The expression is assumed here as it's unclear looking
If it's P=(P_o)ln0.015t then the below solution of Part B is correct else they may vary.
#a
0.015 represents rate of change with respect to t.#b
As per our assumed equation
It's.
8000=(P_o)ln0.015^tSimplify
tln0.015=8000/P_oInitial amount of account is not given so you have to solve the above equation after putting known P_o
#3
ln16ln4²2ln42(1.38)2.76(Approx)Hence it's less than 3 and greater than 2
An internet cafe charges $3.75 to use a computer and $.45 per minute while accesing the internet. What function rule describes this situation?
Answer:
y = $3.75(x) + .45$
Step-by-step explanation:
Take the input and subsitute
a teacher gets a bag of lollipops for her class. She buys a large bag of 84 lollipop. If she wants each child to have 3 lollipops how many students must be in her class?
nth term for 300,250,200
The nth term of the arithmetic sequence 300,250,200 is 350-50n if the common ratio is -50
What is a sequence?It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.
We have an arithmetic sequence:
300,250,200
The first term a = 300
Common difference d = 250-300 = -50
nth term:
A(n) = a + (n-1)d
A(n) = 300 + (n-1)(-50)
A(n) = 300 -50n + 50
A(n) = 350—50n
Thus, the nth term of the arithmetic sequence 300,250,200 is 350-50n if the common ratio is -50
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12(5-5)+3x5 evaluate the expression
Answer:
Using PEMDAS we can see that P or parenthesis is first so we would subtract 5 from 5 in the beginning. That would result in a 0 which would then get multiplied with 12 to still have 0.
[tex]12(5-5) + 3 * 5[/tex]
[tex]12(0) + 3 * 5[/tex]
[tex]0 + 3 *5[/tex]
Now that we completed that part, the only thing that we have left to do is to multiply the last two numbers, 3 and 5.
[tex]3*5[/tex]
[tex]15[/tex]
Therefore, our final solution is 15.
Hope this helps!
pls help
tomorrow exam that's why
Answer:
Step-by-step explanation:
a) Four points
A, T , B , U
b) A ray has a fixed starting point but no end point. It extends infinitely in one direction
PA ; PB ; QT ; QU
c) A line segment is a part of a line that is bounded by two distinct end points.
PQ , PR
d) Parallel lines are two lines in the same plane that are at equal distance from each other and they never intersect.
AP // TQ and PB // QU
e) Two or more lines which share exactly one common point are called intersecting lines.
AB & PQ
f) ∠QPB and ∠BPR
2.38 Baggage fees: An airline charges the following baggage fees: $25 for the first bag and $30 for the second. Suppose 54% of passengers have no checked luggage, 30% have only one piece of checked luggage and 16% have two pieces. We suppose a negligible portion of people check more than two bags.
The average baggage-related revenue per passenger is $16.30 per passenger.
Expected valueExpected value formula: x×p(x)
First step
No passenger=0×.54
No passenger=0
Second step
One checked luggage for first bag=.30×$25
One checked luggage for first bag=$7.50
Third step
Two piece for the first and second bag=.16×($25+$30)
Two piece for the first and second bag=.16×$55
Two piece for the first and second bag=$8.80
Last step
Expected value=$7.50+$8.80
Expected value=$16.30
Therefore the average baggage-related revenue per passenger is $16.30 per passenger.
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Cos (pi/5) + cos (2pi/5)+ Cos (3pi/5)
+ Cos (4pi/5)
Answer:
0
Keys:
When going over functions like this, we must use these cosine rules:
[tex]\cos \left(s\right)+\cos \left(t\right)=2\cos \left(\frac{s+t}{2}\right)\cos \left(\frac{s-t}{2}\right)[/tex][tex]\cos \left(-x\right)=\cos \left(x\right)[/tex][tex]\cos \left(\frac{\pi }{2}\right)=0[/tex]Step-by-step explanation:
[tex]=\cos \left(\frac{\pi }{5}\right)+2\cos \left(\frac{2\cdot \frac{\pi }{5}+3\cdot \frac{\pi }{5}}{2}\right)\cos \left(\frac{2\cdot \frac{\pi }{5}-3\cdot \frac{\pi }{5}}{2}\right)+\cos \left(4\cdot \frac{\pi }{5}\right)\\=\cos \left(\frac{\pi }{5}\right)+2\cos \left(\frac{\pi }{2}\right)\cos \left(-\frac{\pi }{10}\right)+\cos \left(\frac{4\pi }{5}\right)\\=\cos \left(\frac{\pi }{5}\right)+2\cos \left(\frac{\pi }{2}\right)\cos \left(\frac{\pi }{10}\right)+\cos \left(\frac{4\pi }{5}\right)[/tex]
[tex]cos\left(\frac{\pi }{5}\right) = \frac{\sqrt{5} + 1}{4}\\=\frac{\sqrt{5}+1}{4}+2\cdot \:0\cdot \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}-\frac{1+\sqrt{5}}{4}\\=0[/tex]
Providing for doubtful accounts
At the end of the current year, the accounts receivable account has a debit balance of $844,000 and sales for the year total $9,560,000.
a. The allowance account before adjustment has a debit balance of $11,400. Bad debt expense is estimated at 1/4 of 1% of sales.
b. The allowance account before adjustment has a debit balance of $11,400. An aging of the accounts in the customer ledger indicates estimated doubtful accounts of
$36,500.
c. The allowance account before adjustment has a credit balance of $4,700. Bad debt expense is estimated at 1/2 of 1% of sales.
d. The allowance account before adjustment has a credit balance of $4,700. An aging of the accounts in the customer ledger indicates estimated doubtful accounts of
$39,000.
Determine the amount of the adjusting entry to provide for doubtful accounts under each of the assumptions (a through d) listed above.
Based on the account receivable balance and the adjustments, the adjusting entries for doubtful debt under various assumptions is:
a. $23,900b. $47,900c. $47, 800d. $34,300What are the entries for doubtful debt?a. Bad debt is 1/4 of 1% of sales:
= 9,560,000 x 0.25%
= $23,900
b. Debit balance of $11,400:
= Estimated doubtful accounts + Debit balance
= 36,500 + 11,400
= $47,900
c. Credit balance of $4,700 and 1/2 of 1% of sales:
= Sales x 0.50%
= 9,560,000 x 0.50%
= $47,800
d. Credit balance of $4,700 and estimated doubtful of $39,000:
= Estimated doubtful accounts - credit balance
= 39,000 - 4,700
= $34,300
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Circle O has a radius of 5 centimeters and central angleAOB with a measure of 60°.
The arc length can be found using the formula, ∅ × r, which is: (5π)/3.
What is the Arc Length?Arc length = ∅ × r, where ∅ is the central angle in radians, and r is the radius of the circle.
Given the following:
∅ = 60° = 60° × π/180 (in radians)r = 5 cmLength of the arc = 60° × π/180 × 5 = (60 × π × 5)/180
Length of the arc = (300π)/180 = (5π)/3
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what’s 826,125 to the nearest ten thousand ?
Answer:
830000.
Step-by-step explanation:
Given number is 825125
The number at the thousands place is 5 which is equal or above 5. So, round up the value.
rounded value of 825125 is 830000.
Therefore, 825125 rounded to the nearest Ten Thousands is 830000.
Answer:
830,000
Step-by-step explanation:
bbbvxxbbbdhdhdvdvshdbsbskzi99999999
If g(x) =2x^2-4 and g(x)=10 find .g(-8)
Functions are written in terms of variables. The value of the function when x is -8 is 124
Functions and valuesFunctions are written in terms of variables. Given the function below;
g(x) = 2x^2 - 4
If the value of x is -8, substiute
g(-8) = 2(-8)^2 -4
g(-8) = 2(64) - 4
g(-8) = 124
Hence the value of the function when x is -8 is 124
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13 × (11 + 11) - (4 × 17) - 6 = X
Answer: 212
Step-by-step explanation:
13 * 22 - 68 - 6 = X
286 - 68 - 6 = X
286 - 74 = X
X = 212
HELP PLEASE - 50 POINTS - The ceiling of Stacy's living room is a square that is 30 ft long on each side. Stacy knows the diagonal of the ceiling from corner to corner must be longer than 30 ft, but she doesn't know how long it is. Solve for the length of the diagonal of Stacy's ceiling in two ways: (a) Using the Pythagorean Theorem.
Answer:
The length of the diagonal of Stacy’s ceiling is 30√2 or 42.43
Step-by-step explanation:
a² + b² = c²
30² + 30² = c²
900 + 900 = c²
√1,800 = √c²
30√2 = c
1. Total spending in the US on lotteries in 2017 was about $75 billion. Given a US Population of 325
million of which 23% are under age 18, and the fact that about half of American adults play the
lottery in any given year, about how much does the average American spend on lotteries each
year?
Based on the statistics, an average American spends $299.7 on lotteries each year
How to determine the amount an American spend on lotteries?The population is given as:
Population = 325 million
23% are under the age of 18.
This means that this category is not eligible to play lotteries.
The eligible population is:
Eligible = (1 - 23%) * 325 million
Evaluate
Eligible = 250.25 million
The total amount is given as:
Total = $75 billion
So, the amount spent by each is:
Amount = Total/Eligible
This gives
Amount = $75 billion/250.25 million
Evaluate
Amount = $299.7
Hence, an average American spends $299.7 on lotteries each year
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A chemist is using 354 milliliters of a solution of acid and water. If 19.8% of the solution is acid, how many milliliters of
acid are there? Round your answer to the nearest tenth.
milliliters
In the given figure, ΔABC is a right triangle.
What is true about ΔABC?
(file is attached below!)
Answer:
its an isosceles triangle which means that the sides a and c are the same
so C is the correct answer!!
Step-by-step explanation:
Need help with this question p
Answer:
4x² + 12x + 9
Step-by-step explanation:
Using identity:(a +b)² = a² + 2ab + b²
Here, a = 2x & b = 3
(2x +3 )² = (2x)² + 2*2x*3 + 3²
= (2x*2x) + 12x + 3*3
= 4x² + 12x + 9
Solve the equation. 2ª = 0.36 O + or - 0.5 O+ or - + or - 0.6 + or -0.7 06 please answer quickly
Answer:
2nd answer is correct.
Step-by-step explanation:
z² = 0.36
z² = [tex]\frac{36}{100}[/tex]
z² = [tex]\frac{6 * 6}{ 10 *10}[/tex]
z = ± √ ( [tex]\frac{6 * 6}{ 10 *10}[/tex] )
z = ± [tex]\frac{6}{10}[/tex]
z = ± 0.6
Therefore,
z = + or - 0.6
Question 9 of 40
Factor this polynomial completely.
6x² + 7x-20
O A. (3x-4)(2x + 5)
OB. (6x- 5)(x+4)
O C. (2x-4)(3x + 5)
OD. (6x-4)(x+5)
Answer:
6x² + 7x-20
A. (3x-4)(2x + 5)
please please help! i need to submit in 15 minutes!!!
Answer:
Step-by-step explanation:
I need the question to answer please :)
Among black respondents to the 2008 GSS, 167 had no small children at home, and 44 did have small children at home. Among those black respondents who had no small children at home, 62 of them had been to a zoo in the past year. Among those black respondents who did have small children at home, 23 of them had been to a zoo in the past year. Build a crosstab with these results, percentage it, run a chi-square test, and explain your results.
Answer:
Step-by-step explanation:
Write the equation of the line in slope-intercept form.
The equation of the line in slope-intercept form is ___
Answer:
y = - 10x + 40
Step-by-step explanation:
Two points
[tex](0,40), (4, 0)[/tex]
Slope
[tex]m=\frac{0-40}{4-0} =-\frac{40}{4} =-10[/tex]
Equation:
[tex]y-40=-10(x-0)[/tex]
[tex]y-40=-10x[/tex]
[tex]y=-10x+40[/tex]
Hope this helps
QUESTION 1 - 1 POINT
Graph the linear inequality -15x - 6y < 30.
Select the correct answer below:
Answer + Step-by-step explanation:
the inequality by finding the boundary line, then shading the appropriate area.
y > − 5/2x − 5
(anything in shaded region)
Which of the following linear functions have a y-intercept of 4? Select all that apply.
y = 4
x=4
Ug=2z 8
y=x+4
y=-2 +4
Answer:
y=4
y=x+4
y=-2+4
Step-by-step explanation:
the trick is to consider x as 0.
A store manager wants to estimate the proportion of customers who spend money in this store. How many customers are required for a random sample to obtain a margin of error of at most 0.075 with 80% confidence?
The 73 customers who spend money in this store if a MOE of at most 0.075 with 80% confidence.
What is the margin of error(MOE)?MOE is an error that provides an estimate of the percentage of errors in real statistical data.
The formula for finding the MOE:
MOE = z x s/√n
Where ,
Z = the z-score at the confidence interval
s = the standard deviation
n = the number of samples.
We have p = 0.50 MOE = 0.075
Z = 1.282 at 80% confidence
0.075 = 1.282 x √0.50(1- 0.50)/ n
After solving,
n = (0.5)(0.5)/(0.0585)²
n = 73
Thus, the 73 customers who spend money in this store if a MOE of at most 0.075 with 80% confidence.
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The hull speed of a boat is approximated by the function
v = 1.34 StartRoot l EndRoot ,
where l is the hull length in feet and v is the hull speed in knots.
Suppose the Santa Monica has a hull length that is 10 ft shorter than that of the Nina Pinta. What expression represents the hull speed of the Santa Monica in terms of the length, ln of the Nina Pinta?
v Subscript s Baseline = a StartRoot b EndRoot
Where a =
and b = ln
What are the restrictions on ln?
ln >
The hull speed of the Santa Monica in terms of the length, ln of the Nina Pinta is given as a√b where a = 1.34 and b = ln - 10
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Given that:
v = 1.34√l
where l is the hull length in feet and v is the hull speed in knots.
Santa Monica has a hull length that is 10 ft shorter than that of the Nina Pinta and ln is the length of Nina. Hence:
v = 1.34√(ln - 10) = a√b
The hull speed of the Santa Monica in terms of the length, ln of the Nina Pinta is given as a√b where a = 1.34 and b = ln - 10
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Answer:
What are the restrictions on ln? the answer is 10
Step-by-step explanation:
did it on edge
what is circumference?
The distance/measurement around a circle.
Use long division method to solve & following.
5 on 8
Answer:
0.625
Step-by-step explanation:
20 + 549+ 48574 - 46567476 x 987665 +1 if a apple is a shoo wath is a ñ
if (20 + 549+ 48574 - 46567476 x 987665) is the calculations of a number of apples, its total value is mathematically given as
X=−4.59930662*10^13
What is the number of apples?Generally, the equation for the statement is mathematically given as
20 + 549+ 48574 - 46567476 x 987665 +1
Let's equate it to x, Therefore
X= 20 + 549+ 48574 - 46567476 x 987665 +1
Using BODMAS
X= 20 + 549+ 48574 - 4.59930662*10^13 +1
X=49143-4.59930662×10^13
X=−4.59930662×10^13
In conclusion, the number of apples
X=−4.59930662*10^13
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f(x) = 3x2²2 = 13
Find f(2)
Enter the number that belongs in the green box.
Simplify completely.
Answer: 5/13
Step-by-step explanation:
[tex]f(2)=\frac{3(2)^{2}-7}{4(2)^{2}-3}=\boxed{\frac{5}{13}}[/tex]