16. Given the unbalanced equation:
_Al + CuSO4 → _A1,(SO2), + --Cu
When the equation is balanced using
the smallest whole-number coefficients,
what is the coefficient of AI?
(1) 1 (2) 2 (3) 3
(4) 4

Answer:

the desert (33% of the worlds surface)

Explanation:

Most of the world's surface is covered in water, in the form of oceans. The remaining landmass of Earth amounts to approximately 29 per cent of the surface. Of this remaining 29 per cent, deserts of all types constitute an estimated 33 per cent, or one-third, of the Earth's total landmass.

In simplest terms, water makes up about 71% of the Earth's surface, while the other 29% consists of continents and islands.

Only about 7.5% of the Earth's surface provides the agricultural soil on which we depend for the world's food supply and this fragment competes, sometimes unsuccessfully, with all other needs: housing, cities, schools, hospitals, shopping centres, landfills, etc.

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soda is fuzzy and can help heal the swell caused by a bee sting

Answer:

1. Vapor pressure of dry oxygen gas = 747.68 torr

2. Volume at STP = 39.97 mL

3. Number of oxygen gas molecules = 1.074 × 10²¹ molecules

4. Percent purity of KClO3 = 97.3 %

Explanation:

The balanced equation for the reaction is given below :

2 KClO3 (s) ------> 2 KCl (s) + 3 O2 (g)

1) Since the water level in the eudiometer was below the outside water level in the beaker,

Vapor pressure of dry oxygen gas = Total pressure + pressure due to difference in water levels - vapor pressure of water

Vapor pressure of water at 20 °C is 17.535 mm (torr).

Pressure due to difference in water level = 4.22 cm × 10mm/cm / 13.534 (13.534 is the density of mercury) = 3.118 mm (torr).

Vapor pressure of dry oxygen gas = 762.10 torr + 3.118 torr - 17.535 torr

Vapor pressure of dry oxygen gas = 747.68 torr

2) P₁ = 747.68 torr; V₁ = 43.60 ml; T1 = 20 °C + 273.15 = 293.15 K

P₂ = 760 torr; T₂ = 273.15 K; V₂ = ?

Using the general gas equation = P₁V₁/T₁ = P₂V₂/T₂

V2₂= P₁V₁T₂ / P₂T₁

V₂ = (747.68 × 43.60 × 273.15 ) / (760 × 293.15)

V₂ = 39.97 ml

Volume of dry oxygen gas at STP = 39.97 mL

3) Volume of oxygen gas at STP 39.97 mL = 0.03997 L

Number of moles of oxygen gas in 0.03997 L = volume of gas at STP /molarvolume at STP

Number of moles of oxygen gas = 0.03997/22.4 L

Number of molecules of oxygen gas = 0.03997/22.4 L × 6.03 × 10²³ molecules

Number of oxygen gas molecules = 1.074 × 10²¹ molecules

e) Number of moles of oxygen gas = 0.03997/22.4 = 0.001784 moles

From the equation, mole ratio of oxygen gas and potassium chlorate is 3 : 2

Moles KClO3 = 2/3 × 0.001784 moles = 0.001189 moles

Molar mass of KClO3 = 39 + 35.5 + 3 × 16 = 122.5 g

Actual mass of KClO3 decomposed = 122.5 grams × 0.001189 mole = 0.146 grams

Percent purity = (actual mass KClO3 decomposed / sample mass of impure KClO3) × 100%

Percent purity = (0.146/0.150) × 100% = 97.3 %

Answer:

sexual reproduction produces offspring with more variation, some of which may be better adapted to a new environment.

Explanation:

this allows more of the organisms to survive a change in the environment

Answer:

sexual reproduction produces offspring with more variation, some of which may be better adapted to a new environment.

Explanation:

Answer:

1. 2 M

2. 2 M

Explanation:

1. Determination of the final concentration.

Initial Volume (V₁) = 2 L

Initial concentration (C₁) = 6 M

Final volume (V₂) = 6 L

Final concentration (C₂) =?

The final concentration can be obtained as follow:

C₁V₁ = C₂V₂

6 × 2 = C₂ × 6

12 = C₂ × 6

Divide both side by 6

C₂ = 12 / 6

C₂ = 2 M

Therefore, the final concentration of the solution is 2 M

2. Determination of the final concentration.

Initial Volume (V₁) = 0.5 L

Initial concentration (C₁) = 12 M

Final volume (V₂) = 3 L

Final concentration (C₂) =?

The final concentration can be obtained as follow:

C₁V₁ = C₂V₂

12 × 0.5 = C₂ × 3

6 = C₂ × 3

Divide both side by 3

C₂ = 6 / 3

C₂ = 2 M

Therefore, the final concentration of the solution is 2 M

Answer:

Solute is Pottasium Nitrate and Solvent is Water.

Explanation:

The electron dot diagram for an element shows the valence electrons for the element. Oxygen is in group 16/VIA, so it has six valence electrons. Draw the symbol for oxygen. Then place one dot at each side of the symbol.

Answer:

All in All, All in All.

Explanation:

Answer:

40

Explanation:

M = n/v  hope this helps :b

Answer:

There are approximately 366.25 sidereal days in a year so that the Earth spins 366.25 times with respect to distant stars in a year

hope this helps

have a good day :)

Explanation:

Answer:

Polymerization, any process in which relatively small molecules, called monomers, combine chemically to produce a very large chainlike or network molecule, called a polymer. The monomer molecules may be all alike, or they may represent two, three, or more different compounds.

Answer:

B. Branched Alkene

HOPE THIS HELPS :-)

Answer:

hi hi hi hi hi hi hi hi hi hi hib uj hi u Inuit hi hi hi. hi hi hi hi hib hi hib hi hi hi hi hi hi hi hi hi hi hi hi hi b

Explanation:

vugjb oh in luv ug ug yf fyi dxezw f f g gjhc ydzt

Answer:

red litmus paper change into blue when it is dipped into Pineapple juice.

hope it helps

The red litmus paper will stay red when dipped in pineapple juice.

Acids are substances that can donate a proton to another substance. A base is a substance that can accept a hydrogen ion from an acid.

Acidic substances are often characterized by their sour taste. An acid commonly can be energetically favorable after a loss of H⁺ ion and is also known to turn blue litmus paper into red.

Bases are generally recognized for their bitter taste and slippery texture. A base that can dissolve in water is also referred to as alkali and is also known to turn red litmus paper into blue.

The pH value of the pineapple juice lies between 2.5 to 3.9. Therefore, it is acidic in nature as the pH of acidic substances lies in the range of 0 to 7. So the red litmus paper will stay red in pineapple juice.

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Answer:

0.703g Na must reacted

Explanation:

The reaction of Sodium, Na, With water, H₂O is:

2Na(s) + 2H₂O(l) → 2NaOH(aq) + H₂(g)

Where 2 moles of sodium reacts with an excess of water to produce 1 mole of hydrogen

To solve this question we have to use PV = nTR to solve the moles of the gas. With the moles of hydrogen we can find the moles of sodium that reacted and its mass:

Moles H₂:

PV = nRT

PV /RT = n

Where P is pressure = 1.15atm

V is volume in liters = 0.325L

R is gas constant = 0.082atmL/molK

T is absolute temperature = 25°C + 273 = 298.0K

1.15atm*0.325L / 0.082atmL/molK*298.0K = n

0.0153 moles of hydrogen are produced

Moles Na:

0.0153 moles H₂ * (2moles Na / 1mol H₂) = 0.0306 moles Na

Mass Na -Molar mass: 22.99g/mol-:

0.0306 moles Na * (22.99g / mol) =

Answer:

7.76 x 10^-3 M

Explanation:

pH = -log(x)

2.11 = -log (x)

10^-2.11 = 7.76x10^-3 M

Considering the definition of pH, the concentration [H⁺] is  7.76×10⁻³ M

You need to know that pH is the Hydrogen Potential. It is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

Mathematically, pH is calculated as the negative base 10 logarithm of the activity of hydrogen ions:

pH= - log [H⁺]

The numerical scale that measures the pH of substances includes the numbers from 0 to 14. The pH value 7 corresponds to neutral substances. Acidic substances are those with a pH lower than 7, while basic substances have a pH higher than 7.

In this case, being pH= 2.11, you can replace this value in the definition of pH:

2.11= -log [H⁺]

Solving:

[H⁺]= 10⁻² ¹¹ M

[H⁺]= 7.76×10⁻³ M

Finally, the concentration [H⁺] is  7.76×10⁻³ M

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Nitrous oxide decomposes into nitrogen and oxygen, according to 2 N2O (g) -> 2 N2 (g) + O2 (g). ... In an experiment, a stream of N2O is passed through a tube 25 mm in diameter and 20 cm long. The flow rate of the gas is 0.75 L/min.

Answer:

[tex]\boxed {\boxed {\sf 836.8 \ Joules \ lost}}[/tex]

Explanation:

Since we are given the mass and change in temperature, we should use the following formula for heat.

[tex]q= mc \Delta T[/tex]

In this formula, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

We know the mass of the water is 10 grams. We will have to look up water's specific heat, because it is not given. It is 4.184 J/g °C.

Let's find the change in temperature. This is the difference of the final and initial temperature. The water started at 80 °C and cooled to 60°C.

Now we have values for each variable.

Substitute the values into the formula.

[tex]q= 10 \ g * 4.184 \ J/g \textdegree C * -20 \textdegree C[/tex]

Multiply the first 2 numbers. The units of grams will cancel each other out.

[tex]q= 41.84 \ J/ \textdegree C * -20 \textdegree C[/tex]

Multiply again. This time, the degrees Celsius cancel.

[tex]q= -836.8 \ J[/tex]

A total of 836.8 Joules are lost.

Answer:

[tex]\boxed {\boxed {\sf 24.2624 \ g}}}[/tex]

Explanation:

Density measures mass per volume. The volume is

[tex]\rho=\frac{m}{v}[/tex]

The density of limestone is 2.72 grams per cubic centimeter. We have a piece of limestone with a volume of 8.92 cubic centimeters.

Substitute the values into the formula.

[tex]2.72 \ g/cm^3=\frac{m}{8.92 \ cm^3}[/tex]

Now we solve for m, the mass, by isolating the variable.

m is being divided by 8.92 cubic centimeters. The inverse of division is multiplication, so we multiply both sides by 8.92 cubic centimeters.

[tex]8.92 \ cm^3 * 2.72 \ g/cm^3=\frac{m}{8.92 \ cm^3}* 8.92 \ cm^2[/tex]

[tex]8.92 \ cm^3 * 2.72 \ g/cm^3=m[/tex]

The units of cubic centimeters cancel out.

[tex]24.2624 \ g =m[/tex]

The mass of this piece of limestone is 24.2624 grams.

Answer:The lungs expel the carbon dioxide and bring in new oxygen-containing air. Only when both systems are working together can oxygen and carbon dioxide be successfully exchanged between cells and environment. There are many other examples of this cooperation in your body.

Explanation:

Hope it will help

Question:

A body system is a group of organs that work together to keep the organism

alive. How does the respiratory system help to keep an organism alive?

A. The respiratory system helps the organism respond to its

environment.

B. The respiratory system helps the organism absorb nutrients from

its environment.

O C. The respiratory system takes in oxygen and releases carbon

dioxide.

O D. The respiratory system carries oxygen to the organism's cells.​

Answer:

O C. The respiratory system takes in oxygen and releases carbon

dioxide.

Explanation:

Breathing uses chemical and mechanical processes to bring oxygen to every cell of the body and to get rid of carbon dioxide. Our body needs oxygen to obtain energy to fuel all our living processes. Carbon dioxide is a waste product of that process

Hope This Helps?

Answer: [tex]CF_{4} + 2Br_{2} \rightarrow CBr_{4} + 2F_{2}[/tex] is a single replacement reaction.

Explanation:

A chemical reaction in which one element of a compound is replaced by another element is called single replacement reaction.

For example, [tex]CF_{4} + 2Br_{2} \rightarrow CBr_{4} + 2F_{2}[/tex]

Here, fluorine element in the compound [tex]CF_{4}[/tex] is replaced by the element bromine.

Therefore, it is a single replacement reaction.

Thus, we can conclude that [tex]CF_{4} + 2Br_{2} \rightarrow CBr_{4} + 2F_{2}[/tex] is a single replacement reaction.

Answer:subscript

Explanation:

Answer: The molecular formula of the compound is [tex]P_2O_6[/tex]

Explanation:

The molecular formula is the chemical formula that tells about the number of atoms of each element present in a compound. Molecular formula and empirical formula can also be the same when the number of atoms is in the simplest whole-number ratio.

To calculate the molecular formula, the number of atoms of the empirical formula is multiplied by a factor known as valency that is represented by the symbol, 'n'.

[tex]n=\frac{\text{Molecular mass}}{\text{Empirical mass}}[/tex]        ...(1)

Given empirical formula is [tex]PO_3[/tex]

Empirical mass = [tex][(1\times 30.97) + (3\times 15.99)]=78.94 g/mol[/tex]

Molecular mass = 157.9 g/mol

Plugging values in equation 1:

[tex]n=\frac{157.9 g/mol}{78.94g/mol}\\\\n=2[/tex]

Molecular formula of the compound becomes [tex]P_{2\times 1}O_{2\times 3}=P_2O_6[/tex]

Hence, the molecular formula of the compound is [tex]P_2O_6[/tex]

Answer:

they have the same density

Answer:

Ni(NO₃)₂ + Na₂CO₃ ⇒ NiCO₃ + 2 NaNO₃

Explanation:

Let's consider the unbalanced equation for the reaction that occurs when aqueous solutions of nickel(II) nitrate and sodium carbonate are combined. This is a double-replacement precipitation reaction.

Ni(NO₃)₂ + Na₂CO₃ ⇒ NiCO₃ + NaNO₃

We will balance the equation using the trial and error method.

First, we will balance Na atoms by multiplying NaNO₃ by 2.

Ni(NO₃)₂ + Na₂CO₃ ⇒ NiCO₃ + 2 NaNO₃

As we can see, the equation is balanced.

Answer:

5 half lives

Explanation:

Given that

Thorium - 236 contains the half-life of 10.0 minutes

And there is 250 grams

We need to find out the number of half lives that took place after 50.0 minutes

As in the question

1 half life is 10 minutes

So for 50 minutes, it would be

= 50 minutes ×  1 half life ÷ 10 minutes

= 5 half lives

Answer:

If reaction is taking place at room temperature and pressure(rtp)

= 360 litres of O₂ at rtp

If reaction is taking place at  standard temperature and pressure(stp):

= 336 litres of O₂ at stp

Explanation:

2C₂H₆ + 70₂ → 4CO₂ + 6H₂O

1 mole of C₂H₆ =  (12 × 2) + (1 × 6) = 24 + 6 = 30g

2 moles of C₂H₆ = 30 × 2 = 60g

From the equation:

1 mole of 0₂ reacts with 2 moles of C₂H₆

1 mole of 0₂ reacts with  60g  of C₂H₆

? moles of 0₂ react with 90g of C₂H₆

[tex]\frac{90}{60}[/tex]= 1.5 moles of O₂

Considering condition of reaction taking place whether room temperature and pressure(rtp) or standard temperature and pressure(stp)

If room temperature and pressure(rtp):

1 mole of 0₂ occupies 24 liters/24000 cm³/ 24 dm³ of O₂

1.5 moles of O₂ occupies (24 × 1.5)  litres of O₂

= 360 litres of O₂ at rtp

If standard temperature and pressure(stp):

1 mole of 0₂ occupies 22.4 liters/22400 cm³/ 22.4 dm³ of O₂

1.5 moles of O₂ occupies (22,4 × 1.5)  litres of O₂

= 336 litres of O₂ at stp

Answer:

Q1) B

Q2) C

Kelvin is the SI unit of temperature.