1. (An example of non-point-source pollution is
A. Wastewater from a leaking pipe.
B. Fertilizer runoff from lawns.
C. Oil from a leaking underground tank.
D. Chemicals released from a paper mill

Answer:

%KCl = 7.05%

%Water = 92.95%

Explanation:

Step 1: Given data

Step 2: Calculate the mass of the solution

The mass of the solution is equal to the sum of the masses of the solute and the solvent.

m = 36 g + 475 g = 511 g

Step 3: Calculate the mass percentage of the solution

We will use the following expression.

%Component = mComponent/mSolution × 100%

%KCl = 36 g/511 g × 100% = 7.05%

%Water = 475 g/511 g × 100% = 92.95%

Answer:

A. mushroom

Explanation:

Answer:

11.1249387366083

Explanation:

you do -log([H+]

Answer:

Cu⁺² is being reduced in that reaction.

Explanation:

When a substance is reduced, its oxidation number is reduced -changing to a lower value than original-.

Cu⁺² turned into Cu. Meaning that the oxidation number changed from +2 to 0.

Thus, Cu⁺² is being reduced in that reaction.

Answer: electrons

Explanation: An atom consists of a positively charged nucleus, surrounded by one or more negatively charged particles called electrons.

Answer:

bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb

Explanation:

kh uh

Answer:

Partial pressure of Ar = 100.5 KPa

Explanation:

The following data were obtained from the question:

Number of mole of Ne = 1 mole

Number of mole of Ar = 2 moles

Total pressure = 150.0 KPa

Partial pressure of Ar =?

Next, we shall determine the mole fraction of Argon (Ar). This can be obtained as follow:

Number of mole of Ne = 1 mole

Number of mole of Ar = 2 moles

Total mole = 1 + 2 = 3 moles

Mole fraction of Ar = mole of Ar / total mole

Mole fraction of Ar = 2/3

Mole fraction of Ar = 0.67 mole

Finally, we shall determine the partial pressure of argon (Ar). This can be obtained as follow:

Mole fraction of Ar = 0.67 mole

Total pressure = 150.0 KPa

Partial pressure of Ar =?

Partial pressure = mole fraction of gas × total pressure

Partial pressure of Ar = 0.67 × 150

Partial pressure of Ar = 100.5 KPa

Answer:

[tex]\boxed {\boxed {\sf A. \ NaI \ and \ Pb(NO_3)_2}}[/tex]

Explanation:

In a chemical reaction, the reactants are the substances that start the reaction and change into other substances. The results at the end of the reaction are products.

Typically, the reactants are to the left of the arrow, while products are to the right.

We are given this chemical equation:

[tex]2 \ NaI + Pb(NO_3)_2 \rightarrow 2NaNO_3 +PbI_2[/tex]

We are asked to find the reactants. Remember, these go into the reaction and are on the left.

[tex]\bold {2 \ NaI + Pb(NO_3)_2 } \rightarrow 2NaNO_3 +PbI_2[/tex]

Therefore, the reactants are NaI (sodium iodide) and Pb(NO₃)₂ (lead nitrate). Choice A is correct.

The magnitude of surface tension of liquid depends on the attractive forces between the molecules. Arrange the following in increasing order of surface tension:

water, alcohol (C2H5OH) and hexane [CH3(CH2)4CH3)].  

Answer:

Hexane, Methanol, Water

Explanation:

I did the assessment

Answer:

4.2 mol NH3

Explanation:

First, balance your reaction.

N2 + 3H2 --> 2NH3

Multiply 6.3 mol H2 by the mole ratio of 2 mol NH3 for every 3 mol H2 to get moles of NH3 produced.

6.3 mol H2 • (2 mol NH3 / 3 mol H2) = 4.2 mol NH3

Answer:

18.0g of CO₂ are present in 9.16L

Explanation:

To solve this question we must use:

PV = nRT

In order to find the moles of the gas and with its molar mass (44.01g/mol for CO₂) we can find the mass of the gas

Assuming STP conditions:

P = 1atm at STP

V = 9.16L

n are the moles of CO₂

R = 0.082atmL/molK

T = 273.15K

Replacing:

PV / RT = n

1atm*9.16L / 0.082atmL/molK*273.15K = n

0.409 moles = Moles of CO₂

The mass is:

0.409 moles CO₂ * (44.01g / mol) =

Answer:

Topographic maps are used by hikers and backpackers to plan routes, estimate travel times, find water, good campsites, and track their progress on hikes. They're designed to depict the three dimensional shape of the world (mountains, valleys, plains, etc.)

Explanation:

Answer:

Trees

Explanation:

I think sorry if I get it wrong

Answer:

c

Explanation:

Answer:

A. your running speed 1.5 m/s

B. your mass 70 kg

C. your de Broglie wavelength [tex]6.32x10^{-36}[/tex]m

Explanation:

Hello there!

In this case, since the equation for the calculation of the Broglie wavelength is:

[tex]\lambda =\frac{h}{m*v}[/tex]

We can assume a running speed of about 1.5 m/s and a mass of 70 kg, so the resulting Broglie wavelength is:

[tex]\lambda =\frac{6.626x10^{-34}kg\frac{m}{s} }{70kg*1.5\frac{m}{s} }\\\\\lambda =6.32x10^-36m[/tex]

Best regards!

Answer:

35.8g of Cl₂ is the yield

Explanation:

Based on the reaction:

MnO₂ + 4HCl → MnCl₂ + 2H₂O + Cl₂

1 mole of MnO₂ and 4 moles of HCl react producing 1 mole of Cl₂

To solve this question we must find limiting reactant. with limiting reactant we can find the theoretical yield of Cl₂. As the actual yield is the 62.7% we can find actual yield of Cl₂ in grams:

Moles MnO₂ -Molar mass: 86.9368g/mol-:

70.0g * (1mol / 86.9368g) = 0.805 moles

Moles HCl -Molar mass: 36.46g/mol-:

128.0g * (1mol / 36.46g) = 3.51 moles

For a complete reaction of 3.51 moles of HCl are required:

3.51 moles HCl * (1mol MnO₂ / 4mol HCl) = 0.878 moles MnO₂.

As there are just 0.805 moles of MnO₂, MnO₂ is limiting reactant.

1 mole of MnO₂ produce 1 mole of Cl₂. The theoretical moles of Cl₂ produced are 0.805 moles.

As the yield is of 62.7%, the yield of Cl₂ is:

0.805 moles * (62.7 / 100) = 0.505 moles Cl₂. In grams:

0.505 moles Cl₂ * (70.906g / mol) =

Answer:

First and last sentence .‍♀️

Explanation:

An important thing to keep in mind about the Reading Comprehension section of the GRE as we use PowerPrep online to study is that it is just that—reading comprehension. In other words, as difficult as it may seem, and it can be pretty tricky, the test makers will always give us all the information we need in the passage to answer the question.

Answer:

C₆H₁₂O₆ + 6 O₂ = 6 CO₂ + 6 H₂O

2 KO₂ + H₂O = 2 KOH + 1.5 O₂

Explanation:

Let's consider the following unbalanced equation.

C₆H₁₂O₆ + O₂ = CO₂ + H₂O

We will start balancing H atoms (higher atomicity) by multiplying H₂O by 6.

C₆H₁₂O₆ + O₂ = CO₂ + 6 H₂O

Then, we will balance C atoms by multiplying CO₂ by 6.

C₆H₁₂O₆ + O₂ = 6 CO₂ + 6 H₂O

Finally, to get the balanced equation, we will multiply O₂ by 6.

C₆H₁₂O₆ + 6 O₂ = 6 CO₂ + 6 H₂O

---

Let's consider the following unbalanced equation.

KO₂ + H₂O = KOH + O₂

We will multiply KO₂ and KOH by 2 to balance K and H atoms.

2 KO₂ + H₂O = 2 KOH + O₂

Finally, to get the balanced equation, we will multiply O₂ by 1.5.

2 KO₂ + H₂O = 2 KOH + 1.5 O₂

Answer:

In physics, motion means a continuous change in the position of a body relative to a reference point, as measured by a particular observer in a particular frame of reference.

Explanation:

Answer:

Hello your question is incomplete attached below is the complete question

answer : 6,7-dimethyl-3-nonanone ( B )

Explanation:

The product for the following reaction sequence as attached below is

6,7-dimethyl-3-nonanone

The following reaction sequence can be categorized under Carbon Nucleophiles.

Carbon Nucleophiles which can be used to convert  aldehydes and ketones into  carboxylic acids or alkenes.

The product for the given reaction sequence is 6,7-dimethyl-3-nonanone.

IUPAC (International Union of Pure and Applied Chemistry) naming is a systematic method used to name chemical compounds according to a set of rules established by the IUPAC.

The purpose of IUPAC naming is to provide a consistent and unambiguous way to communicate the structure of a compound through its name.

The outcome of the subsequent chain of reactions, which is appended below, is 6,7-dimethyl-3-nonanone

Under the heading of Carbon Nucleophiles, the following reaction chain can be categorised.

Aldehydes and ketones can be transformed into carboxylic acids or alkenes using carbon nucleophiles.

Thus, the answer is 6,7-dimethyl-3-nonanone.

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Your question seems incomplete, the probable complete question is:

Answer:

175.5

Explanation:

Answer: The formula of chromium fluoride is CFr2.

Answer:

Number of different animals

Explanation:

Number of different animals is not an abiotic factor that influences an ecosystem rather it is  a biotic factor.

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.

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Answer:

Explanation:

are where most bits of broken rock are deposited.

This is because oceans are where most bits of broken rock are deposited.

Answer:

Br2+ 2H2O + SO2= 2HBr + H2SO4

Let's Compare the left side of the equation to the right side of the equation.

Left: Br= 2, H= 2, S= 1, O = 1+2

Right: Br=1, H= 1+2, S=1, O= 4

We can see that only S is balanced and not the other 3 elements.

I'll try to make each element balance.

For Br; I'll multiply by 2 on the left to make it equal to the right.

For H; Since the 2 for Br on the right affected also H, that H ( for HBr) Already has a 2, but then it adds with the other H2( for H2SO4) to give a total of 4 H on the right side. But then there's only 2 H on the left. so we multiply that 2 by a 2 ( which is written infront of the H2O to give a total of 4 H on the left side.

For O; Because of the 2 infront of the H2O, it affects the O in H2O..so now we have 2 O plus the 2 O ( in SO2) to give a total of 4 O which is equal to the right side.

Answer:

C. gravity causing a curved path as an object tries to go straight.

Answer:

1. stomach

2. veins

3.both are functions

Explanation:

1. The cardiovascular system consists of the heart, and a closed system of vessels called arteries, veins, and capillaries. (Stomach is not included)

2.The inferior vena cava is the largest vein in the body and carries deoxygenated blood from the lower half of the body into the heart

3. Blood transports oxygen and nutrients to the lungs and tissues, and  brings waste products to the kidneys and liver, which filter and clean the blood.

Hope this helps!

The mass of the rectangular piece of copper is 18,869 g (approx).In conclusion, the mass of a rectangular piece of copper with dimensions 24.4cm x 11.4 cm x 7.9 cm and a density of 8.92 g/cm³ is 18,869 g (approx.).

The given dimensions of the rectangular piece of copper are:Length = 24.4 cmWidth = 11.4 cmHeight = 7.9 cmThe formula to calculate the mass of an object is given by;

Mass = Density x Volume

Here, the density of copper is given as 8.92 g/cm³.

Therefore, the first step is to calculate the volume of the rectangular piece of copper.The formula to calculate the volume of a rectangular object is given by:

Volume = Length x Width x Height

So,Volume = 24.4 cm x 11.4 cm x 7.9 cm= 2115.432 cm³Now we will use the mass formula:

Mass = Density x Volume= 8.92 g/cm³ x 2115.432 cm³= 18,869.27824 g= 18,869 g (approx.)

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Answer:

25 minutes

Explanation:

V = Volume = [tex]90\ \text{m}^3[/tex]

[tex]C_0[/tex] = Radon concentration under steady state = 1.5 Bq/L

k = Radon decay rate = [tex]2.09\times 10^{-6}\ \text{s}^{-1}[/tex]

[tex]Q[/tex] = Venting rate = [tex]0.14\ \text{m}^3/\text{s}[/tex]

[tex]C_f[/tex] = Final concentration of radon = 0.15 Bq/L

Theoretical detention time is given by

[tex]\theta=\dfrac{V}{Q}\\\Rightarrow \theta=\dfrac{90}{0.14}\\\Rightarrow \theta=642.86\ \text{s}[/tex]

We have the relation

[tex]C_f=C_0e^{-(\dfrac{1}{\theta}+k)t}\\\Rightarrow t=\dfrac{\ln\dfrac{C_f}{C_0}}{-(\dfrac{1}{\theta}+k)}\\\Rightarrow t=\dfrac{\ln\dfrac{0.15}{1.5}}{-(\dfrac{1}{642.86}+2.09\times 10^{-6})}\\\Rightarrow t=1478.25\ \text{s}=\dfrac{1478.25}{60}=24.63\approx 25\text{minutes}[/tex]

The time taken to reach the acceptable level of concentration is 25 minutes.