1. if a mass of 0.55 kg attached to a vertical spring stretches the spring 2.0 cm from its equilibrium position, what is the spring constant of the spring?

Answers

Answer 1

The spring constant of the spring is 270N.

The force needed to extend or compress a spring is divided by the lengthening or shortening is used to determine the spring constant. It refers to the proportional constant k. It measures the spring's rigidity.

Given mass (m) = 0.55 kg, x = -2 cm = -0.2 m, and g = 9.81 m/s.

The net force is given by, NetF = Elastic Force + Gravity

Elastic force = -kx (k is spring constant and x is stretch length) and Gravity = -mg (m is mass and g is gravitational constant)

Net F = 0 = -kx-mg

Then, the spring constant is calculated as follows,

k=-mg/x

k=-(0.55 kg×9.81 m/s)/-0.2 m

k=270N

The answer is 270N.

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Related Questions

the 2-lb brick slides down a smooth roof, such that when it is at a it has a velocity of 5 ft/s.

Answers

The unstretched length so that it does not allow the block to leave the surface until θ= 60° is L = 4.574 ft.

Given:

The weight of the block W = 2 lb

The initial velocity of the block v_i = 0

The stiffness of the spring k = 2 lb/ft

The radius of the cylindrical surface r = 2 ft

Compute the velocity of the block at θ= 60°. Use Newton's second equation of motion in direction normal to the surface.

= F_n = m X a_n

Where, a_n is the centripetal acceleration or normal component of acceleration as follows:

= a_n = v²_2 / r

Substitute:

= F_n = m*v²2 / r

Where, F_n normal force acting on block by the surface is:

= F_n = W X cos(θ)

Substitute:

W*cos(θ) = m*v^2_2 / r

v_2 = sqrt ( r*g*cos(θ) )

Plug in the values:

v²_2 = 2 X 32.2 X cos(60)

v²_2 = 32.2 (ft/s)²

Apply the conservation of energy between points A and B where θ= 60° :

T_A + V_A = T_B + V_B

Where,

T_A : Kinetic energy of the block at initial position = 0

V_A: potential energy of the block initial position

V_A = 0.5 X k X x_A²

x_A = 2 X π- L           ( L is the original length )

V_A = 0.5X 2 X (2 X πi - L)² =

= (2 X pi - L)²

T_B = 0.5 X W/g X v_2² =

= 0.5 X 2 / 32.2 X 32.2 = 1

V_B = 0.5 X k X x_B² + W X 2 X cos(60)

and, x_B = 2 X 0.75 X π - L             ( L is the original length )

V_B = 0.5 X 2 X (1.5 X π - L)² + 2 X 1

= 2 + ( 1.5 X π- L )²

Input the respective energies back in to the conservation expression:

= 0 + (2π - L)² = 1 + 2 + ( 1.5π - L )²

= 4π² - 4πL + L² = 3 + 2.25π² - 3πL + L²

= πL = 1.75π² - 3

= L = 4.574 ft

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The complete question;

the 2-lb brick slides down a smooth roof, such that when it is at a it has a velocity of 5 ft/s. The 2-lb block is released from rest at A and slides down along the smooth cylindrical surface. Of the attached spring has a stiffness k = 2 lb/ft. Determine its unstretched length so that it does not allow the block to leave the surface until θ= 60°.

you apply a 20 n force to a box and the friction force is 8 n. the box slides 2 m. what is the total work done on the box?

Answers

The total work done on the box is found to be 24 Joules.

A force of 20 newton is applied on the box where the friction force of 8 newton is also working the box is slide to a distance of 2m.

The total work done on the box can be calculated by using the relation,

W = (F-Fr)d

Where,

W is the work done,

F is the applied force,

Fr is the frictional force and,

d is the distance to which the box slides.

Here, we are subtracting the applied force and the frictional force because they are in the opposite directions.

Putting values,

W = (20-8)2

W = (12)2

W = 24 J.

So, the work done on the box is 24 Joules.

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describe how the milky way's light output compares with those of the most luminous galaxies in the blue cloud, based on the information in

Answers

The Milky Way is near the top of the luminosity range for blue cloud galaxies. Spiral galaxies usually have a luminosity of a few hundred billion Suns and Milky Way's luminosity is about 1.5 x 10¹⁰, making it near the top of the blue cloud galaxies.

Generally, a galaxy's absolute magnitude (a measure of luminosity) is related to its mass. The relationship can be visualized in a galaxy color-magnitude diagram with three populations:

Red sequence: includes most red galaxies that are usually elliptical shaped. They are red because of a highly far distance, contain many old, red stars, or are really dusty.Green valley: composed of either late-type galaxies (star formation is getting exhausted) or early-type galaxies.Blue cloud: includes most blue galaxies that are usually spiral-shaped.

The Milky Way is a spiral galaxy. Spiral galaxies usually produce more stars because the spiral arms generate dense compression areas that provide a good environment for the formation of stars.

Your question seems incomplete, but most likely the completed version is as follows:

The luminosity of our Milky Way galaxy is about 1.5 x 10¹⁰ Lsun. Describe how the Milky Way's light output compares with those of the most luminous galaxies in the blue cloud, based on the information in Figure 1.

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can an elliptical galaxy evolve into a spiral? explain your answer. can a spiral turn into an elliptical? how?

Answers

Due to the fundamental differences between these two galaxy types, galaxies cannot evolve from elliptical to spiral (or spiral to elliptical).

It seems that spirals do create elliptical galaxies when they collide. Each one starts out as a spiral galaxy, and an elliptical galaxy is created when galaxies collide and combine.

For example, in contrast to spiral galaxies, which include gas and dust as well as hot, bright O and B type stars, elliptical galaxies are devoid of visible gas and dust and hot, brilliant stars.

A galaxy with an elliptical shape and a uniform brightness distribution is called an elliptical galaxy (no spiral arms). Elliptical galaxies are stretched galaxies with an elliptical shape, according to astronomical physics. The light is distributed evenly and smoothly throughout this type of galaxy, which is typically composed of old stars.

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why can we readily observe diffraction effects for sound waves and water waves, but not for light? is this because light travels so much faster than these other waves? explain.

Answers

Wavelengths of sound waves fall within such obstacles and are easily diffracted.

Sound waves have higher wavelengths, which are comparable in dimension to opaque encounters in our everyday life. Thus, diffraction effects are more visible in sound waves than in light waves. Sound waves have much longer wavelengths than visible light waves.

Wavelength is the distance between identical points in adjacent cycles of a waveform signal propagating in space or along a wire. In wireless systems, this length is usually expressed in meters, centimeters, or millimeters. Wavelength is the distance between two wave crests and the same for wave troughs.

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identify the stage in star life cycle in which hydrogen is the primary fuel for nuclear fusion?

Answers

Answer:

Main sequence star: (b) burns hydration as its primary fuel.

Explanation:

what is the energy of the atom in each of the levels (n=1, n=2, etc.) shown in the figure?

Answers

Since the second energy level has more energy than the first, the electron must gain energy to travel from n = 1 to n = 2. To increase to the second energy level, it must gain (-3.4) - (-13.6) = 10.2 eV of energy.

By absorbing light, the electron can obtain the energy it requires. The electrons in an atom revolve around the nucleus. Small, negatively charged particles known as electrons move in a circular orbit around the nucleus. They are unable to move around at will in any location. Depending on their energy levels, their revolution is limited to certain orbits. Energy levels are nothing more than the electrons' set distances from an atom's nucleus. The electron shell is another name for the energy levels. An electron can migrate across energy levels, but it cannot remain in one energy level while in another.

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if the highest frequency of a circuit is 10 khz and the lowest frequency is 900 hz, the bandwidth available for this circuit is:

Answers

When the highest and lowest frequency of a circuit is given then bandwidth is  calculated as 9100 Hz.

What is bandwidth?

Maximum amount of data transmitted over an internet connection in given amount of time is known as bandwidth. Bandwidth is actually the volume of information that can be sent over a connection in a measured amount of time.

In signal processing, bandwidth describes difference between upper and lower frequencies in transmission signals. The measurement of bandwidth of a signal is done in hertz (Hz).

Given highest frequency of circuit is 10 kHz

= 10000 Hz

and lowest frequency of circuit is 900 Hz

Bandwidth = 10000 Hz -900 Hz

So, Bandwidth = 9100 Hz.

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a 8.0-m long wire with a mass of 10 g is under tension. a transverse wave for which the frequency is 570 hz, the wavelength is 0.10 m, and the amplitude is 3.7 mm is propagating on the wire. the maximum transverse acceleration of a point on a wire is closest to:______.

Answers

The maximum transverse acceleration of a point on a wire is closest to 47,458.2 m/s²

What is the angular speed of the transverse wave?

The angular speed of the transverse wave is calculated as follows;

ω = 2πf

where;

f is the frequency of the wave

ω = 2πf

ω = 2π ( 570 )

ω = 3,581.4 rad/s

The maximum transverse acceleration of a point on a wire is calculated as follows;

a = ω²A

where;

A is the amplitude of the wave = 3.7 mm = 0.0037 m

a = ω²A

a = (3581.4)²(0.0037)

a = 47,458.2 m/s²

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The input preure on a hydraulic lift i 1200 Pa. If the output force on the other ide i 800 N, what i the output urface area?

Answers

A hydraulic lift's input pressure is 1200 Pa. If the output force on the other side is 800 N, the output surface area is 0.67m^2

Given the input pressure (P1) = 1200Pa

Output force (F2) = 800N

We know that P= F/A where A is area of cross section

Let the input force be F1 and area is A1

Then by pascals law we say that:

F1/A1 = F2/A2

1200 = 800/A2 (since P1= F1/A1)

A2 = 8/12 = 0.67m^2

Hence the area of other side = 0.67m^2

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FILL IN THE BLANK. The period of a sine or cosine function is given by ______. phase shift. For the function given by y = sin(bx-c), c/b represents the ______ ______ of the ...

Answers

The period of a sine or cosine function is given by 2Pi/b.

For the function given by y = sin(bx-c), c/b represents the phase shift of the graph of the function.

A period is the amount of time between two waves, whereas a periodic function is one whose values recur at regular intervals or periods. In other terms, a periodic function is one whose values recur after a specific interval.

If we have f (a + m) = f (a), then a function f will be periodic with period m for every m > 0.

It demonstrates that after an interval of "m," the values of the function f(a) remain the same.

One may state that the function f repeats all of its values after every interval of "m."

Phase shift merely denotes that the two signals are, at any given time, at different positions in their cycle.

Phase shift, which depicts how each wave moves through its cycle, is measured as the angle (in degrees or radians) between two points on a circle at the same moment.

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The electric force between two or more charged objects depends on which of the following quantities?

a. charge and distance between the charged objects
b. quantity of charges and their masses
c. charge and mass of charged objects
d. mass and distance between the charged objects

Answers

The electric force between two or more charged objects depends on the charge and the distance between the charged objects

What is Coulomb's law?

Coulomb's law states that the force of attraction or repulsion between two charged bodies is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Coulomb's law shows the relationship between the force , charge and the distance between the bodies

therefore F= kq1q2/r²

where q1 is the charge of body 1 and q2 is the charge of body 2. r is the distance between them and k is called electrostatics constant which have a value of 9,×10⁹ Nm²/C²

Therefore what can affect the force between two charges are the product of the charge of the two bodies and the distance between the two charge.

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Explain why the angle is important when launching projectile motion 

Answers

Answer:

The angle at which a projectile is launched is important because it determines the initial velocity of the projectile and the direction in which it will travel. The angle also affects the projectile's trajectory, or the path that it follows through the air. The steeper the launch angle, the higher the projectile will go and the farther it will travel horizontally. A shallower launch angle will result in a flatter trajectory that does not go as high or travel as far. Therefore, the angle at which a projectile is launched is a key factor in determining how far and how high it will go.

Explanation:

The angle is important when launching projectile motion because it in the calculation of the maximum height, range and time of flight, angle of launching  is as important as the magnitude of initial velocity.

What is projectile motion?

When a particle is hurled obliquely near the surface of the earth, it travels along a curved path while accelerating continuously in the direction of the planet's center (we assume the particle stays close to the surface of the globe). Such a particle's motion is known as projectile motion, and its route is referred to as a projectile.

Two distinct rectilinear motions occur simultaneously in a projectile motion:

Uniform velocity along the x-axis is what causes the particle to move horizontally (ahead).Uniform acceleration along the y-axis is what causes the particle to move vertically (downwards).

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A child on a spinning ride at a playground has a centripetal acceleration of 0.80 m/s2. The child completes a full circle every 4.2 s.

How far from the center of the ride is the child?

Answers

The velocity of the child is 3.36 m/s. Then, the distance it covered is 14 meters. The radius from the centre is then, 2.24 m.

What is centripetal acceleration?

Centripetal acceleration is the acceleration of a body moving through a circular paths. It is the rate of change of its angular velocity.

The acceleration of the child = 0.80 ms/²

time  = 4.2 s

velocity = time interval × acceleration

             = 4.2 s ×  0.80 ms/²= 3.36 m/s.

Then the distance covered  = velocity × time

= 3.36 m/s × 4.2 = 14.22 m.

This is the circumference of the circular path which is equal to 2πR.

The distance from the centre = radius of the path.

2πR = 14.22 m

R = 2.24 m

Therefore, the child will be 2.24 m far from the center of the ride.

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016 (part 1 of 2) 10.0 points
A neutron in a reactor makes an elastic headon collision with the nucleus of an atom initially at rest.
Assume: The mass of the atomic nucleus is
about 11.1 the mass of the neutron.
What fraction of the neutron’s kinetic energy is transferred to the atomic nucleus?
017 (part 2 of 2) 10.0 points
If the initial kinetic energy of the neutron is
4.2 × 10−13 J, find its final kinetic energy.
Answer in units of J.
No Rounding

Answers

The fraction of the neutron's kinetic energy transferred to the atomic nucleus is 2.05

If the initial kinetic energy of the neutron is

4.2 × 10−13 J, its final kinetic energy  will be 2.50 joules

What is kinetic energy?

kinetic energy of an object is described as the energy that it possesses due to its motion which is also the work needed to accelerate a body of a given mass from rest to its stated velocity.

In elastic head-on collision, the energy of the system and total momentum is conserved.

For the neutron,

m - mass

Vi - initial velocity

Vf - final velocity

For the atom ,

M- mass

Mi - initial velocity

Mf - final velocity

Conserved momentum on the head-on collision

mvi = mvf + MVF

vi - vf = MmVf

Vi- vf = 11.1 vf...... (i)

The kinetic energy is

Vi²- vf² = 11.1 v²f.......(ii)

Combining both equations

Vi + Vf = Vf

Solve equation (I) and (III) for Vi

vi = 5.4vf

Now, the fraction of the neutron's kinetic energy transferred to the atomic nucleus,

1/2 mv²f/ 1/2 mv²i = 11.1/ 5.4

If the initial kinetic energy of the neutron is

4.2 × 10−13 J, its final kinetic energy  will be 2.50 joules

Hence, we can conclude that the fraction of the neutron's kinetic energy transferred to the atomic nucleus is 2.05

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in the bohr model description, what is the kinetic energy of the electron? express your answer in electron volts.

Answers

An electron in the first Bohr orbit has a kinetic energy of 13.6 eV. A tiny, positively charged nucleus is around by rotating, negatively charged electrons in set orbits, according to the Bohr Atomic Model.

What is Bohr's atomic model?

The Bohr model postulates that the electrons orbit the nucleus at fixed energy levels and also concluded that electron has more energy if it is located away from the nucleus whereas the electrons have less energy if located near the nucleus.

Bohr proposed that electrons do not radiate energy as they orbit nucleus, but exist in state of constant energy that is called stationary states. Bohr's work was based on the emission spectra of hydrogen.

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where tt is measured in days. what is the instantaneous rate of change of the mass of the colony, in grams per day, at the moment the colony reaches a mass of 6 grams?

Answers

The instantaneous Bof change of the mass of the colony is t=2.059277.

The immediate charge of exchange is the exchange inside the rate at a specific immediate, and it's miles identical because of the trade inside the spinoff cost at a specific point. For a graph, the immediate fee of trade at a specific point is similar to the tangent line slope. that is, it's miles a curve slope.

Calculation:-

P(t)=2+5tan−1(t2)

=6P(t)=2+5tan−1(t2)=6.

The solution is t=2.059277.

Because the spinoff P′P′ may be interpreted because of the immediate fee of alternate.PP with respect to time, the calculator is used to numerically calculate the by-product of PP at this fee of tt.

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complete question is -

Where tt is measured in days. what is the instantaneous rate of change of the mass of the colony, in grams per day, at the moment the colony reaches a mass of 6 grams?

Which of the following is the correct order of wavelength?
A
Radio waves
>
UV rays >
X-rays
>
γ
â
rays
B
UV rays >
Radio waves
>
X-rays
>
γ
â
rays
C
γ
â
rays
>
X-rays
>
UV rays >
Radio waves
D
X-rays
>
γ
â
rays
>
UV rays >
Radio waves

Answers

The wavelengths are listed below in ascending order from left to right. Gamma rays, X-rays, UV, visible, infrared, microwaves, and radio waves are all types of radiation.

The electric field and magnetic field combine to form the numerous waves that make up the electromagnetic spectrum. The electromagnetic wave is considered to have both wave and particle behavior.

The wavelength and frequency of electromagnetic waves are essentially determined by the wave's particle-like components, known as photons, which carry the wave's energy. The term "electromagnetic spectrum" refers to the class of electromagnetic waves.

In order of increasing wavelength, electromagnetic waves include gamma rays, x-rays, ultraviolet, visible, infrared, microwaves, and radio waves.

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what if? suppose one of the professors proctored the exam by traveling on spacecraft i and stopped the exam after 88.0 min elapsed on her clock.

Answers

The speed of spacecraft relative  exam after 88.0 min elapsed on her clock is 73.65 min.

What is speed ?

A direction or speed at which an object's position changes.

What is space craft ?

An object that orbits the Earth, the moon, or another celestial body is referred to as a satellite, whereas a spacecraft is a vehicle or technology designed for travel or operation outside the Earth's atmosphere.

Given speed of space craft perpendicular is v₁= 0.68 c

speed of space craft 2 is V₂= 0.24 c

They travel towards each other .

time elapsed in spacecraft 1 is = 54 mins

SO, speed of space craft ⊥ relative to space craft 2 is

v¹= V₁+V₂/1+V₁ V₂/C²

∴ V¹= (0.68+ 0.24) C/ 1+(0.68* 0.24 ) C²/C² = 0.791 C

∴ Time eclipsed in spacecraft 2 is, t¹ = t/[tex]\sqrt{1-v12/c2}[/tex] = 54/sqrt{1- (0.7911)2}[tex]\sqrt{1- 0.791}[/tex]

= 88.25 min

speed of spacecraft relative to earth is = 0.68c

∴time on earth t¹¹= t/[tex]\sqrt{r-v1/l1}[/tex]

= 54/ [tex]\sqrt{1- (0.08) 2}[/tex] = 73.65 min

Therefore, speed of spacecraft relative  exam after 88.0 min elapsed on her clock is 73.65 min.

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in which direction is the puck moving at t = 3 s ? give your answer as an angle from the x-axis.

Answers

The puck is moving at an angle of 51 degrees from the x-axis.

As we can see from the graph of the question the value of x component of velocity  [tex]v_{x}[/tex] is nearly 24 cm/s and the value of y component of velocity [tex]v_{y}[/tex] is constant throughout the journey of puck and is equal to 30cm/s. For any instant of time the direction is given by the slope of the graph tanθ which is equal to the y component divided by the x component.

At the instant when t= 3s

[tex]v_{x}= 24 cm/s\\v_{y}= 30 cm/s\\[/tex]

Direction is given by the slope of the graph  

tanθ= [tex]\frac{v_{y} }{v_{x} } = \frac{30}{24}[/tex]=  1.25

θ= 51 degrees from x-axis (in anti-clockwise manner)

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coherent light with single wavelength falls on two slits separated by 0.710 mm. in the resulting interference pattern on the screen 2.00 m away, adjacent bright fringes are separated by 1.80 mm. what is the wavelength (in nanometers) of the light that falls on the slits? use formula for the small angles of diffraction

Answers

The coherence qualities of various light sources are explored, as well as how they affect the image quality of a holographic display.

Temporal coherence is connected to the intrinsic spectrum bandwidth of the light source, but spatial coherence is determined by light source size and propagation distance. These two coherence properties, as well as the quality of the holographic reconstructed images, are measured for various light sources of diode-pumped solid-state (DPSS) laser, laser diode (LD), light emitting diode (LED), super luminescent light emitting diode (sLED), and micro light emitting diode (mLED) in various settings. Although image sharpness and speckle are both related to coherence parameters, our findings and subsequent research reveal that spatial coherence is directly connected to image sharpness.

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an object weighs 432 n on the surface of earth. at a height of 3rearth above earth's surface, what is its weight?

Answers

On the earth's surface, an object weighs 432N. At a height of 3R above earth's surface, its weight will be 27N

Given the weight on surface of earth (F) = 432N

let radius of earth be R

Height increased (h) = 3R

Weight at certain height of 3R = F2

We know that  the force due to gravity decreases by the square of the radius.

From the formula: g1 = g(R/R+h)^2

g1 = g(R/R+3R)^2 = g(1/4)^2

g1 = g/16

We know that Force(F) = mg

Force at a height of 3R from surface of earth = F2

F2 = mg1 =mg/16 = F/16

Weight at this height = 432/16 = 27N

Hence the weight of object at a height of 3R from surface of earth is 27N

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A circular hoop of mass m, radius r, and infinitesimal thickness rolls without slipping down a ramp inclined at an angle θ with the horizontal.
A. What is the acceleration αα of the center of the hoop?
B. What is the minimum coefficient of (static) friction μminμmin needed for the hoop to roll without slipping?

Answers

1/2tan(tetha) is the minimal coefficient of static friction required for the hoop to roll without slipping, and 1/2g sin(tetha) is the acceleration of the hoop's centre.

In mechanics, acceleration is the rate at which an object's velocity with respect to time changes. The vector quantity of accelerations (in that they have magnitude and direction). The direction of the net force imposed on an object determines its acceleration in relation to that force. In other words, static friction is the force that maintains an object's resting position.

acceleration A = 1/2g sin where an Ihoop = m*r2 ma = mg sin (o) -Fr ma = mgsin(o) -ma (0)

The least possible static friction coefficient

Alpha = r(mug cos) (tetha)

Mu - a/g cos(tetha) = 1/2 (tan(tetha)

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a technician is testing a power seat that operates slower than normal. the dome light noticeably dims while operating the power seat motors. the problem is likely .

Answers

A slower-than-normal power seat is being tested by a technician. When the power seat motors are running, the dome light noticeably dims. Most likely, the seat mechanism's binding is the issue.

Instead of using manual levers, cranks, or knobs to alter the position or recline of the seat, power seats in automobiles use electric motors. They make it simpler for both the driver to select the ideal driving posture and for the passengers to settle into a comfortable position for the ride. A power seat motors doesn't have a predetermined lifespan. The switch will wear down more quickly the more frequently you change your seat. The scenario is identical to that of power door locks or windows. The switch's contacts deteriorate more quickly the more you use it. The price of an aftermarket seat motor can range from $50 to $340. According to a number of factors, including

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Which of the following is not true of a magnetic disk?
A. It is expensive relative to magnetic tape
B. It provides only sequential access to stored data
C. Users can easily update records by writing over the old data
D. It does not provide an automatic audit trail
E. All of the above are true

Answers

The correct answer is B

A and B are both false.

A 600-kg car is moving at 5 m/s then comes to a stop
in 3 seconds. How much average force is necessary?

Answers

The average force acting on the car is 1000 N.

What is force?

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

Given that: A 600-kg car is moving at 5 m/s then comes to a stop in 3 seconds.

Now according to Newton's 2nd law of motion:

Magnitude of force applied on the body = change in momentum/time interval

= I final momentum - initial momentum I/time interval

= I 0 - 600×5 I /3 N

= 10000 N

Hence, average force acting on the car is 1000 N.

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what fraction of a piece of silicon will be submerged when it floats in mercury?

Answers

The fraction of a piece of silicon will be submerged when it floats in mercury is 17%

Density silicon = 2.33 g/cm³,

Density mercury 13.6 g/cm³.

2.33=/13.6 = 0.17 = 17% silicon submerged and 83%  above surface of mercury.

With the symbol Si, silicon is an atomic number 14 chemical element. It is a hard, brittle crystalline solid with a blue-grey metallic sheen that is a tetravalent metalloid and semiconductor. Because silicon is abundant in the Earth's crust, natural goods with silicon as their main component have been used for thousands of years.

The most abundant substance found in the crust of the Earth is silicon dioxide (SiO₂).

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A cart of mass 10 kg is rolling on a level floor at 5 m/s. A 4 kg mass dropped from rest lands in the cart.


what is the momentum of the system before the object drops?


what is the momentum of the system after the object drops?


what is the final speed of the cart and the mass?

Answers

The momentum of the system before the object drops is 50 kg m/s.

The momentum of the system after the object drops is 50 kg m/s.

The final speed of the cart and the mass is 3.57 m/s.

We know that, momentum is the product of mass and velocity of the system.

Mathematically,

P = m* v

where,

m is the mass

v is the velocity

Given that,

Mass of the cart m₁ = 10 kg

Velocity of the cart before the object drops v₁ = 5 m/s

Mass of the object dropped m₂ = 4 kg

Velocity of the cart after the object drops v₂ = ?

According to the principle of conservation of linear momentum,

Total momentum of the system before the object drops = total momentum of the system after the object drops

So, mathematically,

m₁* v₁ = (m₁ + m₂)* v₂

10 * 5 = (10 + 4) v₂

14 v₂ = 50

v₂ = 3.57 m/s

Thus, Final speed of the cart = 3.57 m/s

Final mass of the cart = 10 + 4 = 14 kg

The momentum of the system before the object drops = m₁* v₁ = 10* 5 = 50 kg m/s

The momentum of the system after the object drops = (m₁ + m₂)* v₂ = 14* 3.57 = 49.98 ≈ 50 kg m/s

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an element of atomic number 88 decays radioactively to an element of atomic number 82.
Which of the following emissions achieve this result?
a. one alpha particle and one beta-minus particle
b. three alpha particles
c. one alpha particle
d. six beta-minus particles

Answers

An element of atomic number 88 decays radioactively to an element of atomic number 82 six beta-minus particles.

Isotopes are atoms that share the same atomic number but have various neutron numbers, which change their mass numbers. The standard atomic weight of an element is determined by the average isotopic mass of an isotopic mixture for that element in a specific environment on Earth (referred to as the relative atomic mass; see monoisotopic elements). Less than three-quarters of naturally occurring elements are isotope mixtures (see monoisotopic elements). In the 19th century, chemists were able to measure the amounts of the elements based on their relative atomic weights to hydrogen. Prior to the modern synthesis of concepts from physics and chemistry, an element's numerical position in the periodic table, which at the time was roughly in the following order, was all that the customary symbol Z represented.

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a dog and a mouse run along a road with the same kinetic energy. the faster runner is the

Answers

The faster runner is the mouse.

Kinetic energy is the type of energy carried by any moving object or subatomic particle. Any object or particle in motion possesses kinetic energy. Kinetic energy manifests itself in many everyday phenomena, such as walking, throwing a baseball, dropping a crumb, traveling through an electric field, etc. Only things in motion can store kinetic energy, hence a still object has none.

Potential energy is held by inanimate objects like rocks and plants. A body's potential energy is transformed into kinetic energy whenever a force, such as gravity, acts upon it and sends it into motion. For example, stretching a rubber band stores energy as elastic potential, which is then converted to motion when the band is released from its stretched state.

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