12.5 mL of 0.280 M HNO3 and 5.0 mL of 0.920 M KOH are mixed. Is the resulting solution acidic, basic or neutral?

Answers

Answer 1

Answer:

The resulting solution is basic.

Explanation:

The reaction that takes place is:

HNO₃ + KOH → KNO₃ + H₂O

First we calculate the added moles of HNO₃ and KOH:

HNO₃ ⇒ 12.5 mL * 0.280 M = 3.5 mmol HNO₃KOH ⇒ 5.0 mL * 0.920 M = 4.6 mmol KOH

As there are more KOH moles than HNO₃, the resulting solution is basic.

Answer 2

The resulting solution is basic.

• It is known that KOH is a base and HNO3 is an acid, so when they mix they undergo a neutralization reaction.  

• The reaction between there will be,  

HNO3 + KOH ⇔ KNO3 + H2O

Based on the given information,

• The volume of HNO3 is 12.5 ml and the molarity is 0.280 M, and the volume of KOH is 5 ml and the molarity is 0.920 M.

Now 1 mole of HNO3 completely reacts with 1 mole of KOH,

The millimoles of HNO3 is,

[tex]= Molarity * Volume (in ml)\\= 0.280 * 12.5\\= 3.5 mmol[/tex]

The millimoles of KOH is,

[tex]= Molarity * Volume (in ml)\\= 0.920 * 5.0\\= 4.6 mmol[/tex]

Now it can be seen that 3.5 millimoles of HNO3 completely reacts with 3.5 millimoles of KOH. Now we are left with 4.6-3.5 = 1.1 mmol of KOH.

Thus, KOH is in excess amount present in the solution, and as it is basic in nature, therefore, the resultant solution would be basic in nature.

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Related Questions

How often waves repeat is called their

Answers

Answer:

Wave Frequency

Wave frequency is the correct answer

What is the reason for the trend in Atomic Radii? Select all that apply.
A. number of valence electrons.
B. number of neutrons in the nucleus
C. number of protons in the nucleus
D. larger atomic mass number
E. number of energy levels around the nucleus​

Answers

A and E, hope this helped

What is percent error calculation used to determine

Answers

Determining precision for your calculations after you have made calculations for known values.

If 17.8 g grams of lithium (Li) are combined with 50.0 grams of water (H20) there is
24.7 grams of hydrogen gas (H2) produced. How much lithium hydroxide (LiOH) was
also produced?

Answers

Answer:

Explanation:

Li+H2O..................LiOH+H2

mass of Li=17.8 g

No of moles of Li=17.8/7=2.5

mass of H2O=50.0 g

No of moles of H2O=50.0/18=2.8

limiting reagent is Li so 1 mole of Li produce 1 mole of LiOH therefore 2.5 mole of Li produce 2.5 moles of LiOH now we have to convert it into grams

moles=given mass/molar mass

given mass=moles*molar mass

molar mass of LiOH=24

mass=2.5*24=60 gram

Which of the following is an example of a physical change?
А.
sugar and oxygen reacting to produce water and carbon dioxide
B
honey dissolving in tea
С
a raw egg being cooked
D
metal rusting after being left out in the rain

Answers

Answer:

B. honey dissolving in tea

Explanation:

Yep the answer is B :)))

IMESSAGE GAMES ANYONE?

Answers

lollllllllllllllllllll

Answer:

oop whats dis

Explanation:

What may form when magma comes to the surface?

Answers

Answer

When magma reaches the surface it is called lava. After lava has cooled it forms solid rock.

Answer:

Volcano

Explanation:

when magma reaches the surface it cools and then magma  will start coming out over and over and over again. Then we have a volcano. hopemthis helps

What is the balanced NET ionic equation for the reaction when aqueous Cs₃PO₄ and aqueous AgNO₃ are mixed in solution to form solid Ag₃PO₄ and aqueous CsNO₃

Answers

Answer:

[tex]PO_4^{3-}(aq)+3Ag^+(aq)\rightarrow Ag_3PO_4(s)[/tex]

Explanation:

Hello!

In this case, since the net ionic equation of a chemical reaction shows up the ionic species that result from the simplification of the spectator ions, which are those at both reactants and products sides, we take into account that aqueous species ionize into ions whereas liquid, solid and gas species remain unionized. In such a way, for the reaction of cesium phosphate and silver nitrate we can write the complete molecular equation:

[tex]Cs_3PO_4(aq)+3AgNO_3(aq)\rightarrow Ag_3PO_4(s)+3CsNO_3(aq)[/tex]

Whereas the three aqueous salts are ionized in order to write the following complete ionic equation:

[tex]3Cs^+(aq)+PO_4^{3-}(aq)+3Ag^+(aq)+3NO_3^-(aq)\rightarrow Ag_3PO_4(s)+3Cs^+(aq)+3NO_3^-(aq)[/tex]

In such a way, since the cesium and nitrate ions are the spectator ions because of the aforementioned, the net ionic equation turns out:

[tex]PO_4^{3-}(aq)+3Ag^+(aq)\rightarrow Ag_3PO_4(s)[/tex]

Best regards!

One mole of an ideal gas expands reversibly and isothermally from 10. bar to 1.0 bar at 298.15K.

Required:
a. Calculate the values of w, q, âU and âH?
b. Calculate w if the gas were to have expanded to the same final state against a constant pressure of 1 bar.

Answers

Answer:

a. W = 5,708 J, Q = 5,708 J, ΔU = 0 and ΔH = 0.

b. 2,231 J.

Explanation:

Hello!

a. In this case, since this is an isothermal process (constant temperature) it is possible to infer that the work is computed as shown below:

[tex]W=nRTln(\frac{p_1}{p_2} )=1mol*8.314\frac{J}{mol*K}*298.15Kln(\frac{10.bar}{1.0bar} )\\\\W=5708J[/tex]

Now, since this is an isothermal process we know by definition ΔU = 0 and ΔH = 0, therefore the involved heat is:

[tex]Q-W=0\\\\Q=W=5708J[/tex]

b. In this case, since the process is isobaric but goes to the same final volume in part a, we can compute the initial and final volume based on the part a's conditions by using the ideal gas equation:

[tex]V_1=\frac{nRT}{p_1} =\frac{1mol*0.083145\frac{*L}{mol*K}*298.15K}{10.bar} =2.48L\\\\V_2=\frac{nRT}{p_2} =\frac{1mol*0.083145\frac{*L}{mol*K}*298.15K}{1.bar} =24.8L[/tex]

Thus, the work done here is:

[tex]W=p(V_2-V_1)=1bar(24.8L-2.48L)=22.3bar*L*\frac{1x10^5Pa}{1bar} *\frac{1m^3}{1000L} \\\\W=2231J[/tex]

Best regards!

A student masses a green crystal sample and records 1.253 grams. He then dissolves the green crystal in water and does a titration, and calculates that his sample has 7.35x10-3 moles of C2O4-2.

What is the percent of C2O4-2 in the sample?
a. not enough information is given
b. 51.63%
c. 129%
d. 0.5866%
e. 20.62%

Answers

Answer:

b. 51.63%

Explanation:

Step 1: Given data

Mass of the sample: 1.253 gMoles of oxalate (C₂O₄²⁻): 7.35 × 10⁻³ mol

Step 2: Calculate the mass corresponding to 7.35 × 10⁻³ moles of oxalate

The molar mass of C₂O₄²⁻ is 88.02 g/mol.

7.35 × 10⁻³ mol × 88.02 g/mol = 0.647 g

Step 3: Calculate the mass percent of oxalate in the sample

% w/w = mass of oxalate / mass of the sample × 100%

% w/w = 0.647 g / 1.253 g × 100%

% w/w = 51.63%

pretty please help me (:

Answers

Okay I need an explanation from YOU. when is this due? If it’s last minute, why didn’t you do it when you had time? This is very irresponsible, unless you have a personal reason. Please quit commenting on others just for the points. I helped you with one, because I thought it was just one question you needed help with. No one is going to finish this for you. I’m sorry but it’s the truth, everyone here needs help. No one is here TO help. So please be cooperative and try to learn. Of course, I’m sorry if it is for a very personal reason as it happens to everyone where you need the work ASAP because of a reason. Hopefully, it’s not because you were lazy. Appreciate your education as not many people in the world have it.

.What is the effective number of bonds between the sulfur atom and each oxygen atom in the sulfate ion

Answers

Answer:

The effective number of bonds in sulfate ion is 1.5

Explanation:

The number of chemical bonds between two atoms is known as the bond order.

In covalent bonds between two atoms, a single bond has a bond order of one, a double bond has a bond order of two, a triple bond has a bond order of three.

If there are more than two atoms in a molecule, the effective number of bonds can be determined by applying the following steps:

1. Draw the Lewis structure.

2. Count the total number of bonds.

3. Count the number of bond groups between individual atoms.

4. Divide the number of bonds between atoms by the total number of bond groups in the molecule.

For the sulfate ion, the resonance structure is shown in the attachment below. From the structure;

Total number of bonds = (2 × 2) + (2 × 1) = 6

Total number of bond groups = 4

Effective number of bonds = 6/4 = 1.5

Therefore, the effective number of bonds in sulfate ion is 1.5

What is the main goal of cloning? A. To make living things that have identical DNA
B. To improve the process of asexual reproduction
C. To add medicines to the foods that people eat
D. To spread genes from transgenic plants to wild plants​

Answers

Answer:

A

Explanation:

A p e x

A covalent bond is formed by:

loss of electrons between atoms
sharing of electrons between atoms
gain of electrons between atoms
valence electron shells overlaping, forming a "sea of electrons"

Answers

Answer:

sharing of electrons between atoms

How much energy, in kilojoules, must you add to 3.00 quarts of olive oil to warm it from 23.0 °C to 100.0 °C? The specific heat of olive oil is 0.1.79 J/g·°C and its density is 0.916 g/mL

Answers

Answer:

3.58*10^-4kJ

Explanation:

Given

T1=23.0 °C

T2=100.0 °C

c=1.79 J/g·°C

Volume of olive =3 quarts

Converting to liter

1 quart =0.946353 L

3 quarts=x

Cross multiplying

x=0.946353*3

x=2.83L

To mL= 0.0028mL

We are given the density as 0.916 g/mL

Mass= density *volume

Mass= 0.916*0.0028

Mass=0.0026g

We know that the quantity of heat is expressed as

Q=mcΔT

Q=0.0026*1.79(23-100)

Q=0.004654*(77)

Q=0.358J

In kJ we divide 0.36 by 1000

=0.000358358

=3.58*10^-4kJ

13. As heat is added to a lúguid that is boiling at constant
pressure, the temperature of the liquid
A) decreases B) increases
C) remains the same
A
B

Answers

Tbh I would pick A because the liquid* decreases. B doesn’t increase

Pleaseeee help I’m stuck on this problem


What is the mole fraction of KCI in a
mixture of 0.564 g NaCl, 1.52 g KCI,
and 0.857 g LICI?

Answers

Answer:

0.4

Explanation:

Given parameters:

Mass of NaCl  = 0.564g

Mass of KCl  = 1.52g

Mass of LiCl = 0.857g

Unknown:

Mole fraction of KCl = ?

Solution:

First, find the number of moles of the given species;

     Number of moles  = [tex]\frac{mass}{molar mass}[/tex]

Molar mass of KCl  = 39 + 35.5 = 74.5g/mol

Molar mass of NaCl  = 23 + 35.5 = 58.5g/mol

Molar mass of LiCl  =  7 + 35.5  = 42.5g/mol

  Number of moles of KCl  = [tex]\frac{1.52}{74.5}[/tex]   = 0.02mol

  Number of moles of NaCl  = [tex]\frac{0.564}{58.5}[/tex]   = 0.0096mol

  Number of moles of LiCl  = [tex]\frac{0.857}{42.5}[/tex]   = 0.02mol

Sum of moles  = 0.02mol + 0.0096mol + 0.02mol  = 0.0496mol  

Mole fraction of KCl  = [tex]\frac{0.02}{0.0496}[/tex]   = 0.4

Answer:

.4

Explanation:

If a liquid is said to have high viscosity it is...

Answers

Answer:

Viscosity is the measure of resistance of a fluid to flow. A fluid that is highly viscous has a high resistance (like having more friction) and flows slower than a low-viscosity fluid. To think of viscosity in everyday terms, the easier a fluid moves, the lower the viscosity

Explanation:

Question 2
The higher the energy, the higher or lower the wavelength? This is an example of a/an direct or inverse relationship?

Answers

Answer:

the higher the energy tje lower the wavelength

Explanation:

inverse relationship

Answer:

It's an example of an inverse relationship :)

Which substance has the most thermal energy and will have the most heat flow from it?

A. a stovetop burner on medium (200°C)
B. a nuclear reactor core (1000°C)
C. the human body (36°C)
D. air at room temperature (32°C)

Answers

Answer:

B. a nuclear reactor core (1000°C)......

B. A nuclear reactor corw

A 50.0 mL sample of HCl required 25.81 mL of 0.1250 M KOH for neutralization. What is the molarity of the acid?

Answers

Answer:

0.065M

Explanation:

The reaction expression is given as:

         HCl   +   KOH  →  KCl + H₂O

Given parameters:

Volume of KOH  = 25.81mL  = 0.02581L

Molarity of KOH = 0.125M

Volume of HCl  = 50mL  = 0.05L

Unknown:

Molarity of the acid  = ?

Solution:

To find the molarity of the acid, HCl, let us use the mole concept.

  First, find the number of moles of the base, KOH;

Number of moles of KOH = molarity of KOH x volume of KOH

   Number of moles of KOH  = 0.125 x 0.0258 = 0.003225mol

From the balanced reaction equation:

   1 mole of KOH reacted with 1 mole of HCl

   0.003225mol of KOH will react with 0.003255mole of HCl

Molarity of HCl  = [tex]\frac{number of moles of HCl}{Volume of HCl}[/tex]

Molarity of HCl  = [tex]\frac{0.003255}{0.05}[/tex]   = 0.065M

A 10.00 mL sample of a 1.07 M solution of potassium hydrogen phthalate (KHP, formula mass = 204.22 g/mol) is diluted to 250.0 mL. What is the molarity of the final solution?

Answers

Answer:

[KHP] = 0.0428M

Explanation:

2 methods to calculate concentration after dilution

1. Use dilution equation

Molarity of concentrate (M₁) x Volume of Concentrate (V₁)

           =    Molarity of dilute (M₂) x Volume of dilute (V₂)

M₁ x V₁ = M₂ x V₂ => M₂ = M₁ x V₁ / V₂ = (1.07M)(10ml)/(250ml) = 0.0428M

2. Concentration Equation

moles KHPh = Molarity (M)  x  Volume (V) = 1.07M x 0.010L =0.0107 moles KHP

Concentration KHP = moles solute / volume of solution in Liters

= 0.0107 moles KHP / 0.25L = 0.0428M

The molarity of 10.00 mL sample of a 1.07 M solution of potassium hydrogen phthalate diluted to 250.0mL is 0.0428M.

HOW TO CALCULATE MOLARITY:

The molarity of a diluted solution can be calculated by using the following formula:

C1V1 = C2V2

Where;

C1 = initial concentration of solutionC2 = final concentration of solutionV1 = initial volume of solutionV2 = final volume of solution

According to this question,

C1 = 1.07MC2 = ?V1 = 10.0mLV2 = 250mL

1.07 × 10 = C2 × 250

10.7 = 250C2

C2 = 10.7 ÷ 250

C2 = 0.0428M

Therefore, the molarity of 10.00 mL sample of a 1.07 M solution of potassium hydrogen phthalate diluted to 250.0mL is 0.0428M.

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How many atoms of hydrogen would need to bond with a single atom of selenium to form a molecular compound?​

Answers

Answer:

Hydrogen sulfide reacts with aqueous selenous acid to produce selenium disulfide:

H2SeO3 + 2 H2S → SeS2 + 3 H2O

Selenium disulfide consists of 8-membered rings. It has an approximate composition of SeS2, with individual rings varying in composition, such as Se4S4 and Se2S6. Selenium disulfide has been used in shampoo as an antidandruff agent, an inhibitor in polymer chemistry, a glass dye, and a reducing agent in fireworks.[15]

Selenium trioxide may be synthesized by dehydrating selenic acid, H2SeO4, which is itself produced by the oxidation of selenium dioxide with hydrogen peroxide:[17]

SeO2 + H2O2 → H2SeO4

Hot, concentrated selenic acid can react with gold to form gold(III) selenate.[18]

The reference point in motion is:
A. The point in space and time at which the motion ended
B. The point in space and time at which the motion began
C. The focal point
D. The origin

Answers

Answer: the focal point

Convert from 1.56×1030 particles of sodium chloride (NaCl) to grams of sodium chloride.

Answers

Answer:

15.14×10⁷ g

Explanation:

Given data:

Number of particles of NaCl = 1.56×10³⁰ particles

Mass of sodium chloride = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ particles

1.56×10³⁰ particles × 1 mol / 6.022 × 10²³ particles

0.259 ×10⁷ mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.259 ×10⁷ mol × 58.44 g/mol

Mass = 15.14×10⁷ g

Question 1 Give the correct number of significant figures for 4500, 4500., 0.0032, 0.04050
Question 2 Give the answer to the correct number of significant figures:
4503 + 34.90 + 550 = ?
the correct number of significant figures.
uction 2 Give

Answers

Answer:

Question 2

5087.9 or 5088

Calculate the amount of grams of water that was used when 5525J of energy was used to boil this amount of water.

Answers

Answer:

2.445 g

Explanation:

Step 1: Given and required data

Energy in the form of heat required to boil the water (Q): 5525 JLatent heat of vaporization of water (∆H°vap): 2260 J/gMass of water (m): ?

Step 2: Calculate the mass of water

We will use the following expression.

Q = ∆H°vap × m

m = Q / ∆H°vap

m = 5525 J / (2260 J/g)

m = 2.445 g

How many grams of KOH are required to prepare 500. mL of 0.450 KOH solution?

Answers

Answer:

KOH  molar mass = 39 + 16 + 1 = 56g

To make 1 L of 1M soln needs 56g KOH

To make 500mL 1M needs 56/2 = 28g

To make 500mL 0.2M needs 28 x 0.2gn:

If 8.2 mL of 0.055 M NaOH is required to titrate a 5.5 mL sample of potassium bitartrate, what is the [K +]?

Answers

Answer:

.082 M

Explanation:

You just do C1V1=C2V2

The concentration of the potassium bitartrate acid is determined as 0.082 M.

Concentration of the acid

The concentration of the potassium bitartrate acid is calculated as follows;

C1V1 = C2V2

where;

C1 is the concentration of the base = 0.055V1 is the volume of the base = 8.2 mlC2 is the concentration of the acidV2 is the volume of the acid = 5.5 ml

C2 = (C1V1)/(V2)

C2 = (0.055 x 8.2)/(5.5)

C2 = 0.082

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#SPJ2

Which property (volume , mass , or density) is a measure of the space it takes up?

Answers

Answer:

mass

Explanation:

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