Head restraints are energy-absorbing device that protects against such injuries.
Head restraints are a car protection characteristic, connected or included into the pinnacle of each seat to restrict the rearward motion of the grownup occupant's head, relative to the torso, in a collision to save you or mitigate whiplash or damage to the cervical vertebrae.
Powerful head restraints are designed to reduce the rearward motion of the head in a rear-end crash and reduce the probability of occupants maintaining whiplash neck injuries. Head restraints are generally known as head rests.
Make certain the top of the top restraint is at least a degree from the pinnacle of your head. The role is the pinnacle restraint so it's as near the again of your head as possible. You may need to alter the again of seat.
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The speed that a tsunami can travel is modeled by the equation , where s is the speed in kilometers per hour and d is the average depth of the water in kilometers. What is the approximate depth of water for a tsunami traveling at 200 kilometers per hour?.
0.32 km
How to reach the answer:
The formula below provides the tsunami's speed in response to the query.
s = 356√d
when the tsunami's speed is 200 km/h, the equation's "s" is changed to "200," and the equation of speed is then expressed as follows.
200 = 356√d
The equation can be changed to compute the depth of the water as,
√d = 200÷356
√d = 0.562
Now on squaring both sides:
(√d)² = (0.562)²
d = (0.562)² = 0.316 or 0.32
Therefore the approximate depth of water for a tsunami travelling at 200km/h is 0.32 km
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A 5.9 kg box slides a 9.3 m distance on ice. If the coefficient of kinetic friction is 0.206, what is the work done by the friction force
Work done by the friction force is 110.77 J
Calculation of friction force:
here box has mass, m=5.9 kg
It slides the distance of, d=9.3 m
coefficient of kinetic friction is 0.206
Now we can say that,
net force on the object is applied force and friction force
The net force according to Newton's second law:
F(net)=m*a
F(applied) - f(friction) = m*a
The work done by friction force will be
W= -k*mg*d
here g is gravitational acceleration.
substituting the values we get,
W=-(0.206)*(5.3)(9.8)*(9.3)
W= -110.77 J
negative sign denotes the opposite direction.
work done by the friction force is 110.77 J
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Suppose a large star explodes in a supernova, leaving a core that is 10 times the mass of the Sun. What would happen to the core of the star
If a large star explodes in a supernova and leaves a core that's 10 times the mass of the Sun, the core of the star would collapse.
What is a star?A star can be defined as a giant astronomical object that contains a luminous sphere of plasma, and it is bounded together by its own gravitational force.
Based on astronomical information, if a large star explodes in a supernova and leaves a core that's 10 times the mass of the Sun, the core of the star would collapse due to its own gravity which creates a violent explosion known as a supernova.
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Now put the two equations together. Substitute your result in equation A for the (vaverage) term in equation B. Your final equation should only have d, a, and t terms.
An average velocity can be defined as the total distance covered by a physical object divided by the total time taken.
Mathematically, you can find average velocity (Vaverage) from acceleration (a) and time (t) by using this formula:
Average velocity = acceleration × time
Vaverage = at .......equation A.
Also, you can find distance (d) from average velocity (Vaverage) and time (t) by using this formula:
Distance = average velocity × time
d = vt .......equation B.
Now, putting the two equations together and substituting the Vaverage term in equation B:
d = (at) × t
d = at²
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Complete Question:
A. How do you find average velocity (Vaverage) from acceleration (a) and time (t)?
B. How do you find distance (d) from average velocity (Vaverage) and time (t)?
C. Now put the two equations together. Substitute your result in equation A for the (Vaverage) term in equation B. Your final equation should only have d, a, and t terms.
A girl exerted 150 Newtons to lift a barbell 2.0 m in 4.0 s. If she did the same thing in 8.0 s, the work done on the barbell by the girl would be
Which of the statements given below is correct? Give reason
to support your statement.
i. In winter the winds flow from the land to the ocean.
ii. In summer the winds flow from the land towards the
ocean
If the net force acting on a stationary object is zero, then the object will A. remain at rest. B. accelerate in the direction of the strongest force. C. decelerate at a steady rate of speed. D. begin moving backwards.
The object will remain at rest
Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.
Here net force is zero
An object with a net force of zero acting on it will remain at rest, if initially at rest, or it will maintain a constant velocity.
F=MA
Force F=0
Than Acceleration A=0
With zero Acceleration stationary object will remain at rest.
Hence Remain at rest is the correct answer
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The flywheel in the shape of a solid cylinder of mass 75.0 kg and diameter 1.40 m rotates about an axis passing through the center of mass. a. what constant torque is required to bring it up to an angular speed of 320 rev/min in 8.00 s, starting from rest?
The torque required for the cylinder is 76.99 N m.
What is torque?
Torque may be defined as the product of the force and the distance perpendicular to the force from the axis of rotation.
Calculation of the angular acceleration:
The first kinematic equation for the rotational motion is,
ω=ω₀+αt
where ω₀ is the initial angular velocity, ω is the final angular velocity, α is the angular acceleration and t is the time. Since the cylinder starts from the rest, its initial angular velocity is zero.
Here, ω=320 rev/min or ω=320*2π/60 rad/sec, ω₀=0 and t=8.00 sec. Put these values in the above equation and solve it to get the value of angular acceleration.
320*2π/60=0+α*8
α=320*2π/(8*60)
α=4.19 rad/s^2
Calculation of the torque:
The torque T is given by the formula,
T=Iα
where I is the moment of inertia.
For the cylinder, I=1/2*mr^2
where m is the mass of the cylinder and r is the radius of the cylinder.
So,
T=1/2*mr^2*α
Here m=75 kg, radius r is half of the diameter r=1.4/2=0.7 m, and α=4.19 rad/s^2. Using these values in the formula of torque.
T=1/2*(75)*(0.7)^2*4.19
T= 76.99 N m
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Can God make a rock that He can't carry?
Answer:
The answer to the question lies in the character of God. God is either finite or infinite. If God is finite and limited, then God could make a rock He could not lift. If God is unlimited in power, then He could create a rock of any size and weight and still be able to lift it.
Explanation:
when an object rolls down a ramp with sliding. Does its motion translational motion or rotational motion ?
Explanation:
torque is just a force that acts off-center and causes an object to spin. Practically every quantity in translational motion has a rotational equivalent. Instead of linear acceleration, we have rotational (or angular) acceleration. Instead of forces, we have torques.
A special purpose nozzles that are often lowered through holes or other openings to the cellar of an occupancy are called
A special purpose nozzles that are often lowered through holes or other openings to the cellar of an occupancy are called cellar nozzles.
What is a nozzle:
A nozzle is a device in which steadily flowing fluid can be made to accelerate by a pressure drop along the duct in a cross-sectional area.
So when a fluid flows through a nozzle, its velocity increases continuously and pressure decreases continuously.
There are different types of tips like hollow cone, solid cone or flat fan.
The cellar nozzle (also called a Bresnan nozzle) is designed to be used under the surface the operator is standing on.
Hence,
The cellar nozzles are often lowered through holes or other opening to the cellar of an occupancy.
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You jump off a truck and accelerate toward the surface of the Earth. Does the Earth accelerate toward you?
When we jump from the truck and accelerate towards the earth surface, the earth also accelerates towards us but it's acceleration is very negligible.
To find the answer, we need to know about the acceleration of earth due to the gravitational attraction.
What's the gravitational force between the earth and a person?Gravitational attraction force is GMm/r² between the earth and a person. M= mass of the earthm= mass of the person
r= separation between them.
What's the acceleration of the earth towards the person when he jumps from a truck?According to Newton's second law, Force = M×accelerationAcceleration= Force / MHere, Force = GMm/r²,so acceleration of earth= Gm/r²
As this acceleration is very small, so we can't notice it.Thus, we can conclude that the earth also accelerates towards us.
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A brine solution of salt flows at a constant rate of l/min into a large tank that initially held l of pure water. The solution inside the tank is kept well stirred and flows out of the tank at a rate of l/min. If the concentration of salt in the brine entering the tank is kg/l, determine the mass of salt in the tank after t min. When will the concentration of salt in the tank reach kg/l?.
To reach 01.kg/L concentration of salt in the tank will take around 18.9 min.
What is concentration in a solution?The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or solution.
A concentrated solution is one that has a relatively large amount of dissolved solute. A dilute solution is one that has a relatively small amount of dissolved solute.
The concentration ,C(t) of salt at time t is given by the mass x(t) at time t divided by the volume t + 100 at time t.
That is C(t) = x(t)/ (t+100)
So that,
C(t) = 0.2 - [tex]\frac{2 * 10^4}{(t + 100)^4}[/tex]
The concentration of salt is 0.1 kg/L ,
we solve C(t) =0.1 ,
Giving the equation,
0.10.2 - [tex]\frac{2 * 10^4}{(t + 100)^4}[/tex]
t = [tex]100\sqrt[4]{2} -100[/tex]
≈ 18.9 minutes
Therefore,
To reach 01.kg/L concentration of salt in the tank will take around 18.9 min.
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If the hoist tower is not enclosed, the hoist platform or car must be totally enclosed on all sides for the full height between the floor and:
If the hoist tower isn't enclosed, the hoist platform must be totally enclosed on all sides for the full height between the floor and the overhead protective covering.
What is a hoist tower?A hoist tower can be defined as temporary elevator shaft made of scaffolding that is constructed and used to provide pathways for hoisting materials during a building-construction work.
According to the Occupational Safety and Health Administration (OSHA), the hoist platform must be totally enclosed on all sides for the full height between the floor and the overhead protective covering when the hoist tower isn't enclosed.
In conclusion, the hoist platform must be totally enclosed on all sides in order to prevent a potential injury to construction workers or an accident during a building-construction work.
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A block is attached to one end of a spring, while the other end of the spring is attached to a fixed axis. The block is moving in a horizontal circle centered at the axis at a constant speed, held in the circular path only by the spring. The system has a total energy of 2 Joules, the spring has a stiffness of 200 Newton/meter, and the unstretched spring has a length of 50 centimeters. Find how much the spring is stretched from its natural length as the block moves in this circle.
The spring is stretched about 3.5cm from its natural length as the block moves in this circle.
Acceleration is given by formula = [tex]\frac{v^{2} }{r}[/tex] where,..... (1)
v= velocity and r = total distance
In this case r = L+Δx where,
L is the length of unstretched spring
Δx = Change in Spring length
According to Hooke's law
F=kΔx …..(2) where,
F= force , k is constant and Δx= change in spring length
Also,
F=ma …..(3) where,
F= force , m= mass of body and a = acceleration
From equation (2) and (3)
ma = kΔx
Now, from equation (1)
mv²/L+Δx = kΔx
mv² = kΔx(L+Δx)…. (4)
Total energy(E) = 1/2mv² + 1/2kx²
From equation (4)
E = 1/2kΔx(L+Δx) + 1/2kΔx²
By solving this equation, this becomes
kΔx² + 1/2kΔxL - E = 0
Given,
k=200N/m L=50cm=0.5m E=2J
Δx = 0.035 m = 3.5cm
Hence, the spring is stretched about 3.5cm from its natural length as the block moves in this circle.
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A person who normally weighs 580 N is riding in an elevator that is moving upward, but slowing down at a steady rate. If this person is standing on a bathroom scale inside the elevator, what would the scale read
Answer:
M au = Fs - M g au = upwards acceleration; Fs = scale reading
Fs = M (au + g) scalar quantities where g is positive downwards and au is positive upwards - Fs is the net force acting on the person
If the acceleration is zero Fs = M g and the scale reads the persons weight
If the elevator is decelerating then au is negative and the scale reading Fs = (g - au) M and the scale reading is less than the weight of the person
wishing to collect weather data on a remote island, you come up with an idea for sending a weather balloon to the location. You attach a +1 C charged object to the balloon and plan to propel the balloon to the island using an electrostatic force. Given the balloon's size and standard wind patterns en route, you realize you will need to be able to overcome an opposing air resistance of up to 100N at any point on the balloon's 750km journey to the island. How big oof a charge will you need at your location to propel the +1C balloon, even in the face if the opposing wind, up to a distance of 750 km away?
The magnitude of the second charge needed to propel the first charge is 6,250 C.
Magnitude of the second charge to propel the first charge
The magnitude of the second charge is calculated by applying Coulomb's law as follows;
F = kq₁q₂/r²
where;
k is Coulomb's constantq₁ is magnitude of first chargeq₂ is magnitude of second charger is the distance between the chargesFr² = kq₁q₂
q₂ = Fr²/kq₁
q₂ = (100 x 750,000²)/(9 x 10⁹ x 1)
q₂ = 6,250 C
Thus, the magnitude of the second charge needed to propel the first charge is 6,250 C.
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9. What could cause scientist to change their mind?
New technology allows for new understandings of old ideas
b. The findings are not popular with the public.
C.
The findings are not widely accepted as true.
d. No one has been able to prove they are right.
Betelgeuse is a supergiant star that will eventually supernova, which means that by mass it is classified as
Betelgeuse is a supergiant star that by mass is classified as a high-mass star.
What is a celestial body:
Celestial bodies are natural objects that are a part of the massive universe. Even though the universe has vast expanses of empty space, it is inhibited by them. The following are the 7 categories in which the celestial bodies are classified in:
Thus, as Betelgeuse is a supergiant star that will eventually result in a supernova it is classified as a high-mass star.
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A point charge with charge q1 = 2.40 μC
is held stationary at the origin. A second point charge with charge q2
= -4.90 μC moves from the point (0.170 m, 0) to the point (0.230 m , 0.270 m ).
How much work is done by the electrostatic force on the moving point charge?
Express your answer in joules.
The work done by the electrostatic force on the moving point charge is 1.014 J.
Displacement of the second charge
d = √[(0.23 - 0.17)² + (0.27 - 0)²] = 0.277 m
Force between the two chargesF = kq₁q₂/r²
where;
q₁ is magnitude of first chargeq₂ is magnitude of second charger is the distance between the two chargesk is Coulomb's constantF = (9 x 10⁹ x 2.4 x 10⁻⁶ x 4.9 x 10⁻⁶)/(0.17)²
F = 3.66 N
Work done in moving the point chargeW = Fd
W = 3.66 x 0.277
W = 1.014 J
Thus, the work done by the electrostatic force on the moving point charge is 1.014 J.
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it is observed that in water the meniscus in the capillary tube is higher than the meniscus in the beaker,while in mercury the meniscus in the capillary tube is lower tha the meniscus in the beaker.Explain these observations
The adhesion forces between mercury and glass are far weaker than the cohesive forces between mercury atoms causing the meniscus in the capillary tube to be lower than the meniscus in the beaker.
What is surface tension?
The force operating at a border between two phases is measured as surface tension.
Surface tension at liquid-air interfaces is caused by the higher attraction of liquid molecules to each other than air molecules.
Due to the relatively strong attraction of water. Hence molecules of water have high surface tension.
Because the water wets the glass and seeps up the tube's side when it is contained in a glass tube, the meniscus of the water has a concave form.
The cohesive forces between mercury atoms, on the other hand, are far stronger than the adhesion forces between mercury and glass.
The meniscus in the capillary tube is, therefore, higher than the meniscus in the beaker, but with mercury, the meniscus in the capillary tube is lower than the meniscus in the beaker.
Hence, the meniscus in the capillary tube is lower than the meniscus in the beaker
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What temperature increase is necessary to increase the power radiated from an object by a factor of 8
The temperature increase that is necessary to increase the power radiated from an object by a factor of 8 is to increase the temperature by a factor of 1.68.
What is radiation?
Radiation is the emission of energy in the form of waves or particles through space.
The magnitude of radiation emitted by an object is given as;
E = kσT⁴
where;
k is Boltzmann constantσ is the emissivity of the objectT is temperatureE₁/T₁⁴ = E₂/T₂⁴
T₂⁴ = T₁⁴E₂/E₁
T₂⁴ = T₁⁴(8E₁) / E₁
T₂⁴ = T₁⁴8
T₂ = (T₁⁴8)^(¹/₄)
T₂ = 1.68T₁
Thus, the temperature increase that is necessary to increase the power radiated from an object by a factor of 8 is to increase the temperature by a factor of 1.68.
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There is an electric field near the Earth's surface whose magnitude is about 130 V/m . How much energy is stored per cubic meter in this field
The electric energy stored per unit cubic meter is 7.5×10^(-8) joule/m³.
To find the answer, we need to know about the electric energy density.
What's the mathematical expression of electric energy density?In a vacuum where the permittivity is 8.85× 10^(-12), the electric energy density is 1/2 ×ε₀ ×E²
What's the energy density for electric field of 130 V/m?Energy density= (1/2)× 8.854×10^(-12)×130²
= 7.5×10^(-8) joule/m³
Thus, we can conclude that the energy density is 7.5×10^(-8) joule/m³.
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Based on what you have learned about the cultural influence on moral decisions, explain how your culture influences your moral choices. Consider what we learned in Unit 1 about the many layers of cultural identity. What cultural layers have played a part in constructing your sense of right and wrong?
Our culture greatly influences our moral decisions because the culture give us the way of living.
How your culture influences your moral choices?
Moral judgments and behaviors are dependent on the culture. We learn our behaviour and way of living from the culture that is present in our surrounding environment.
Sub-layer cultural is the layer that have played a part in constructing your sense of right and wrong because we grown up in this layer of culture.
So we can conclude that Our culture greatly influences our moral decisions because the culture give us the way of living.
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A stone is thrown upwards into the air. Describe what is the magnitude and direction of its acceleration.
Answer:
Every object on the surface of the earth is pulled towards its surface because of a force known as the gravitational force. It is a force of attraction that exists between any two objects with mass.
The gravitational force of the earth pulls every object towards the surface of the earth. Because of this, an object free in the air is accelerated. The acceleration caused by the gravitational force is known as the acceleration due to gravity.
The magnitude of the acceleration is constant in a downward direction.
What is acceleration?Acceleration is the rate of change in velocity.
price at which speed adjustments with time, in phrases of each pace and direction. A factor or an object shifting in a direct line is extended if it hastens or slows down.Earth's acceleration is always in the downward direction.so when an object is thrown upward its acceleration is directed downward.if the object is downward then also the acceleration is downward.Learn more about acceleration here:-https://brainly.com/question/460763
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What is the formula of gravity?
Answer:
F=Gm1m2 / r2
Explanation:
F = force
G = gravitational constant
m_1 = mass of object 1
m_2 = mass of object 2
r = distance between centres of the masses
answer is in the attachment
☆...hope this helps...☆
_♡_mashi_♡_
At what speed must a 150-kg football player be moving to have the same momentum as a 15.0-g bullet traveling at 300 m/s
The football must have the speed of 0.03 m/s to have the same momentum.
What is momentum conservation:
It states that, the total amount of momentum remains constant; momentum is neither created nor destroyed, but only changed through the action of forces as described by Newton's laws of motion.Momentum defines by formula: P = m*vhere,
mass of football, m1 = 150 kg
mass of bullet, m2 = 15 g = 0.015 kg
speed of bullet, v2 = 300 m/s
According to conservation of momentum:
m1*v1 = m2*v2substituting the values in equation,
150* v1 = ( 0.015 )* (300)
v1 = 0.03 m/s
Hence,
The football must have the speed of 0.03 m/s to have the same momentum.
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A 40.0 N cart slides from rest down a rough 6.0 m long ramp inclined at 30.00 with the horizontal. Find the velocity of the cart at the bottom of the ramp if the force of friction between the cart and ramp is 6.0 N. Group of answer choices 8.7 m/s 3.3 m/s 4.5 m/s 6.4 m/s
The velocity of the cart at the bottom of the ramp is 6.42m/s
Given that 40N cart slides from rest down a rough 6.0 m long ramp and the degree given is 30 and the friction force given is 6.0N
We need to find the velocity of the cart at the bottom of the ramp
One of two types of energy is known as potential energy and is the latent energy present in an item at rest.
According to the rule of conservation of energy, energy can only be transformed from one form of energy to another and cannot be generated or destroyed.
Potential energy of the crate at the top =40N×6sin30°m=120J
Energy lost due to friction =6N×6m=36J
Let the speed of the crate at the bottom be v.
Applying the law of conservation of energy,
120−36=0.5×(40/g)×v2
Therefore,
v=6.42m/s
Hence the velocity of cart at the bottom of the ramp is 6.42m/s
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A jogger runs 6.0 km [E], then 4.0 km [N], and finally 2.0 km [W]. The entire trip takes 2.0 h to complete. Calculate the jogger's
(a) average speed
(b) average velocity
(a) The trip covers a total distance of 6.0 + 4.0 + 2.0 = 12.0 km, so the jogger's average speed is (12.0 km)/(2.0 h) = 6.0 km/h.
(b) The jogger undergoes a total displacement given by the vector
(6.0 km) i + (4.0 km) j + (-2.0 km) i = (4.0 km) (i + j)
where i is the unit vector pointing due East and j is the unit vector pointing due North. This vector has magnitude
||(4.0 km) (i + j)|| = (4.0 km) √(1² + 1²) ≈ 5.7 km
so the jogger's average velocity is approximately (5.7 km)/(2.0 h) ≈ 2.8 km/h.
The wheel of a bicycle with a radius of 0.85 m is traveling at a speed of 5.0 m/s. Calculate its angular speed.
Group of answer choices
A) 4.3 rad/s
B. 5.9 rad/s
C. 9.2 rad/s
D. 1.7 rad/s
Answer:
B
Explanation:
Angular speed=velocity/radius
5/0.85=5.9