Given:
Quadratic equation
To write a quadratic equation that cannot be factored or cannot be solved by factoring, we note first that factoring is the easiest method to solve a quadratic equation as long as the equation is easily factorable. If not, we'll need alternative approaches like employing the quadratic formula.
We also note that factoring cannot always be used to solve quadratic equations.
Below is an example of an equation that can be solve by factoring:
[tex]\begin{gathered} x^2-3x-10=0 \\ (x-5)(x+2)=0 \end{gathered}[/tex]Now, the equation that cannot be factored or cannot be solved by factoring is:
[tex]x^2+x-1=0[/tex]We cannot apply factoring to the above equation. Therefore, the answer is:
[tex]x^2+x-1=0[/tex]I need help with this question but no one is helping me! Can someone please help me
Answer: 36.00%
60% can be written as 0.60 and/or 6/10, which simplifies to 3/5 for easier operations. The probability of 2 students both drink coffee with breakfast can be shown as 0.60 • 0.60 = 0.36. This means there is a 36% chance of both students drinking coffee with breakfast in the morning.
Step-by-step explanation:
6.4 The ratio of length and breadth of a rectagular field is 4:3. If perimeter of the field is 700m, find (i) length and breadth of the field (ii) area of the field.
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As part of a charity drive, 50 fourth grade students each donated an equal number of dimes and 30 third grade students each donated the same number of nickels. Let d represent the number of dimes and n represent the number of nickels. Determine which of the expressions shows the total amount (in cents) donated by the 3rd and 4th grade students. A.) 10(50d)+5(30n)B.) 80cC.) 10d+5nD.) 50d+30n
Last year, 49% of business owners gave a holiday gift to their employees. A survey of business owners conducted this year indicates that 40% planned to provide a holiday gift to their employees. Suppose the survey results are based on a sample of 85 business owners.
b. Suppose the business owners in the sample do as they plan. Conduct a hypothesis test that can be used to determine whether the proportion of business owners providing holiday gifts had decreased from last year.
State the hypotheses.
Compute the test statistic and p-value.
c. Using a 0.01 level of significance, would you conclude that the proportion of business owners providing gifts decreased?
Using the z-distribution, it is found that:
b)
The hypotheses are: null [tex]H_0: p \geq 0.49[/tex], alternative [tex]H_1: p > 0.49[/tex]The test statistic is of z = -1.69.The p-value is of 0.0455.c) There is not enough evidence to conclude that the proportion of business owners providing gifts decreased using a 0.01 significance level.
What are the hypotheses tested?At the null hypotheses, it is tested if there is no evidence that the proportion decreased from 49%, that is:
[tex]H_0: p \geq 0.49[/tex]
At the alternative hypotheses, it is tested if there is evidence that the proportion decreased from 49%, that is:
[tex]H_1: p > 0.49[/tex]
What is the value of the test statistic?The test statistic is given according to the following rule:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
In which the parameters are described as follows:
[tex]\overline{p}[/tex] is the sample proportion.p is the proportion tested at the null hypothesis.n is the sample size.Considering that 40% of the sample of 85 planned to provide a gift, and the proportion tested is of 49%, the values of the parameters are given as follows:
[tex]\overline{p} = 0.4, p = 0.49, n = 85[/tex]
Hence the test statistic is given by:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
[tex]z = \frac{0.4 - 0.49}{\sqrt{\frac{0.4(0.6)}{85}}}[/tex]
z = -1.69.
What is the p-value of the test and what is the conclusion?Considering a left-tailed test, as we are testing if the proportion is less than a value, with z = -1.69, using a z-distribution calculator, the p-value is of 0.0455.
Since the p-value of the test is greater than 0.01, there is not enough evidence to conclude that the proportion of business owners providing gifts decreased using a 0.01 significance level.
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solve each formula for the indicated letter. circle the letter next to your answer. write the letter in the box below.
(1) d = rt so, r = d/t
(2) a = F/m so, F = ma
(3) p = w/t so, t = w/p
(4) h = V/B so, B = V/h
(5) A = (abc)/(4r) so, r = (abc)/(4A)
(6) P/Q = R/S so, S = QR/P
(7) a = (v-i)/t so, v = at + i
(8) E/e = (R + r)/r so, e = Er/(R+r)
(9) 1/p + 1/q = 1/f so, f = (pq)/(p+q)
(10) 1/p + 1/q = 1/f so, p = qf/(q-f)
(11) 1/R = 1/r1 + 1/r2 so, R = (r1 r2)/(r1 + r2)
(12) 1/t = (1/a) + (1/b) so, b = (at)/(a - t)
(13) A/B = C/D so, C = AD/B
(14) A = h(a+b)/2 so, b = 2A/h - a
(15) V = Q/r1 - Q/r2 so, Q = Vr1 r2/(r2 - r1)
(16) u = F(P/T - E) so, P = (uT + EFT)/F
find the value of x and y that make the quadrilateral
The quadrilateral have equal opposite sides, for example:
Then, (4x + 6) must be equal to (7x - 3), and (4y - 3) is equal to (3y + 1), therefore
[tex]4x+6=7x-3[/tex]We can solve that equation for x
[tex]\begin{gathered} 4x+6=7x-3 \\ \\ 3x=9 \\ \\ x=\frac{9}{3}=3 \end{gathered}[/tex]Hence, x = 3. Now let's solve the other equation
[tex]\begin{gathered} 4y-3=3y+1 \\ \\ y=4 \end{gathered}[/tex]Then the value of y is 4.
Final answers:
x = 3
y = 4
The average amount of time spent grocery shopping is 45 minutes with a standard deviation of 12 minutes. Using the Empirical Rule, what percent should spend less than 33 minutes?
You have:
mean = 45
standard deviation = 12
Use the following formula:
Select the correct answer from each drop-down menu.
A triangle FGH, right angle at H is shown. Base GH has length labeled 3 units. Height FH has length labeled 4 units, and hypotenuse FG has length 5 units.
Use the figure to complete the following statements.
sin(F) =
cos(F) =
sin(G) =
cos(G) =
The value of given expressions will be sin(F) = 3/5, cos(F) = 4/5, sin(G) = 4/5 and cos(G) = 3/5.
A triangle may be defined as a closed figure having three sides and three angle, the sum of which is equal to 180°. A right-angled triangle is the one which has one angle as 90°. We consider a right-angled triangle FGH which is right-angled at H. The sine of any angle is given by the division of Perpendicular to its Hypotenuse. The cosine of any angle is given by the division of Base to its Hypotenuse. Now, we need to find
sin(F) = Perpendicular/Hypotenuse, for angle at F perpendicular will be GH and Hypotenuse will be FG. So, sin(F) = 3/5
cos(F) = Base/Hypotenuse, for angle at F Base will be FH and Hypotenuse will be FG. So, cos(F) = 4/5
sin(G) = Perpendicular/Hypotenuse, for angle at G perpendicular will be FH and Hypotenuse will be FG. So, sin(F) = 4/5
cos(G) = Base/Hypotenuse, for angle at G Base will be GH and Hypotenuse will be FG. So, cos(F) = 3/5
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A manufacturer of ski clothing makes ski pants and ski jackets. The profit on a pair of ski pants is $3 and on a jacket is $2. Both pants and jackets require the work of sewing operators and cutters. There are 60 minutes of sewing operator time and 48 minutes of cutter time available. It takes 8 minutes to sew one pair of ski pants and 4 minutes to sew one jacket. Cutters take 4 minutes on pants and 8 minutes on a jacket. The manufacturer wants to make a minimum of 4 ski pants and 2 ski jackets, Let x represent the number of ski pants. Let y represent the number of ski jackets.
For the sewing operator:
[tex]8x\text{ + 4y }\leq\text{ 60}[/tex]For cutter:
[tex]4x\text{ + 8y }\leq48[/tex]The two above equation is solve to obtain the graph
The solution of the graph is where the two lines meet
The coordinate is (10, 4), at the this point the maximum profit is made
So 10 ski pants and 4 ski jackets is made to get maximum profit
The profit made is given by
P = 3x + 2y
x =10 , y = 4
P = 3(10) + 2(4)
P = 30 + 8 = $38
Thursday
Each 4th grade class at Garza Elementary collected plastic water bottles to recycle.
Each number on the stem and leaf plot represents how many bottles each class
brought in. Record each answer in the blank box next to each question.
Help fill the table please.
1. how many fourth grade classes brought in between 90 and 100 bottles
2. How many classes brought in more than 100 water bottles
3. how many classes brought in less than 99 water bottles
4. How many fourth grade glasses are represented on the stem and leaf plot
The number of students that collected between 90 and 100 bottles is 3.
The number of students that collected more than 100 bottles are 7.
The number of students that collected less than 90 students are 2
The total number of classes represented is 10.
Here is the completed frequency table
Number of bottles collected Classes
90 - 100 3
101 - 110 6
111 - 120 1
What is a stem and leaf plot?A stem-and-leaf plot is a table that splits a number into a stem and leaf. The stem is the first number in the digit while the leaf is the last number. For example the stem in 45 is 4 and the leaf is 5.
An advantage of the stem-and-leaf plot is that it provides an easy way to present and interpret a dataset. A disadvantage of the stem-and-leaf plot is that it cannot be used for a large dataset.
Bottles collected that are between 90 and 100 are 94, 98, 99
Bottles that are greater than 100 are 105, 107, 107, 113, 114, 119, 120
Bottles that are less than 99 are 94, 98
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A radioactive substance decays according to A=A0e−0.0028t, where A0 is the initial amount and t is the time in years. If A0=710 grams, find the time for the radioactive substance to decay to 366 grams. Round your answer to two decimal places, if necessary.
Solution
- The function given is:
[tex]A=A_0e^{-0.0028t}[/tex]- We have been given:
[tex]\begin{gathered} A_0=710g \\ A=366g \end{gathered}[/tex]- We are required to find the time for the radioactive substance to decay. That means we need to find the value of t in the equation.
- Thus, we have that:
[tex]\begin{gathered} 366=710e^{-0.0028t} \\ \text{ Divide both sides by 710} \\ \frac{366}{710}=e^{-0.0028t} \\ \\ \text{ Take the natural log of both sides} \\ \ln(\frac{366}{710})=\ln(e^{-0.0028t}) \\ \\ \ln(\frac{366}{710})=-0.0028t \\ \\ \text{ Divide both sides by -0.0028} \\ \\ \therefore t=\frac{1}{-0.0028}\ln(\frac{366}{710}) \\ \\ t=236.6541...\approx236.65\text{ years} \end{gathered}[/tex]Final Answer
The answer is 236.65 years
Which of the following statements best describe the branches of the hyperbola?Select one:a.It is not possible to determine how the branches of the hyperbola open.b.The branches of the hyperbola are positioned at a 30⁰ angle.c.The branches of the hyperbola open up and down.d.The branches of the hyperbola open side to side.
Answer:
Explanation:
The first step is to plot the graph of the parabola. It is shown below
Looking at the graph, the branches open up and down. Thus, the correct option is
c. The branches of the hyperbola open up and down.
Fill in the missing parts to these two column proofs:
According to the picture:
For the first statement
[tex]AB\cong CD[/tex]The reason is: Given.
This is because it is given in the information to solve the problem.
The second statement must be:
[tex]BC\cong DA[/tex]And the reason is also: Given.
For the third statement:
[tex]AC\cong AC[/tex]The reason is the Reflexive property.
The fourth statement must be:
[tex]\Delta ABC=\Delta ADC[/tex]The reason is Side Side Side congruence postulate.
The fifth statement must be:
[tex]\measuredangle ABC=\measuredangle CDA[/tex]The reason is congruent triangles definition.
If P is the centroid of the triangle JKL, JK = 22, KN = 13, and OL = 18, find each measure.
Given
JK = 22
KN = 13
OL = 18
Procedure
Centroid formulation
KM = JK/2 = 22/2 = 11
KM = 11
NL = KN
NL = 13
KL = 2KN = 2(13) = 26
KL = 26
JO = OL = 18
JO = 18
JL = 2OL = 2(18)
JL = 36
A trendline is given to depict the enrollment at a local college where x is the year and y represents enrollment. y=178.09x−353194Use the trendline to estimate the enrollment for 2009. Round to the nearest whole number.
To determine the enrollment in 2009 we need to plug x=2009 in the equation given to determine the value of y:
[tex]\begin{gathered} y=178.09(2009)-353194 \\ y=357782.81-353194 \\ y=4588.81 \end{gathered}[/tex]Therefore, in the year 2009, there were 4589 students enrolled
Simplify 2(x+8)+6x Write your answer in factored form
Answer:
8x + 16 is your answer
Step-by-step explanation:
Which of the following equations represents a line that is perpendicular toy=-3x+6 and passes through the point, (3, 2)?A. y=-3x+1B. y=(1/3x)+3C. y=(-1/3x)+1OD. y=(1/3x)+1
Step 1
For perpendicular lines
[tex]m_1=-\frac{1}{m_2}[/tex][tex]m_1=-3[/tex][tex]\begin{gathered} -3=-\frac{1}{m_2} \\ m_2=-\frac{1}{-3} \\ m_2=\frac{1}{3} \end{gathered}[/tex]Step 2
[tex]\begin{gathered} Given\text{ points \lparen3,2\rparen} \\ y=mx+b---\text{ Standard equation of a line} \\ y=\frac{1}{3}x+b \end{gathered}[/tex][tex]2=\frac{1}{3}(3)+b[/tex]Find b, the y-intercept
[tex]\begin{gathered} 2=1+b \\ b=2-1=1 \end{gathered}[/tex]Answer; Option D
[tex]y=\frac{1}{3}x+1[/tex]answers pleaseeee
im struggling
Answer:
y=3/4x-2
Step-by-step explanation:
slope=3/4x
y-intercept=-2
Question: how do I figure out if a number is rational or irrational
A number is said to be rational if it can be written or transformed into the p/q form, where p and q are integers and q is a non-zero number; if it cannot be written in this form, it is said to be irrational.
Any number that can be written or stated in the p/q form, where p and q are integers and q is a non-zero number, is said to be rational.
A number that is irrational, on the other hand, cannot be stated in p/q form, and its decimal expansion is non-repeating and non-terminating.
Example: √2, √7, √11
Hence we get the required answer.
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The area of a trapezoid is A = 12 (b 1 + b 2)h. Which equation represents the area of a trapezoid when solved for b 1?
If the area of a trapezoid is A = [tex]\frac{1}{2} (b_{1}+ b_{2})h[/tex], then the equation represents the value of [tex]b_{1}[/tex] is [tex]b_{1}=\frac{2A}{h}-b_{2}[/tex]
The trapezoid is a quadrilateral with at least one pair of parallel sides is called trapezoid. There are four vertices and four edges in the trapezoid.
The area of the trapezoid A = [tex]\frac{1}{2} (b_{1}+ b_{2})h[/tex]
Where [tex]b_{1}[/tex] and [tex]b_{2}[/tex] are the length of the parallel sides of the trapezoid
h is the height of the trapezoid
A = [tex]\frac{1}{2} (b_{1}+ b_{2})h[/tex]
Move 1/2 to other side
[tex](b_{1}+ b_{2})h[/tex] = 2A
Move h to other side
[tex](b_{1}+ b_{2})[/tex] = [tex]\frac{2A}{h}[/tex]
Move [tex]b_{2}[/tex] to other side
[tex]b_{1}=\frac{2A}{h}-b_{2}[/tex]
Hence, if the area of a trapezoid is A = [tex]\frac{1}{2} (b_{1}+ b_{2})h[/tex], then the equation represents the value of [tex]b_{1}[/tex] is [tex]b_{1}=\frac{2A}{h}-b_{2}[/tex]
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Given that f(x) = x sqaured - 10x + 16 and g(x) = x - 8, find f (x) · g(x) andexpress the result in standard form.
Given the functions
[tex]f(x)=x^2-10x+16[/tex][tex]g(x)=x-8[/tex]You have to calculate
[tex]f(x)\cdot g(x)[/tex][tex](x^2-10x+16)\cdot(x-8)[/tex]To solve this you have to apply the distributive property of multiplications, that is, you have to multiply each term of the first parenthesis with each term of the second parenthesis.
As follows:
[tex]\begin{gathered} (x^2-10x+16)\cdot(x-8) \\ (x^2\cdot x)+(x^2)\cdot(-8)+(-10x\cdot x)+(-10x)\cdot(-8)+(16\cdot x)+(16\cdot(-8)) \\ x^3-8x^2-10x^2+80x+16x-128 \end{gathered}[/tex]Now simplify the like terms
[tex]\begin{gathered} x^3+(-8x^2-10x^2)+(80x+16x)-128 \\ x^3-18x^2+96x-128 \end{gathered}[/tex]The result in standard form is
[tex]f(x)\cdot g(x)=x^3-18x^2+96x-128[/tex]it takes 126 cubes that have edge lengths of 1/3feet to completely fill this plastic bin what is the area of the base of bin
Answer: 1) Each of the 126 cubes has a volume = (1/3)3 = 1/3 × 1/3 × 1/3 = 1/27 cubic feet.
2) It takes 126 cubes to fill the bin, so the bin has a volume of 126 × 1/27 = 126/27 cubic feet. (Don't do this division yet - leave it as an improper fraction)
3) The volume of the bin is also given by the formula Volume = Area of Base × Height. Plus we know the volume is 126/27 cubic feet and the height is 2 1/3 = 7/3 of a foot, so:
Step-by-step explanation: Volume = Area of Base × Height
126/27 = Area of Base × 7/3
126/27 × 3/7 = Area of Base
The area of the base of bin is 2 feet².
What is Volume of Cube?The formula of volume of the cube is given by: Volume = a³, where a is the length of its sides or edges.
Given:
Edge = 1/3 feet
Volume of 1 cube= l³= (1/3)³ = 1/27
Totals cubes= 126
So, Volume of 126 cube= 126 x 1/27 = 126/ 27
Then, Volume of Plastic Bin= Area of base x height
126 / 27 = Area of base x 7/3
Area of base = 126 /27 x 3 /7
Area of base = 2 ft²
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Find the standard form for the equation of a circle ( x − h )^2 + ( y − k )^2 = r^2 with a diameter that has endpoints ( − 4 , − 8 ) and ( 6 , − 4 ) .h=k=r=
Answer:
[tex](x-1)^2+(y+6)^2=29[/tex][tex]\begin{gathered} h=1 \\ k=-6 \\ r=\sqrt{29} \end{gathered}[/tex]Explanation:
Given:
Endpoints of the diameter of a circle as (-4, -8) and (6, -4)
To find:
Equation of a circle in standard form
The equation of a circle in standard form is generally given as;
[tex](x-h)^2+(y-k)^2=r^2[/tex]where (h, k) is the coordinate of the center of the circle and r is the radius of the circle.
We'll go ahead and determine the coordinates of the midpoint of the endpoints of the diameter which will be the coordinates of the center of the circle as seen below wi;
[tex]h=\frac{x_1+x_2}{2}=\frac{-4+6}{2}=\frac{2}{2}=1[/tex][tex]k=\frac{-8+(-4)}{2}=\frac{-12}{2}=-6[/tex]So the center of the circle has coordinates (1, -6)
Since h = 1, and k = -6 and we have that x1 = -4 and y1 = -8, we can go ahead and solve for r as seen below;
[tex]\begin{gathered} (-4-1)^2+(-8-(-6))^2=r^2 \\ (-5)^2+(-2)^2=r^2 \\ 25+4=r^2 \\ 29=r^2 \\ \therefore r=\sqrt{29} \end{gathered}[/tex]We can now write the equation of the circle in standard form as;
[tex]\begin{gathered} (x-1)^2+(y-(-6))^2=29 \\ (x-1)^2+(y+6))^2=29 \end{gathered}[/tex]what is 42/100 of x over 35%
The value of x in the expression 42/100 of x over 35% is 0.147.
What is an expression?It should be noted that an expression is simply used to show the relationship between the variables or number given.
Therefore, the information will be expressed as:
42/100 × x/35%
= 42/100 × x/0.35
Cross multiply
100 × x = 0.35 × 42
100x = 14.7
Divide.
x = 14.7 / 100
x = 0.147
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(-8.8)(-9) =
(0.5)(-0.5)=
(-0.2)(-5)
Answer:
(-8.8)(-9)= 79.2
(0.5)(-0.5)= -0.25
(-0.2)(-5)= 1
Factories 6ax2-3ay-8bx2+4by
=[2[tex]x^{2}[/tex]-y][3a-4b] This is the factorized form of 6a[tex]x^{2}[/tex]-3ay - 8 b[tex]x^{2}[/tex] + 4by
What is factorization ?To factorize a number, use the factorization formula. Factorization is the process of dividing a whole into components that, when multiplied together, equal the original number. The factorization approach simplifies any algebraic or quadratic equation by using the basic factorization formula, which represents the equations as the product of factors rather than expanding the brackets. Any equation may have an integer, a variable, or the algebraic expression itself as a factor.
6a[tex]x^{2}[/tex]-3ay - 8 b[tex]x^{2}[/tex] + 4by
Rearrange the expression
6a[tex]x^{2}[/tex] -8bx² -3ay +4by
2[tex]x^{2}[/tex][3a-4b] - y[3a-4b]
=[2[tex]x^{2}[/tex]-y][3a-4b]
This is the factorized form of 6a[tex]x^{2}[/tex]-3ay - 8 b[tex]x^{2}[/tex] + 4by
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Factories often add filler when making meatballs sold by the bag. One factory obtained 90 kg of beef from overseas. They want to add 1.4 oz of filler for each
pound of beef. How many ounces of filler will the factory need in order to make meatballs out of this shipment of beef?
Use 1 Ib=0.45 kg and do not round any
computations.
One factory that obtained 90 kg of total beef from overseas. The company needs 390 oz of meat filler to make meatballs out of this shipment of beef.
What are meat fillers?In processed meat products, starches are frequently employed as fillers to bind water that would otherwise leak out of the product, increasing its texture and sensory qualities.
As cheap fillers or inferior fiber sources, items including corncobs, feathers, soy, cottonseed hulls, peanut hulls, citrus pulp, screening, weeds, straw, and cereal by-products are frequently used.
One factory that has obtained 135 kg of beef from overseas.
They want to add a total of 1.3oz of filler for each pound of beef.
Given is:
0.45 kg = 1 pound
So, 135 kg = 300 pounds
The company that wants to add a total of 1.3 oz of filler for each pound of beef.
So, for 300 pounds they will need = 390 oz of filler.
Therefore, the company needs 390 oz of filler.
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A bag contains 120 marbles. Some are red and the rest are black. There are 19 red marbles for every black marble. How many red marbles are in the bag?
A bag contains 120 marbles. Some are red and the rest are black. There are 19 red marbles for every black marble. How many red marbles are in the bag?
The number of red marbles in the bag is 114 .
in the question ,
it is given that ,
total number of marbles in the bag = 120 marbles
let the number of red marbles [tex]=[/tex] r
let the number of black marbles [tex]=[/tex] b
so , According to the question
b + r = 120 ...eqn(1)
also given that for every black marble there is 19 red marbles
which is represented by , r = 19b
Substituting r = 19b in eqn (1) , we get
b + 19b = 120
simplifying further , we get
20b = 120
b = 6
and r = 19(6) = 114
Therefore , The number of red marbles in the bag is 114 .
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(+2) The
The ratio of
women children = 11:3 and the
ratio of
men children = 5:2
Find the ratio of men:women
The ratio of both men and women 15:22
What is Ratio ?
A ratio displays the multiplicity of two numbers. For instance, if a dish of fruit contains eight oranges and six lemons, the ratio of oranges to lemons is eight to six. The ratio of oranges to the overall amount of fruit is 8:14, and the ratio of lemons to oranges is 6:8.
Given,
The ratio of men and children = 5:2
The ratio of women and children = 11:3
To find the ratio of men and women we have to divide both the ratio:
men/children/women/children
or,
men/children x children/women
putting the values
=5/2 x 3/11
=15/22
Hence, the ratio of men:women is 15:22
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22. A 250W carrier is to be modulated at an 85% modulation level. What is the total transmitted power? a. 340.3 W b. 25.32 dB c. 0.340 kW d. 55.32 dBm e. All of the above.
The total transmitted power is a. 340.3 W.
The transmitted and carrier power is related with modulation through the formula -
[tex] P_{t} = P_{c}(1 + \frac{ {m}^{2} }{2} )[/tex]
where [tex]P_{t}[/tex] is transmitted power, [tex]P_{t}[/tex] is carrier power and m is modulation.
Keep the values in formula to find the value of total transmitted power.
[tex]P_{t}[/tex] = 250 (1 + 85%²/2)
Taking square of percentage
[tex]P_{t}[/tex] = 250 (1 + 0.7225/2)
Performing division in the bracket
[tex]P_{t}[/tex] = 250 (1 + 0.36125)
Performing addition in the bracket
[tex]P_{t}[/tex] = 250×1.36125
Performing multiplication
[tex]P_{t}[/tex] = 340.3125
Thus, the total transmitted power when carrier power is 250 W and modulation is 85% is a. 340.3 W.
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