Answer:
Friction is a force that resists the relative motion of objects sliding against each other. It depends on the nature of the surfaces of the two objects interacting with each other, as well as how much they are pressed together.
Explanation:
Answer: Friction.
Explanation: is a force that resists the relative motion of objects sliding against each other. It depends on the nature of the surfaces of the two objects interacting with each other, as well as how much they are pressed together.
discuss the types and operation of active and passive filters in measurements and instrumentation
Resistors, capacitors, and inductors are the only passive elements used in passive filters. In contrast, active filters don't employ inductors and instead use resistors, capacitors, and active components like op-amps.
What makes it a passive filter?A common type is called a passive filter because it uses solely passive inductive (L), capacitive (C), and resistive (R) components rather than active ones like transistors. Passive filters do not require a power source.
As they separate and only permit certain sinusoidal input signals to pass, passive RC filters "filter-out" undesirable signals.
What are various types of passive filters?Low Pass Filters.High Pass Filters.Band Pass Filters.Band Stop/Reject Filters.Power Line Filters.SAW Filters.Signal Filters.Sinusoidal Filters.To know more about Passive filter visit:
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Module 1 question 12
Assume that an MX missile goes from rest to a suborbital velocity of 3.50 km/s in 40.0 s (the actual speed and time are classified). What is its average acceleration in m/s2?
m/s2
What is its average acceleration in multiples of g?
g
The average acceleration of the MX missile is 87.5 m/s^2. The average acceleration in multiples of g is 8.9g.
The rate at which the velocity changes is known to as average acceleration. To determine the average acceleration of an object, we divide the change in velocity by the amount of time that has passed. The formula of acceleration is,
a = (v_f - v_i)/t
Where a = acceleration, v_f = final velocity, v_i = initial velocity and t = time.
Here, the initial velocity is zero, final velocity is 3.5 km/s and time is 40.0 seconds. The acceleration will be
a = (3.50*1000 - 0)/40.0
a = 3500/40
a = 87.5 m/s^2
The value of acceleration due to gravity (g) is 9.8 m/s^2. The acceleration of the MS missile in multiples of g is,
a = 87.5/9.8
a = 8.9g
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A ball of mass 1.2 kg is suspended by two wires from a horizontal arm, which is attached to a vertical shaft, as shown in the figure. The rate of rotation of the shaft and ball is such that the tensions in the two wires are equal. What is the radial acceleration of the ball?
The radial acceleration of the ball of mass 1.2 kg that is suspended by two wires from a horizontal arm, which is attached to a vertical shaft is 4.9 m / s²
Since the wires form a right angled triangle with the horizontal arm,
tan θ = Opposite side / Adjacent side
tan θ = 0.6 / 0.8
θ = [tex]tan^{-1}[/tex] ( 0.75 )
θ = 36.9°
m = 1.2 kg
W = m g
W = 1.2 * 9.8
W = 11.76 N
T1 = T2 = T
∑ [tex]F_{y}[/tex] = 0
T1 + T2 sin θ - W = 0
T + T sin 36.9° - 11.76 = 0
T + 0.6 T = 11.76
T = 11.76 / 1.6
T = 7.35 N
[tex]F_{c}[/tex] = m v² / r
[tex]F_{c}[/tex] = Centripetal force
∑ [tex]F_{x}[/tex] = m v² / r
T cos 36.9° = m * [tex]a_{r}[/tex]
[tex]a_{r}[/tex] = 7.35 * 0.8 / 1.2
[tex]a_{r}[/tex] = 4.9 m / s²
Therefore, the radial acceleration of the ball = 4.9 m / s²
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WHAT FAMILY DOES THIS BELOND TO?
PLEASE ANSWER WILL MARK BRAINIEST
Answer:
See below
Explanation:
2 - 8 - 2 is the configuration for Mg Magnesium is an alkaline earth metal
If the distance between the Earth and Sun were decreased by a factor of 4, how much would the gravitational force on the Earth change?
The gravitational force between the sun and the earth will become 16 times of the original force if distance between the Earth and Sun were decreased by a factor of 4.
What is universal law of gravitation?The universal law of gravitational states that the force of attraction between two masses is directly proportional to product of their masses and inversely proportional to the square of the distance between them.
Given are the Earth and Sun and the distance between them is decreased by a factor of 4.
Assume that the mass of sun is m[S] and that of earth is m[E] and the distance between them be R. Then the gravitational force of attraction would be -
F [1] = Gm[S]m[E]/R²
If the distance is decreased by the factor of 4, then we can write -
F [2] = Gm[S]m[E]/(R/4)²
Now,
F[1]/F[2] = {Gm[S]m[E]/R²}/{Gm[S]m[E]/(R/4)²}
F[1]/F[2] = (R/4)²/R²
F[1]/F[2] = (R²/16)/R²
F[1] /F[2] = 1/16
F[2] = 16 F[1]
Therefore, the gravitational force between the sun and the earth will become 16 times of the original force if distance between the Earth and Sun were decreased by a factor of 4.
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What would the mechanical advantage of a ramp be if the length is 20 feet and the height is 5 feet?
100
8
1000
4
please use a multiple choice answer for branliest (how ever you spell it)
which mass is the lightest between 5m/s,0m/s and 3m/s?
A restaurant owner attaches a sign to the side of his building as shown in the image. A beam is bolted to the building to support the cable, and the cable is anchored to the end of the beam and tensioned such that it bears the full weight of the sign. The beam is exactly horizontal with respect to the earth, the upper portion of cable makes a 30.0o angle with the beam, and the mass of the sign is 10.0 kg.
Determine the magnitude of the tension in the cable
The magnitude of the tension in the cable is determined as 49 N.
What is tension force?
Force of tension is defined as the force transmitted through a rope, string or wire when pulled by forces acting from opposite sides.
The upward tension of the cable is equal to the downward weight of the beam.
Mathematically, the formula for calculating the tension in the cable is calculated as follows;
T = W sinθ
where;
W is the weight of the beam due to force of gravity pulling it downwardsθ is the angle of inclination of the cable above the horizontalT = mg sinθ
Substitute the given parameters and solve for the tension,
T = (10 kg x 9.8 m/s²) x sin(30⁰)
T = 49 N
Thus, we can conclude that the tension in the cable as it bears the full weight of the beam is 49 N.
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The radius of a wheel is 0.680 m. A rope is wound around the outer rim of the wheel. The rope is pulled with a force of magnitude 5.00 N, unwinding the rope and making the wheel spin CCW about its central axis. Ignore the mass of the rope.What is the angular displacement Δθ, in radians, of the wheel during 1.20 revolution?
Givens.
• The radius of the wheel is 0.680 m.
,• The applied force is 5.00 N, and it's a tangential force.
,• The number of revolutions is 1.20.
We need to find the circumference of the wheel, use the circumference formula.
[tex]C=2\pi r[/tex]Where r = 0.680 m and pi = 3.14.
[tex]C=2\cdot3.14\cdot0.680=4.27m[/tex]The circumference of the wheel is 4.27 meters.
It's important to notice that the circumference represents 1 revolution, so for 1.20 revolutions we have
[tex]1.20\text{rev}\cdot\frac{4.27m}{1\text{rev}}=5.12m[/tex]This means the total distance covered is 5.12 m. However, the displacement is different because it takes into account only the change of position, so basically, the displacement would be 0.20 revolutions because at 1 revolution we are at the same starting point.
[tex]0.20\text{rev}\cdot\frac{4.27m}{1\text{rev}}=0.854m[/tex]Therefore, the total displacement is 0.854 meters.
However, we need to find the angular displacement, so
[tex]\theta=\frac{d}{r}=\frac{0.854m}{0.680m}=1.26\text{rad}[/tex]Hence, the angular displacement is 1.26 radians.
3.-A projectile has an initial horizontal velocity of
5 m/s and an initial vertical velocity of 3 m/s second upward. At what angle was the projectile
fired?
Answer:
Explanation:
tg α = V₂ / V₁ = 3 / 5 = 0.6
α ≈ 31°
A ball is rolled at a speed of 12 m/seconds after 36 seconds it comes to stop what is the acceleration of the ball
Answer:
Approximately [tex](-0.33)\; {\rm m\cdot s^{-2}}[/tex] ([tex](-1/3)\; {\rm m\cdot s^{-2}}[/tex]) on average.
Explanation:
Acceleration is the rate of change in velocity.
For the ball in this question:
Initial velocity: [tex]u = 12\; {\rm m\cdot s^{-1}}[/tex].Final velocity: [tex]v = 0\; {\rm m\cdot s^{-1}}[/tex] since the ball has stopped.Time required: [tex]\Delta t = 36\; {\rm s}[/tex].Subtract the initial velocity [tex]u[/tex] from the final velocity [tex]v[/tex] to find the change in velocity:
[tex]\begin{aligned}(\text{change in velocity}) &= (\text{final velocity}) - (\text{initial velocity}) \end{aligned}[/tex].
[tex]\begin{aligned}\Delta v &= v - u \\ &= 0\; {\rm m\cdot s^{-1}} - 12\; {\rm m\cdot s^{-1}} \\ &= (-12)\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].
(Note that the change in velocity is negative because the final velocity [tex]v = 0\; {\rm m \cdot s^{-1}}[/tex] is more negative than the initial velocity [tex]u = 12\; {\rm m\cdot s^{-1}}[/tex].)
To find the average acceleration [tex]a[/tex] (average rate of change in velocity,) divide the change in velocity [tex]\Delta v[/tex] by the time [tex]\Delta t[/tex] required to achieve such change:
[tex]\begin{aligned}(\text{average acceleration}) &= \frac{(\text{velocity change})}{(\text{time required for change})}\end{aligned}[/tex].
[tex]\begin{aligned} a &= \frac{\Delta v}{\Delta t} \\ &= \frac{(-12)\; {\rm m\cdot s^{-1}}}{36\; {\rm m\cdot s^{-1}}} \\ &\approx (-0.33) \; {\rm m\cdot s^{-2}}\end{aligned}[/tex].
(Average acceleration is negative since velocity is becoming less positive.)
module 2 question 2
Find the components of vtot along the x and y axes in Figure 3.25, where = 25.0° and vtot = 6.00 m/s.
vtot, x =
what is x? I've seen others put 4.41 but it is wrong.
m/s
vtot, y = 5.07
The x and y component of [tex]V_{tot}[/tex] where θ = 25° and [tex]V_{tot}[/tex] = 6 m / s are 4.68 m / s and 3.72 m / s respectively.
Resolving [tex]V_{tot}[/tex] into its x and y components,
sin θ = [tex]V_{tot,y}[/tex] / [tex]V_{tot}[/tex]
sin 51.5° = [tex]V_{tot,y}[/tex] / 6
[tex]V_{tot,y}[/tex] = 4.68 m / s
cos θ = [tex]V_{tot,x}[/tex] / [tex]V_{tot}[/tex]
cos 51.5° = [tex]V_{tot,x}[/tex] / 6
[tex]V_{tot,x}[/tex] = 3.72 m / s
These are called as trigonometric ratios. Some of the basic formulae are:
sin θ = Opposite side / Hypotenusecos θ = Adjacent side / Hypotenusetan θ = Opposite side/ Adjacent sideTherefore, the x and y component of [tex]V_{tot}[/tex] are 4.68 m / s and 3.72 m / s respectively.
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When a car brakes hard and skids, the maximum deceleration is 3.1m/s^2. The coefficient of friction between the tires and the road is ___.
When a car brakes hard and skids, the maximum deceleration is 3.1m/s^2. The coefficient of friction between the tires and the road is [tex]\mu=0.61[/tex].
This is further explained below.
What is the coefficient of friction?Let us assume that the mass of the vehicle is m, and that the coefficient of friction between the tires and the road is mu.
We have determined this by using Newton's second rule of motion.
f=m a
[tex]\mu[/tex]m g=m a
[tex]&\mu=\frac{a}{g}[/tex]
[tex]&a=6 \mathrm{~m} / \mathrm{s}^2 \\\\&g=9.8 \mathrm{~m} / \mathrm{s}^2 \\[/tex]
Therefore
[tex]\mu=\frac{6}{9.8}[/tex]
[tex]\mu=0.61[/tex]
In conclusion,0.61 is the value of the coefficient of friction that exists between the tires and the vehicle.
[tex]\mu=0.61[/tex]
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Pupiletras los diptongos
A 55.0-kg person steps on a scale which is on a horizontal floor. What is the normal force acting on the individual by the scale?
ANSWER:
-539 N
STEP-BY-STEP EXPLANATION:
We know that the normal force is the force opposite to the force exerted by the weight, therefore, we can calculate the normal force as follows:
[tex]\begin{gathered} F_N=-W \\ W=m\cdot g \\ F_N=-m\cdot g \\ \text{ replacing:} \\ F_N=-55\cdot9.8 \\ F_N=-539\text{ N} \end{gathered}[/tex]The normal force is -539 N
1.) Describe the process you would use to find the magnitude (length) of the resultant of two perpendicular vectors, one in the x-direction, and another in the y-direction.
Pythagorean theorem is the process use to find the magnitude of the resultant of two perpendicular vectors.
The Pythagorean Theorem is used to calculate the steepness of slopes of hills or mountains. A surveyor appears via a telescope in the direction of a measuring stick a fixed distance away, so that the telescope's line of sight and the measuring stick form a right angle.
It allows to explain the space round us and is important no longer only in construction however suitably tailored in equations of thermodynamics and preferred relativity.
The Pythagorean Theorem is useful for two-dimensional navigation. you may use it and two lengths to discover the shortest distance. The distances north and west will be the two legs of the triangle, and the shortest line connecting them might be the diagonal. The same ideas may be used for air navigation.
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velocity of a body of mass 20kg decreases from 20m/s to 5m/s in a distance of 100m . force on the body is
The force on the body of 20 kg mass is F = 11.2 N
Equation :To calculate the force of the body use the formula
F = ma
Where,
F is force
m is mass
a is acceleration
Given data are :
m = 20 kg
a = ?
v = 20 m/s
u = 5 m/s
s = 100 m
So, as we have the values of initial velocity, (u), final velocity, v and distance s. First we need to calculate acceleration
Use formula for equation of motion,
v² = u² + 2as
(20 m/s)² = (5 m/s)² + 2 x a x 100 m
400 m/s = 25 m/s + 200 m a
a = 225 m/s / 400 m/s
a = 0.56 m/s²
Now, we have the acceleration.
Calculating force by formula given above;
F = ma
F = 20kg x 0.56 m/s²
F = 11.2 N
Hence, the force on the body of 20 kg mass is F = 11.2 N
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Calculate the percentage error in a steel tape used for measurement on a cold day when the temperature is -5 ℃ if it was calibrated at 20 ℃. [αsteel=1.1×10-5 ℃-1]
The percentage error in a steel tape used for measurement on a cold day when the temperature is -5 ℃ is - 0.028
Coefficient of linear thermal expansion for steel, α = 1.1 * [tex]10^{-5}[/tex] / C
Let the length of the tape at 20 ℃ be L.
New length of the steel tape after cooling, L' = L ( 1 + α ΔT )
ΔL = L' - L
ΔL = L ( 1 + α ΔT ) - L
ΔL = L ( 1 + α ΔT - 1 )
ΔL = L α ΔT
ΔT = T - [tex]T_{0}[/tex]
T = Final temperature
[tex]T_{0}[/tex] = Initial temperature
ΔT = - 5 - 20
ΔT = - 25 ℃
ΔL = L * 1.1 * [tex]10^{-5}[/tex] * ( - 25 )
ΔL = - 27.5 * [tex]10^{-5}[/tex] * L
Percentage error = ΔL / L * 100
Percentage error = - 27.5 * [tex]10^{-5}[/tex] * L / L * 100
Percentage error = - 0.028
Therefore, the percentage error in the steel tape is - 0.028
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Explain the difference
between the 4 states of
matter in terms of shape,
volume, forces, molecular
movement
In states of matter, Solid has definite shape and volume, liquid has no shape but have definite volume, gas and plasma has no shape as well as no volume.
What are the difference between different states of matter?A solid has a definite shape and volume, liquid has a definite volume, but has no specific shape. A gas has no defined shape or has no volume. Plasma is similar to a gas but a gas is neutral whereas plasma has a charge. Solids and liquids have a definite volume. Gases and plasma have no definite volume. The force of attraction between the molecules of solid is maximum, less in liquid, least in gases and very less in plasma. Gas vibrate and move freely at very high speeds. liquid vibrate and slide past each other. Solid vibrate but do not move from place to place.
So we can conclude that solid has shape and volume, liquid has volume but no shape, gas and plasma has no shape and no volume.
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Angle of incidence is 70 degrees what is the relection and refraction ray
The angle of incidence = 35°.
The normal divides the angle between the incident and reflected rays into two equal angles. The angle between the incident ray and the normal is called the angle of incidence. The angle between the reflected ray and the normal is called the reflection angle. When a ray of light approaches a smooth and polished surface and bounces off it, it is called a light reflection.
An incident ray striking a surface is reflected by the surface. A reflected ray is called a reflected ray. The difference between light reflection and refraction is simple. In reflection, a ray hitting a plane returns to its original source/medium as the wave bounces off the surface. However, when refracted, the wave passes through the surface, changing its speed and direction.
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What is momentum?.
.
.
.
The quantity of motion of a moving body, measured as a product of its mass and velocity.
What is velocity?The primary indicator of an object's position and speed is its velocity. It is the distance that an object travels in one unit of time. The displacement of the item in one unit of time is the definition of velocity.velocity is a term that describes the speed and direction of a point's motion.Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path.To learn more about : Velocity
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Q: Compare and contrast the different parts of the Electromagnetic Spectrum. Evaluate the usefulness of each part and decide which part is most useful, or most important, to you and society as a whole. You must provide two reliable sources to back up your opinion. Recall that reliable sources include scientific sites or publications, education sites or publications, and government sites or publications.
The purpose of this assignment is to debate and consider different opinions on this topic. There is no right or wrong answer. However, this discussion should represent varying opinions. You will need to do some research and back up your opinions with facts. Remember to cite your sources!
A: The different parts of the electromagnetic spectrum are ultraviolet lights, infrared lights, x-rays, gamma rays, and radio waves. All of these colors are called the electromagnetic spectrum. Each of these parts have different energy levels, wavelengths, and frequencies. According to scied.ucar,edu, Gamma rays have the highest energies and radio waves have the lowest. As imagine.gsfc.nasa.gov states, a comparison of all of the parts is that their radiations are defined by the amount of energy found in the photons. They will still have different energies but they all use photons. Usefulness for Radio: It captures radio waves emitted by radio station which makes our favorite tunes. Microwave: cooks popcorn in a few mins. Infrared: night vision goggles use this light. Helps us map dust between stars. Visible: Our eyes detect visible light. Fireflies, light bulbs, and stars all emit visible light. Ultraviolet:Emitted by sun and reason why skin tans and burns. X-ray:Dentist uses to view teeth, airport security to see through your bag, used to see inside things. Gamma ray: Doctors use it to image inside your body. I think the most important would be the visible ones because those are the ones everyone uses no matter what. If there was no light we wouldn't see. We can see light with our vision.
The infrared and ultraviolet parts of the electromagnetic spectrum can be used in the field of chemical analysis.
The sections of the EM spectrum are named in order of increasing energy gamma rays X-rays ultraviolet-visible light infrared, and radio waves. Microwaves used in microwave ovens are a subsection of the radio segment of the EM spectrum.
Electromagnetic energy travels in waves and covers a wide spectrum from very long radio waves to very short gamma rays. The human eye can only see a small portion of this spectrum known as visible light. The electromagnetic spectrum includes all frequencies of electromagnetic radiation that carry energy and travel through space in the form of waves. Low frequencies and long wavelengths make up the radio spectrum.
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A projectile is fired from the edge of a cliff 200.0 m high with an initial speed of 30.0 m/s at an angle of 45° above the horizontal.
Determine the maximum horizontal range.
The maximum horizontal range of the projectile is 91.8 m.
What is maximum horizontal range of a projectile?
The maximum horizontal range of a projectile is the maximum horizontal distance travelled by the projectile.
Mathematically, the horizontal range of a projectile is given as;
R = u² sin(2θ) / g
where;
u is the initial velocity of the projectileθ is the angle of projection of the projectileg is acceleration due to gravityR is the range of the projectileR = (30² x sin(2 x 45))/9.8
R = 91.8 m
Thus, we can conclude that the maximum horizontal distance travelled by the projectile occurs when the angle of projection is 45 degrees.
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Assume that when we go to Mars, we discover that there is a previously unknown planet between Mars and Jupiter. The newly found planet is 2.5 Astronomic Units (A.U.) from the Sun.
What is the period around the Sun of the new Planet?
The period of the revolution as obtained from the question is 3.95 years.
What is the solar system?We know that the solar system is composed of the sun and the planets. The sun is at the center of the solar system and the sun is surrounded by the planets which tend to form concentric circles.
From the Kepler's laws, we can see that the square of the period is directly proportional to the cube of the radius of the planet;
Hence;
T^2 α r^3
T = period
r = distance
T = r^3/3
T = (2.5)^3/2
T = 3.95 years
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1. Which of the following statement(s) are true about the atoms of any element?
A. The number of protons in an atom of an element is unique to each element.
B. The number of protons and neutrons in an atom of an element is unique to each element.
C. A proton is an atom of one element that is identical to a proton in an atom of another element.
D. The number of protons in an atom of an element is the same for all elements.
2. Which of the following statements explains why atoms are always neutral in charge
A. They have the same number of protons as the atoms of all other elements.
B. They have protons that are identical to the protons of all other elements.
C. They have the same size as the atoms of all other elements.
D. They have the same number of protons as electrons.
3. What is the atomic number of an atom? Why is this number important?
4. Where are the electrons in an atom located?
5. Where are the neutrons in an atom located?
6. Where are the protons in an atom located?
7. What is the relationship between protons and elements?
8. Compare and contrast electrons, neutrons, and protons.
The answers include the following:
The number of protons in an atom of an element is the same for all elements is the true statement about atoms of other elements and is denoted as option B.They have the same number of protons as electrons explains why atoms are always neutral in charge and is denoted as option D.Atomic number is the charge number on an atomic nucleus and it is important because it helps in identifying elements.The electrons in an atom is located in the outermost shell.The neutrons in an atom is located inside the nucleus.The protons in an atom is located inside the nucleus.The relationship between protons and elements is that they are equal and the same.Electrons, protons and neutrons are subatomic particles in which electron is negatively charged, protons is positively charged and neutrons is neutral.What is an Atom?This is referred to as the smallest unit of a chemical element and has subatomic particles such as proton, neutron etc.
The electron is negatively charged, protons is positively charged and neutrons is neutral.
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Mario drives his Kart at an average speed of 42 miles per hour for 1.7 minutes. How far does he drive? Include units in your answer. More information.Note: For this question and all questions on subsequent WebAssignments, answers to problems should have three significant digits and should include proper units.
Given:
The speed of Mario's kart is
[tex]v=42\text{ miles/h}[/tex]To find:
How far does he drive in 1.7 minutes?
Explanation:
The speed is,
[tex]\begin{gathered} v=42\text{ miles/h} \\ =42\times1.6\text{ km/h} \end{gathered}[/tex]The distance Mario drives is,
[tex]\begin{gathered} d=vt \\ =42\times1.6\times\frac{1.7}{60}\text{ km} \\ =1.90\text{ km} \end{gathered}[/tex]Hence, the required distance is 1.90 km.
what does a closed circuit need to work?
Answer:
Explanation what does a closed circuit need to work?
Closed Circuit: In a closed circuit, the connected source and load form a closed-loop path. We need a switch to make (ON) and break (OFF) the circuit for the electrical and electronic circuits to work (open circuit and closed circuit).
Help number five physics In the three diagrams, the circles represent small balls that carry electric charges. In Diagram A, ball 1 carries a negative charge, and ball 2 is repelled byball 1. In Diagram B, we see that ball 2 now repels ball 3. In Diagram C, we see that ball 3 now attracts ball 4. Based on these diagrams, what is theelectric charge on ball 4?
Question 5
Given:
Ball 1 has negative charge.
Ball 2 is repelled by ball 1.
Ball 2 repels ball 3.
Ball 3 attracts ball 4.
To find the electric charge on ball 4.
Explanation:
Like charges repel each other.
Example - Positive and positive charge repel each other.
Also, negative and negative charge repel each other.
Unlike charges attract each other.
Positive and negative charge attract each other.
In the first diagram, ball 1 and ball 2 repel each other which means ball 2 has negative charge.
In the second diagram, ball 2 and ball 3 repel each other which means ball 3 has negative charge.
Now, in the diagram 3, ball 3 and ball 4 attract each other which means ball 4 has positive charge.
Thus, ball 4 has positive charge.
a 10 kg block of ice slide down the ramp 20 m long. inclined at 10 degrees to the horizontal.
if the ramp is frictionless what is the acceleration of the block of ice
if the coefficient of friction is 0.10 how long will it take the block to slide down the ramp if it starts from rest
At the given coefficient of friction of the ramp, the acceleration is 0.97 m/s².
The time taken for the block to travel down the ramp is 6.42 s.
What is the acceleration of the block?The acceleration of the block is calculated as follows;
Apply Newton's second law of motion to determine the acceleration of the block.
μmgcos(θ) = ma
μgcos(θ) = a
where;
μ is coefficient of frictiong is acceleration due to gravityθ is the angle of inclination of the planea = (0.1)(9.8) cos(10)
a = 0.97 m/s²
The time taken for the block to travel down the inclined plane is calculated as follows;
s = vt + ¹/₂at²
where;
v is the initial velocity = 0s is the length of the ramp20 = 0 + ¹/₂(0.97)t²
40 = 0.97t²
t² = 40/0.97
t² = 41.24
t = √41.24
t = 6.42 seconds
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What is the relationship of the force on the spring and stretch of the spring? (I have a picture of a spring that weights can be added to) as seen
Given data:
The mass of the first weight is
[tex]m_1=250\text{ g}[/tex]second
[tex]m_2=100\text{ g}[/tex]The mass of the third weight is
[tex]m_3=100\text{ g}[/tex]The mass of the fourth weight is
[tex]m_4=50\text{ g}[/tex]The force on the spring can be expressed as,
[tex]F=mg[/tex]Here, g is the acceleration due to gravity which is considered as a constant value.
The force on the spring depends on the mass of each weight. Higher is the weight then more will be the force on each spring.
,
The mass relation for each weight can be given as:
The relationship between the forces acts on the spring can be given as,
[tex]F1>F_2=F_3>F_4[/tex]Here, suffixes (1,2,3, and 4) numbers related to the first, second, third, and fourth weights.Thus, the relationship of the force on the spring is
[tex]F_1>F_2=F_3>F_4[/tex][tex]\begin{gathered} F=kx \\ x=\frac{F}{k} \end{gathered}[/tex]Here, x is the stretch of the spring and k is the spring constant.
The stretch of the spring depends on the force of the spring.
The stretch of the spring relationship for the given weights can be given as:
[tex]x_1>x_2=x_3>x_4[/tex]Thus, the relationship of the stretch of the spring is
[tex]x_1>x_2=x_3>x_4[/tex]