0.12g of compound "Y" dissolves in 10mlof acetone at 25 degree celsuis and 0.85g of the same compound dissolves in 10ml of boiling acetone. what volume of acetone would be required to purify a 5.0g sample of compound?

Answer:

Sound is Produced → Speaker → Wave Display → Microphone → Wave Display → Audience Hears Sound

Explanation:

Here is a more detailed explanation of each step in the sequence chain:

3.01 grams are determined to be the acetylsalicylic acid theoretical yield.

Describe the limiting reagent.

The limiting reagent is a substance that prevents a chemical reaction from occurring completely. When a limiting reagent is used in a chemical reaction, the atoms, molecules, or ions of the other reactant that it (the limiting reagent) reacts with will either stay free or unreacted.

Salicylic acid has a molar mass of 138.12 g/mol. As a result, the quantity of salicylic acid we have is:

n = mass/molar mass i.e. 2.31 g/138.12 g/mol

n = 0.0167 mol

Acetylsalicylic acid has a molar mass of 180.16 g/mol. Theoretically, the production of acetylsalicylic acid is therefore:

mass = n x molar mass

mass = 0.0167 mol x 180.16 g/mol = 3.01 g

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Answer:

a. The frequency or amplitude of the sound waves will not change.

d. The frequency or amplitude of the sound waves could change as the song plays.

g. Sound waves that the audience hears are mechanical waves.

These are the true statements.

others are false.

b. Sound waves that the audience hears are not electromagnetic waves. Sound waves are a type of mechanical wave, which means that they require a medium to travel through, and in this case, the medium is air.

c. Hearing the sound does not change the wave type. The wave type remains a mechanical wave, even after it reaches the audience's ears.

e. and f. are also not true, as the process of hearing sound does not change the wave type from mechanical to electromagnetic or vice versa.

The energy change for the change in state of 1.0 mol H2O (l) at 79∘C to H2O(g) at 114∘C is 42,643 J/mol.

The heat capacity of a thing is the amount of energy needed to raise its temperature by one degree Celsius. The amount of energy needed to increase the temperature of 1 gram of a substance by 1oC is known as a substance's specific heat.

We have to calculate the power needed to warm one mole of liquid water from 79∘C to 100∘C:

q1 = nCΔT

= (1.0 mol)(75.3 J/molK)(100-79 K)

= 1593 J

we have to calculate the energy,

q2 = nΔHvap

= (1.0 mol)(40.7×10^3 J/mol)

= 40,700 J

Now, we have to calculate the energy,

q3 = nCΔT

q3 = (1.0 mol)(25.0 J/molK)(114-100 K)

q3 = 350 J

The total energy change is:

ΔE = q1 + q2 + q3

ΔE = 1593 J + 40,700 J + 350 J

ΔE = 42,643 J/mol

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The moles of the ammonia that is produced is 3.33 moles.

Stoichiometry is an important tool in chemical analysis, and it is used in a wide range of industries, including pharmaceuticals, materials science, and environmental science.

The balanced reaction equation in this case can be given as;

[tex]N_{2} (g)+3H_{2} (g)--- > 2NH_{3} (g)[/tex]

If 3 moles of hydrogen produces 2 moles of ammonia

5 moles of hydrogen will produce 5 * 2/3

= 3.33 moles

Thus we have 3.33 moles of ammonia.

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Methamphetamine is an amphetamine that stimulates the central nervous system (CNS).

Methamphetamine works by facilitating the release of catecholamines from brain nerve terminals, including noradrenaline, dopamine, and serotonin, as well as by inhibiting their uptake. As a result, the concentration of these neurotransmitters in the synaptic cleft rises, stimulating postsynaptic receptors more intensely.

The catalytic reduction of 1-phenyl-2-propanone (P-2-P, benzyl methyl ketone, BMK, or phenylacetone) in the presence of ammonia or methylamine is the fundamental reaction in all processes used to create methamphetamine. The Leuckart method (non-metallic reduction) and catalytic metal reduction are currently the most widely used reduction techniques.

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Answer:

Water is a non polar molecule

Explanation:

Water interacts differently with charged and polar substances than with nonpolar substances because of the polarity of its own molecules. Water molecules are polar, with partial positive charges on the hydrogens, a partial negative charge on the oxygen, and a bent overall structure.

Answer:

139.20856102 this is thee answer

Answer:

139,18

Explanation:

Answer:

If a 0.5 mL air bubble is present in the tip of a burette, the initial reading will be too high by 0.5 mL. If the air bubble is dislodged during the dispensing of the samples, the final reading will be too low by 0.5 mL. This will result in a systematic error in the volume measurements.

To calculate the percent error in the volume measurements, we can use the formula:

% error = (systematic error / true value) x 100

For a 5-mL sample, the true value is 5 mL. If the air bubble is dislodged, the measured volume will be 4.5 mL, resulting in a systematic error of 0.5 mL. Therefore, the percent error is:

% error = (0.5 / 5) x 100 = 10%

For a 20-mL sample, the true value is 20 mL. If the air bubble is dislodged, the measured volume will be 19.5 mL, resulting in a systematic error of 0.5 mL. Therefore, the percent error is:

% error = (0.5 / 20) x 100 = 2.5%

For a 25-mL sample, the true value is 25 mL. If the air bubble is dislodged, the measured volume will be 24.5 mL, resulting in a systematic error of 0.5 mL. Therefore, the percent error is:

% error = (0.5 / 25) x 100 = 2%

So, the percent error in the volume measurements will be higher for smaller samples, and lower for larger samples.

The percent error for a 5 mL sample is 10%, for a 20 mL sample is 2.5%, and for a 25 mL sample is 2%.

The percent error can be calculated using the formula:

Percent Error = ((Actual Value - Experimental Value) / Actual Value)×100%

In this case, the actual value is the volume of the sample (5 mL, 20 mL, or 25 mL) and the experimental value is the volume obtained if the air bubble is dislodged.

The percent error for a 5 mL sample would be:

Percent Error = ((5 mL - 4.5 mL) / 5 mL ) ×100% = 10%

The percent error for a 20 mL sample would be:

Percent Error =( (20 mL - 19.5 mL) / 20 mL) ×100% = 2.5%

The percent error for a 25 mL sample would be:

Percent Error = ((25 mL - 24.5 mL) / 25 mL) × 100% = 2%

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At -79.6 °C, the standard free energy change for this reaction is -67.24 kJ/mol.

Use the following equation to calculate the standard free energy change at a different temperature:

ΔG = ΔH - TΔS

where ΔH = enthalpy change, ΔS = entropy change, and T = temperature in Kelvin.

Given:

ΔH = 53.29 kJ/mol

ΔS = 623.51 J/(mol⋅K)

T = -79.6 + 273.15 K = 193.55 K

First, convert ΔH from kJ/mol to J/mol:

ΔH = 53.29 × 10³ J/mol

Next, convert ΔS from J/(mol⋅K) to kJ/(mol⋅K):

ΔS = 623.51 J/(mol⋅K) ÷ 1000 = 0.62351 kJ/(mol⋅K)

Plug in the values:

ΔG = (53.29 × 10³ J/mol) - (193.55 K × 0.62351 kJ/(mol⋅K))

ΔG = 53.29 kJ/mol - 120.53 kJ/mol

ΔG = -67.24 kJ/mol

Therefore, the standard free energy change for this reaction at -79.6 °C is -67.24 kJ/mol.

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Answer:

c. The waves from the speaker are mechanical waves.

d. The frequency or amplitude of the waves could change.

g. The speaker does not change the wave type.

These statements are true. The waves that come out of the speaker are mechanical waves, meaning they require a medium to travel through, such as air or water. The frequency and amplitude of the waves could change, depending on the characteristics of the sound being played through the speaker. The speaker does not change the type of wave from mechanical to electromagnetic, or vice versa.

Explanation:

Ideal gas law

PV = n R T        If P and V increase then T must increase

   ( n  and R   are constant)

Answer:

4 NH3(0) + 3 O2(g) → 2 N2(g) + 6H20() ... How many grams of water would be formed from 96.0 g NH3 in a reaction represented by the balanced equation below.

Missing: 6 ‎H₂O( ‎l)​

Explanation:

Sodium dichromate is the empirical formula for the chemical.

An allotrope of carbon with the chemical formula carbon 6, benzotriyne or cyclo[6]carbon is a hypothetical molecule. Six carbon atoms form the molecule's ring, which is joined by alternating triple and single bonds.

We must identify the compound's simplest whole-number atom ratio in order to obtain the empirical formula. To begin, we can convert the masses of each element to moles as follows:

moles of sodium = 29.84 g / 22.99 g/mol = 1.299 mol

moles of creatinine = 67.49 g / 52.00 g/mol = 1.298 mol

moles of oxygen = 72.67 g / 16.00 g/mol = 4.542 mol

sodium.creatinine.oxygen = 1.299 mol / 1.298 mol : 1.298 mol / 1.298 mol : 4.542 mol / 1.298 mol

sodium.creatinine.oxygen = 1.001 : 1.001 : 3.500

sodium.creatinine.oxygen = 1001 : 1001 : 3500

sodium.creatinine.oxygen = 1001/GCF : 1001/GCF : 3500/GCF

sodium.creatinine.oxygen = 143 : 143 : 500.

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Answer:  C1V1=C2V2

Explanation: i hope this help im want to help you please

leave 5

A sealed container holds 12.0 L of gas at 2.5 atm pressure. A valve is opened and some gas escapes. The pressure decreases. Option C is correct.

When a valve is opened in a sealed container of gas, some of the gas molecules inside the container escape.

This means that the total number of gas molecules inside the container decreases, which in turn causes the pressure to decrease. This can be explained by the ideal gas law.

If some gas escapes from the sealed container, the number of gas molecules inside the container decreases.

As a result, the pressure inside the container decreases as well.

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The answer is 14.8 grams, which is option (d).

Therefore keep in mind that we are using molecular masses here. Therefore, 58 0.5 g of sodium chloride and one more will be obtained. Divide the mass of Sodium chloride by its molar mass to determine the number of moles: 0.941 moles are equal to 55 g/58.44 g/mol. 55 g of Sodium chloride is therefore equal to 0.941 moles of Sodium chloride.

A unit of mass is a gramme. One kilogramme weighs one thousandth of a gramme. The weight of a cube of pure water that is one centimetre in size and four degrees Celsius was the original definition of a gramme. The gramme has the sign g.

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Question:

How many grams are in 1.48 x10⁷μg?

1.48 x103³

1.48 x10¹³

1.48

14.8

none of the above

Answer:

The balanced chemical equation for the combustion of C2H4 (ethylene) is:

C2H4 + 3 O2 → 2 CO2 + 2 H2O

From the balanced chemical equation, we can see that 1 mole of C2H4 reacts to produce 2 moles of H2O.

First, we need to convert the given mass of C2H4 to moles using its molar mass. The molar mass of C2H4 is:

2(12.01 g/mol) + 4(1.01 g/mol) = 28.05 g/mol

Now, we can calculate the moles of C2H4:

moles of C2H4 = mass of C2H4 / molar mass of C2H4

moles of C2H4 = 16 g / 28.05 g/mol

moles of C2H4 ≈ 0.570 mol (rounded to three decimal places)

According to the balanced chemical equation, 1 mole of C2H4 produces 2 moles of H2O.

moles of H2O = 2 * moles of C2H4

moles of H2O = 2 * 0.570 mol

moles of H2O ≈ 1.140 mol (rounded to three decimal places)

Finally, we can convert the moles of H2O to grams using the molar mass of water (H2O), which is 18.015 g/mol.

mass of H2O = moles of H2O * molar mass of H2O

mass of H2O = 1.140 mol * 18.015 g/mol

mass of H2O ≈ 20.53 g (rounded to two decimal places)

So, approximately 20.53 grams of H2O will be produced by the combustion of 16 grams of C2H4.

The solution has a molarity of 0.0924 M.

The number of moles of solute per litre of solution is known as molarity.. For instance, water is both the solution and the solute when table salt is dissolved in it. Each mole of sodium chloride weighs 58.44 grammes. 58.44 grammes of sodium chloride are dissolved in one litre of water to produce one molar solution, or 1M.

Moles of solute per litre of solution is known as molarity (M).

Given: moles of NH3 = 0.355, volume of solution = 3.84 L

Molarity = 0.355 moles / 3.84 L = 0.0924 M

Therefore, the molarity of the solution is 0.0924 M.

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A: begin to cool and daylight hours decrease.

Plants go through seasonal changes from summer to fall because of the changes in temperature and the length of daylight hours. As summer ends and fall begins, temperatures begin to cool down and the days become shorter. This change in temperature and daylight hours triggers physiological changes in plants, such as the slowing down of growth and the production of pigments like anthocyanins, which give leaves their characteristic red and orange colors in the fall. These changes allow the plant to prepare for the colder winter months and conserve energy for the upcoming spring growth season.

Answer:

a. begin to cool and daylight hours decrease

hope this helps ;)

The sky appears blue to us because of a phenomenon known as Rayleigh scattering.

Sunlight is made up of many different colors, each with a different wavelength. When sunlight enters Earth's atmosphere, the shorter blue wavelengths are scattered more easily than the longer red wavelengths. This is because the blue light interacts more with the molecules in the air, causing it to be redirected in many different directions.

As a result, when we look up at the sky, we see the blue light being scattered in all directions, giving the sky its blue color. At sunrise and sunset, when the sun is closer to the horizon, the light has to pass through more of the atmosphere, causing more of the blue light to be scattered away and leaving behind the longer red wavelengths, which gives the sky a reddish or orange hue.

For a student wishing to contribute to the preservation of coral reefs, oceanography would be the most beneficial topic of study because it is ocean-focused.

An underwater environment known as a coral reef is characterized by corals that construct reefs. Coral polyp colonies are bound together by calcium carbonate to build reefs. Stony corals, whose polyps gather together, make up the majority of coral reefs.

Coral reefs offer chances for recreation, serve as a barrier against erosion and storm damage, and support local economies. They are also a source of fresh medications and food. More than 500 million people rely on reefs for safety, income, and food.

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When 216.59 g of HgO completely reacts, 16.00 g of O2 will be produced.

The oxygen produced

The balanced chemical equation for the reaction:

2HgO(s) → 2Hg(l) + O2(g)

states that 2 moles of HgO will produce 1 mole of O2.

We can use the molar mass of HgO and the mole ratio of HgO to O2 to calculate the mass of O2 produced from a given mass of HgO.

The molar mass of HgO is 216.59 g/mol (200.59 g/mol for Hg + 16.00 g/mol for O).

So, 1 mole of HgO has a mass of 216.59 g.

According to the balanced equation, 2 moles of HgO produce 1 mole of O2.

Therefore, 1 mole of O2 has a mass of 32.00 g.

Using stoichiometry, we can calculate the mass of O2 produced when a certain mass of HgO reacts completely.

For example, if we start with 216.59 g of HgO (1 mole), then the amount of O2 produced will be 0.5 moles (1 mole of O2 for every 2 moles of HgO), which is equivalent to 16.00 g of O2 (0.5 moles of O2 x 32.00 g/mol).

So, when 216.59 g of HgO completely reacts, 16.00 g of O2 will be produced.

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31.5 g of Sulfuric acid can be produced from the given amounts of Sulfur trioxide and Water.

Option 'c' is the right response to this question because sulphur trioxide cannot be directly dissolved in water to create sulphuric acid because doing so produces a thick fog of the acid that is difficult to condense.

Sulfur trioxide + Water → Sulfuric acid

moles of Sulfur trioxide = mass/molar mass = 25.7 g / 80.06 g/mol = 0.321 mol

moles of Water = volume x density/molar mass = 12.7 mL x 1.00 g/mL / 18.02 g/mol = 0.705 mol

The amount of Sulfuric acid that can be produced is equal to the number of moles of Sulfur trioxide, which is 0.321 mol. To convert this to grams, we multiply by the molar mass of Sulfuric acid:

mass of Sulfuric acid = moles of Sulfuric acid x molar mass = 0.321 mol x 98.08 g/mol = 31.5 g

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Mangrove trees' robust roots aid in stabilizing the soil and preventing soil erosion. This is especially crucial in swampy coastal locations, where the soil is frequently loose and prone to wind and wave erosion. Mangrove trees work to stabilize the coastline and stop land erosion by securing the soil in place.

Mangrove trees also aid in removing contaminants from the water, enhancing the quality of the water in coastal areas while serving as an essential home for a variety of wildlife species. Mangrove trees contribute significantly to environmental protection and are an essential component of coastal ecosystems.

Mangrove trees are crucial for environmental preservation because they hold the soil in place and stop erosion in marshy coastal areas. They also provide crucial habitats for numerous wildlife species, stabilize the coastline, and stop the land from being lost to erosion while enhancing water quality by filtering pollutants from the ocean.

Mangrove trees are an essential part of coastal ecosystems overall, and preserving them is essential for preserving a healthy and sustainable environment.

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The step during which the student handling pure substance is : B.) Step 4 only.

In step 4, student added 5 grams of glucose to 50 mL of water, which is a pure substance. Glucose is a compound with the chemical formula C₆H₁₂O₆, and it is a pure substance because it consists of only one type of molecule.

In steps 1, 2, and 5, student was handling water, glucose, and iron filings respectively, but these are not pure substances in those steps because they are mixed with other substances or impurities.

In steps 6 and 7, the student added iron filings to beaker and stirred the mixture, but iron filings are not pure substance either because they may contain impurities or other metals in addition to iron.

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Amount of Cuo formed when 63.5g of copper is heated strongly in air is
A:The mass of CuO formed when 63.5g of Copper is heated strongly in air is 79.5g

1.How do we determine the mass of Cuo formed ?

For that we have to write the balenced equation of the reaction and it is given below

2Cu + O2 -----> 2CuO

We have to determine mass of Cuo formed from the reaction

Molar mass of Cu = 63.55 g/mol

Mass of Cu from balenced equation = 2*63.55 = 127.1 g

Molar mass of CuO = 79.55 g/mol

Mass of Cuo from balenced equation = 2*79.55 = 159.1g

From balenced equation 127.1g of Cu reacted to form 159.1 g of CuO

Thus ,63.5 g of Cu will react to form = (63.5*159.1)/127.1 = 79.5 g

Mass of CuO formed is 79.5 g

2.How do you find the mass of a compound produced ?

Multiply atomic weight from periodic table of each element by the number of atoms of that element present in the compound . Add it all together and put units of grams/mole after the number

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(a) (i) NH3: Translational, rotational, and vibrational modes of motion.

(ii) CO2: Translational and vibrational mode of motion.

(iii) CH4: Translational, rotational, and vibrational modes of motion.

This simply refers to the oscillatory movement of a physical system around its equilibrium position. This phenomenon is characterized by a complex interplay of forces and energy transfer mechanisms, which can lead to a wide range of intriguing dynamical behaviors.

The part b of the first question, the reaction given is incomplete, and the products are missing. Please provide the complete balanced chemical equation for the reaction so that the enthalpy change can be calculated.

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The magnetic quantum number (ml) represents the orientation of the orbital in three-dimensional space the only possible value of the magnetic quantum number ml for a 1s electron is 0.

Quantum is the smallest possible unit of a physical quantity, such as energy or momentum. It is a fundamental concept in quantum mechanics, which is the branch of physics that deals with the behavior of matter and energy at the atomic and subatomic level.

The idea of quantization was first proposed by Max Planck in 1900, when he discovered that energy is emitted and absorbed in discrete units called "quanta" when studying the behavior of light and blackbody radiation. Later, this idea was extended to other physical quantities, such as the momentum and position of particles.

According to quantum mechanics, the behavior of particles and systems cannot be fully described using classical mechanics, which assumes that particles have definite positions and velocities at all times. Instead, the behavior of particles and systems is described using wave functions, which represent the probability of finding a particle at a given position and time.

The principles of quantum mechanics have important applications in many areas of physics, including atomic and molecular physics, condensed matter physics, and particle physics. They are also the basis.

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Answer:

c. The frequency or amplitude of the sound waves will change if the singer varies their voice.

d. The produced sound waves are mechanical waves.

f. Producing the sound does not change the wave type.

g. The frequency or amplitude of the sound waves will not change

These statements are true. Sound waves are mechanical waves, meaning they require a medium to travel through, such as air or water. Producing sound involves creating vibrations in the medium, which then propagate as sound waves. The frequency and amplitude of the sound waves will change depending on the characteristics of the source producing the sound. However, producing sound does not change the type of wave from mechanical to electromagnetic, or vice versa