A horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. How much work is done by the 40 - N force?
E2. A woman does 160 J of work to move a table 4 m across the floor. What is the magnitude of the force that the woman applied to the table if this force is applied in the horizontal direction?
E3. A force of 60 N used to push a chair across a room does 300 J of work. How far does the chair move in this process?
E4. A rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. A frictional force of 120 N opposes this motion.
a. What is the work done by the force applied by the rope?
b. What is the work done by the frictional force?
c. What is the total work done on the crate?
The same formula of work can be applied to all the questions. The answers are:
E1. 100J
E2. 40N
E3. 5m
E4. a.) 360 J b.) 240 J c.) 120 J
El. If a horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. The formula to get the much work that will be done by the 40 - N force will be
Work done = force x distance
Work done = 40 x 2.5
Work done = 100 J
E2. If a woman does 160 J of work to move a table 4 m across the floor. We will use the same formula to calculate the magnitude of the force that the woman applied to the table assuming the force is applied in the horizontal direction.
Work done = force x distance
160 = 4F
F = 160/4
Force F = 40 N
E3. Given that a force of 60 N used to push a chair across a room does 300 J of work. Same formula to get how far the chair move in this process.
Work done = force x distance
300 = 60 x distance
distance = 300/60
Distance = 5 m
Therefore, the chair moved 5m away.
E4. Given that a rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. And a frictional force of 120 N opposes this motion.
a. The work done by the force applied by the rope can be found by
W = F x S
W = 180 x 2
W = 360 J
b. What is the work done by the frictional force?
W = [tex]F_{r}[/tex] x s
W = 120 x 2
W = 240 J
c. What is the total work done on the crate?
W = (F - [tex]F_{r}[/tex]) x distance
Where [tex]F_{r}[/tex] = frictional force
Substitute all the parameters
W = (180 - 120) x 2
W = 60 x 2
W = 120 J
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1. Which of these is not a spherical mirror?
a) Concave mirror
b) Convex mirror
c) Plane mirror
d) None of these
Answer:
C.Plane mirror this is the answer of this question.
None of the above. That is option D.
A spherical mirror is defined as a mirror that has a surface that reflects curved rays. It is also called a curved mirror.
Types of spherical mirror include:
Concave mirror: This has a reflective surface that is curved inward and away from the light source. It reflects light inward to one focal point.Example of concave mirror are Torch lights and automobile headlights.
Convex mirror: These are the spherical mirror that reflects light outwards and towards the light source.Example of convex mirror is the magnifying glasses and telescopes.
Plane mirrors: This is a type of spherical mirror with a flat surface. Reflection of light occurs in plane mirror but it's center of curvature is infinite because it's flat.Therefore, concave, convex and plane mirrors are all examples of a spherical mirror.
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A man pushes a box with a force of 75N across a 12M loading dock. How much work did he do on the box?
Once again, Have a Happy, Merry Christmas!! =)
Answer: 75n,a * (12m)
Explanation I'm trying to understand the question but this is what i got.
Happy Holidays!
We can use the following equation to calculate work done on an object.
W = F · d
Work (J) = Force (N) · displacement (m)
Plug in the given values into the equation:
W = 75 · 12 = 900 J
what is value of 2.37 in sl units
Porque la densidad de un solido es alta?
[tex] \large \sf{hola \: amigo ♡ }[/tex]
Porque, las partículas en los sólidos están muy juntas. Están empaquetados herméticamente, dando a los sólidos altas densidades.
espero que ayude ♡♡
You are pulling a child in a wagon. The rope handle is inclined upward at a 60∘ angle. The tension in the handle is 20 N.
Part A
How much work does the rope do on the wagon if you pull the wagon 200 m at a constant speed?
Answer:
2000 J
Hope you could get an idea from here.
Doubt clarification - use comment section.
S O L U T I O N:
Here we've been provided with the information i.e
Force (F) = 20N Distance (s) = 200m Angle (θ) = 60°Ans we have given to find out what is work done (W) = ?
The standard formula to calculate work done is given by,
[tex]:\implies\sf{w = f \times s \times cos \theta}[/tex]
[tex]:\implies\sf{w = 20 \times 200 \times cos60}[/tex]
[tex]:\implies\sf{w = 20 \times 200 \times \frac{1}{2} }[/tex]
[tex]:\implies\sf{w = 20 \times 100 \times 1}[/tex]
[tex]:\implies\sf{w = 2000J}[/tex]
Total work done done by rope is 2000J.A wave completes one vibration as it moves a distance of 2 meters at a speed of 20 meters per second. What is the frequency of the wave?
I need the Formula,Known,Substitute & Solve Answer with Units
Answer:
I put the answer
Explanation:
Can you see it
10Hz is the frequency of the wave.
How to find the frequency of the wave?
To calculate the frequency of a wave, divide the velocity of the wave by the wavelength. Write your answer in Hertz or Hz
Given,
F = 2
λ=2m
v=20m/s
By applying the formula, we get
V = Fλ
F = V / λ
F = 20 / 2
=10Hz
Wave frequency is the number of waves that pass a fixed point in a given amount of time.
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Annie comes to a sudden stop to avoid hitting a deer crossing the road at night. As she hits the breaks, her speed drops from 12 m/s to zero in 1.5 seconds.(p1) How far did she travel during that time? (p2)What was her average acceleration?
Distance(p1)
9 m
8 m
10 m
13.5 m
Acceleration(p2)
6 m/s2
8 m/s2
12 m/s2
16 m/s2
Answer:
1. around 22m
Explanation:
Annie traveled 9 meters during that time. Her average acceleration was -8 m/s².
Annie's initial speed was 12 m/s.
Her final speed was 0 m/s.
The time it took her to stop was 1.5 seconds.
Therefore, the distance she traveled during that time is:
distance = (initial speed + final speed)/2 * time
= (12 m/s + 0 m/s)/2 * 1.5 seconds
= 9 meters
Annie's average acceleration is calculated by dividing her change in velocity by time it took for that change to occur.
In this case, her change in velocity is from 12 m/s to 0 m/s, which is a decrease of 12 m/s.
The time it took for this change to occur is 1.5 seconds.
Therefore, Annie's average acceleration is:
acceleration = change in velocity / time
= -12 m/s / 1.5 seconds
= -8 m/s²
The negative sign indicates that Annie was slowing down.
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An aircraft flying at a steady velocity of 70 m/s eastwards at a height of 800 m drops a package of supplies.
a) Express the initial velocity of the package as a vector. What
observer on the ground.
b) How long will it take for the package to reach the ground?
c) How fast will it be going as it lands? Express your answer as
a vector.
d) Describe the path of the package as seen by a stationary
assumptions have you made about the frame of reference?
e) Describe the path of the package as seen by someone in the
aeroplane.
The motion of the package can be described as the motion of a projectile,
given that it has an horizontal velocity and it is acted on by gravity.
a) [tex]\vec{v}[/tex] = 70·ib) The package will reach ground in approximately 12.77 seconds.c) The speed of the package as it lands is approximately 145.51 m/s.d) The path of the package based on a stationary frame of reference is parabolice) The path of the package as seen from the plane is directly vertical downwards
Reasons:
Velocity of the aircraft = 70 m/s
Direction of flight of the aircraft = Eastward
Height from which the aircraft drops the package, h = 800 m
a) The initial velocity of the package, [tex]\vec{v}[/tex] = 70·i
b) The time it will take the package to reach the ground, t, is given by the formula;
[tex]\displaystyle h = \mathbf{\frac{1}{2} \cdot g \cdot t^2}[/tex]
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
Therefore;
[tex]\displaystyle t = \mathbf{\sqrt{ \frac{2 \cdot h}{g} }}[/tex]
Which gives;
[tex]\displaystyle t = \sqrt{ \frac{2 \times 800}{9.81} } \approx \mathbf{12.77}[/tex]
The time it will take the package to reach the ground, t ≈ 12.77 seconds
c) The vertical velocity just before the package reaches the ground, [tex]v_y[/tex], is given as follows;
[tex]v_y^2[/tex] = 2·g·h
Therefore;
[tex]v_y[/tex] = √(2·g·h)
Which gives;
[tex]v_y[/tex] = √(2 × 9.81 × 800) ≈ 125.28
[tex]v_y[/tex] ≈ 125.28 m/s
Which gives; [tex]\vec{v}[/tex] = 70·i - 125.28·j
Therefore, |v| = √(70² + (-125.28)²) ≈ 143.51
The speed of the package as it lands, |v| ≈ 143.51 m/s
d) The motion of the package that includes both horizontal and vertical motion is a projectile motion.
Therefore;
The path of the package is the path of a projectile, which is a parabolic shape.
e) As seen by someone on the aeroplane, the horizontal velocity will be
zero, therefore, the package will appear as accelerating directly vertical
downwards.
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A single covalent bond is stronger than a single hydrogen bond so why does a group of polar molecules tend to have a higher boiling point than a group of non polar molecules
Answer:
this question makes no sense
Explanation:
like how do you get this question
Answer:They require more energy to break intermolecular forces hence polar molecules have higher melting points and boiling points than non-polar molecules of similar size, shape and number of electrons.
Explanation:
explain why an astronaut on moon seems to be attracted only to the moon
Answer: the gravitational attraction on the Moon is much less than it is here on Earth, and a person weighs less on the Moon.
Explanation:
Define "one solar day".
Answer:
the interval between transits of the apparent or mean sun across the meridian at any place.
Find B when θ=35, E=10V, t=5, N=250, A=1.20m^2
a. -0.321 T
b. -0.653 T
c. -0.231 T
d. -0.293 T
Answer:
its most definitely c. trust me
Explanation:
A pitcher throws a softball
Answer:
Did you forget the answers
Explanation:
if so leave in comments and i will try to figure out
Answer:
what is the question and the answers??
how to find initial velocity without acceleration
Answer:
actually you can't find it without acceleration.
you need to use one of these three equations
1- Vf = Vi + at
2- 2ad = Vf^2 - Vi^2
3- d = Vit + 1/2 at^2
The mass of a car is 2000 lbs, and is traveling 100 mi/hr on the freeway, what is its momentum?
Answer:
momentum= 145999324.8(kg(m/s))
Explanation:
formula for momentum: p=mv
where p= momentum, m=mass, and v=velocity.
p=2000lbs(100mi/hr)
The standard unit for mass is kg
2000lbs=907.2kg
standard unit for velocity is meters/sec
100mi=160934meters.
907.2kg(160934m/s)=145999324.8
ii. Which of these has a heating element with a low melting point?
a, electric bell
c. electric iron
b. fuse
d. all of these
Draw the following vector: 350 N, 30° south of east [1 cm = 50 N]
The magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.
The given parameters:
Magnitude of the vector = 350 NPosition of the vector = 30⁰ South eastThe vector is represented with arrow pointing out from south-east represented in a Cartesian coordinate.
The length of the arrow represents the magnitude of the vector which is 350 N. The direction of the arrow indicated by the arrow head represents the position of the vector.The position of the vector is 30 degrees South of East.Thus, the magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.
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whats 10x10 PLEASE I NEED THIS
Answer:
100
Explanation:
a swimmer experiences a total (absolute) pressure of 117,500 pa in a pool. how far below the surface are they located?
Answer:
Explanation:
We know that the pressure can be calculated in the following way:
p = d·g·h
with d being the density of the water, g the gravitational acceleration and h the depth.
Also d of the water = 1000 kg/m^3 circa and g = 9.8 m/s^2 circa
117,500 Pa = 1000kg/m³ · 9.8m/s² · h
Therefore h = 11,9 m
why is water soaked cloth used on forehead during fever?please can you tell me answer
This is because the cloth soaked in water can absorb and evaporate the heat from your forehead.
Explanation:This technique is used to cool down your fever, and to help you feel better.
why is creavity important inn constructing scientific methods
1) A creative method can save money when you have limited resources
2) A scientific experiment is always very boring
3) There is only one experiment that can test each hypothesis
4) There is no creativity in the scientific community.
Answer:
The answer is C
Explanation:
Scientists use creativity to determine which smaller questions are likely to yield results, imagine possible answers to their questions, and devise ways to test those answers.
Creativity is the key to make the scientific experiments more efficient and and economic and hence, a creative method can save money when you have limited resources.
What is a scientific method?A scientific method is constituted by a set of stages and instructions to conduct a scientific experiment to attain a possible solution for a problem. Scientific methods have to be reproducible and effective to bring a valid solution for a hypothesis based on an observation.
Creative thinking is always paramount significance because it leads more ways and identifies the pitfalls in the available scientific methods. Creativity improves the way of designing a scientific experiments and to gather informations also.
Therefore, creative method can save money when you have limited resources is a true statement regarding a scientific method.
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The density of gold is 19.3 g/cm3. What is the volume of a 13 g gold nugget? (Density: D = m/v)
Answer:
Formula = D = m/v
Given value of D = 19.3 and m = 13g
19.3 = 13/v
V × 19.3 = 13
v = 13/19.3
v = 0.67
stella is driving down a steep hill. she should keep her car __________ to help _________.
Answer:
Stella is driving down a steep hill. She should keep her car in a lower gear to help slow her vehicle.
Explanation:
Mike drops a rock from the top of a suspension bridge. If the rock falls for 4.88 seconds,
how high is the bridge?
This question involves the concepts of the equations of motion in vertical direction.
The height of the bridge is "116.8 m".
We will use the second equation of motion in vertical direction to find out the height of the bridge.
[tex]h=v_it+\frac{1}{2}gt^2\\\\[/tex]
where,
h = hieght = ?
vi = initial speed = 0 m/s
t = time taken = 4.88 s
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]h=(0\ m/s)(4.88\ s)+\frac{1}{2}(9.81\ m/s^2)(4.88\ s)^2[/tex]
h = 116.8 m
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A 2-column table with 5 rows. The first column has entries empty, time of trial number 1 (seconds), time of trial number 2 (seconds), time of trial number 3 (seconds), average time (seconds). The second column labeled one quarter checkpoint has entries 2. 15, 2. 05, 02. 02, 02. 7. Use the table to answer the questions. What is the fastest time trial for the first quarter checkpoint? seconds What is the slowest time trial for the first quarter checkpoint? seconds What is the range of times measured for this checkpoint? seconds.
The fastest time trial for the first quarter checkpoint is 2.02 s.
The slowest time trial for the first quarter checkpoint is 2.7 s.
The range of the times measured for the checkpoint is 0.68 s.
The given parameters;
Time for quarter checkpoint, = 2.15, 2.05, 2.02, 2.7The fastest time trial for the first quarter checkpoint is the least measured time value.
fastest time trial = least time measured
fastest time trial = 2.02 s
The slowest time trial for the first quarter checkpoint is the highest measured time value.
slowest time trial = 2.7 s
The range of the times measured for the checkpoint is difference between the fastest time and slowest time.
Range = fastest time - slowest time
Range = 2.7 - 2.02
Range = 0.68 s
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Answer:
2.02, 2.15, 0.13
Explanation:
A 2-column table with 5 rows. The first column has entries empty, time of trial number 1 (seconds), time of trial number 2 (seconds), time of trial number 3 (seconds), average time (seconds). The second column labeled one quarter checkpoint has entries 2.15, 2.05, 2.02, 2.07.
Use the table to answer the questions.
What is the fastest time trial for the first quarter checkpoint?
2.02
seconds
What is the slowest time trial for the first quarter checkpoint?
2.15 seconds
What is the range of times measured for this checkpoint?
0.13 seconds
It takes a car 4 seconds to slow down from 22 m/s to 6 m/s , what was its acceleration?
To Find The Acceleration of A Car Slowing Down:
The change in speed is the final speed minus the initial speed. To find acceleration, divide the change in velocity by the length of time during which the velocity changed.