Answers
Given data:
Mass of each block;
[tex]m=12\text{ kg}[/tex]Acceleration;
[tex]a=1.2\text{ m/s}^2[/tex]The free-body diagram for A,
The free-body equation for A is given as,
[tex]F-N_1=ma\ldots(1)[/tex]The free-body diagram for B is given as,
The free-body equation for B is given as,
[tex]\begin{gathered} F_B=N_1-N_2 \\ ma=N_1-N_2\ldots(2) \end{gathered}[/tex]The free-body equation for C is given as,
The free-body equation for C is given as,
[tex]\begin{gathered} F_c=ma \\ N_2=ma\ldots(3) \end{gathered}[/tex]Equating equation (2) and (3),
[tex]\begin{gathered} N_1-N_2=N_2_{} \\ N_1=2N_2 \\ N_1=2ma \end{gathered}[/tex]Part (1),
The horizontal force on block A due to block B is given as,
[tex]\begin{gathered} F_{AB}=N_1 \\ =2ma \end{gathered}[/tex]Substituting all known values,
[tex]\begin{gathered} F_{AB}=2\times(12\text{ kg})\times(1.2\text{ m/s}^2) \\ =28.8\text{ N} \end{gathered}[/tex]Therefore, the net horizontal force on block A due to block B is 28.8 N.
Part (2)
The net horizontal force on block B is given as,
[tex]\begin{gathered} F_B=N_1-N_2 \\ =2ma-ma \\ =ma \end{gathered}[/tex]Substituting all known values,
[tex]\begin{gathered} F_B=(12\text{ kg})\times(1.2\text{ m/s}^2) \\ =14.4\text{ N} \end{gathered}[/tex]Therefore, the net horizontal force on block B is 14.4 N.
Part (3)
The horizontal force on block B due to block C is given as,
[tex]\begin{gathered} F_{BC}=N_2 \\ =ma \end{gathered}[/tex]Substituting all known values,
[tex]\begin{gathered} F_{BC}=(12\text{ kg})\times(1.2\text{ m/s}^2) \\ =14.4\text{ N} \end{gathered}[/tex]Therefore, the horizontal force on block B due to block C is 14.4 N.
Related Questions
consider the graph. which would best represent wearing a helmet during a blow to the head in a crash, explain.
Answers
By wearing the helmet, the time isextended during which the change in momentum of the body takes place during the crash.
This increase in time for the force acting on the body will decrease the impact of force on the body.
In the given graph, the value of force on the head is less and time taken is more in the first graph.
Thus, the first graph (1) represent the wearing helmet case.
The force on the head is more and time is less in the second case.
Thus, the second graph (2) represents the without helmet case.
A bicycle wheel, of radius 0.300 m and mass 1.47 kg (concentrated on the rim), is rotating at 4.00 rev/s. After 56.4 s the wheel comes to a stop because of friction. What is the magnitude of the average torque due to frictional forces? Nm
Answers
Given,
The radius of the wheel, r=0.300 m
The mass of the wheel, m=1.47 kg
The initial angular frequency of the wheel, f=4.00 rev/s
The time it takes for the wheel to come to a stop, t=56.4 s
The final angular velocity of the wheel, ω=0 rad/s
The initial angular velocity of the wheel is
[tex]\begin{gathered} \omega_0=2\pi f \\ =2\pi\times4.00 \\ =25.13\text{ rad/s} \end{gathered}[/tex]From the equation of motion,
[tex]\omega=\omega_0+\alpha t[/tex]Where α is the angular acceleration of the wheel.
On substituting the known values,
[tex]\begin{gathered} 0=25.13+\alpha\times56.4 \\ \Rightarrow\alpha=\frac{-25.13}{56.4} \\ =-0.45\text{ rad/s}^2 \end{gathered}[/tex]The moment of inertia of the wheel whose mass is concentrated on the rim is given by,
[tex]I=mr^2^{}[/tex]The torque applied by the friction is given by,
[tex]\begin{gathered} \tau=I\alpha \\ =mr^2\alpha \end{gathered}[/tex]On substituting the known values,
[tex]\begin{gathered} \tau=1.47\times0.300^2\times-0.45 \\ =-0.06\text{ Nm} \end{gathered}[/tex]The negative sign of the torque indicates that the torque is applied to the wheel in the direction opposite to the direction of rotation of the wheel.
Thus the magnitude average torque due to frictional force is 0.06 Nm
Help! I've tried solving it a few times!
An electron travels 2.68 m in 6.11 × 10^-8 s. How fast does it travel in cm/s? Answer in units of cm/s.
Answers
If an electron travels 2.68 m in 6.11 × 10^-8 s, it will travel at a speed of 43.86 * [tex]10^{8}[/tex] cm / s
v = d / t
v = Velocity
d = Distance
t = Time
d = 2.68 m
t = 6.11 * [tex]10^{-8}[/tex]
v = 2.68 / 6.11 * [tex]10^{-8}[/tex]
v = 0.4386 * [tex]10^{8}[/tex] m / s
v = 0.4386 * [tex]10^{8}[/tex] * 10² cm / s
v = 43.86 * [tex]10^{8}[/tex] cm / s
One meter is equal to 100 centimeters. So in order to convert a meter value into centimeter, multiply the meter value by 100 or 10².
Therefore, the electron travels at 43.86 * [tex]10^{8}[/tex] cm / s
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A satellite orbiting Earth at an orbital radius r has a velocity v. Which represents the velocity if the satellite is moved to an orbital radius of 5r?(1 point)
Answers
The equation which represent the velocity, if the satellite is moved to an orbital radius of 5r is V = V/[tex]\sqrt\\5[/tex].
What is Orbital velocity?Orbital velocity or orbital speed is the minimum velocity a body must maintain to stay in an orbit. Due to the inertia of a moving body, the body has the tendency to move on in a straight path.
It is given that the radius is 5r
To find out the equation which represent the velocity if the satellite is moved to an orbital radius of 5r.
Mathematically, the orbital velocity is calculated by the formula:
V = [tex]\sqrt{GM}[/tex]/r
where, V = orbital velocity,
G = gravitational constant
M = mass of a satellite
r = radius
Substituting the value of r in this equation, we have:
V = [tex]\sqrt{GM}[/tex]/r
V = 1/ [tex]\sqrt{5}[/tex] × [tex]\sqrt{GM}[/tex]/r
V = [tex]\sqrt{GM}[/tex]/r
Therefore,
V = 1/ [tex]\sqrt{5}[/tex] × V
V = V/[tex]\sqrt{5}[/tex]
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When you drop a 0.38 kg apple, Earth exerts a force on it that accelerates it at 9.8 m/s2 to- ward the earth’s surface. According to Newtons third law, the apple must exert an equal but opposite force on Earth. If the mass of the earth 5.98 x 10^24 kg, what is the magnitude of the Earth's acceleration toward the apple? Answer in units of m/s^2
Answers
The magnitude of the earth’s acceleration toward the apple with a mass of 0.38 kg is 6.2 × 10⁻²⁵ m/s².
What is gravity?Gravity is a fundamental force which is responsible for causing mutual attraction between all the things with mass or energy.
The gravitational force can be calculated by the formula:
F = m.a
where, F = force
m = mass of an object
a = acceleration of the object
Here, the mass of the apple, m = 0.34 kg
The acceleration of the apple towards the earth's surface (a) = 9.8 m/s²
The mass of the Earth, M = 5.98 × 10²⁴ kg
Now, by applying Newton's Law of the motion,
The magnitude of the force on the apple due to Earth is can be calculated as:
F = m × a
F = 0.34 × 9.8
F = 3.724 N
According to the Newton's third law of motion, the apple must exert an equal but opposite force on Earth.
So, the magnitude of the force on Earth due to the apple will be:
F = 3.724 N
Let the magnitude of the earth’s acceleration towards the apple be 'A' m/s².
Thus, the magnitude of the earth’s acceleration towards the apple will be given by:
F = MA
M = mass of the Earth
A = acceleration of the Earth
3.724 = [5.8 × 10²⁴] × A
A = 3.724 / [5.8 × 10²⁴]
A = 0.6227 × 10⁻²⁴
A = 6.2 × 10⁻²⁵ m/s²
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This is astronomy and give explanations
Answers
The scientific study of all celestial objects is known as astronomy. Galaxies, planets, stars, comets, meteors, and other events affecting the celestial bodies are all observed and studied by astronomers.
The words "Astro," which means "star," and "nomos," which means "rule," are derived from ancient Greek. Astronomy, when combined, refers to "star law." The natural sciences are the ones that it is the oldest.
Since there are so many celestial objects to study, it is practical to divide astronomy into various branches.
Here are some of the more well-known astronomical fields-
1. Planetary Astronomy
2. Solar Astronomy
3. Stellar Astronomy
4. Galactic Astronomy
5. Observational Astronomy; etc.
Let's know more about its distinction with space exploration
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1. A force of 20 N is applied to extend a horizontal spring by 5 cm. What is the spring constant?
2. A spring has a spring constant of 15 N/cm. Which of the following hanging mass would produce an extension of 3.0 cm?
Answers
The spring constant is 400 N/m and The mass which would produce an extension of 3.0 cm is 0.0459 kg.
Here we are dealing with a problem related to hook's law which states that the force required to expand or compress a spring by a few distances is corresponding to that distance. This can be expressed scientifically as F= -kx, where F is the force connected to the spring and x is the displacement of the spring, with negative esteem illustrating the displacement of the spring once it is extended; and here k is the spring constant.
For the first case, we are given the force applied which is 20 N, and the extended length which is 5cm =0.05 m,
So the spring constant will be, k= F/x= 20/0.05 = 400 N/m
For the second case we are given that the spring constant which is 15 N/m and the extension is 3.0 cm =0.03 m.
Since we know F= mg ( where g is the acceleration due to gravity )
So the hanging mass, will be
=>F= kx
=>mg=kx
=>m=kx/g
=15 x0.03/9.8
= 0.0459 kg
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Identify the different types of energy transformation in each1. windmill Energy Transformation:2. FlashlightEnergy Transformation:3. Firecracker Energy Transformation:4. Bicycle Energy Transformation:5.Microwave Energy Transformation:Nonsense answer-reportGreat answer-brainliest
Answers
We will have the following:
1. Windmill: From wnd energy to mechanical energy.
2. Flashlight: From chemical energy to ligth energy and thermal energy.
3. Firecracker: From chemical energy to thermal energy and kinetic energy.
4. Bycicle: From mechanical energy to kinetic energy.
5. Microwave: From electric energy to thermal energy,
A lamp draws 0.50 A from a 120 V generator. (a) How much power does the generator deliver to the lamp? (b)How much electric energy does the lamp convert to light and heat in a period of 5.0 minutes?
Answers
Given:
The lamp draws the current is
[tex]I=0.50\text{ A}[/tex]The voltage supplied by the generator is
[tex]V=120\text{ V}[/tex]The time for which energy converted is
[tex]\begin{gathered} t=5\text{ min} \\ t=5\times60\text{ s} \\ t=300\text{ s} \end{gathered}[/tex]Explanation:
(a)
The power delivered by the generator is given by
[tex]P=VI[/tex]Plugging all the values in the above equation, we get
[tex]\begin{gathered} P=120\text{ V}\times0.50\text{ A} \\ P=60\text{ watt} \end{gathered}[/tex]The power delivered by the generator is
[tex]60\text{ watt}[/tex](b)
Energy is converted by the electric lamp is given by
[tex]E=Pt[/tex]Plugging all the values in the above relation, we get
[tex]\begin{gathered} E=60\text{ watt}\times300\text{ s} \\ E=18000\text{ J} \end{gathered}[/tex]Thus, the electric energy convert by the lamp is
[tex]18000\text{ J}[/tex]
19, 20, and 21 are confusing
Answers
1) Solid ,whose molecules are compactly arranged . so ,letter N
2) liquid state -the state in which molecules are arranged neither too compact nor loose . SO, letter O is pure liquid
3) letter Q is a pure gas
What is heat of fusion?The quantity of heat energy needed to convert a substance from a solid to a liquid is known as the heat of fusion. Enthalpy of fusion is another name for it. Joules per gram (J/g) or calories per gram (Cal/g) are typically used as its units. The solution to this example problem shows how to determine how much energy is needed to melt a sample of water ice.
What are the points to remember?The quantity of heat energy required to convert solid stuff into liquid is known as the heat of fusion (melting.)
Q = mHf is the formula for calculating heat of fusion.
The temperature is not a factor in the equation or the computation because matter does not truly change temperature when it changes states.
Heat of fusion is usually a positive value, with the exception of when melting helium.
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When a force is exerted on a box, an equal and opposite force is exertedby the box. These forces are calledforces.O action-reactionO frictionalO centripetalO gravitational
Answers
Explanation
Newton's third law states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction.
let's check a box on a table
Three point charges are located along the x-axis: q1 = +5.0 μC is at 20 cm, q2 = +4.0 μC is at 0 cm, and q3 = +10.0 μC is at –30 cm. What is the net electrostatic force on q2? 0.50 N to the left 500 N to the right 0.50 N to the right 8.5 N to the left
Answers
The correct answer is option C, 0.50 N to the left.
Given,
The charges,
q₁=5×10⁻⁶ C
q₂=4.0×10⁻⁶ C
q₃=10.0×10⁻⁶ C
The distance between the 1st charge and the second charge, r₁=20 cm=0.20 m
The distance between 2nd charge and the 3 rd charge, r₂=30 cm=0.30 m
As all the charges have the same sign, the nature of the force is repulsive. Thus the force applied by the q₂ is directed to the left. And the force applied by the charge q₃ is pointed to the right.
From Coulomb's law, the net electrostatic force on q₂ is given by,
[tex]\begin{gathered} F=\frac{kq_1q_2}{r^2_1}-\frac{kq_2q_3}{r^2_2} \\ =kq_2(\frac{q_1}{r^2_1}-\frac{q_3}{r^2_2}) \end{gathered}[/tex]On substituting the knwon values,
[tex]\begin{gathered} F=9\times10^9\times4\times10^{-6}(\frac{5\times10^{-6}}{0.20^2}-\frac{10\times10^{-6}}{0.30^2}) \\ =0.5\text{ N} \end{gathered}[/tex]Thus the magnitude of the net electrostatic force on the charge q₂ is 0.5 N
As the force to the left is greater than the force to the right, the net force will be directed to the left.
Therefore the correct answer is option A, 0.50 N to the left.
A wagon weighing 1000kg moves 50km/h on smooth rails. Later, a mass of 250 kg is placed in the wagon what is the velocity with which it moves?
Answers
The final velocity V is 40 km/h.
The final velocity V.
Mass of wagon m = 1000 kg
Initial velocity of wagon v = 50 km/h
Mass dropped velocity M = 250 kg
The final velocity =V
Initial system linear momentum [tex]P_{i}[/tex] = mv
=1000*50
=5*[tex]10^{4}[/tex] kg km/h
The system with the final velocity (wagon + mass dropped) be V .
Final system linear momentum [tex]P_{f}[/tex] = (m + M) V
=(1000+250)V
=1250 V
Basic principle of conservation of linear momentum,
[tex]P_{f}[/tex] = [tex]P_{i}[/tex]
1250V=5*[tex]10^{4}[/tex]
V=[tex]\frac{5*10^{4} }{1250}[/tex]
V= 40 km/h
So, the final velocity V is 40 km/h.
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Please help!!
Question in the picture
Answers
Set of equation which is true for the situation is
c) 2SA = SB and 2BA=BB
What is pressure?
Force applied perpendicular to the surface of an object per unit area is called pressure
SI unit of pressure is one newton per square meter (N/m2).
Given, length = 3 foot, width= 1 foot and height = 1 foot
1foot = 0.305m
Volume of tank A = 3*0.305*0.305*0.305
= 0.085
density of water= 1000kg/m^3
Pressure= 1000kg/m^3 *gravity * height
=1000kg/m^3 * 9.8 m/s^2* 0.305
=2989 N
Force exerted by water at bottom= P * A
= 2989*0.085
=254.065 Nm^2
similarly, for tank B
Given ,length = 6 foot, width =1 foot and height= 1foot
Volume of tank B = 6*0.305*0.305*0.305
=0.17
pressure= 1000kg/m^3 * 9.8m/s^2 * 0.305
= 2989 N
Force exerted by water at bottom = P*A
= 2989 * 0.17
=508.13 Nm^2
Hence proved that pressure exerted by tank B is twice that of tank A.
And same goes for pressure exerted on the side of the tank.
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my opponent will say that recycling is in an issue here but that's just because they don't care about the sea turtles or other marine life affected by plastic in the ocean what is a logical fallacy
Answers
The main three logical fallacies
AD HOMINEM
is intended at an individual rather than the argument they are making
STRAW MAN
presenting someone's point falsely or inaccurately in order to undermine it.
SLIPPERY SLOPE
supposing that a single, relatively unimportant incident will have a number of unforeseen effects and produce a noteworthy result.
A block is pulled to the right by a rope as shown above. Which of the following statements are true about the block?I. The normal force is equal to the weight.II. The normal force is mgcosθ.III. The horizontal component of F is Fcosθ.answer choice-I only.II and III onlyIII only.II only.I and III only.
Answers
Answer:
III only
Explanation:
The net vertical force is equal to 0 because the block is not moving up. Then, we can write the following equation
Fnet = N + Fsinθ - mg = 0
Where Fsinθ is the vertical component of the force F. Solving for the normal force N, we get:
N = mg - Fsinθ
Therefore, the normal force is not equal to the weight and the normal force is not mgcos(θ)
However, the horizontal component of F is Fcos(θ). So, the answer is
III only.
A pilot wishes to fly 2500km due South. The air speed of the plane is 300km/h and there is a wind of 50km/h from the West. What heading should the pilot take and what is the time required to complete the flight?
Answers
Since there is a wind speed of 50 km/h to the west, this speed needs to be compensated by the heading of the plane.
If we decompose the plane speed, one component will be used to cancel out the wind speed:
To find the orientation theta, we can calculate the east component of the plane speed and equate it to the wind speed:
[tex]\begin{gathered} V_{\text{east}}=V_{\text{wind}} \\ V\cdot\sin (\theta)=50 \\ 300\cdot\sin (\theta)=50 \\ \sin (\theta)=\frac{50}{300}=\frac{1}{6} \\ \theta=\sin ^{-1}(\frac{1}{6}) \\ \theta=9.59\degree \end{gathered}[/tex]Now, let's calculate the south component:
[tex]\begin{gathered} V_{\text{south}}=V\cdot\cos (9.59\degree) \\ V_{\text{south}}=300\cdot0.986 \\ V_{\text{south}}=295.8\text{ km/h} \end{gathered}[/tex]Calculating the required time of flight, we have:
[tex]\begin{gathered} \text{distance}=\text{speed}\cdot\text{time} \\ 2500=295.8\cdot t \\ t=\frac{2500}{295.8} \\ t=8.45\text{ hours} \end{gathered}[/tex]Therefore the orientation is 9.59° east of south and the time required is 8.45 hours.
If a car accelerated from 55 mi/hr to 16 mi/hr. in 3.2s how far did the car go while it was accelerating?
Answers
The cargo while it was accelerating at a distance of 0.602 meters.
Acceleration is the name we give to any system wherein the speed changes. on the grounds that speed is a pace and a direction, there are only two approaches so that you can boost up.
Velocity is the rate of change of displacement. Acceleration is the price of alternate velocity. velocity is a vector quantity because it consists of both significance and direction. Acceleration is likewise a vector quantity as it's far simply the charge of alternate velocity.
initial velocity = 55 m/hr
= 55/60× 60 m/sec
= 0.0152 m/sec
final velocity = 16 mi/hr
= 16/3600
= 0.0044 m/sec
time = 3.2 sec
V = u - at
a = ( U - V )/t
= (0.0152 - 0.0044)/t
= 0.0108 m/sec²
S = ut + 1/2at²
= 0.0152 × 3.2 sec + 1/2 × 0.0108 m/sec² × (3.2)²
= 0.0486 + 0.553
= 0.602 meter.
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The proper time between two events is measured by clocks at rest in a reference frame in which the two events: The proper time between two events is measured by clocks at rest in a reference frame in which the two events: a. are separated by the distance a light signal can travel during the time interval
b. occur at the same time
c. satisfy none of the above
d. occur in Nashville occur at the same coordinates
Answers
The correct option is option (D) occur in Nashville occur at the same coordinates.
In general proper time is the time interval between two events as measured by an observer who sees the event occur at the same position.
In geometry, a coordinate system is a device that makes use of one or more numbers, or coordinates, to uniquely determine the location of the points or different geometric factors on a manifold which includes Euclidean area.
Math coordinates discover the vicinity of a factor on a graph or map. The ordered pair, (x, y) is the cope with of the factor. The Cartesian coordinate gadget is the graph used to locate the point. The graph is split up into four quadrants.
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A 10 kg rubber block sliding on a concrete floor (µ = 0.65) Calculate the frictional force.
Answers
Answer:
Therefore the friction Force is 65 N.
Explanation:
Look at the image above.
The frictional force of the rubber block is 63.7N.
What is Frictional force?Friction is defined as a force that opposes the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are many types of friction such as dry friction which is defined as the force that opposes the relative lateral motion of two solid surfaces in contact.
This friction force is directed in the opposite direction to the motion of the object itself because the friction described so far between surfaces in relative motion is called kinetic friction.
For above given information,
mass of the block, m =10kg
coefficient of friction, µ=0.65
f=coefficient of the friction ×normal= µ*R
R= normal =mg = 9.8×10=98N
So, f =0.65×98=63.70N
≈65N(when g is taken as 10m/s²)
Thus, the frictional force of the rubber block is 63.7N.
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A bullet is shot from a rifle with a speed of 600 m/s. If a target is 2000 meters away, how long will it take
to hit the target?
Answers
The time taken for the bullet moving with a speed of 600 m/s to hit a target 200 meters away is 3.33 s.
What is time?
Time is the measured or measurable period during which an action, process, or condition exists or continues.
To calculate the time it takes the bullet to hit the target, we use the formula below.
Formula:
v = d/t.......... Equation 1Where:
v = Velocityd = distancet = timeMake t the subject of the equation
t = d/v............ Equation 2From the question,
Given:
d = 2000 metersv = 600 m/sSubstitute these values into into equation 2
t = 2000/600t = 3.33 secondsHence, the time it will take to hut the target is 3.33 seconds.
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Which ideas describe the big crunch? (1 point)
O After the universe reaches its expansion limit, gravity will pull it all back together.
O The big bang actually never occurred, and the universe must have a different origin.
O The universe goes through infinite cycles of expansion and contraction.
O The universe is not only composed of the objects that we can see.
Answers
Answer:
a
Explanation:
after the universe reach the limit, gravity does its thing
I’m not really sure if these answers are right so I’d really like some clarification! :)
Answers
A grinding wheel 0.35 m in diameter rotates at 2500 rpm. What is the linear speed of apoint on the edge of the grinding wheel?
Answers
Linear velocity (V) = r* w
where:
r = radius = diameter/2= 0.35 /2 = 0.175 m
w= angular velocity = rpm = 2500 = 2500/60 = 125/3 rps
1 revolution = 360° = 2pi rad/s = 125/3 2pi rad/s
= 261.8 rad/s
v = 0.175 m * 261.8 m/s = 45.8 m/s
A car starts from rest with constant acceleration achieves a velocity 15m/s when it travels a distance of 200m. Determine its acceleration and the time required.
Answers
3.7996 seconds are needed to accelerate it.
How does acceleration work?acceleration is the rate of change in both speed and direction of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. Because the direction is always shifting, motion on a circle accelerates even while the speed is constant.
So we have u= 0m/s, v=15m/s, s= 200m
So,2as= v^2-u^2
A= V^2 - U^2/2s
= 225/400
=0.5625 m/s^2
V=u + a*(t^2)
15=0+0.5625(t^2)
15-0.5625= t^2
=14.4375=t^2
root14.4375= root(t)
Time= 3.7996 seconds
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Archaeological samples are often dated by radiocarbon dating. The half-life of carbon-14 is 5,700 years.
After how many half-lives will the sample have only 1/64 as much carbon-14 as it originally contained?
How much time will have passed?
If the daughter product of carbon-14 is present in the sample when it forms (even before any radioactive decay happens), you cannot assume that every daughter you see is the result of carbon-14 decay. If you did make this assumption, would you overestimate or underestimate the age of the sample?
Answers
There are six half lives that have passed within 34,200 years. When we assume that we have some of the products present initially, then we overestimate the age of the sample.
What is the half life?The half life is the time taken to obtain only half of the number of atoms that were originally present in the radioactive material. We know that living things do contain the carbon- 14 isotope together with the carbon - 12 isotope in the substance. When the organism dies, the carbon - 14 which is radioactive begins to decay and its half life could be used to estimate the age of the sample as we know.
Given that after each half life, we have only half of the original amount that remains. We would have 1/64 of the original amount left after six half lives and this means that 34,200 years have passed.
If we the daughter product of carbon-14 is present in the sample when it forms (even before any radioactive decay happens), then we would over estimate the age of the sample.
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If a piece of ribbon were tied to a stretched string carrying a transverse wave, then how is the ribbon observed to oscillate?a.)perpendicular to wave directionb.)both perpendicular to and parallel to wave direction
Answers
The ribbon was observed to oscillate perpendicular to the wave direction. Option A.
In transverse waves, particles move perpendicular to the direction of wave propagation. Examples of transverse waves are string vibrations and water waves. By moving the Slinky vertically up and down, you can create horizontal transverse waves. Her one type of mechanical wave is the transverse wave.
where the motion of the medium is perpendicular to the direction of energy propagation. A transverse wave is a wave whose vibration is perpendicular to the direction of wave propagation. This is in contrast to longitudinal waves, which propagate in the direction of oscillation. Water waves are an example of transverse waves.
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In your readings you learned that “correlation does not imply causality.” Which of the following is the best interpretation of this statement?
A. Just because there is a relationship between two behaviors does not mean that one causes the other
B. Many factors influence the relationship between two behaviors.
C. A relationship between two behaviors does not mean that one or both behaviors are testable.
D. Correlated behaviors are the result of operational conditioning.
SOMEONE PLEASE HELP!
Answers
Just because there is a relationship between two behaviors does not mean that one causes the other. Option A.
Natural observation is a research method that observes objects in their natural environment. This approach is commonly used by psychologists and other social scientists. It is a process of deep reflection, questioning, and evidence evaluation. A study in which researchers look for relationships between people's demographic neighborhood and their level of prejudice.
Psychologists use this because it is the most objective method known to produce reliable insights. The science of behavior and mental processes. It attempts to describe and explain aspects of human thinking feeling perception and behavior. Naturalistic observation is a method of observation that involves observing people's behavior in environments in which they normally occur. Laboratory Observation observing behavior in a more artificial environment focusing on a small number of carefully defined behaviors.
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A vector is 148 m long and
points in a -96.3 degree
direction.
Find the x-component of the
vector.
Answers
The x-component of the vector is determined as -16.24 m.
What is the x-component of a vector?
The x-component of a vector is the vector component measured along x - direction. It is the vector acting in the x-coordinate.
The magnitude of x -component of a vector is given by the following formula as shown below;
Vₓ = V cosθ
where;
Vₓ is the x - component of the vectorV is the magnitude of the vector = 148 mθ is the angle of the vector = -96.3 degreesVₓ = 148 m x cos(-96.3)
Vₓ = -16.24 m
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Answer:
Y= -147
X= -16.24
Explanation:
A 75 kg student drives a 650 kg car. What is the applied force on the car if * 5 points the car starts from rest and accelerates to 60 m/s in 8 seconds?
Answers
Answer:
4500 N
Explanation:
Bc f is equal to mass times acceleration and the acceleration is 60
If a 75 kg student drives a 650 kg car, then the car starts from rest and accelerates to 60 m/s in 8 seconds, then the applied force on the car would be 5437.5 Newtons.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
The mathematical expression for Newton's second law is as follows
F = m × a
As given in problem an If a 75 kg student drives a 650 kg car, the car starts from rest and accelerates to 60 m/s in 8 seconds.
The acceleration of the car = 60 / 8
= 7.5 m / s²
The force applied on the car = 725 × 7.5
= 5437.5 Newtons
Thus, the applied force on the car would be 5437.5 Newtons.
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