Answer:
127160224
or use a calculator
For each relation, decide whether or not it is a function.
Relation 1: Yes, each input corresponds to only one output.
Relation 2: No, the input of -1 corresponds to two outputs: sun and moon.
Relation 3: Yes, each input corresponds to only one output.
Relation 4: Yes, each input corresponds to only one output.
What is the slope of a line that passes the points (-1,4 ) and ( 3,9 ) ?
Answer:
slope = 5/4
Step-by-step explanation:
What is the slope of a line that passes the points (-1,4 ) and ( 3,9 ) ?
slope = change in y ÷ change in x
slope = (9-4) ÷ (3 - (-1))
slope = 5/4
8. Find the slope between (-5, 4) & (0,3). * O m = 1/5 O O m = -5 m = 5 O m = -1/5
We can determine the slope using the following expression:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Now, using the two points given, we have:
[tex]m=\frac{3-4}{0-(-5)}\Rightarrow m=-\frac{1}{5}[/tex]From this, we have that the slope(m) equals -1/5.
1)EF=JHFEG = HJGXProve FEG = HJGStatement1) EF = JHReason1) given2)2) given3) Vertical angles are conguent3)4)4)Theorem
2.
[tex]\angle FEG\cong\angle HJG[/tex]3.
[tex]\angle HGJ\cong\angle EGF[/tex]The tables of ordered pairs represent some points on the graphs of lines q and v. Line 9 Line v Х -9 -3 2. Х 0 10 у 0 18 33 у 10 8 3 Which system of equations is represented by lines q and v? F 21x - y = 9 5x + 6y = 40 G 3x - y = -27 x + 2y = 16 H 21x - y = 9 5x - 6y = 20 3 9x - y = -27 x + 2y = 8
One of the forms we can write the equation of a line is like this:
y - y1 = m(x - x1)
Where (x1, y1) is a point where the line passes through, and the value of m, the slope of a line is given by the following formula:
[tex]m=\frac{y2-y1}{x2-x1}[/tex]Then, for the first line (line q), we can take the points (-9, 0) and (-3, 18), then we get:
[tex]mq=\frac{18-0}{-3-(-9)}=\frac{18}{-3+9}=\frac{18}{6}=3[/tex]By replacing the value of the slope and the coordinates of the point (-9, 0), we get:
y - 0 = 3(x - (-9))
y = 3(x + 9)
y = 3x + 27
y - y = 3x + 27 - y
0 = 3x + 27 - y
-27 = 3x + 27 - 27 - y
-27 = 3x - y
For line v, we can take the points (-4, 10) and (0, 8), then we get:
[tex]mv=\frac{8-10}{0-(-4)}=\frac{-2}{4}=-\frac{1}{2}[/tex]By taking -1/2 for the slope and the coordinates of the point (0,8), we gat:
y - 0 = -1/2(x - 8)
y = -1/2x + 4, multiplying both sides by 2:
2y = -x + 16
2y + x = -x + x + 16
2y + x = 16
Then, the system represented by the lines q and v is option G
The figure shows a quarter circle and an equilateral triangle. What is thearea of the shaded part? Give your answer to 3 significant figures. (Take it= 3.14.)7 cm
Since the triangle is equilateral, all of its interior angles have a measure of 60º.
Substract the area of the triangle from the area of a circular sector with radius 7cm enclosed by an angle of 60º to find the area of the shaded region.
The area of an equilateral triangle with side length L is:
[tex]A=\frac{\sqrt[]{3}}{4}L^2[/tex]The area of a circular sector of radius r enclosed by an angle of θ degrees is:
[tex]A=\frac{\theta}{360}\times\pi r^2[/tex]Replace θ=60 and r=7cm to find the area of the circular sector:
[tex]A_c=\frac{60}{360}\times3.14\times(7\operatorname{cm})^2=25.643\ldots cm^2[/tex]Replace L=7cm to find the area of the triangle:
[tex]A_T=\frac{\sqrt[]{3}}{4}\times(7\operatorname{cm})^2=21.2176\ldots cm^2[/tex]Then, the area of the shaded region is:
[tex]\begin{gathered} A_C-A_T=25.6433\ldots cm^2-21.2176\ldots cm^2 \\ =4.4257\ldots cm^2 \\ \approx4.43\operatorname{cm}^2 \end{gathered}[/tex]Therefore, the area of the shaded region to 3 significant figures, is:
[tex]4.43\operatorname{cm}^2[/tex]What’s the correct answer answer asap for brainlist
Answer:
A. a chorus
Step-by-step explanation:
While solving an equation 2x^2+32=0 the answer calculated is x=+-4i I understand the +- means the answer can be positive or negative but what does the i mean
Answer:
Explanation:
Given:
[tex]\begin{gathered} 2x^2+32=0 \\ \text{The answer is x=}+-4i \end{gathered}[/tex]To fully understand how we get the given answer, we simplify the equation first:
[tex]\begin{gathered} 2x^2+32=0 \\ \text{Simplify and rearrange} \\ 2x^2=-32 \\ x^2=-\frac{32}{2} \\ x^2=-16 \\ \end{gathered}[/tex]Next, we apply the rule:
[tex]\begin{gathered} \text{For x}^2=f(a),\text{ the solutions are } \\ x=\sqrt[]{f(a)} \\ x=-\sqrt[]{f(a)} \end{gathered}[/tex]So,
[tex]\begin{gathered} x^2=-16 \\ x=\sqrt[]{-16},x=-\sqrt[]{-16} \end{gathered}[/tex]Then, we also apply the radical rule:
[tex]\begin{gathered} \sqrt[]{-a}=\sqrt[]{-1}\sqrt[]{a} \\ So, \\ x=\sqrt[]{-16} \\ =\sqrt[]{-1}\sqrt[]{16} \\ \text{Then, apply the imaginary number rule:} \\ \sqrt[]{-1}=i \\ \text{Hence,} \\ x=4i \end{gathered}[/tex]For
[tex]\begin{gathered} x=-\sqrt[]{-16} \\ Use\text{ the same steps} \\ x=-4i \end{gathered}[/tex]Therefore the x-values are: x=4i, x=-4i. The i on the answer means imaginary number. It is a number that, when squared, has a negative result.
Given the general form: F( x )= a(x^2)+bx+cConvert it to vertex form (also known as standard form) by putting the values for a,h and k into the correct boxes.F(x)=a(x-h)^2+kIdentify the vertex(x,y)General form: F( x )=1 x^2+6 x +-1 Vertex form: F( x )= Answer for part 1 and coordinate 1 (x- Answer for part 1 and coordinate 2 )^2 +Answer for part 1 and coordinate 3Vertex: (Answer for part 2 and coordinate 1,Answer for part 2 and coordinate 2)
1) In order to convert from the standard version to the vertex form we'll need to find the vertex of that parabola:
[tex]f(x)=x^2+6x-1[/tex]We can find the vertex, using these formulas:
[tex]\begin{gathered} x=h=-\frac{b}{2a}=\frac{-6}{2}=-3 \\ k=(-3)^2+6(-3)-1=9-18-1=9-19=-10 \\ V(-3,-10) \end{gathered}[/tex]So this is the vertex of that parabola at point (-3,-10)
2) Now, note that the coefficient a = 1, and with the vertex, we can now rewrite that equation into the vertex form:
[tex]\begin{gathered} y=a(x-h)^2+k \\ y=(x-(-3))^2+(-10) \\ y=(x+3)^2-10 \end{gathered}[/tex]
I'll send a picture! please answer fast!
Given data:
The given expression for the points is,
[tex]10w-3t+5[/tex]Thus, the expression or
10. The product of 6 and a number when added to 5 is equal to 1 less than 9 times the number.
Answer:
x = 2
Step-by-step explanation:
Hello!
Let the unknown number be x. The product of 6 and that number can be represented by 6x. And since we are adding 5, we can use 6x + 5 to represent that expression.
This equation is equal to the difference of 9x and 1, or 9x - 1.
Solve for x6x + 5 = 9x - 15 = 3x - 16 = 2x2 = xThe value of x is 2.
Graph the line that has an z-intercept of (-3,0) and a y-intercept of (0, - 5). What is the slope of this line?
Answer:
the slope is -5/3
Step-by-step explanation:
it is that because to find slope u do y2-y1/x2-x1
use the two given points and calculate the slope.(6,4),(4,-1)
EXPLANATION:
Given;
We are given two points which are shown below;
[tex]\begin{gathered} (6,4) \\ (4,-1) \end{gathered}[/tex]Required;
We are required to calculate the slope.
Step-by-step solution;
To calculate the slope given two points, we shall use the following formula;
[tex]\begin{gathered} Slope: \\ m=\frac{y_2-y_1}{x_2-x_1} \end{gathered}[/tex]Where the variables are;
[tex]\begin{gathered} (x_1,y_1)=(6,4) \\ (x_2,y_2)=(4,-1) \end{gathered}[/tex]We can now substitute these values and solve;
[tex]m=\frac{-1-4}{4-6}[/tex][tex]m=\frac{-5}{-2}[/tex][tex]m=\frac{5}{2}[/tex]Therefore.
ANSWER:
[tex]m=\frac{5}{2}[/tex]What is the scale factor of Figure B to Figure A?48.6B2510A1021.5A. O 6.25B.O 2.5C.0.16D. 0.4
As per given by the question,
There are given that two traingle, figure A and figure B.
Now,
The ratio of a dimension on figure B to the corresponding dimension on figure A is,
[tex]4\colon10=8.6\colon21.5=10\colon25[/tex]So,
The scale factor is,
[tex]\begin{gathered} k=\frac{10}{4}=\frac{25}{10}=\frac{21.5}{8.6}=2.5 \\ \end{gathered}[/tex]The scale factor of figure B on the figure A is 2.5.
Hence, the option B is correct.
i need help with this problem
Answer:
whats the problme?
Step-by-step explanation:
Working 5 hours a day, A can Complete a work in 8 days and working 6 hours a day, B can complete the same work in 10 days. Working 8 hours a day, they can jointly complete the work in how many days?
After solving the equation, If both A and B of them worked together, then Working 8 hours a day, they can jointly complete the work in 6 days.
What is an equation?Two mathematical expressions' values are said to be equal in an equation, which is a statement of this fact. A mathematical formula declares that two things are equal.
The equals sign ('=') is used to indicate it.
Let the work completed be W
For A
W = 5hours = 1/8 days
1 hour = 1/8 days ÷ 5
1 hour = 1/40 days
For B
W = 6 hours = 1/10 days
1 hour = 1/60 days
Add both the equation
1 hours + 1 hours = 1/40 days + 1/60 days
2 hours = 5/120 days
2 hours = 1/24days
If both of them worked for 1 hour a day
1 hour = 1/48 days
If both of them worked for 8hour a day
8 hours = 1/48 × 8
= 1/6 days
Thus, if both of them worked together, then Working 8 hours a day, they can jointly complete the work in 6 days.
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What is the value of (–3 + 3i) + (–2 + 3i)?
Answer: -5+6i
Step-by-step explanation:
Jamar finds some nickels and quarters in his change purse. How much money (in cents) does he have if he has 4 nickels and 11 quarters? How much money (in cents) does he have if he has n nickels and q quarters?
1 nickel is worth 5 cents and 1 quarter is worth 25 cents.
So, if he has 4 nickels, this is worth 4 times 5 cents and if he has 11 quarters, this is worth 11 times 25 cents.
Both are worth the sum of these, so:
[tex]4\cdot5+11\cdot25=20+275=295[/tex]So, he has 295 cents.
If he has n nickels and q quarters, he has 5 times n plus 25 times q worth, so he has:
[tex]5n+25q[/tex]can somebody please help me with this question
Answer:
I don't really understand this but I think will be a great way to solve this so 123.00
Step-by-step explanation:
.
The total cost, in dollars of a membership in a fitness center is given by the function c(m) = 40m +10, where m is the number of months a person is a member. In dollars, how much is the cost of a membership for 1 year?
The cost of a membership for 1 year is 490
How to determine the cost of a membership for 1 year?The equation of the membership is given as
c(m) = 40m + 10
From the question, we understand that:
m represents the number of months
For the cost of a membership for 1 year, the number of months is 12
i.e. m = 12
Substitute the known values in the above equation
So, we have
c(12) = 40 * 12 + 10
Evaluate
c(12) = 490
Hence, the cost is 490
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What is Qualitative Data and what is the discreate and Continuous in qualitative data?
Answer:
Qualitative data is the data that is not represented by numbers, for example, favorite food or country.
On the other hand, the quantitative data is represented by numbers and it is classified as discrete and continuous. The discrete data is the data that only can take specific values, for example, the number of people is always a whole number, there can't be 5.5 people. The continuous data is the data that can take decimal values, for example, the mass of an object can be 4.06 kg.
Solve the following. List all possible possible solutions for the ambiguous case. #7
The sum of the interior angles of any triangle is always 180º:
[tex]A+B+C=180[/tex]Use the equation above and the given data to find C:
[tex]\begin{gathered} C=180º-A-B \\ C=180º-38º-72º \\ C=70º \end{gathered}[/tex]Law of sines:
[tex]\frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}[/tex]Use the pair of ratios for a and b to solve a:
[tex]\begin{gathered} \frac{a}{sinA}=\frac{b}{sinB} \\ \\ a=sinA*\frac{b}{sinB} \\ \\ a=sin38º*\frac{12}{sin72º} \\ \\ a=7.8 \end{gathered}[/tex]Use the pair of ratios for b and c to solve c:
[tex]\begin{gathered} \frac{c}{sinC}=\frac{b}{sinB} \\ \\ c=sinC*\frac{b}{sinB} \\ \\ c=sin70º*\frac{12}{sin72º} \\ \\ c=11.9 \end{gathered}[/tex]Thenm, the solution for the given triangle is:A=38ºB=72ºC=70ºa=7.8b=12c=11.9while digging in his garden , will pushes a shovel into the ground at an 80 degree angle with 585 newtons of force . show the resolution of the force into its retangular components
Solution
Part a
Part b
For this case we can do this:
Fx= 585 N* cos 80= 101.58 N
Fy= 585N * sin 80= 576.11 N
Then the best answer is:
B. (102, 576) N
Given the formula FV = P + Prt, what is the future value of a savings account that had an initial deposit of $7,900 earning 6.5% simple interest for 4 years?$10,074.23$9,954.00$9,376.85$10.756.43None of these choices are correct.
Step 1: Use the formula below to find the future value:
Fv = P + Prt
P = present value or initial deposit
r = rate in %
t = time in years
Step 2: List the given data
P = $7900
r = 6.5% = 0.065
t = 4 years
Step 3: Substitute the values of P, r and t to find the future value.
FV = P + Prt
= 7900 + 7900 x 0.065 x 4
= 7900 + 2054
= $9954.00
Stop 4: Final answer
Future value = $9954.00
I need help with this practice,I will send you an additional pic that goes along with this problem Freya went to her local park to find 5 organisms/species She found 5 and wrote down the name of these organisms and the quantity of each she seen:Eastern gray squirrels/14 individualsWolf spiders/2 individualsPaper wasps/9 individualsBlack vulture/1 individualNorthern cardinals/7 individuals
ANSWER :
The answer is 5/33 or 0.15
EXPLANATION :
From the problem, we have a total of 5 number of species.
Using the given Biodiversity Index formula :
[tex]\frac{\text{ total number of species}}{\text{ total number of individuals}}=\frac{5}{14+2+9+1+7}=\frac{5}{33}\quad or\quad0.1515[/tex]Find the equation for the circle with a diameter whose endpoints are (8,17) and (4, - 15).
Answer:
Given that,
Circle with a diameter whose endpoints are (8,17) and (4, - 15).
To find the equation for the circle
we know that,
Equation of the circle is of the form,
[tex](x-h)^2+(y-k)^2=r^2[/tex]where r is the radius and (h,k) is the center of the circle.
If the end points of the diameter is given, then the equation of the circle is,
[tex](x-x1)(x-x2)+(y-y1)(y-y2)=0[/tex]Substitute the points we get,
[tex](x-8)(x-4)+(y-17)(y+15)=0[/tex]On simplifying this we get,
[tex]x^2-8x-4x+32+y^2-17y+15y-255=0[/tex][tex]x^2+y^2-12x-2y-223=0[/tex]In how many ways can a committee of 5 be chosen from 9 people given that Jones must be one of them?
There are 126 ways to choose a committee of five from a group of nine people using combinations; one of them must include JONES.
What do we mean by COMBINATIONS?Combinations are a mathematical method for calculating the number of alternative arrangements. In a collection of objects where the order of the selection is irrelevant. You are free to choose any combination of the available things.Mathematically it can be expressed as : nCr = n! / r!(n-r)!So, we have a comiitte of 5 be chosen from 9 people and JONES must be one of them -
Using the rule of combinantion - nCr = n! / r!(n-r)!We have n = 9 and r= 59C5 = 9! / 5!(9-5)!C(9,5) = 3024/24C(9,5) = 126Therefore, there are a total of 126 ways in which we can decide that JONES must be on it.
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If sin 0= -3/5 in quadrant 3, what is cos 0?
Given
[tex]sin\theta=-\frac{3}{4}[/tex]Solution
Recall : SOHCAHTOA
The final answer
Option A
[tex]Cos\text{ }\theta=-\frac{4}{5}[/tex]Use the ALEKS calculator to write as a percentage.
31
32
Round your answer to the nearest tenth of a percent.
0%
X 5
?
Divide 31 into 32 and then multiply the result by 100 to get the percent:
[tex]\begin{gathered} \frac{31}{32}=0.96875 \\ \\ 0.96875*100=96.875 \end{gathered}[/tex]Then, to the nearest tenth of a percent the given fraction is 96.9%Select the correct answer. What is the solution to the equation? (x - 2)^1/2 + 4 = x A. -3 and -6 B. 3 and 6 C. -3 D. 6
Answer:
D. x = 6
Step-by-step explanation:
Given equation:
[tex](x-2)^{\frac{1}{2}}+4=x[/tex]
Subtract 4 from both sides:
[tex]\implies (x-2)^{\frac{1}{2}}+4-4=x-4[/tex]
[tex]\implies (x-2)^{\frac{1}{2}}=x-4[/tex]
Square both sides:
[tex]\implies \left( (x-2)^{\frac{1}{2}}\right)^2=(x-4)^2[/tex]
[tex]\implies x-2=(x-4)^2[/tex]
Expand the brackets on the right side:
[tex]\implies x-2=(x-4)(x-4)[/tex]
[tex]\implies x-2=x^2-8x+16[/tex]
Subtract x from both sides:
[tex]\implies x-2-x=x^2-8x+16-x[/tex]
[tex]\implies -2=x^2-9x+16[/tex]
Add 2 to both sides:
[tex]\implies -2+2=x^2-9x+16+2[/tex]
[tex]\implies 0=x^2-9x+18[/tex]
[tex]\implies x^2-9x+18=0[/tex]
Factor the left side of the equation:
[tex]\implies x^2-6x-3x+18=0[/tex]
[tex]\implies x(x-6)-3(x-6)=0[/tex]
[tex]\implies (x-3)(x-6)=0[/tex]
Apply the zero-product property:
[tex]\implies x-3=0 \implies x=3[/tex]
[tex]\implies x-6=0\implies x=6[/tex]
Therefore, the solutions of the quadratic equation are:
[tex]x=3, \quad x=6[/tex]
Input both solutions into the original equation to check their validity:
[tex]\begin{aligned}x=3 \implies (3-2)^{\frac{1}{2}}+4&=3\\(1)^{\frac{1}{2}}+4&=3\\1+4&=3\\5&=3\end{aligned}[/tex]
[tex]\begin{aligned}x=6 \implies (6-2)^{\frac{1}{2}}+4&=6\\(4)^{\frac{1}{2}}+4&=6\\2+4&=6\\6&=6\end{aligned}[/tex]
Therefore, the only valid solution to the given equation is x = 6.
Answer:
The answer is D. 6
Step-by-step explanation:
Add both sides:
(x - 2)^1/2 + 4 + (-4) = x + (-4)
(x - 2)^1/2 = -4
Solve exponent:
(x - 2)^1/2 = x - 4
((x - 2)^1/2)^2 = (x - 4)^2
x − 2 = x^2 − 8x + 16
x − 2 − (x^2 − 8x + 16) = x^2 − 8x + 16 − (x^2 − 8x + 16)
−x^2 + 9x − 18 = 0
(−x + 3)(x − 6) = 0
−x + 3 = 0 or x − 6 = 0
x = 3 or x = 6
Check the answers: (Plug them in to see what will work.)
x = 3 (won't work)
x = 6 (does work)
Therefore,
x = 6