The spontaneous disintegration of a nucleus into a slightly lighter and more radioactive nucleus is accompanied by the emission of particles, electromagnetic radiation, or both.
Radioactivity is the phenomenon of the spontaneous disintegration of unstable atomic nuclei into atomic nuclei to shape greater energetically strong atomic nuclei.
Radioactive decay is a tremendously exoergic, statistically random, first-order system that occurs with a small amount of mass being converted to strength.
Spontaneous disintegration of a radionuclide with the emission of lively particles or radiation, consisting of alpha or beta debris or gamma rays.
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write differences between homogeneous mixture and heterogeneous mixture
Answer:
Homo means same
Hetero means different.
Homogeneous mixtures have one phase, it all looks the same, Fruit juice is homogeneous, solutions are homogeneous.
Heterogeneous mixtures have different phases, you can see the different parts, pepper is an example of a heterogeneous mixture.
A homogeneous mixture - Think Kool Aid (Completely Dissolved)A heterogeneous mixture - Like pepper poured into a glass of milk.In a homogeneous mixture the constituents are able to dissolve in each other due to their similar intermolecular forces, whereas in a heterogeneous mixture the constituents are not miscible- meaning they can't dissolve in each other.
To clarify: intermolecular forces describe the way that types of molecules will interact with each other. For instance, water (a polar molecule) and naphthalene (a non-polar molecule) are said to be "immiscible" because their intermolecular forces do not match. The saying goes: "like dissolves like". Meaning that molecules that have similar IFs will be mutually soluble (miscible, in other words).
Homogenous means the same all over...every cubic millimeter is about the same as every other one. Like water or soda.Heterogenous means difference in places, like salsa, with slightly different chunks of stuff depending on where you dipped your chip.How many moles of PCl5 can be produced from 28.0 g of P4 (and excess Cl2 )? Express your answer to three significant figures and include the appropriate units.
0.903 mol of PCl₅ can be produced from 28.0 g of P₄ (and excess Cl₂).
What is Stoichiometry ?Stoichiometry helps us to use the balanced chemical equation to measure the quantitative relationship and it is to calculate the amount of product and reactants that are given in a reaction.
What is Balanced Chemical Equation ?The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now write the balanced chemical equation
P₄ + 10 Cl₂ → 4PCl₅
1 mole of P₄ react with 10 mole of Cl₂ produces 4 moles of PCl₅.
According to Stoichiometry
[tex]\frac{n_{P_4}}{1} = \frac{n_{PCl_5}}{4}[/tex]
[tex]n_{P_4} = \frac{\text{Given Mass}}{\text{Molar mass}}[/tex]
= [tex]\frac{28\ g}{124\ g/mol}[/tex]
= 0.22580645161 mol
Now put the value in above equation
[tex]\frac{n_{P_4}}{1} = \frac{n_{PCl_5}}{4}[/tex]
[tex]\frac{0.22580645161}{1} = \frac{n_{PCl_5}}{4}[/tex]
[tex]n_{PCl_5} = 0.903[/tex] mol
Thus from the above conclusion we can say that 0.903 mol of PCl₅ can be produced from 28.0 g of P₄ (and excess Cl₂).
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How can the arrangement of furniture in a room influence an individual’s behavior?
a.
The arrangement of furniture in a public room can either encourage or discourage social interaction.
b.
The arrangement of furniture in a room can influence an individual’s attitude toward survival.
c.
An individual’s overall mental health can be severely negatively impacted by the arrangement of furniture in a room.
d.
An individual’s behavior cannot be influenced by the arrangement of furniture in a room.
Please select the best answer from the choices provided
The arrangement of furniture in a public room can either encourage or discourage social interaction. The correct option is A.
What is social interaction?It is the process of exchanging information with others, verbally or otherwise.
The arrangement of furniture in a room filled with people can go a long way to encourage or discourage social interactions.
If physical barriers are put in between two seats such that people can barely see each other, the message may be that very little to no social interaction is allowed.
Without any physical barriers between seats, the message may be that people are free to interact, all other things being equal.
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You have been asked to determine the thermometer correction for a melting point apparatus. You obtain a pure sample of benzoic acid and determine its melting point range carefully. After several trials, you obtain a very sharp melting point of 125.7 degrees celsius. What is the thermometer correction at this temperature
The thermometer correction at this temperature is =125.7 -122.4
=3.3 degrees celsius
(Very pure benzoic acid has a melting point of 122.4 degrees Celsius.)
ThermometerA thermometer is a device used to measure and display temperature. It normally consists of a short, glass tube that is hermetically sealed, graduated, and has a mercury or alcohol bulb at one end that expands and contracts with temperature changes.
Calibration of thermometers:-A significant source of measurement error in melting points could be our thermometer. It is occasionally possible for ordinary laboratory thermometers to be inaccurate and to read temperatures up to 10°C high or low. we should calibrate your thermometer regularly to identify any errors and be able to make adjustments. This will help us avoid this issue.
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One of the nuclides in spent nuclear fuel is U-235 , an alpha emitter with a half-life of 703 million years. How long will it take for an amount of U-235 to reach 29.0% of its initial amount
It will take 1.254 billion years to reach 29% of the original amount of U-235.
First-order Radioactive Decay:The rate constant can be calculated from the half-life. The relationship of the two is shown below:
[tex]t_{0.5} =\frac{In 2}{k}[/tex]
[tex]k=\frac{In 2}{703}[/tex]
[tex]= 9.86[/tex] × [tex]10 ^-^{4} my^{-1}[/tex]
The first-order integrated rate law of a nuclide undergoing radioactive decay is;
ln[A]_t = -kt + ln[A]_0.
[tex]ln 0.29 = ln1 - 9.86[/tex] × [tex]10^-^4[/tex] [tex]t[/tex]
[tex]ln0.29= -9.86[/tex] × [tex]10^-^4[/tex]
[tex]t=[/tex] [tex]1254.5 my[/tex]
It will take 1.254 billion years to reach to 29% of the original amount.
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Use distributive law evaluate
Answer:
The distributive property of multiplication is used when we need to multiply a number with the sum of two or more addends. The distributive property of multiplication is applicable to addition and subtraction of two or more numbers.
Hope its helpful!
Answer:
The distributive property of multiplication is used when we need to multiply a number with the sum of two or more addends. The distributive property of multiplication is applicable to addition and subtraction of two or more numbers.
Explanation:
Commercial products commonly report concentration in terms of "percentage." Using this
technique, a 1% solution is considered to have 1 gram of solute for 100 milliliters of solution, and a
2% solution is considered to have 2 grams of solute for 100 milliliters of solution, and so on.
Clorox bleach claims to be 6.00% NaCIO. What is the molarity of NaCIO in Clorox bleach? Do not
type units into your answer.
The answer to the question is 0.8055 as the answer should not include units in it.
Molarity (M) = n/v
n = moles of solute
v = liters of solution
According to question
1% solution → 1 gram of solute for 100 milliliters of solution
2% solution → 2 grams of solute for 100 milliliters of solution
6% NaClO solution → 6 grams of NaClO (solute) for 100 milliliters of solution
Molar mass of NaClO = (22.98 + 35.5 + 16)g/mol = 74.48 g/mol
Atomic mass of Na = 22.98 g/mol
Atomic mass of Cl = 35.5 g/mol
Atomic mass of O = 16 g/mol
1 mol NaClO = 74.48 grams NaClO
74.48 grams NaClO = 1 mol NaClO
6 grams NaClO = (1×6) / 74.48 mole = 0.08055 mole
As unit molarity is mole / liter
So 100 milliliters = 0.1 liters
1 liter = 1000 milliliters
100 milliliters = 100/1000 liters = 0.1 liters
Molarity of NaClO = moles of solute (NaClO) / liters of solution or volume of solution
Molarity of NaClO = 0.08055 / 0.1 mole/L = 0.8055 mole/L
As in question it is mentioned that 'Do not type units into your answer'
So, Molarity of NaClO in clorox bleach = 0.8055
Thus we find out the value of molarity of NaClO in Clorox bleach which came out to be 0.8055 as we dont have to give the answer with units.
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Cold solvents are preferred for recrystallization because Group of answer choices Hot solvents catch fire easily to prevent dissolution of the crystals impurities are expected to have high solubility in cold solvents Cold solvents are cost effective
Crystals impurities are expected to have high solubility in cold solvents. Hence, option C is correct.
What is a cold solvent?Cold solvent cleaning is a process used to remove grease, wax and other impurities from metal and other parts.
The process is also called degreasing. Cold solvents are sprayed onto the dirty part and it is brushed clean.
Once the filtration process is done the collected crystals should be washed with a little more ice-cold solvent to remove final soluble impurities which would otherwise be left on the surface of the crystals.
Hence, option C is correct.
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Project: practice in measuring metric volumes
Either a Pyrex measuring cup or a graduated cylinder can be used to measure the metric volumes of any liquid.
What is a graduated cylinder?A graduated cylinder is also called a measuring cylinder and it can be defined as a narrow, cylindrical piece of laboratory equipment with marked lines, which are used to measure the volume of a liquid.
How to measure metric volumes?Generally, a student or researcher can use a Pyrex measuring cup to measure the metric volumes of any liquid when a graduated cylinder isn't available.
In conclusion, you should record your estimates and the actual measurements for all the containers that were used in your project.
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1.What is the specific heat capacity of granite when 20 kg absorbs 237 000 J of heat energy, causing its temperature to increase by 15 °C? (you are finding c)
Given :
Amount = 20 kgHeat energy absorbed = 237,000 JTemperature change = 15 °CFormula applied :
[tex]\boxed {Q = mc \triangle T}[/tex]
Q = absorbed heatm = massc = specific heat capacityΔT = temperature changeLet's solve for c !
⇒ 237,000 = 20 × c × 15
⇒ c = 237,000 ÷ 300
⇒ [tex]\boxed {c = 790 J kg^{-1} K^{-1}}[/tex]
∴ The specific heat capacity of granite is 790 J kg⁻¹ K⁻¹.
word equation into balanced formula equation and also mention the types of reaction sodium➕chlorinesodium chloride
Answer:
it's
answer
is
chlorinesodium gives sodium a different texture
.
.
.
.
.
.
.
.
.
.
.
.
Which of the following diagrams
represents a compound? Each color
represents a different element. Circles
that are directly touching represent
elements that are chemically combined.
Please helpppp!!!!!!!
Answer:
NaCl + H²O
Double replacement
Answer:
HCL + NAOH ------ Nacl + h2o here double displacement reaction takes place Na displaces h from its salt solution and form a bond with cl to make Nacl. the remaining H and OH forms a bond as h+ and oh- gives H2o( water) na+ and cl- as NaclAn intravenous solution is noted as having a concentration of glucose equal to 0.312 M. What volume of solution (in mL) is needed to deliver 0.078 moles of glucose to the patient?
From the calculations, the volume of the solution is 0.25 L.
What is concentration?The term concentration refers to the amount of solute in a solution. It is obtained as the ratio of the number of moles and the volume.
Given that;
number of moles = 0.078 moles
concentration = 0.312 M
n = CV
V = n/C
V = 0.078 moles / 0.312 M
V = 0.25 L
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Calculate the pH of 720. mL of a 0.425-M solution of hydrocyanic acid before and after the addition of 0.249 mol of sodium cyanide.
The pH of hydrocyanic acid before and after the addition of sodium cyanide is 0.371 and 9.121
Calculation of pH of 720:
Given: Concentration of hydrocyanic acid (HCN) = 0.425 M
To find: pH
Reaction:
[tex]HCN \,\,\,\,\,\rightarrow \,\,\,\,\,\,H^+ + CN^-[/tex]
0.425M 0.425M
[tex]pH= -[logH^+]\\pH=-[log\,0.425]\\pH= 0.371[/tex]
pH after adding 0.249 mol of sodium cyanide (NaCN)
Pka of HCN= 9.21
Concentration of sodium cyanide = [tex]\frac{0.249}{0.720}\,M[/tex]
Concentration of NaCN= 0.346 M
According to Henderson–Hasselbalch equation:
[tex]pH= p_k_a + log\frac{salt}{acid}[/tex]
Putting the values in the above equation,
[tex]pH= 9.21 + log\frac{0.346}{0.425} \\\\pH= 9.21 - 0.089\\pH= 9.121[/tex]
Note: Pka value of HCN is assumed as 9.21
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Identify the Bronsted-Lowry base:
the numbers are subscripts.
Group of answer choices
a)KOH
b)BF3
c)KCl
d)Her
Answer:
Bronsted-Lowry's base is A)KOH
KOH
KOH on dissolving in water gives two ions K+ and OH-OH- can accept one H+As it accepts proton it acts as bronsted Lowry baseWhen excess dilute hydrochloric acid was added to sodium sulphite 960 of sulphuric (iv) oxide was produced. calculate the mass of sodium sulphate that was used
The mass of sodium sulfite that was used will be 1,890 grams.
Stoichiometric problemsFirst, the equation of the reaction:
[tex]NaSO_3 + 2HCl --- > NaCl_2 + H_2O + SO_2[/tex]
The mole ratio of SO2 produced and sodium sulfite that reacted is 1:1.
Mole of 960 grams SO2 = 960/64 = 15 moles
Equivalent mole of sodium sulfite that reacted = 15 moles
Mass of 15 moles sodium sulfite = 15 x 126 = 1,890 grams
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Samples of this drawing medium have been dated back to 30,000 BCE. Group of answer choices silverpoint charcoal pencil color pencil pastel
Charcoal is the sample of this drawing medium have been dated back to 30,000 BCE and is denoted as option B.
What is Charcoal?This is referred to a black carbon residue which is heated in insufficient oxygen to give it a light weight.
It is used for drawing and has been in existence for as long as 30,000 BCE hence the reason why it is the most appropriate choice.
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A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The calorimeter and the water have a combined mass of 250.0 g and an overall specific heat of 1.035 cal/g•°C. The initial temperature of the calorimeter is 10.00°C. The system reaches a final temperature of 11.08°C when the metal is added.
Taking into account the definition of calorimetry, the specific heat of metal is 0.165 [tex]\frac{cal}{gC}[/tex].
Definition of calorimetryCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where:
Q is the heat exchanged by a body of mass m.C is the specific heat substance.ΔT is the temperature variation.Specific heat capacity of the metalIn this case, you know:
For metal:
Mass of metal = 50 gInitial temperature of metal= 45 °CFinal temperature of metal= 11.08 ºCSpecific heat of metal= ?For water:
Mass of water = 250 gInitial temperature of water= 10 ºCFinal temperature of water= 11.08 ºCSpecific heat of water = 1.035 [tex]\frac{cal}{gC}[/tex]Replacing in the expression to calculate heat exchanges:
For metal: Qmetal= Specific heat of metal× 50 g× (11.08 C - 45 C)
For water: Qwater= 1.035 [tex]\frac{cal}{gC}[/tex] × 250 g× (11.08 C - 10 C)
If two isolated bodies or systems exchange energy in the form of heat, the quantity received by one of them is equal to the quantity transferred by the other body. That is, the total energy exchanged remains constant, it is conserved.
Then, the heat that the gold gives up will be equal to the heat that the water receives. Therefore:
- Qmetal = + Qwater
- Specific heat of metal× 50 g× (11.08 C - 45 C)= 1.035 [tex]\frac{cal}{gC}[/tex] × 250 g× (11.08 C - 10 C)
Solving:
- Specific heat of metal× 50 g× (-33.92 C)= 1.035 [tex]\frac{cal}{gC}[/tex] × 250 g× 1.08 C
Specific heat of metal× 1696 g×C= 279.45 cal
Specific heat of metal= [tex]\frac{279.45 cal}{1696 gC}[/tex]
Specific heat of metal= 0.165 [tex]\frac{cal}{gC}[/tex]
Finally, the specific heat of metal is 0.165 [tex]\frac{cal}{gC}[/tex].
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Science is divided in various fields of study except:
Science is divided into various fields of study except for pseudoscience which is not based on the scientific method.
What is science?Science refers to the total body of knowledge obtained by applying the scientific method.
Science can be divided into physical sciences, mathematics, life sciences, and social sciences.
In conclusion, science is divided into various fields of study except for pseudoscience which is not based on the scientific method.
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Are isotopes similar to ions, yes or no?
You wish to make a 0.375 M hydroiodic acid solution from a stock solution of 6.00 M hydroiodic acid. How much concentrated acid must you add to obtain a total volume of 175 mL of the dilute solution
We need to add 2.09 mL of concentrated acid to obtain 75 mL of 0.335 M HBr solution.
You are performing a dilution of HBr going from a concentration of 12M to 0.335M, and you want to end up with a final volume of 75 ml of the dilute solution.
Consider the dilution formula: M1V1 = M2V2.
The basis behind this formula is that the number of moles of the acid before and after the dilution must remain constant.
M1 = the molarity of the stock solution,
M2 = the molarity of the diluted solution,
V2 = the final volume of the diluted solution.
In this case, we need to determine V1, which is the volume of the stock solution used to prepare the diluted sample. With this knowledge, we can plug our numbers into the equation and we obtain the following:
(12 mol/L)*V1 = (0.335mol/L)*(0.075L).
Keeping in mind that molarity is the moles of a substance in one liter of solution, we will use mol/L instead of M. By doing this, we are reminded that in order to use this equation, we must convert 75 mL into units of liters.
After rearranging the equation and solving for V1, we find that V1 = 0.00209L.
Finally, we must convert back from liters to mL by multiplying the final answer by 1000.
This way we end up with V1 = 2.09 mL.
This means that we need to add 2.09 mL of concentrated acid to obtain 75 mL of 0.335 M HBr solution.
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Calculate the mole fraction of each component in a solution of 42 g CH3OH, 35 g of chloroform CHCl3, and 50 g C3H7OH
Considering the definition of mole fraction, the mole fraction of each component in the solution is:
CH₃OH: 0.54 CHCl₃: 0.118C₃H₇OH: 0.342Mole fractionThe molar fraction is a way of measuring the concentration that expresses the proportion in which a substance is found with respect to the total moles of the solution.
Mole fraction of each component
In this case, in first place you should know that the molar mass of each component is:
CH₃OH: 32 [tex]\frac{g}{mole}[/tex] CHCl₃: 121.35 [tex]\frac{g}{mole}[/tex]C₃H₇OH: 60 [tex]\frac{g}{mole}[/tex]Now, the number of moles of each compound can be calculated as:
CH₃OH: [tex]\frac{42 g}{32\frac{g}{mole}}[/tex]= 1.3125 molesCHCl₃: [tex]\frac{35 g}{121.35\frac{g}{mole}}[/tex]= 0.2884 molesC₃H₇OH: [tex]\frac{50 g}{60\frac{g}{mole}}[/tex]= 0.8333 molesSo, the total moles of the solution can be calculated as:
Total moles = 1.3125 moles + 0.2884 moles + 0.8333 moles
Total moles = 2.4342 moles
Finally, the more fraction of each component can be calculated as follow:
CH₃OH: [tex]\frac{1.3125 moles}{2.4342 moles}[/tex]= 0.54 CHCl₃: [tex]\frac{0.2884 moles}{2.4342 moles}[/tex]= 0.118C₃H₇OH: [tex]\frac{0.8333 moles}{2.4342 moles}[/tex]= 0.342In summary, the mole fraction of each component in the solution is:
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Will a real gas ever reach absolute zero? Will an ideal gas ever reach absolute zero? Why or why not? Compose a report that answers these two questions. 125 words.
It is impossible to reach absolute zero because the magnitude of work that is required to remove energy from a gas in order to attain the absolute zero is so high.
What is the absolute zero?The absolute zero is the temperature at which the movement of all the gas molecules is theoretically believed to cease. At the absolute zero, gas molecules remain at fixed positions because according to the third law of thermodynamics, the entropy of a perfectly ordered system is zero.
It is impossible to reach absolute zero because the magnitude of work that is required to remove energy from a gas in order to attain the absolute zero is so high such that it is impractical to attain the absolute zero.
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To which group does copper belong?
a. Metalloid
b. Alkaline earth metal
c. Alkali metal
d. Transition metal
Answer:
d. Transition metal
Explanation:
Copper is in transition metal block in periodic table.
Answer:
Copper belongs to the d. transition metal group.
Explanation:
Copper's d-shell is partially filled making it a transition metal. Copper is one of the few transition metals that has a set charge. Copper's charge is +2.
When referring to the periodic table, copper is in the middle section of the table which is the transition metals. It is between the metals and the non-metals.
Use the given data set to determine the rate equation, including the constant, for each of the following reactions. Assume the reaction has the form X + Y → Z. State the overall reaction order for each reaction.
The overall order of reaction is 2.
What is the rate of reaction?The rate of reaction is the rate at which reactants are converted into products.
Now we have;
0.050/0.025 = k[0.4]^x [0.1]^y/k[0.2]^x [0.1]^y
2= 2^x
x = 1
Also;
0.075/0.025 = k[0.2]^x [0.3]^y/[0.2]^x [0.1]^y
3 = 3^y
y =1
Overall order of reaction = x + y = 1 + 1 = 2
The overall order of reaction is 2.
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When drawing structures from compound names, _____ are given priority in numbering carbons over _____.
Answer:
Triple bonds; double bonds
Explanation:
Triple bonds; double bonds
300 mL of salt solution contains 6.5 grams of NaCl (molecular mass of sodium chloride is 58.44 ul.
What is its molarity?
M=n/V
M=(6.5/58.44) mol : 0.3 L
M=0.371
Answer:
.371 M
Explanation:
Molarity, M, is calculated as moles solute/ liters of solvent
6.5 gms of salt is 6.5 / 58.44 = .111225 moles
300 ml = .3 L
.111225 moles / .3 L = .371 M
3.03 Plate Tectonics
Objective(s):
In your own words, what was the purpose of this lab?
Hypothesis:
In this section, please include the if/then statements you developed during your lab activity for each location on the map. These statements reflect your predicted outcomes for the experiment.
Location One: Select two events that you predict will be observed. If I explore two continental plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Two: Select three events that you predict will be observed. If I explore two continental plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Three: Select three events that you predict will be observed. If I explore two continental plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Four: Select two events that you predict will be observed. If I explore two oceanic plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Five: Select three events that you predict will be observed. If I explore two oceanic plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Six: Select two events that you predict will be observed. If I explore two oceanic plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Procedure:
The procedures are listed in your virtual lab. You do not need to repeat them here. Please be sure to identify the test variable (independent variable), outcome variable (dependent variable).
Reminder: Test variable = the item you are changing or manipulating; Outcome variable = the item you are measuring
Test variable (independent variable):
Outcome variable (dependent variable):
Data:
Record the data from each location below.
Location Name
Boundary Type
(C=Convergent, D=Divergent, or T=Transform)
Year Observed
(5, 10, or 20 million years)
Geologic Events Observed
(earthquakes, faults, ocean formation, mountains, volcanoes, island chains, seafloor spreading)
Location One
Himalayas
5
Event 1-
20
Event 2-
Location Two
East Africa
5
Event 1-
10
Event 2-
20
Event 3-
Location Three
San Andreas fault zone
5
Event 1-
10
Event 2-
20
Event 3-
Location Four
Aleutian Islands
5
Event 1-
20
Event 2-
Location Five
Mid-Atlantic Ridge
5
Event 1-
10
Event 2-
20
Event 3-
Location Six
Alpine Fault
5
Event 1-
20
Event 2-
Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please write in complete sentences.
What types of geological events or changes occur at divergent plate boundaries?
What types of geological events or changes occur at convergent plate boundaries?
What types of geological events or changes occur at transform plate boundaries?
Explain how these geological processes and interactions have changed Earth's surface through the years. Be sure to use evidence to support your answer.
The types of geological events or changes that occur at divergent plate boundaries are earthquakes and magma because there is a fault when two plates move away from each other.
The types of geological events or changes that occur at convergent plate boundaries are earthquakes, volcanoes, and the formation of mountains because the tectonic plates are moving towards each other.
The types of geological events or changes that occur at transform plate boundaries are shallow earthquakes, lateral displacement of rock, and a broad zone of crustal deformation.
These geological processes have changed the surface of the earth as they have helped to form ocean basins, and mountain chains, and the formation of glaciers and volcanoes, and earthquakes have changed the underground geology of the earth.
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How many moles of ammonia are in 0.40 l of a 6.00 m ammonia solution?
if this solution were diluted to 1.00 l, what would be the molarity of the resulting solution?
Moles of ammonia is 2.4 moles
Molarity of solution after dilution is 2.4 M
Given:
volume of ammonia solution = 0.40 l
molarity of solution = 6.00 m
To Find:
moles of ammonia
Solution:
1 molar (M) solution will contain 1.0 GMW of a substance dissolved in water to make 1 liter of final solution
M = n / V
M is the molality of the solution that is to be calculated
n is the number of moles of the solute
V is the volume of solution given in terms of litres
n = M x V
= 6 x 0.4
= 2.4 moles
So moles of ammonia are 2.4 moles
molarity of the resulting solution after dilution
M = n/V
= 2.4/1
= 2.4 M
So Molarity after dilution will be 2.4 M
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