18. Un avión de rescate de animales que vuela hacia el este a 36.0 m/s deja caer una paca de
heno desde una altitud de 60.0 m. Si la paca de heno pesa 175 N, ¿cuál es el momentum
de la paca antes de que golpee el suelo?

Answers

Answer 1

Answer:

Definimos momento como el producto entre la masa y la velocidad

P = m*v

(tener en cuenta que la velocidad es un vector, por lo que el momento también será un vector)

Sabemos que el peso de la paca de heno es 175N, y el peso es masa por aceleración gravitatoria, entonces.

Peso = m*9.8m/s^2 = 175N

m = (175N)/(9.8m/s^2) = 17.9 kg

Ahora debemos calcular la velocidad de la paca justo antes de tocar el suelo.

Sabemos que la velocidad horizontal será la misma que tenía el avión, que es:

Vx = 36m/s

Mientras que para la velocidad vertical, usamos la conservación de la energía:

E = U + K

Apenas se suelta la caja, esta tiene velocidad cero, entonces su energía cinética será cero y la caja solo tendrá energía potencial (Si bien la caja tiene velocidad horizontal en este punto, por la superposición lineal podemos separar el problema en un caso horizontal y en un caso vertical, y en el caso vertical no hay velocidad inicial)

Entonces al principio solo hay energía potencial:

U = m*g*h

donde:

m = masa

g = aceleración gravitatoria

h = altura  

Sabemos que la altura inicial es 60m, entonces la energía potencial es:

U = 175N*60m = 10,500 N

Cuando la paca esta próxima a golpear el suelo, la altura h tiende a cero, por lo que la energía potencial se hace cero, y en este punto solo tendremos energía cinética, entonces:

10,500N = (m/2)*v^2

De acá podemos despejar la velocidad vertical justo antes de golpear el suelo.

√(10,500N*(2/ 17.9 kg)) = 34.25 m/s

La velocidad vertical es 34.25 m/s

Entonces el vector velocidad se podrá escribir como:

V = (36 m/s, -34.25 m/s)

Donde el signo menos en la velocidad vertical es porque la velocidad vertical es hacia abajo.

Reemplazando esto en la ecuación del momento obtenemos:

P = 17.9kg*(36 m/s, -34.25 m/s)  

P = (644.4 N, -613.075 N)


Related Questions

When you blow across the top of a soda bottle, it acts like a closed pipe. If the inside of the bottle is 0.150 long, what is the fifth harmonic frequency

Answers

Answer:

The fifth harmonic frequency is 2.9 KHz.

Explanation:

For a closed tube, the fifth harmonic frequency is also the second overtone. So that;

fifth harmonic frequency = [tex]\frac{5V}{4L}[/tex]

where V is the velocity of the sound in air, and L is the length of the tube.

But L = 0.15 m and V = 343 m/s, then:

fifth harmonic frequency = [tex]\frac{5*343}{4*0.15}[/tex]

                                     = [tex]\frac{1715}{0.6}[/tex]

                                     = 2858.33 Hertz

fifth harmonic frequency = 2.9 KHz

The fifth harmonic frequency of the soda bottle is approximately 2.9 KHz.

Answer:

2828.33

Explanation:

answer for acellus

Which best describes a tsunami?

Answers

Answer:

A tsunami is a series of waves in a water body caused by the displacement of a large volume of water, generally in an ocean or a large lake. Earthquakes, volcanic eruptions and other underwater explosions above or below water all have the potential to generate a tsunami. Unlike normal ocean waves, which are generated by wind, or tides, which are generated by the gravitational pull of the Moon and the Sun, a tsunami is generated by the displacement of water.

Answer:

A tsunami is series of waves caused by heavy winds. Hurricanes can cause tsunami

Explanation:

Students have 4 different pairs of sunglasses, each with lenses where the polarization filter is oriented in different directions (indicated by the direction of lines drawn on the lenses below). They are planning to ride rafts down a river on a sunny day where there is lots of glare on the water. Which pair would they want to wear to eliminate the glare from the sun

Answers

Answer:

the lens you must select has an angle of 143º measured with respect to the horizontal, this angle is 53º with respect to the vertical.

Explanation:

The glare is caused by the reflection of light in the water, the polarization of the reflected light is polarized in a direction parallel to the surface of the water, the polarization is total for the angles

         n = tan  [tex]\theta_{p}[/tex]

         \theta_{p} = tan⁻¹ n

the refractive index for seawater is 1.33

         \theta_{p}= tan⁻¹  1.33

         \theta_{p} = 53º

for this angle the light is totally polarized, for the other angles the polarization is partial.

Based on this, the lenses must eliminate this polarization, so its polarization direction must have 90º with respect to this polarization,

          \theta_{lens} = 53 +90

           \theta_{lens}= 143º

Therefore, the lens you must select has an angle of 143º measured with respect to the horizontal, this angle is 53º with respect to the vertical.

A lens that could work is one that is polarized 45º with respect to the vertical.

The glass that is worn to eliminate glare must be able to remove glare away from the user.

What are sunglasses?

The term sunglasses refers to the kind of glasses that are worn to prevent glare from the sun. This is because the glasses are made of polaroid materials that eliminate glare.

The question is incomplete as the sunglasses are not shown. However, the glass that is worn to eliminate glare must be able to remove glare away from the user.

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#SPJ5

[tex] \sf{ What \: is \: a \: parallel \: circuit? }[/tex]
[tex] \\ \\ \\ \\ \\ [/tex]

Answers

Answer:

parallel circuit is a kind of circuits in which all components are connected between the same two sets of electrically common points, creating multiple paths for the current to flow from one end of the battery to the other:

Answer:

Gadhe hote hai log and usme sabse pehele aati hai Jonain jaise log waah waah xD

Brainliest krdena warna chappal padenge -,-

a girl stands on a boat and feels the boat rise and fall 7 times In 1 minute. what is the period of the water wave? give your answer to 3 significant figures​

Answers

Explanation:

hope it's helpful

have a nice day!!!! ;)

What are the functionsssss of geostationary satellite and non-geostationary satellite?​

Answers

Answer:

What is the difference between a geostationary satellite and a non-geostationary satellite? Geostationary (GSO) satellites occupy an orbital position 36,000 km above the earth, and remain in a stationary position relative to the Earth itself.

A uniform solid ball has a mass of 20 g and a radius of 5 cm. It rests on a horizontal surface. A sharp force is applied to the ball in the horizontal direction 9 cm above the surface. The force rises linearly from 0 to a peak value of 40,000 N in 10^(-4) s then decreases linearly to 0 in another 10^(-4) s. (The moment of inertia for a solid ball is 2/5 mR^2 ) What is the velocity of the ball after the impact

Answers

Answer:

i think the answer is 32 something

Explanation:

what types of cuts do jig saw sanders make?​

Answers

The jigsaw can be used to make both straight and curved cuts in a wide variety of materials, including wood, particleboard, plywood, plastic, metal, even ceramic tile. There is also way more than those, but those are just the basics or common things. Hope this helps!

The Chernobyl reactor accident in what is now Ukraine was the worst nuclear disaster of all time. Fission products from the reactor core spread over a wide area. The primary radiation exposure to people in western Europe was due to the short-lived (half-life 8.0 days) isotope 131I
131 I, which fell across the landscape and was ingested by grazing cows that concentrated the isotope in their milk. Farmers couldn't sell the contaminated milk, so many opted to use the milk to make cheese, aging it until the radiactivity decayed to acceptable levels. How much time must elapse for the activity of a block of cheese containing 131I 131 I to drop to 1.0% of its initial value?

Answers

Answer:

The correct answer is "53.15 days".

Explanation:

Given that:

Half life of [tex]131_{I}[/tex],

[tex]T_{\frac{1}{2} }= 8 \ days[/tex]

Let the initial activity be "[tex]R_o[/tex]".and, activity to time t be "R".

To find t when R will be "1%" of [tex]R_o[/tex], then

⇒ [tex]R=\frac{1}{100}R_o[/tex]

As we know,

⇒ [tex]R=R_o e^{-\lambda t}[/tex]

or,

∴ [tex]e^{\lambda t}=\frac{R_o}{R}[/tex]

By putting the values, we get

        [tex]=\frac{R_o}{\frac{R}{100} }[/tex]

        [tex]=100[/tex]

We know that,

Decay constant, [tex]\lambda = \frac{ln2}{T_{\frac{1}{2} }}[/tex]

hence,

⇒ [tex]\lambda t=ln100[/tex]

     [tex]t=\frac{ln100}{\lambda}[/tex]

        [tex]=\frac{ln100}{\frac{ln2}{8} }[/tex]

        [tex]=53.15 \ days[/tex]  

Sources A and B emit long-range radio waves of wavelength 360 m, with the phase of the emission from A ahead of that from source B by 90°. The distance rA from A to a detector is greater than the corresponding distance rB from B by 130 m. What is the magnitude of the phase difference at the detector?

Answers

Answer:

[tex]X=165 \textdegree[/tex]

Explanation:

From the question we are told that:

Wavelength [tex]\lambda =360m[/tex]

Angle [tex]\theta=90 \textdegree[/tex]

Distance variation [tex]d=130m[/tex]

Generally the equation for phase difference X is mathematically given by

 [tex]X=\theta+\frac{d}{\lambda}*100[/tex]

 [tex]X=90+\frac{150}{360}*100[/tex]

 [tex]X=165 \textdegree[/tex]

Therefore Phase difference X is given as

 [tex]X=165 \textdegree[/tex]

Calculate the electric field intensity
at a Point 15cm from a charge of 10 uc​

Answers

Answer:

it's very easy and simple answer u can't do it

The electric field intensity at a point of 15cm from a charge of 10 μc will be 3.9 ×10⁶ N/C.

What is the intensity of the electric field?

The electric field is defined as the area over an electric charge where its impact may be felt. The force experienced by a unit positive charge deposited at a given position is known as the electric field intensity.

The formula for the electric field intensity is given as;

[tex]\rm E= \frac{q}{4 \pi \epsilon d^2 } \\\\ \rm E= \frac{10 \times 10^{-6}}{4 \times 3.14 \times 8.85 \times 10^{-12}(15 \times 10^{-2}^2 } \\\\ E=3.9 \times 10^6 \ NC^{-1}[/tex]

Hence the electric field intensity at a point of 15cm from a charge of 10 μc will be 3.9 ×10⁶ N/C.

To learn more about the intensity of the electric field refer to the link;

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URGENT: Testing shows that a sample of wood from an artifact contains 50% of the
original amount of carbon-14. Given that the half-life of carbon-14 is 5730
years, how old is the artifact?
O A. 22,920 years
B. 11,460 years
C. 5730 years
O D. 2865 years

Answers

Answer:

Im so so sorry but I do now know how to do this

Explanation:

Please help me ASAP!!

Answers

Answer:

the ball lose kentic energy and gains potential energy rolling upward

Answer:

c

Explanation:

when a ball is rolling down it loses potential and gains kinetic, but in this case since the ball is going upwards it is losing kinetic energy and gaining potentail like a roller coaser

How were the barriers to critical thinking presented?

Answers

Answer:

At a personal level, barriers to critical thinking can arise through: ... self-centred or societal/cultural-centred thinking (conformism, dogma and peer-pressure) unconscious bias, or selective perception. an inability to be receptive to an idea or point of view that differs from your own (close-mindedness)

Explanation:

Which of the following creates the night-and-day cycle experienced on Earth?
A) Orbit of Earth around the Sun
B) Rotation of the Sun
C) Rotation of the Earth
D) Tilt of the axis of Earth

Answers

the answer should be C

What’s the answer to 19 please please help me

Answers

Answer:

A.

Explanation:

A po sa tingin ko

sana po makatulong

Answer A it transmits red and absorbs all the other colors

What was the name of the voyages taken by Zheng he during the Ming dynasty on behalf of China

Answers

Answer:

Ming treasure voyages

Explanation:

The Moon is attracted to the Earth. The mass of the Earth is 6.0x1024 kg and the mass of the Moon is 7.4x1022 kg. If the Earth and Moon are 345,000 km apart, what is the gravitational force between them?

Answers

Sorry I don't know the answer

why do trucks need a runaway ramp

Answers

Answer:

in case they lose control going downhill.

Explanation:

which is why they usually have a steep incline and are quite long. You see them used typically when the trucks brakes fail.

what type of signal is utilized by the GP's satellite ?

Answers

Answer:

Hi how are you doing today Jasmine

Answer:

The answer is B

Explanation:

I did the USA test prep


Which of the following is most consistent with the modern theory of evolution?
O Parents pass their physical traits to their offspring; those offspring with traits that help the
O Parents change their physical traits in order to survive in the environment, then those pa
O Life on this planet came from another planet far out in space.
O Living organisms have not changed for hundreds of millions of years.

Answers

Answer:

The theory of evolution by natural selection, first formulated in Darwin's book "On the Origin of Species" in 1859, is the process by which organisms change over time as a result of changes in heritable physical or behavioral traits

A 16.2-g bullet with an initial speed of 850 m/s embeds itself in a 40.0-kg block, which is attached to a horizontal spring with a force constant of 1000 N/m. What is the maximum compression of the spring

Answers

The maximum compression in the spring is 0.06883 meters.

Given to us,

mass of bullet, [tex]m= 16.2\ grams[/tex]

velocity of bullet, [tex]v= 850\ meter/second[/tex]

mass of the block, [tex]m_2= 40\ kilograms[/tex]

velocity of block, [tex]v_2= 0\ meter/second[/tex]

spring constant, [tex]k = 1000\ Newton/meter[/tex]

Combined mass after collision,

[tex]\begin{aligned}M&= m_1+m_2\\&= 40.0162\ Kilograms\end{aligned}[/tex]

Using the momentum conservation equation, to find out final velocity of the system(bullet and block combined)

[tex]m_1v_1+m_2v_2= MV\\[/tex]

[tex]0.0162\times 850+40\times 0 = 40.0162\times V\\V= 0.3441 meter/sec[/tex]

Now using the Conservation of Energy (Kinetic energy of the system will be equal to potential energy in the spring), to find out the displacement of the spring [tex](x)[/tex]

[tex]\frac{1}{2}kx^2 = \frac{1}{2}MV^2\\\\\frac{1}{2}\times 1000\times x^2= \frac{1}{2} \times40.0162\times0.3441^2\\\\x^2= 0.004738\\\\x= 0.06883\ meters[/tex]

Hence, the maximum compression in the spring is 0.06883 meters.

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help ASAP 100 POINTS

Question 1 (1 point)
According to theory, which term best describes the universe before the big bang?

Question 1 options:

a star


a cloud of gas and dust


a small densely packed ball of matter


a planet

Question 2 (1 point)
Which example is used as evidence that the universe began with the big bang?

Question 2 options:

leftover energy in the form of background radiation in the universe from the event


the force of gravity


craters on the moon


the existence of atoms

Question 3 (1 point)
How do scientists use the Doppler effect to understand the universe?

Question 3 options:

to determine motion of objects


to determine light brightness


to determine planet compositition


to determine the ages of planets

Question 4 (1 point)
The Doppler effect indicates that the universe is expanding because_________.

Which phrase best completes the sentence.

Question 4 options:

light from other galaxies is the same color


light from other galaxies is the different color


light from other galaxies is blue shifted


light from other galaxies is red shifted

Question 5 (1 point)
What does a blue shift in light from stars indicate?

Question 5 options:

The stars are moving randomly.


The stars are moving closer.


The stars are moving farther away.


The stars are stationary.

Answers

Answer:

Explanation:

Question 1 (1 point)

According to theory, which term best describes the universe before the big bang?

a small densely packed ball of matter

Question 2 (1 point)

Which example is used as evidence that the universe began with the big bang?

Question 2 options:

leftover energy in the form of background radiation in the universe from the event

Question 3 (1 point)

How do scientists use the Doppler effect to understand the universe?

to determine motion of objects

 

Question 4 (1 point)

The Doppler effect indicates that the universe is expanding because_________.

Which phrase best completes the sentence.

light from other galaxies is red shifted

Question 5 (1 point)

What does a blue shift in light from stars indicate?

The stars are moving closer.

map.
Which best describes the motion of the object
between 1 and 4 seconds?
کے م
The object has decreasing acceleration and
increasing velocity.
The object has positive acceleration and eventually
stops.
The object has decreasing acceleration and
decreasing velocity.
The object has negative acceleration and eventually
stops.

Answers

Answer:

The object has decreasing acceleration and decreasing velocity.

A , D
B , C
C , B
B , D

Answers

Answer:

c and b

Explanation:

hope this helped!

A nylon rope that has a 0.73 cm radius and is 12 meters long is used to lift a 24 kg object straight up. If the object is lifted at constant velocity, how much is the rope stretched by? The Young's modulus of the nylon is 5.0 × 109 N/m2 and use 9.81 m/s2 for the acceleration of free fall. Express your answer in centimeters and round to the nearest hundredth.

Answers

Answer:

The rope is stretched by 0.3373 cm

Explanation:

As we know  

Youngs Modulus ([tex]5.0 * 10^9[/tex] N/m2) is Stress divided by strain

Stress = force/Area = (65*9.8)/(pi * (7.3*10^-3)^2)

Starin = change in length/original length of the rope = l/12 meters

Substituting the given values we get  

[tex]5.0 * 10^9[/tex] N/m2 = {([tex]\frac{\frac{24*9.8}{\pi *(7.3*10^{-3})^2} }{\frac{\delta L}{L} }[/tex])

[tex]5.0 * 10^9[/tex] N/m2 = {([tex]\frac{\frac{24*9.8}{\pi *(7.3*10^{-3})^2} }{\frac{\delta L}{12} }[/tex])

[tex]\frac{\delta L}{12} = \frac{\frac{65*9.8}{pi * (7.3*10^-3)^2} }{5.0 * 10^9}[/tex]

The rope is stretched by 0.3373 cm

Which of the following best explains the greater difficulty in stopping a 1000-kg car
moving at 174 km/h compared to an identical 1000-kg car moving at 100 km/h?

Answers

Stopping a 1000 kg car moving at a speed of 174 km/h will be more difficult than stopping an identical car moving at 100 km/h.

This can be explained by using Newton's second law of motion which says that the rate of change of momentum of a body is equal to the force applied.

We know that momentum of a body is the product of its mass and velocity.The momentum of the car moving at 174 km/h = [tex]1000\, kg \times 174\, km/h = 174000 \, kg.km/h[/tex].The momentum of the car moving at 100 km/h = [tex]1000\, kg \times 100\, km/h=100000 kg.km/h[/tex].

Therefore, the car moving at 174 km/h has higher momentum and from Newton's second law of motion, a higher force would be required to stop this car.

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the path of the earth around the sun is called​

Answers

Answer:

Orbit.

Explanation:

An orbit is a regular, repeating path that one object in space takes around another one, it's an imaginary path of the Earth around the Sun.

sino ang legendary hacker ng pilipinas?​

Answers

Answer:

Onel de guzman now he's 44,the first world's computer virus has admitted to his guilt.

(●’◡’●)ノ (ᗒᗣᗕ)՞ ༼ つ ◕◡◕ ༽つ

A grindstone in the shape of a solid disk has a shaft attached to allow a force to be exerted on. The grindstone has a diameter of 0.650m and a mass of 55.0 kg. The shaft is 0.300 m from the center of the stone and has a mass of 4.00 kg. The grindstone has a motor attached and it is rotating at 450rev/min at a run when the motor is shut off. The grindstone comes to rest in 9.50 s.
a. What is the moment of inertia of the grindstone including the shaft?
b. What is the angular acceleration of the grindstone?
c. What average torque is done by friction to bring the grindstone to rest?
d. How many revolutions has it taken the grindstone to come to rest?
e. What is the linear acceleration of the shaft in this process?
f. What is the linear distance that the shaft traveled?

Answers

Answer:

a)  3.265 kg-m^2

b)  - 4.96  rad/s^2

c) 16.1944 N-m

d) 35.625

e)  - 1.488 m/s^2

f)  67.1175 m.

Explanation:

Given data:

Diameter of grindstone ( D ) = 0.650 m ,  Radius ( R ) = 0.325 m

mass of grindstone ( M ) = 55 kg

Radius of shaft ( r ) = 0.300 m

mass of shaft ( m ) = 4 kg

Initial Angular velocity = 450 rev/min = f = 7.5 rev/s = w  =15π rad/s

time ( t ) = 9.50 secs

a) Determine the moment of inertia of the grindstone including the shaft

moment of inertia of grindstone = MR^2 / 2 = 55* (0.325)^2 / 2 = 2.905

moment of inertia of shaft = mr^2 = 4 *0.3^2 = 0.36

∴ moment of inertia including shaft = 2.905 + 0.36 = 3.265 kg-m^2

b) Determine the angular acceleration of the grindstone

∝ = - 15π / 9.5 ( i.e.  angular velocity / time )

   = - 4.96  rad/s^2 ( deceleration value )

c) Determine average torque done by friction to bring the grindstone to rest

Torque ( I * ∝ )  = 3.265 x 4.96 = 16.1944 N-m (magnitude)

d) Determine the number of revolutions before grindstone comes to rest

Total revolutions N before grindstone comes to rest

= ( f1 + f2)* t /2 = 7.5 * 9.5 / 2 = 35.625

Note : f2 = 0 as it comes to rest

          f1 = 7.5 rev/s

e) Determine the Linear acceleration of the shaft in this process

This can be calculated using this relation

r * ∝ = 0.3 x (- 4.96 ) = - 1.488 m/s^2

f) Determine the linear distance travelled by the shaft

This can be calculated with the relation below

r * 2 * π * N = 0.3 * 2π * 35.625 = 67.1175 m.

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