1. Graham is hiking at an altitude of 14,040 feet
and is descending 50 feet each minute. Max is
hiking at an altitude of 12,500 feet and is
ascending 20 feet each minute. How many
minutes will it take Graham and Max to meet at
the same altitude ?
a. Equation:
1
2
. Solution:
2. At what altitude will Graham and Max meet?
3
Answers
Answer: Equation 1 to find the time: A₁ - r₁t = A₂ + r₂t Solve for t
14040 - 50t = 12500 + 20t t is the number of minutes
Equation 2 to find the altitude: A₁ - r₁t = A₂ + r₂t A₁ and r₁ are Grahams initial altitude and rate. Use given rates, calculated time and solve for A.
A₂ and r₂ are Max's initial altitude and rate.
They will meet in 22 minutes
They will meet at 12940 ft altitude
Step-by-step explanation: Their original heights plus/minus the altitude change per minute (rate) and the time will be equal when they meet.
14040 - 50t = 12500 + 20t subtract 12500 from both sides; add 50t to both sides.
14040-12500 = 20t + 50t
1540 = 70x
22 = t They will meet in 22 minutes.
To get the altitude where they meet, Multiply the time by the rate for each climber. Add or subtract per equation: A₁ - r₁t = A₂ + r₂t
14040 - 22(50) = 12500 + 22(20)
Graham: 22 min × 50ft/min = 1100 ft
Subtract from his starting altitude:
14040 - 1100 = 12940 ft
Max: 22 min ×20 ft/min = 440 ft
Add to his starting altitude
12500 + 440 = 12940 ft
Answer:
Answer:
M=22, hope this helps
Step-by-step explanation:
Set up Graham's altitude function A(m):
A(m) = 14040 - 50m <-- we subtract for descending
Set up Max's altitude function A(m):
A(m) = 12500 + 20m <-- we add for ascending
Set the altitudes equal to each other to solve for m:
14040 - 50m = 12500 + 20m
We type this equation into our search engine to solve for m and we get:
m = 22
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Hope this helps! :)
Have a great day!
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Answers
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