Adam takes a bus on a school field trip. The bus route is split into the five legs listed in the table. Find the average velocity for each leg of the trip. Then arrange the legs of the trip from highest velocity to lowest. Leg Distance (km) Time (min) A 18 9 B 25 15 C 24 8 D 48 12 E 15 7 leg A leg B leg C leg D leg E
Answer:
The answer is:
VA= 33 m/S
VB= 27.8 m/s
VC= 50 m/s
VD=66.7 m/s
VE=35.7 m/s
So, the Legs from the highest velocity to the lower are:
D - C - E - A - B
The explanation:
we are going to use the velocity formula:
Velocity = distance (m) / time (s)
So,
A) when D = 18 Km = 18000 m
and t = 9 min = 9*60 =540 s
So V = 18000m/ 540 S
= 33 m/S
B) when D = 25 Km = 25000 m
and t = 15 min = 15 * 60 = 900 S
So V = 25000m / 900S
= 27.8 m/s
C) when D = 24 Km = 24000 m
and t = 8 min = 8 * 60 = 480 s
So V = 24000m / 480s
= 50 m/s
D) when D = 48 Km = 48000 m
and t = 12 min = 12 * 60 = 720 s
So V = 48000 m / 720s
=66.7 m/s
E) when D = 15 km = 15000m
and t = 7 min = 7 * 60 = 420 s
So V = 15000m / 420s
= 35.7 m/s
a mule pulls a cart of milk 10 meters, with a force of 50 newtons calculate the work done by the mule
Answer:
500 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 50 × 10
We have the final answer as
500 JHope this helps you
A force of 1.50 N acts on a 0.20 kg trolley so as to accelerate it along an air track. The track and force are horizontal and in line. How fast is the trolley going after acceleration from rest through 30 cm, if friction is negligible?
Answer:
Final velocity, V = 2.1213 m/s.
Explanation:
Given the following data;
Force, F = 1.50N
Mass, m = 0.2kg
Displacement, S = 30cm to meters = 30/100 = 0.3m
To find the acceleration;
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is given by the formula;
[tex] F = ma[/tex] .......equation 1
Where;
F represents force.m represents the mass of an object.a represents acceleration.Making acceleration (a) the subject, we have;
[tex]Acceleration (a) = \frac{F}{m}[/tex]
Substituting into the above equation, we have;
[tex]Acceleration, a = \frac{1.5}{0.2}[/tex]
Acceleration, a = 7.5m/s²
Now to find the final velocity, we would use the third equation of motion;
[tex] V^{2} = U^{2} + 2aS [/tex] .....equation 2
Where;
V represents the final velocity measured in meter per seconds. U represents the initial velocity measured in meter per seconds. a represents acceleration measured in meters per seconds square. S represents the displacement measured in meters.Note: Since the trolley is starting from rest, we know that it's initial velocity is 0.
Substituting the values into equation 2, we have;
[tex] V^{2} = 0^{2} + 2*7.5*0.3[/tex]
[tex] V^{2} = 0 + 4.5[/tex]
[tex] V^{2} = 4.5[/tex]
Taking the square root, we have;
[tex] V = \sqrt {4.5}[/tex]
V = 2.1213 m/s.
Therefore, the speed of the trolley after accelerating from rest through 0.3 m, if friction is negligible is 2.1213 m/s.
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Part 2. Problem Solving
Directions: Follow the GUESS Method of solving problem to get full credit for your works
1. A kid throws a rock off the edge of a cliff 60.0 m high. When he drops the rock, it takes 5,0
sec for it to reach the ground below.
a.) Determine the time it takes to reach the ground below, and
b.) How long would it take the rock to hit the ground if he threw it down with a speed of 15
m/sec?
is hit stmight upward and reach a maximum height of 80.0 m.
Answer:
A.) 5s
B.) 2.29s
C.) 39.6 m/s
Explanation:
Given that a kid throws a rock off the edge of a cliff 60.0 m high. When he drops the rock, it takes 5,0sec for it to reach the ground below.
a.) Determine the time it takes to reach the ground below,
The time is 5s
b.) How long would it take the rock to hit the ground if he threw it down with a speed of 15m/sec?
Using the second equation of motion:
H = Ut + 1/2gt^2
Substitute all the parameters into the formula
60 = 15t + 1/2 × 9.8 × t^2
60 = 15t + 4.9t^2
Multiply all by 10
49t^2 + 150t - 600
t^2 + 3.06t = 12.24
( t + 1.53)^2 = 12.24 + 2.3409
t + 1.53 = sqrt ( 14.5809)
t = 3.82 - 1.53
t = 2.29s
is hit stmight upward and reach a maximum height of 80.0 m.
Using the third equation of motion
V^2 = U^2 - 2gH
At maximum height, V = 0
0 = U^2 - 2 × 9.8 × 80
U^2 = 1568
U = sqrt ( 1568)
U = 39.6 m/s
A positively charged atom has? 1. gained protons. 2. gained electrons. 3. lost electrons. 4. lost protons.
Answer:
3. lost electrons.
Explanation:
An atom that has lost an electron is positively charged because the number of protons is now greater than the number of electrons in the atom.
Protons are positively charged particles in an atom. Electrons are negatively charged particles. Neutrons do not carry any charges.If the number of protons and electrons are the same, the atom has no charge
If the protons > electrons, the atom becomes positively charged
If electrons > protons, the atom becomes negatively charged.
Atoms becomes charged by losing or gaining electrons.
You are traveling down the highway when you notice a cop 200 meters ahead of you. For the next 5 seconds, you step on the bake to avoid a speeding ticket. The brake causes an acceleration on your car of -2.0 m/s^2.
Answer:
ok, I don't see the question.
Explanation:
A wave with a frequency of 230 Hz has a wavelength of 0.25 meters. At what speed will this wave travel?
Which condition must be met in order for an equation to be balanced? The elements in the reactants are the same as the elements in the products. There are fewer elements in the reactants than there are in the products. The number of atoms in the reactants is greater than the number of atoms in the products. The number of atoms in the reactants equals the number of atoms in the products
Answer:
The elements in the reactants are the same as the elements in the products
Explanation:
The condition for a balanced equation is as follows :
The number of atoms for each element in reactant = Number of atoms for each element in product.
Total charge on reactant and product must be same.
The example of a balanced equation is:
Reaction of carbon and hydrogen :
[tex]C+2H_2\rightarrow CH_4[/tex]
No. of carbon atom on Carbon on LHS = 1
No. of carbon atom on Hydrogen on LHS = 4
No. of carbon atom on Carbon on RHS = 1
No. of carbon atom on Hydrogen on RHS = 4
So, for a balanced equation, The elements in the reactants are the same as the elements in the products. Hence, the correct option (a).
Answer:
The answer is A
Explanation:
Suppose someone travels 50 mi at 50 mi/h, then travels 50 mi at 25 mi/h, then travels 50 mi at 10 mi/h.
a). My estimate is 18.75 mph.
b). The average speed is 18.75 mph.
I nailed it.
There is more than one answer
Explanation:
the answers are the first 3.
Answer:
4.6
Explanation:
Ans is 4.6 b coz the difference b/w 4.6 and the other values is comparitively the largest.
A motorcycle has a mass of 240 kg and accelerates at a rate of 4 m/s2
Work out the driving force of the motorcycle.
Solution:
Using
F = m a
F = 240 x 4
F = 960 N
Answer:
960N
Explanation:
Given parameters:
Mass of the motorcycle = 240kg
Acceleration of the motorcycle = 4m/s²
Unknown:
Driving force of the motorcycle = ?
Solution:
According to the Newton's second law of motion "the force on a body is the product of mass and acceleration".
Force = mass x acceleration
Insert the parameters and solve;
Force = 240 x 4 = 960N
An ultrasound machine is being used to try to identify potential kidney stones. The machine is working properly and no kidney stones are found. Which statement best describes this situation? The generated sound wave will not be able to reflect off of the object. The sound wave will not be generated, so there will be no echoes received. The echoes will be made but will not be able to be received by the machine. The machine will not be able to process the received echoes into images.
Answer:
The generated sound wave will not be able to reflect off of the object.
Explanation:
The statement that best describes this situation is: The generated sound wave will not be able to reflect off of the object.
What is an Ultrasound Machine?An ultrasound machine is a device that is used to capture images in the human body for review by a medical examiner. The machine gives off sound waves that are reflected off body structures.
So, for the ultrasound machine being described, the absence of kidney stones will cause a non-reflection of the object to be captured.
Since the machine is in good working condition, the sound wave will be generated.
Learn more about ultrasound machines here:
https://brainly.com/question/6837690
A force of 1.50 N acts on a 0.20kg trolley so as to accelerate it along an air track
The track and force are horizontal and in line . How fast is the trolley going after acceleration from rest through 30cm , if friction is negligible
Answer:
2.12m/s
Explanation:
Given parameters:
Force on trolley = 1.5N
Mass of trolley = 0.2kg
Unknown:
Velocity of the trolley = ?
Solution:
To solve this problem, we first find the acceleration of the trolley;
Force = mass x acceleration
Acceleration = [tex]\frac{Force }{mass}[/tex]
Insert the parameters and solve;
Acceleration = [tex]\frac{1.5}{0.2}[/tex] = 7.5m/s²
Now to find the acceleration;
Initial velocity = 0m/s
v² = u² + 2aS
v is the final velocity
u is the initial velocity
a is the acceleration
S is the distance
Distance = 30cm and this is 0.3m
v² = 0² + 2(7.5)0.3 = 4.5
v = √4.5 = 2.12m/s
there are approximately 19 billion chickens in the world. If one third of them like to cross the road, how many chickens have gone to the other side?
Answer:
57,000,000,000(fifty-seven billion)
Explanation:
19000000000/ 1/3 = 57000000000
A shopping cart given an initial velocity of 2.0 m/s undergoes a constant acceleration of 3.0 m/s2. What is the cart’s displacement after the first 4.0 s of its motion?
What is your car's initial velocity?
How long is the cart accelerating for?
What is the acceleration of the cart?
Write the equation you will use to solve this problem.
What is the displacement of the shopping cart?
32 m
10 m
55 m
80 m
Final Velocity = 14m/s
Displacement = 56m
Explanation:
U (initial velocity) = 2m/s
A (acceleration) = 3m/s^2
T (time) = 4s
v (final velocity) = ?
S (displacement) = ?
FIRST FIND FINAL VELOCITY:
[tex]a = \frac{v - u}{t} [/tex]
(i) Multiply both sides by t:
[tex]a \times t = v - u[/tex]
(ii) Add u to both sides:
[tex](a \times t) + u = v[/tex]
(iii) rearrange formula:
[tex]v = (a \times t) + u[/tex]
v = ( 3 × 4 ) + 2
v = 12 + 2
v = 14m/s
SECOND FIND DISPLACEMENT:
[tex]v = \frac{s}{t} [/tex]
(i) Multiply both sides by t:
[tex]v \times t = s[/tex]
(ii) Rearrange formula:
[tex]s = v \times t[/tex]
s = 14 × 4
s = 56m
Not sure why it isn't one of the options but im pretty sure I did all the steps right...
Look at the Kunoichi's of Naruto but as a Gang.
Who do you think looks the baddest out of the group(but in a good way)?
My opinion is Hinata...just saying
Answer:
hinata for sure
Explanation:
seems reasonable
Identify the wavelength of this wave.
Answer:
A
Explanation:
The line(A) goes throughout the entire picture. So therefore choice A would be it's length.
can someone help me???
Answer:
The correct answer is A. 8.0. In 2011, no fertiziler was added to the soil so the pH was not affected.
Gertrude writes a short story in which the main character must enter a nuclear-powered spaceship’s engine room that has lost its shielding in order to prevent the engine from flooding the rest of the ship with radiation. The main character is not wearing protective gear.
What effects are best for Gertrude to consider when planning what may happen to the character?
non-stochastic effects such as possible DNA mutations later in life resulting from the short-term, high-level exposure
non-stochastic effects such as severe burns and radiation sickness resulting from the short-term, high-level exposure
stochastic effects such as possible DNA mutations that are unlikely to occur from the single, low-level exposure
stochastic effects such as severe burns and radiation sickness resulting from the long-term, low-level exposure
Answer: (B) non-stochastic effects such as severe burns and radiation sickness resulting from the short-term, high-level exposure
Explanation: edgeunity
The impact of best for Gertrude to consider when planning what may happen to the character is non-stochastic effects.
What are non-stochastic effects?
It is that impact where incidence and severity based on dose.
Since as per the given situation, Gertrude writes a short story so here the character should be considered as the non-stochastic effects like burning and the radiation sickness that leads from the short term and high level of exposure.
learn more about flood here: https://brainly.com/question/22708021
Which type of star cluster is shown?
Answer:
♡ madeline here ♡
you forgot the attachment, luv ☆
have a great day!
- madeline/madi ✧･ﾟ: *✧･ﾟ:･ﾟ✧*:･ﾟ✧･ﾟ
Explanation:
OPENNNN
I AM CORRECT AND DATS MY NAMEEE OO I BE LIKE 2POC CHAINS:);)
jose has a mass of 70 kg, what is his weight
Parallel circuits:
O A. provide more than one path for current flow.
O B. will have positive charges flowing in one branch, negative charges
in the other.
C. always need more voltage than series circuits.
O D. are rarely used in the wiring in homes.
Answer:
Provide more than one path for current flow. (answer option A)
Explanation:
When one connects resistors in parallel, one provides more than a single path for the current to flow. The current separates on each branch according to the resistance it experiences.
A small child has a wagon with a mass of 10 kilograms. The child pulls on the wagon with a force of 2 Newton’s. What is the acceleration of the wagon?
PHYSICS
Mass = 10 kg
Force = 2 N
Acceleration = ____?
Answers :
[tex]f \: = m \times a[/tex]
2 = 10 × a
2 / 10 = a
0,2 m/s² = a ✅
if something is shot straight up in the air at a speed of 17 m/s, how much time before I it will hit the ground
A skier leaves the horizontal end of a ramp with a velocity of 25.0 m/s and lands 70.0 m from the base of the ramp. How high is the end of the ramp from the ground? m
Answer:
The end of the ramp is 38.416 m high
Explanation:
Horizontal Motion
When an object is thrown horizontally with an initial speed v and from a height h, it follows a curved path ruled by gravity.
The maximum horizontal distance traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
If the maximum horizontal distance is known, we can solve the above equation for h:
[tex]\displaystyle h=\frac {d^2g}{2v^2}[/tex]
The skier initiates the horizontal motion at v=25 m/s and lands at a distance d=70 m from the base of the ramp. The height is now calculated:
[tex]\displaystyle h=\frac {70^2\cdot 9.8}{2\cdot 25^2}[/tex]
[tex]\displaystyle h=\frac {4900\cdot 9.8}{2\cdot 625}[/tex]
h= 38.416 m
The end of the ramp is 38.416 m high
Which formula can be used to find the tangential speed of an orbiting object? v = StartFraction 2 pi r over T EndFraction v = StartFraction square root of 2 pi r over T EndFraction v = GStartFraction m Subscript central Baseline over r EndFraction v = rStartFraction (m Subscript central Baseline) over G EndFraction
Answer:
It's A v=2pi/T
Explanation:
I took the test and got it correct.
The correct formula that can be used to find the tangential speed of an orbiting object is : ( A ) v = 2π r /T
Tangential speedTangential speed is the speed or velocity of an object moving in a circular path is calculated as 2π r/T where T = time it takes to complete one rotation and 2π r is angular velocity( w ).
Therefore from the options listed above the correct expression for the tangential speed is v =2π r /T
Learn more about Tangential speed : https://brainly.com/question/19660334
Aria is riding her bike. She is bent slightly over, holding onto her handlebars. She wants to go faster. Which best explains what she should do? She should bend her hips so her head is closer to the handlebars. She should sit straight up on the bike, keeping her arms tight to her body. She should spread her arms wide while sitting straight in her seat. She should flap her arms up and down like a bird.
Answer:
She should bend her hips so her head is closer to the handlebars
Explanation:
Answer:
Yea its A
Explanation:
What is conflict resolution?
Two lenses with focal lengths 10cm and 20cm and made of same material are placed coaxially
separated by distance d. The value of d such that the system is achromatic is
A) 20 om
) 30cm
C) 10 cm
D) 15 cm
wave length of sodium light is 5893A express in nanometre
Answer:
589.3 nm
Explanation:
The wavelength of a sodium light is 5893 A.
We need to find the wavelength in nm.
[tex]5893\ A=5893\times 10^{-10}\ m[/tex]
Also, [tex]1\ nm=10^{-9}\ m[/tex]
[tex]5893\ A=5893\times 10^{-9}\times 10^{-1}\ m\\\\=5893\times 10^{-1}\ nm\\\\=589.3\ nm[/tex]
So, the wavelength of sodium light is 589.3 nm.