10. What mass of carbon dioxide is produced when 6.2
moles of propane, C3Hg is burned in oxygen?
C3H2 + ___ O2 →
O2 → _ CO2 + _ H2O
-
-

Answer:

C? Not 100% sure

Step-by-step explanation:

Answer:

30° and 60°

Step-by-step explanation:

Let the interior angles be ∠x₁ (smaller) and ∠x₂ (larger), and the exterior angle ∠X.

Making the statements into equations :

Size of an exterior angle of a triangle is the supplement of smaller of two opposite interior angles ⇒ ∠X + ∠x₁ + ∠x₂ = 180° [Equation 1]

Greater of the opposite interior angles exceeds smaller by 30° :

⇒ ∠x₂ = ∠x₁ + 30° [Equation 2]

By exterior angle property :

⇒ ∠x₁ + ∠x₂ = ∠X [Equation 3]

Substituting Equation 3 in Equation 1 :

⇒ ∠x₁ + ∠x₂ + ∠x₁ + ∠x₂ = 180°

⇒ 2 (∠x₁ + ∠x₂) = 180°

⇒ ∠x₁ + ∠x₂ = 90°

⇒ ∠x₂ = 90° - ∠x₁ [Equation 4]

Substituting Equation 4 in Equation 2 :

⇒ 90° - ∠x₁ = ∠x₁ + 30°

⇒ 2∠x₁ = 60°

⇒ ∠x₁ = 30°

Substituting the value of ∠x₁ in Equation 2 :

⇒ ∠x₂ = 30° + 30°

⇒ ∠x₂ = 60°

The measures of the interior angles are 30° and 60°

Answer:

True, (-∞, ∞)      5 ≤ 11

Step-by-step explanation:

−11 ≤ −5                       Add 16 to both sides

−11 + 16 ≤ −5 + 16

5 ≤ 11

Answer:

650

Step-by-step explanation:

let the unknown feet of room = X

5 paints = 250 square feet of room

13 paints = X

cross multiply

5*X = 250*13

X =3250÷5

X = 650 square feet of room

The partial differential expression is equal to the expression 30 · x · (x³ + y⁴) + 36 · x² · y² · (y² + x²) and the total differential formula is Δz = (0.9 · x² + 0.6 · y²) · cos (x³ + y³).

In the first part of this question we must apply the concept of partial derivatives to find the form of the entire expression, whose variables are two. Partial differentiation is a generalization of the ordinary differentiation:

[tex]\frac{\partial f}{\partial x} = 6\cdot x^{5}+12\cdot x^{3}\cdot y^{4}+y^{6}[/tex]     (1)

[tex]\frac{\partial^{2} f}{\partial x^{2}} = 30\cdot x^{4}+36\cdot x^{2}\cdot y^{4}[/tex]     (2)

[tex]\frac{\partial^{2} f}{\partial x \,\partial y} = 48\cdot x^{3}\cdot y^{3}+6\cdot y^{5}[/tex]     (3)

[tex]\frac{\partial f}{\partial y} = 12\cdot x^{4}\cdot y^{3} +6\cdot x \cdot y^{5}[/tex]     (4)

[tex]\frac{\partial^{2} f}{\partial y^{2}} = 36\cdot x^{4}\cdot y^{2} + 30\cdot x\cdot y^{4}[/tex]     (5)

[tex]\frac{\partial f}{\partial y \,\partial x} = 48\cdot x^{3}\cdot y^{3}+6\cdot y^{5}[/tex]     (6)

Then, the entire expression is:

30 · x⁴ + 36 · x² · y⁴ + 36 · x⁴ · y² + 30 · x · y⁴

30 · (x⁴ + x · y⁴) + 36 · (x² · y⁴ + x⁴ · y²)

30 · x · (x³ + y⁴) + 36 · x² · y² · (y² + x²)

In the second part we must determine the total differential of z with respect to two variables:

[tex]\Delta z = \frac{\partial f}{\partial x}\cdot \Delta x + \frac{\partial f}{\partial y}\cdot \Delta y[/tex]     (7)

If we know that z = sin (x³ + y³), Δx = 0.3 and Δy = 0.2, then the total differential of the function is:

Δz = 3 · cos (x³ + y³) · x² · (0.3) + 3 · cos (x³ + y³) · y² · (0.2)

Δz = (0.9 · x² + 0.6 · y²) · cos (x³ + y³)

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Answer:

8.227 then rounded to tenth is 8.2

Step-by-step explanation:

just smart.

please rate good. have a good day.

Answer:

y out put x input and 3 is input and as 5 . tell me if you get it right

Answer:

sin(t) = 4*sqrt(5) / 21; cos(-t) = 19/21

Step-by-step explanation:

think of a right triangle with an adjacent leg a, opposite leg b, and hypotenuse c.

cos(t) = a/c = 19/21. so we can assume a=19 and c=21.

using Pythagorean's theorem, find b: b = sqrt(21^2 - 19^2) = 4*sqrt(5) or 8.944

since tan(t)> 0, b/a > 0 and a is positive so b must be positive. using this information, we know sin(t) = b/c = 8.944/21 or 4* sqrt(5) / 21

since cos x is an even function, cos(-x) = cos x so cos(-t) = cos(t) = 19/21

height= 8 in

length= 14 in

width= 3 in

the volume of the given rectangular prism.

[tex]v = whl[/tex]

[tex]v = 8 \times 14 \times 3[/tex]

[tex]v = 336 \: {in}^{3} [/tex]

hence, the volume of the given rectangular prism is 336 cubic inches.

answer= option D

[tex]\large\boxed{Formula: V= lbh}[/tex]

All the values are given so we'll simply have to solve.

Let's solve!

Substitute the values according to the formula.

We'll have to multiply the length, breadth and the height.

[tex]V= 14 \times 3 \times 8[/tex]

[tex]\large\boxed{V= 336 \: {in}^{3}}[/tex]

We get a whole number to the final answer so we won't have to round off.

Therefore, the volume of the given rectangular prism is 336 cubic inches.

Correct option: Option D

Answer:

[tex]m <U = 80°[/tex]

Step-by-step explanation:

Before we start calculating we have to first note that the angles in a triangle always add up to 180°. Therefore in order to find the missing angle U we have to add both the angles we know, 37° and 63°, then subtract the sum from 180°

[tex]m < U = 180- (37 + 63) \\ \\ m < U = 180 - 100 \\ \\ m< U = 80[/tex]

Answer:

g(x) = a(x − h)2 + k, where a ≠ 0.

Step-by-step explanation:

The parent function of the quadratic family is f(x) = x2. A transformation of the graph of the parent function is represented by the function g(x) = a(x − h)2 + k, where a ≠ 0.

The equation of the amount charged by Bob will be y = 7.25x.

The equation in mathematics is the relationship between the variables and the number and establishes the relationship between the two or more variables.

Given that:-

The equation will be generated as follow:-

6 hours  =  $  43.50

1 hours   =  $  7.25

9 hours   =  $ 65.2575

1 hours    =  $ 7.25

Let x represent the number of hours Bob works and y represent the amount he charges. The equation will be:-

y  =  7.25x dollars.

Therefore the equation of the amount charged by Bob will be y = 7.25x.

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The data recorded by Ben shows the attendance log of his classmates over a given period of time.

This refers to a simple chart that resembles a histogram that is used to represent small data.

Hence, we can see that because Ben tracked the attendance of the class over a given time period with the frequency on a frequency table, a sample of a dot plot has been provided below,

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The sign of a times -b/b when a = 0 and b < 0 is neutral neither negative nor positive .

An integer is a whole number (not a fractional number) that can be positive, negative, or zero

As b<0 which means b would be negative.

So, -b/b gives a negative value.

Because if any of the either numerator or denominator is negative then the resulting value also be negative.

and if zero '0' is multiplied and number whether it is positive or negative the resulting value will be zero.

So,  a* (-b/b)= 0* negative= negative zero, but zero is neither negative nor positive .

hence, the sign of a times -b/b is neutral neither negative nor positive .

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Answer:the mean is 90

Step-by-step

you find the sum of the values then divide them by the amount of numbers in the set

[tex]\text{Given that,} ~ x-y = 5~ \text{amd}~ xy = 4\\\\\text{Now,}\\\\x^3 -y^3\\\\=(x-y)(x^2 +xy+y^2)\\\\=(x-y)[(x-y)^2 +2xy +xy]\\\\=(x-y)[(x-y)^2 +3xy]\\\\=5(5^2+3\cdot 4)\\\\=5(25+12)\\\\=5(37)\\\\=185[/tex]

Answer:

45, 75

Step-by-step explanation:

3+5 = 8

120 / 8 = 15

15 x 3 = 45

15 x 5 = 75

Answer:

45,75

3+5 = 8

120 / 8 = 15

15 x 3 = 45

15 x 5 = 75

Step-by-step explanation:

have a great day!

Answer:

[tex]y = 5[/tex].

Or, equivalently:

[tex]\begin{aligned}\begin{bmatrix}0 \\ -3 \\ 0\end{bmatrix} \left(\begin{bmatrix}x \\ y \\ z\end{bmatrix} - \begin{bmatrix}1 \\ 5 \\ -3\end{bmatrix}\right) = 0\end{aligned}[/tex].

Step-by-step explanation:

Every plane in [tex]\mathbb{R}^{3}[/tex] could be represented with a vector equation of the form [tex]\vec{n}\, (\vec{r} - \vec{r}_{0}) = 0[/tex], where:

Notice that in this question, the coordinates (and hence the position vectors) of the points in this plane are already given. For example, the position vector of the point [tex](1,\, 5,\, -3)[/tex] is the vector:

[tex]\begin{aligned}\vec{r}_{0} = \begin{bmatrix}1 \\ 5 \\ -3\end{bmatrix}\end{aligned}[/tex].

Specifically in [tex]\mathbb{R}^{3}[/tex], normal vectors of a plane could be found by:

Subtracting position vectors of points in this plane from each other would give directions that are parallel to this plane:

[tex]\begin{aligned}\begin{bmatrix}2 \\ 5 \\ -3\end{bmatrix} - \begin{bmatrix}1 \\ 5 \\ -3\end{bmatrix} = \begin{bmatrix}1 \\ 0 \\ 0\end{bmatrix}\end{aligned}[/tex].

[tex]\begin{aligned}\begin{bmatrix}3 \\ 5 \\ 2\end{bmatrix} - \begin{bmatrix}1 \\ 5 \\ -3\end{bmatrix} = \begin{bmatrix}2 \\ 0 \\ 5\end{bmatrix}\end{aligned}[/tex].

The cross product between these two vectors in [tex]\mathbb{R}^{3}[/tex] would be:

[tex]\begin{aligned} \vec{n} = \begin{bmatrix}1 \\ 0 \\ 0\end{bmatrix} \times \begin{bmatrix}2 \\ 0 \\ 5\end{bmatrix} = & \begin{bmatrix}0 \times 5 - 0 \times 0 \\ 0 \times 2 - 1 \times 5\\ 1 \times 0 - 0 \times 2\end{bmatrix} = \begin{bmatrix}0 \\ -3 \\ 0\end{bmatrix}\end{aligned}[/tex].

(Note that the cross product between other directions parallel to the plane might give other normal vectors that are parallel to the one in this example.)

Using the position vector of the point [tex](1,\, 5,\, -3)[/tex] as [tex]\vec{r}_{0}[/tex], one possible vector equation for this plane would be:

[tex]\begin{aligned}\begin{bmatrix}0 \\ -3 \\ 0\end{bmatrix} \left(\begin{bmatrix}x \\ y \\ z\end{bmatrix} - \begin{bmatrix}1 \\ 5 \\ -3\end{bmatrix}\right) = 0\end{aligned}[/tex].

Expand the dot product and simplify to obtain a scalar equation for this plane:

[tex]\begin{aligned}\begin{bmatrix}0 \\ -3 \\ 0\end{bmatrix} \begin{bmatrix}x - 1 \\ y - 5 \\ z - (-3)\end{bmatrix} = 0\end{aligned}[/tex].

[tex]0\, (x - 1) + (-3)\, (y - 5) + 0\, (z - (-3)) = 0[/tex].

[tex](-3)\, (y - 5) = 0[/tex].

[tex]y = 5[/tex].

Answer:

Given equation:

[tex]10^{5x-2}=2^{8x-3}[/tex]

Take natural logs of both sides:

[tex]\implies \ln 10^{5x-2}= \ln 2^{8x-3}[/tex]

[tex]\textsf{Apply log Power law}: \quad \ln_ax^n=n\ln_ax[/tex]

[tex]\implies (5x-2)\ln 10=(8x-3) \ln 2[/tex]

Expand brackets:

[tex]\implies 5x\ln 10 - 2\ln 10=8x \ln 2 -3 \ln 2[/tex]

Collect like terms:

[tex]\implies 5x\ln 10 - 8x \ln 2 =2\ln 10-3 \ln 2[/tex]

Factor left sides:

[tex]\implies x(5\ln 10 - 8 \ln 2) =2\ln 10-3 \ln 2[/tex]

[tex]\textsf{Apply log Power law}: \quad \ln_ax^n=n\ln_ax[/tex]

[tex]\implies x(\ln 10^5 - \ln 2^8) =\ln 10^2- \ln 2^3[/tex]

[tex]\textsf{Apply log Quotient law}: \quad \ln_a\frac{x}{y}=\ln_ax - \ln_ay[/tex]

[tex]\implies x\left(\ln\left(\dfrac{10^5}{2^8}\right)\right) =\ln\left(\dfrac{10^2}{2^3}\right)[/tex]

Simplify:

[tex]\implies x\left(\ln\left(\dfrac{3125}{8}\right)\right) =\ln\left(\dfrac{25}{2}\right)[/tex]

[tex]\implies x=\dfrac{\ln\left(\dfrac{25}{2}\right)}{\ln\left(\dfrac{3125}{8}\right)}[/tex]

[tex]\implies x=0.4232297737...[/tex]

Applying the angle of intersecting secants and tangents theorem, m(KNL) is: A. 264°.

The angle of intersecting secants and tangents theorem states that the angle formed outside a circle has a measure that equals 1/2 the positive difference of the measures of the intercepted arcs.

60 = 1/2(18x - 6 - 5x - 17) [angle of intersecting secants and tangents theorem]

Solve for x

2(60) = 13x - 23

120 = 13x - 23

120 + 23 = 13x

143 = 13x

x = 143/13

x = 11

m(KNL) = (18x - 6 + 5x + 17)

m(KNL) = 23x + 11

Plug in the value of x

m(KNL) = 23(11) + 11

m(KNL) = 264° (option A)

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The approximate angle that the ladder makes with the ground is 37 degrees

The given question will be solved using the SOH CAH TOA identity.

The given statement will form a right triangle with the following parameters

Hypotenuse = 5m

Height(opposite) .= 3m

Determine the approximate measure of ∠θ

sin ∠θ = opp/hyp
sin ∠θ = 3/5
sin ∠θ = 0.6
∠θ = arcsin(0.6)
∠θ = 37degrees

Hence the approximate angle that the ladder makes with the ground is 37 degrees

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Answer:

A function means that we get one input and one output.  In this example that means for every x-value that we have, we only have one y-value.

Looking at the first option, we can see that there is no x-value that has more than one y-value which means that it is a function.

The rest of the options are seen with at least two values for one x-value in one of the points.  Therefore, they wouldn't be considered a function leaving us with only option A as the solution.

Answer:

Image attached below.

Step-by-step explanation:

Hello!

First let's isolate y:

This means that we are looking at all the values on the coordinate plane that are above the line y = -15.

The red shaded region is the solution region. Note that -15 is not a solution of y > -15 (the dotted line indicates that).

Replacing the first card illustrates an independent event, while not replacing the card illustrates a dependent event

In probability, when a selected card or item is replaced before another item is selected, then the event is an independent event.

This is so because, the selected card do not have effect on the probability of selecting the next card

However, if the card is not replaced, then the event is dependent

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Answer:

y = 3/2x + 6

Step-by-step explanation:

Equation of the given line

Perpendicular

Using Point-slope equation

Answer:

I believe, 6.

Step-by-step explanation:

Not sure if the rest of the question is the answer choices but the absolute of any number, is it's exact opposite. The reason for this is that an absolute number, or |?| is equal to whatever distance it is from 0. Since adding 1, and subtracting 1, both do such but in opposite directions, the absolute value of both would be 1.

Answer:

a5 = 122

Explanation:

Given:

Solve:

a1 = 2

a2 = -3a1+2 = -3(2)+2 = -4

a3 = -3a2 + 2 = -3(-4)+2 = 14

a4 = -3a3 + 2 = -3(14) + 2 = -40

a5 = -3a4 + 2 = -3(-40) + 2 = 122

Answer:

a₅ = 122

Step-by-step explanation:

What is a₅ for the sequence defined by:

[tex]\left\{\begin{array}{ccc}a_1=2\\a_n=-3a_{n-1}+2\\\end{array}\right\\\\\\\hrule[/tex]

Letting n=2:

[tex]a_n=-3a_{n-1}+2\\\\\\\\\Longrightarrow a_2=-3a_{2-1}+2\\\\\\\\\Longrightarrow a_2=-3a_{1}+2\\\\\\\\\Longrightarrow a_2=-3(2)+2\\\\\\\\\therefore a_2=-4[/tex]

Letting n=3:

[tex]a_n=-3a_{n-1}+2\\\\\\\\\Longrightarrow a_3=-3a_{3-1}+2\\\\\\\\\Longrightarrow a_3=-3a_{2}+2\\\\\\\\\Longrightarrow a_3=-3(-4)+2\\\\\\\\\therefore a_3=14[/tex]

Letting n=4:

[tex]a_n=-3a_{n-1}+2\\\\\\\\\Longrightarrow a_4=-3a_{4-1}+2\\\\\\\\\Longrightarrow a_4=-3a_{3}+2\\\\\\\\\Longrightarrow a_4=-3(14)+2\\\\\\\\\therefore a_4=-40[/tex]

Letting n=5:

[tex]a_n=-3a_{n-1}+2\\\\\\\\\Longrightarrow a_5=-3a_{5-1}+2\\\\\\\\\Longrightarrow a_5=-3a_{4}+2\\\\\\\\\Longrightarrow a_5=-3(-40)+2\\\\\\\\\therefore \boxed{\boxed{a_5=122}}[/tex]